InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Gabriel phthalimide synthesis can be used for the preparation of amine fromA. `CH_(3)CH_(2)Br`B. `(CH_(3))_(3)CBr`C. `p-CH_(3)OC_(6)H_(4)Br`D. `p-CH_(3)C_(6)H_(4)Br` |
|
Answer» Correct Answer - A By the use of Gabriel phthalimide synthesis, `1^(@)` alkyl halides can be converted into corresponding `1^(@)` amines. |
|
| 2. |
The end product of the reaction, Ethyl amine `overset(HNO_(2))rarr(A)overset(PCl_(5))rarr(B)overset(KCN)rarr(C )` `(C)` is,A. PropanenitrileB. TrethylamineC. diethylamineD. propylamine |
| Answer» Correct Answer - 1 | |
| 3. |
Hydrolysis of phenyl isocyanide formsA. benzoic acidB. formic acidC. acetanilideD. acetic acid |
|
Answer» `Ph-overset(+)(N)-=overset(-)(C ):underset(H_(2)O)overset(H^(+))rarr[Ph-NH-overset(O)overset(||)(C )-H]overset(H^(+)//H_(2)O)rarrPh-NH_(2)+HCOOH` NOTE Isocyanides are hydrolysed only by acids, and not by alkalies. It is because negative charge present on the carbon atom in isocyanides initially electrophile. `(i.e H^(+))` `R-overset(+)(N)-=overset(-)(C):+H^(+)rarrR-N-=CHunderset(H^(+))overset(H_(2)O)rarr` `R-N=overset(H)overset(|)(C )-OHoverset("Tautomerises")rarrunderset(R-NH_(2)+HCOOH)underset(darrH^(+)//H_(2)O)(R-NH-overset(O)overset(||)(C)-H)` |
|
| 4. |
Tertiary nitro compounds do not tautomerise becauseA. there is no double bondB. there is no `alpha-hydrogenC. oxygen is more electronegative than HD. All of the above |
|
Answer» Correct Answer - B Tertiary nitro compounds do not tautomerise, since there is no `alpha`-hydrogen. |
|
| 5. |
Which statement is incorrect.A. Fluoro benzene can be synthesized in the laboratory from aniline by diazotisation followed by heating with `HBF_(4)`B. Quarternary Ammonium hydroxides having `beta -` hydrogen atom give hlfmann elimination on pyrolysis.C. on reaction with `HNO_(2)` produces D. Benzyl amine on reaction with `NaNO_(2)//HCl` followed by `beta-` Naphthol in slight basic medium forms a coloured dyo. |
|
Answer» Correct Answer - 4 Only aromatic primary amine shows coupling reaction. |
|
| 6. |
Which of the following on reaction with nitrous acid followed by treatment with NaOH produces a blood red colouration?A. `R CH_(2)NO_(2)`B. `R_(3)CNO_(2)`C. `R_(2)CHNO_(2)`D. `PhNO_(2)` |
|
Answer» `R-underset(NO_(2))underset(|)(C)H_(2)+HNO_(2)rarrR-underset("Nitrolic acid")underset(NO_(2))underset(|)(C )=N-OH` Nitrolic acid dissolve in NaOH to give blood red colouration. `R-underset(NO_(2))underset(|)overset(R )overset(|)(C )-R+HNO_(2)rarr"No reaction"` `R-underset(NO_(2))underset(|)overset(R) overset(|)(C)-H+HO-N=Orarrunderset("give blue colouration")underset("Does not dissolve in NaOH but")underset(("Pseudonitrole"))(R-underset(NO_(2))underset(|)overset(R )overset(|)(C )-N)=O+H_(2)O` |
|
| 7. |
Identify the correct statement.A. B. C. A is more basic than BD. |
|
Answer» Correct Answer - 3 Lone pair of `e^(-)` of `N_(B)` is in conjugation. Whereas lone pair electron of `N_(A)` is localized. |
|
| 8. |
Which of the following compounds does not liberate nitrogen with `HNO_(2)`?A. CarbamideB. Primary amineC. Secondary amineD. Alkanamide |
|
Answer» Correct Answer - C `R_(2)NH+HNO_(2)rarrunderset("N-nitroso compound")(R_(2)N. NO+H_(2)O)` |
|
| 9. |
The IUPAC name of the compound, `underset(OH)underset(|)(CH_(2))-underset(NH_(2))underset(|)(CH)-COOH`A. 2-amino-3-hydroxy propanoic acidB. 1-hydroxy-2-aminopropan-3-oic acidC. 1-amino-2-hydroxypropanoic acidD. 3-hydroxy-2-amino propanoic acid |
|
Answer» `underset(OH)underset(|)(C)H_(2)-underset(NH_(2))underset(|)(CH)-COOH` 2-amino-3-hydroxy propanoic acid |
|
| 10. |
Benzylamine may be alkylated as shown in the following equation `C_(6)H_(5)CH_(2)NH_(2)+R-XrarrC_(6)H_(5)CH_(2)NHR` Which of the following alkyl halides is best suited for this reaction through `S_(N)` 1 mechanism?A. `CH_(3)Br`B. `C_(6)H_(5)Br`C. `C_(6)H_(5)CH_(2)Br`D. `C_(2)H_(5)Br` |
| Answer» The species `C_(6)H_(5)Coverset(+)(H_(2))` (benzyl carbocation), therefore, `C_(6)H_(5)CH_(2)Br` is best suited for `S_(N)` 1 reaction. | |
| 11. |
Which nitrogen atom is most basic ? A. 3B. 4C. 5D. 2 |
|
Answer» Correct Answer - 1 Nitrogen 3 is more basic because electron release by nitrogen 4 and 5 to nitrogen 3 |
|
| 12. |
The Cimetidine has serveral nitrogen atom in its structure. Identify the most basic atom of given cimetidine derivative. A. IB. IIC. IIID. V |
|
Answer» Correct Answer - 4 Conjugate acid at `N(V)` is resonance stablised `[` Guanadine type.`]` |
|
| 13. |
The correct increasing order of basic strength for the following compounds is :A. `II lt III lt I`B. `III lt I lt II`C. `III lt II lt I`D. `II lt I lt III` |
|
Answer» Correct Answer - D Electron releasing (`+` l-effect) groups increase the basicity of amines while electron attracting (-l-effect) groups decrease the basicity of amines. Hence, the order is `II lt I lt III` |
|
| 14. |
Amino group, `-NH_(2)` is ortho, para-directing group in case of aromatic electrophilic substitution but nitration of aniline produce a good amount of m-nitroaniline. This is becauseA. `-NH_(2)` gets converted into - `NH^(-)NO_(2)^(+)` which is m-directingB. `NH_(2)` gets converted into `overset(+)(N)H_(3)` which is m-directingC. `-NH_(2)` gets converted into `-NH^(+)SO_(4)^(-)` which is m-directingD. ortho, para activity of `-NH_(2)` group is completely destroyed during nitration |
|
Answer» Correct Answer - B Protonation of `-NH_(2)` leads to the formation of `overset(+)(N)H_(3)` which is m-directing group. |
|
| 15. |
Compound `(x)(m.f=C_(7)H_(8)N)`, on reaction with `NaNO_(2)` and conc. `HCl` at `O^(@)C` followed by `beta -` naphthol gives orange coloured dye. Compound `(x)` is `:`A. B. C. D. All of these |
| Answer» Correct Answer - B | |
| 16. |
Identify `A,C_(6)H_(11)N`, for which the given information is availabel . `(i)"Baeyer reagent - No test "(ii)Ph-SO_(2)Clrarr "acidic compound soluble in "KOH` `(ii)" Dissolves in aq. HCl "(iv)"Optically active"`A. B. C. D. |
|
Answer» Correct Answer - 4 Only `(4)` gives the above characteristic tests. |
|
| 17. |
The positive carbylamine test is not given byA. anilinieB. `2,4-` dimethyl anilineC. `N-` methyl `-O-` methylineD. `p-` methyl benzylamine |
|
Answer» Correct Answer - C Only `1,2,4` has primary amine group. |
|
| 18. |
The primary, secondary and tertiary amines can be best distinguished byA. mustard oil reactionB. carbylamine reactionC. exhaustive alkylationD. `HNO_(2)` treatment |
|
Answer» Correct Answer - D Primary, secondary and tertiary amines on reaction with `HNO_(2)` produces different products. |
|
| 19. |
Arrange following Amines for rate of reaction with `CHCl_(3)+KOH` ? A. `SgtPgtRgtQ`B. `QgtRgtPgtS`C. `SgtPgtQgtR`D. `SgtQgtRgtP` |
|
Answer» Correct Answer - 1 `K_(p)` of amines `prop` Rate of reaction. |
|
| 20. |
What will be the major product when `2-`Aminopropane is treated with nitrous acid ?A. `1-` PropanolB. `2-` PropanolC. PropeneD. Cyclopropane |
|
Answer» Correct Answer - 2 `CH_(3)-underset(underset(NH_(2))|)(C)H-CH_(3)+HNO_(2)rarr CH_(2)-underset(underset(OH)|)(C)H-CH_(3)` |
|
| 21. |
In the diazotisation of anline with sodium nitrite and hydrochloride acid, an excess of hydrochloric acid is used primarily toA. Suppress the concentration of free aniline for couplingB. Suppress hydrolysis of phenolC. Ensure a stoichiometric amount of nitrous acidD. Neutralize the base liberated |
|
Answer» Correct Answer - 1 It is fact |
|
| 22. |
Which of the following product `(s)` will be obtained when isopropylamine is treated with sodium nitrite and hydrochloric acid ?A. `CH_(3)-underset(underset(OH)|)(C)H-CH_(3)`B. `CH_(2)-CH=CH_(2)`C. `CH_(3)-overset(overset(Cl)|)(C)H-CH_(2)`D. All of these |
|
Answer» Correct Answer - 4 `CH_(3)-underset(underset(NH_(2))|)(C)H-CH_(3)+NaNO_(2)+HClrarrCH_(3)-underset(underset(OH)|)(C)H-CH_(3)+CH_(2)=CH-CH_(3)+CH_(3)-overset(overset(Cl)|)(C)H-CH_(3)` |
|