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401.

If A = 16 ∠64°, (A) is

Answer»
402.

In figure the total inductance of the circuit is

Answer» Inductances are in series aiding connection. M terms will become twice because of mutual inductance between L1 and L2 and that between L2 and L1.
403.

For a high pass filter attenuation = 0 at = 0.

Answer» Attenuation is infinite at f = 0 for high pass filter.
404.

In the network of figure, the voltage drops across R, R, R are 6 V, 8 V and 12 V with polarities as shown. The value of R is

Answer» From the given data the current through R1 is 4 A.
405.

Double integration of unit step function leads to

Answer» Integral of unit step function is ramp and integral of ramp is doublet.
406.

A conductor has a cylindrical shape with a diameter . Its resistance is 2 Ω. It is recast into a cylindrical conductor of diameter 0.3. The resistance of new conductor is likely to be

Answer» Since new diameter is 0.3 d, the new area of cross-section a (0.3 d)2. The volume remains the same. Therefore length increase by a factor . Hence .
407.

For an RLC series circuit, Z() will be of the form of

Answer» which is similar to
408.

In the circuit shown in the figure, steady-state was reached when the switch S was open. The switch was closed at = 0. The initial value of the current through the capacitor 2 C is

Answer» At steady state capacitor will be open and inductor will short circuited. V across 2C will be = 12v .
409.

As temperature increases, the temperature coefficient of a metal

Answer» It at is temperature coefficient at t°C and a0 is temperature coefficient at 0°C. .
410.

A wire has a resistance R ohm. If another wire of the same material and same weight has double the diameter (as compared to the first wire), the resistance of the second wire will be

Answer» Since diameter is double, area of cross-section is four times and length is one-fourth. .
411.

In the circuit of figure the current through 5 Ω resistance at = 0 is

Answer» Since 3 ohm resistance is short-circuited by capacitor, I = 20/5 A.
412.

In active filters inductances are divided because they

Answer» Active filters consist of electronic components and have very small size.
413.

Three resistance of 15 Ω each are connected in delta. The resistance of equivalent star will have a value of

Answer»
414.

The circuit in figure(1) is replaced by that in figure(2). It remains same R will be

Answer» Net resistance of circuit is 4.571 R and that of circuit is 0.571 R. Hence R0 be 4R.
415.

In a varistor the - graph is linear.

Answer» The v-i graph, in varistor, is non-linear.
416.

The resistance R in the circuit is

Answer» (6 + 6/5) || (18 + 18/5) = 5.4 5.4 + 3.6 9 Ω.
417.

In the circuit of figure the current through L at = ∞ is

Answer» At t = ∞ inductance behaves as short-circuit.
418.

In using KCL it is necessary that current leaving a node is written as negative.

Answer» It may be written as positive or negative as per convenience.
419.

A resistor is rated at 0.75 watt, 1 kΩ. Its current rating is

Answer» 0.75 = I2 x 1 x 1000 or I = 27.386 mA.
420.

A series R-L circuit has R = 1 Ω and L = 1 H. It is excited by a V battery at = 0. The steady state condition is reached at

Answer» i = 10 (1 - e-t). It reaches steadily state value at t = ∞
421.

The current source in figure, can be replaced by

Answer» The parallel combination of 20 Ω and 5 Ω is 4 Ω. Therefore, strength of current source is 4 x 4 = 16 A and source resistance is 4 ohms.
422.

A parallel plate capacitor with air as dielectric has a capacitance C. If the dielectric has a dielectric constant ∈ and the remaining dimensions are the same, the capacitance will be

Answer» Capacitance ∝ ∈r.
423.

A bulb rated at 60 W, 120 V is used for 30 minutes. The charge associated with this operation is

Answer»
424.

In the circuit shown in the figure, the current supplied by the sinusoidal current source I is

Answer» I = (12)2 + (16)2 = 20 A.
425.

The frame of an electric motor is earthed through three earthing plates resistances 30 Ω, 20 Ω and 10 Ω respectively. During fault the energy dissipated by three plates are W, W and W. Then

Answer» Energy dissipated by the plate with lowest resistance is maximum.
426.

If figure, power dissipated in 30Ω resistance will be maximum when value of R =

Answer» When R = 0, circuit current = and power dissipated = watts, which is the maximum possible value.
427.

Two voltages are 50 ∠0 V and 75 ∠ - 60° V. The sum of these voltages is

Answer» 50Ð0 = 50 + j 0.75∠-60° = 37.5 - j 64.95 Sum = (50 + 37.5) - j 64.95 = 87.5 - j 64.95 = 109∠-36.6°
428.

Two coil have their axis perpendicular to each other. The coefficient of coupling is

Answer» When axis are perpendicular then there is no mutual coupling.
429.

In a series RLC circuit, p-f is leading if X < X.

Answer» If XC < XL power factor is lagging.
430.

If the voltage across the last resistor is V, and all the resistor is unity. Then V is given by

Answer» Let the last voltage is V1 = V, V2 = Voltage across both 1 &ohm; resistor V + V = 2V Current in shunt resistor = i ia = ib + ic 2v + v 3v V3 = ib x R + ia x R 3v + 2v = 5v V4 = 5v + 8v = 13v.
431.

In figure, at = 0 is

Answer» Inductance behaves as O.C. at t = 0+.
432.

In a purely inductive circuit, the current __________ the voltage by __________ .

Answer» In inductive circuit current lags the voltage by 90°.
433.

One commercial unit of energy is equal to

Answer» Consumers are charged on the basis of kWh of energy used.
434.

In figure which is correct at any time

Answer» As per KCL sum of currents entering a node is equal to sum of currents leaving the node.
435.

Two coupled coils with self inductances of 4 mH and 16 mH are connected in series. The maximum possible value of inductance can be

Answer» Inductance = 4 + 16 + 24 x 16 = 36 mH.
436.

Elements R, L, C are connected in parallel and excited by a dc current I. If , and are the currents through R, L, C respectively then at = 0

Answer» Capacitor behaves as a short-circuit at t = 0.
437.

In a practical voltage source, the terminal voltage

Answer» A practical voltage source has some source resistance. Because of voltage drop across source resistance, terminal voltage cannot be higher than source voltage. If current is zero, terminal voltage and source voltage are equal.
438.

When slider of the potentiometer AB is in the position shown in figure, what resistance reading would be indicated by an ohmmeter connected between A and C?

Answer» A to C will act as short circuit, hence R = 0 if it open then R = ∞.
439.

The three sides of an admittance triangle denote

Answer» Admittance triangle depicts admittance Y and its components G and B.
440.

A step voltage E is applied to an R-L series circuit. At = 0, the current in the circuit is

Answer» Inductance does not allow the current to increase instantaneously.
441.

In figure, the magnitude of V

Answer» V depends on magnitudes and phase angles of Va and Vb.
442.

To find current in a resistance connected in a network, Thevenin's theorem is used V = 20 V and R = 5 &ohm;. The current through the resistance

Answer»
443.

A step voltage E is applied to a series R-L circuit. The rate of change of current is maximum at =

Answer»
444.

The energy stored in a coil is 108 J. It is opened suddenly in 10 ms. The power dissipated instantaneously across the blades of switch is

Answer»
445.

Thermistor has a positive temperature coefficient.

Answer» Temperature coefficient of thermistor is negative.
446.

The switch in figure is initially closed. At = 0 the switch is opened. At = 0, the current through R is

Answer» At t = 0+ capacitor behaves as short-circuit.
447.

A network has 10 nodes and 17 branches. The number of different node pair are

Answer» One node is reference node. Therefore the system has 9 node pairs.
448.

In a series RC circuit Z = (R + ωC).

Answer»
449.

If V = 20 + j20, then log(A) A is

Answer» 20 x j 20 = 28.28 Ð45° loge V = loge (28.28) + = 3.342 j.785.
450.

In an ac network the sum of currents entering a node is 10 ∠45°. The sum of currents leaving the node is

Answer» As per KCL sum of currents entering a node is equal to sum of currents leaving a node.