59 + Interview Questions in Number System And Codes in Digital Circuits Page 1 InterviewSolution

1.	The decimal equivalent of the excess-3 number 110010100011.01110101 is _____________(a) 970.42(b) 1253.75(c) 861.75(d) 1132.87This question was addressed to me during an interview.I need to ask this question from Binary Coded Decimal(BCD) topic in division Number System and Codes of Digital Circuits
Answer» Correct answer is (a) 970.42 Explanation: The conversion of binary numbers into digits ‘1100’, ‘1010’, ‘0011’, ‘0111’ and ‘0101’ GIVES ’12’, ‘5’, ‘3’, ‘7’ and ‘5’ respectively. Hence, the DECIMAL number is 970.42.

Discussion

2.	The excess-3 code for 597 is given by __________(a) 100011001010(b) 100010100111(c) 010110010111(d) 010110101101I had been asked this question by my college director while I was bunking the class.My question is taken from Binary Coded Decimal(BCD) topic in portion Number System and Codes of Digital Circuits
Answer» Correct option is (a) 100011001010 To EXPLAIN: The addition of ‘3’ to each digit yields the three NEW DIGITS ‘8’, ’12’ and ’10’. Hence, the corresponding four-bit binary equivalents are 100011001010, in accordance to 8421 format.

Discussion

3.	How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?(a) 12(b) 14(c) 16(d) 18I had been asked this question in an interview.My question is taken from Binary Coded Decimal(BCD) topic in chapter Number System and Codes of Digital Circuits
Answer» Correct CHOICE is (b) 14 Easiest explanation: Total number of decimals to be REPRESENTED = 10000 = 10^4 = 2^n (where n is the number of bits REQUIRED) = 2^13.29. Therefore, the number of bits required for straight binary encoding = 14.

Discussion

4.	Code is a symbolic representation of __________ information.(a) Continuous(b) Discrete(c) Analog(d) Both continuous and discreteThis question was addressed to me during a job interview.I'd like to ask this question from Binary Coded Decimal(BCD) topic in chapter Number System and Codes of Digital Circuits
Answer» The CORRECT choice is (b) DISCRETE To explain I would say: Code is a symbolic representation of discrete information, which MAY be present in the form of numbers, letters or physical quantities. Mostly, it is REPRESENTED using a PARTICULAR number system like decimal or binary and such like.

Discussion

5.	When numbers, letters or words are represented by a special group of symbols, this process is called __________(a) Decoding(b) Encoding(c) Digitizing(d) InvertingThis question was addressed to me in homework.I'd like to ask this question from Binary Coded Decimal(BCD) topic in portion Number System and Codes of Digital Circuits
Answer» The CORRECT choice is (b) Encoding The explanation: When numbers, LETTERS or words are REPRESENTED by a SPECIAL group of symbols, this PROCESS is called encoding. Encoding in the sense of fetching the codes or words in a computer. It is done to secure the transmission of information.

Discussion

6.	A three digit decimal number requires ________ for representation in the conventional BCD format.(a) 3 bits(b) 6 bits(c) 12 bits(d) 24 bitsThis question was addressed to me during an interview for a job.This intriguing question originated from Binary Coded Decimal(BCD) in division Number System and Codes of Digital Circuits
Answer» Correct answer is (c) 12 bits For EXPLANATION: The number of bits needed to REPRESENT a given decimal number is always greater than the number of bits REQUIRED for a straight binary encoding of the same. Hence, a THREE digit decimal number REQUIRES 12 bits for representation in BCD format.

Discussion

7.	Carry out BCD subtraction for (68) – (61) using 10’s complement method.(a) 00000111(b) 01110000(c) 100000111(d) 011111000This question was addressed to me during an online exam.This interesting question is from Binary Coded Decimal(BCD) in division Number System and Codes of Digital Circuits
Answer» Right option is (a) 00000111 Easiest EXPLANATION: FIRST the TWO numbers are converted into their respective BCD form using 8421 SEQUENCE. Then binary subtraction is carried out.

Discussion

8.	The decimal number 10 is represented in its BCD form as __________(a) 10100000(b) 01010111(c) 00010000(d) 00101011I had been asked this question in an interview for internship.My enquiry is from Binary Coded Decimal(BCD) in chapter Number System and Codes of Digital Circuits
Answer» The correct CHOICE is (C) 00010000 The best I can explain: The decimal NUMBER 10 is represented in its BCD form as 0001 0000, in accordance to 8421 for each of the two digits.

Discussion

9.	Add the two BCD numbers: 1001 + 0100 = ?(a) 10101111(b) 01010000(c) 00010011(d) 00101011The question was posed to me in final exam.My doubt stems from Binary Coded Decimal(BCD) in chapter Number System and Codes of Digital Circuits
Answer» Correct CHOICE is (c) 00010011 The BEST I can explain: Firstly, ADD the 1001 and 0100. We GET 1101 as OUTPUT but it’s not in BCD form. So, we add 0110 (i.e. 6) with 1101. As a result we get 10011 and it’s BCD form is 0001 0011.

Discussion

10.	Binary coded decimal is a combination of __________(a) Two binary digits(b) Three binary digits(c) Four binary digits(d) Five binary digitsThe question was posed to me during an interview.This is a very interesting question from Binary Coded Decimal(BCD) topic in division Number System and Codes of Digital Circuits
Answer» RIGHT option is (C) Four BINARY digits Explanation: Binary coded decimal is a combination of 4 binary digits. For example-8421.

Discussion

11.	For arithmetic operations only _________(a) 1’s complement is used(b) 2’s complement(c) 10’s complement(d) 9’s complementThe question was asked in semester exam.Query is from 1’s, 2’s, 9’s & 10’s Complements in division Number System and Codes of Digital Circuits
Answer» The CORRECT option is (B) 2’s COMPLEMENT Explanation: Only 2’s complement is USED for arithmetic operations, as it is more fast.

Discussion

12.	Which one is used for logical manipulations?(a) 2’s complement(b) 9’s complement(c) 1’s complement(d) 10’s complementThis question was posed to me in examination.Enquiry is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» CORRECT answer is (c) 1’s COMPLEMENT Easy explanation: For LOGICAL manipulations, 1’s complement is used, as all logical OPERATIONS take PLACE with binary numbers.

Discussion

13.	The addition of +19 and +43 results as _________ in 2’s complement system.(a) 11001010(b) 101011010(c) 00101010(d) 0111110This question was addressed to me in final exam.I'm obligated to ask this question of 1’s, 2’s, 9’s & 10’s Complements in division Number System and Codes of Digital Circuits
Answer» Correct answer is (d) 0111110 Easy EXPLANATION: The decimal NUMBERS are converted to their respective binary equivalent and then the binary addition RULES are APPLIED.

Discussion

14.	The 1’s complements requires _________(a) One operation(b) Two operations(c) Three operations(d) Combined OperationsThis question was posed to me in final exam.This key question is from 1’s, 2’s, 9’s & 10’s Complements in chapter Number System and Codes of Digital Circuits
Answer» Right CHOICE is (a) One OPERATION To explain: Only one operation is REQUIRED for 1’s complement operation. This INCLUDES only INVERSION of 1’s to 0’s and 0’s to 1’s.

Discussion

15.	1’s complement can be easily obtained by using _________(a) Comparator(b) Inverter(c) Adder(d) SubtractorI got this question in an interview for internship.My enquiry is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» Right option is (B) Inverter The BEST EXPLANATION: With the help of inverter the 1’s complement is easily OBTAINED. Since, during the operation of 1’s complement 1 is converted into 0 and vice-versa and this is well suited for the inverter.

Discussion

16.	The advantage of 2’s complement system is that _________(a) Only one arithmetic operation is required(b) Two arithmetic operations are required(c) No arithmetic operations are required(d) Different Arithmetic operations are requiredThis question was posed to me in an online quiz.My question is taken from 1’s, 2’s, 9’s & 10’s Complements in section Number System and Codes of Digital Circuits
Answer» Right ANSWER is (a) Only one arithmetic operation is required To ELABORATE: The ADVANTAGE of 2’s complement is that only one arithmetic operation is required for 2’s complement’s operation and that is only addition. Just by adding a 1 bit to 1’s complement, we get 2’s complement.

Discussion

17.	Logic circuitry is used to detect _________(a) Underflow(b) MSD(c) Overflow(d) LSDThis question was posed to me during an interview.This intriguing question comes from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» Right option is (c) OVERFLOW To explain: To check the overflow logic CIRCUITRY is used in each case. Overflow occurs when the processor cannot handle the result properly when it produces an out of the range OUTPUT.

Discussion

18.	An overflow occurs in _________(a) MSD position(b) LSD position(c) Middle position(d) Signed BitI have been asked this question in an interview for internship.I would like to ask this question from 1’s, 2’s, 9’s & 10’s Complements topic in portion Number System and Codes of Digital Circuits
Answer» Right option is (a) MSD position For explanation I WOULD SAY: An overflow OCCURS at the Most Significant Digit position. It occurs when the processor cannot handle the result properly when it produces an out of the range OUTPUT.

Discussion

19.	An overflow is a _________(a) Hardware problem(b) Software problem(c) User input problem(d) Input Output ErrorThe question was asked in homework.My question comes from 1’s, 2’s, 9’s & 10’s Complements topic in division Number System and Codes of Digital Circuits
Answer» RIGHT option is (B) Software problem For explanation: An overflow is a software problem which occurs when the PROCESSOR cannot handle the result properly when it PRODUCES an out of the range output.

Discussion

20.	If the number of bits in the sum exceeds the number of bits in each added numbers, it results in _________(a) Successor(b) Overflow(c) Underflow(d) PredecessorThis question was posed to me in examination.The question is from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits
Answer» The CORRECT ANSWER is (b) Overflow The best I can explain: If the number of bits in the sum exceeds the number of bits in each ADDED numbers, it results in overflow and is also known as excess-one. In case of any arithmetic operation, if the result has less number of bits than the operands, then it is known as UNDERFLOW condition.

Discussion

21.	On addition of -33 and -40 using 2’s complement, we get ____________(a) 1001110(b) -110101(c) 0110001(d) -1001001I had been asked this question during an interview for a job.This interesting question is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» Correct answer is (d) -1001001 Best explanation: The BCD form is WRITTEN of the two given numbers, in their SIGNED form. After which, normal BINARY addition is performed. Augend is -40AND SUBTRAHEND is -33.

Discussion

22.	On subtracting +28 from +29 using 2’s complement, we get ____________(a) 11111010(b) 111111001(c) 100001(d) 1I had been asked this question in an interview.My question is from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits
Answer» Right choice is (d) 1 To explain I would say: Steps For SUBTRACTION USING 2’s complement are: -> 2’s complement of the subtrahend is determined and added to the minuend. -> If the result has a carry, then it is dropped and the result is positive. -> Else, if there is no carry, then 2’s complement of the result is FOUND out and a ‘-’ sign preceeds the result.

Discussion

23.	On addition of -46 and +28 using 2’s complement, we get ____________(a) -10010(b) -00101(c) 01011(d) 0100101I had been asked this question in an online quiz.This interesting question is from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits
Answer» Correct answer is (a) -10010 Explanation: The BCD form is written of the TWO GIVEN numbers, in their signed form. After which, normal binary addition is performed. Augend is 28 and Subtrahend is -46.

Discussion

24.	On addition of +38 and -20 using 2’s complement, we get ____________(a) 11110001(b) 100001110(c) 010010(d) 110101011The question was asked in examination.This intriguing question comes from 1’s, 2’s, 9’s & 10’s Complements in division Number System and Codes of Digital Circuits
Answer» The CORRECT option is (C) 010010 Explanation: Steps for Binary Addition Using 2’s complement: -> The 2’s complement of the ADDEND is found out and added to the FIRST number. -> The result is the 2’s complement of the SUM obtained.

Discussion

25.	On subtracting (001100)2 from (101001)2 using 2’s complement, we get ____________(a) 1101100(b) 011101(c) 11010101(d) 11010111I got this question in semester exam.This question is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» Right answer is (B) 011101 Explanation: Steps For SUBTRACTION using 2’s complement are: -> 2’s complement of the SUBTRAHEND is determined and added to the minuend. -> If the result has a carry, then it is dropped and the result is positive. -> Else, if there is no carry, then 2’s complement of the result is found out and a ‘-’ SIGN preceeds the result.

Discussion

26.	On addition of 28 and 18 using 2’s complement, we get ____________(a) 00101110(b) 0101110(c) 00101111(d) 1001111This question was addressed to me during an online interview.This intriguing question comes from 1’s, 2’s, 9’s & 10’s Complements topic in division Number System and Codes of Digital Circuits
Answer» Correct choice is (b) 0101110 Easiest explanation: STEPS for Binary Addition Using 2’s complement: -> The binary EQUIVALENT of the two numbers are OBTAINED and ADDED using the rules of binary addition.

Discussion

27.	On subtracting (010110)2 from (1011001)2 using 2’s complement, we get ____________(a) 0111001(b) 1100101(c) 0110110(d) 1000011I had been asked this question by my college professor while I was bunking the class.I want to ask this question from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits
Answer» Correct choice is (d) 1000011 For explanation: Steps For Subtraction using 2’s complement are: -> 2’s complement of the SUBTRAHEND is determined and ADDED to the minuend. -> If the result has a CARRY, then it is dropped and the result is positive. ->Else, if there is no carry, then 2’s complement of the result is found out and a ‘-’ sign preceeds the result.

Discussion

28.	On subtracting (01010)2 from (11110)2 using 1’s complement, we get ____________(a) 01001(b) 11010(c) 10101(d) 10100I have been asked this question in examination.Question is taken from 1’s, 2’s, 9’s & 10’s Complements in section Number System and Codes of Digital Circuits
Answer» Right option is (d) 10100 For explanation: STEPS For Subtraction using 1’s complement are: -> 1’s complement of the subtrahend is determined and added to the minuend. -> If the result has a CARRY, then it is dropped and 1 is added to the last bit of the result. -> Else, if there is no carry, then 1’s complement of the result is FOUND out and a ‘-’ sign preceeds the result.

Discussion

29.	2’s complement of 11001011 is ____________(a) 01010111(b) 11010100(c) 00110101(d) 11100010I got this question during an interview.My doubt is from 1’s, 2’s, 9’s & 10’s Complements in section Number System and Codes of Digital Circuits
Answer» CORRECT choice is (c) 00110101 Explanation: 2’s COMPLEMENT of a binary NUMBER is OBTAINED by finding the 1’s complement of the number and then adding 1 to it. 2’s complement of 11001011= 00110100 + 1 = 00110101.

Discussion

30.	1’s complement of 1011101 is ____________(a) 0101110(b) 1001101(c) 0100010(d) 1100101I got this question during an online exam.This key question is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits
Answer» The CORRECT answer is (c) 0100010 The EXPLANATION: 1’s COMPLEMENT of a binary NUMBER is obtained by reversing the binary BITS. All the 1’s to 0’s and 0’s to 1’s. Thus, 1’s complement of 1011101 = 0100010.

Discussion

31.	Binary subtraction of 101101 – 001011 = ?(a) 100010(b) 010110(c) 110101(d) 101100This question was addressed to me in an international level competition.This intriguing question originated from Arithmetic Operation in division Number System and Codes of Digital Circuits
Answer» Right ANSWER is (a) 100010 Best EXPLANATION: The rules for BINARY subtraction are: 0 – 0 = 0 0 – 1 = 1 ( BORROW 1) 1 – 0 = 1 1 – 1 = 0

Discussion

32.	Divide the binary numbers: 111101 ÷ 1001 and find the remainder.(a) 0010(b) 1010(c) 1100(d) 0111This question was posed to me in an interview.The above asked question is from Arithmetic Operation in portion Number System and Codes of Digital Circuits
Answer» The CORRECT answer is (d) 0111 To explain: BINARY Division is accomplished using LONG division METHOD.

Discussion

33.	On multiplication of (10.10) and (01.01), we get ____________(a) 101.0010(b) 0010.101(c) 011.0010(d) 110.0011I had been asked this question in an online interview.I need to ask this question from Arithmetic Operation topic in section Number System and Codes of Digital Circuits
Answer» RIGHT choice is (C) 011.0010 Easy EXPLANATION: The rules for binary multiplication are: 0 * 0 = 0 0 * 1 = 0 1 * 0 = 0 1 * 1 = 1

Discussion

34.	100101 × 0110 = ?(a) 1011001111(b) 0100110011(c) 101111110(d) 0110100101This question was addressed to me in a national level competition.I'd like to ask this question from Arithmetic Operation topic in chapter Number System and Codes of Digital Circuits
Answer» Correct ANSWER is (c) 101111110 Easiest explanation: The rules for binary MULTIPLICATION are: 0 * 0 = 0 0 * 1 = 0 1 * 0 = 0 1 * 1 = 1

Discussion

35.	Perform multiplication of the binary numbers: 01001 × 01011 = ?(a) 001100011(b) 110011100(c) 010100110(d) 101010111The question was asked during an interview.The origin of the question is Arithmetic Operation in portion Number System and Codes of Digital Circuits
Answer» The correct OPTION is (a) 001100011 Easiest EXPLANATION: The rules for binary MULTIPLICATION are: 0 * 0 = 0 0 * 1 = 0 1 * 0 = 0 1 * 1 = 1

Discussion

36.	Perform binary subtraction: 101111 – 010101 = ?(a) 100100(b) 010101(c) 011010(d) 011001I have been asked this question in unit test.My query is from Arithmetic Operation in chapter Number System and Codes of Digital Circuits
Answer» CORRECT choice is (c) 011010 The explanation: The rules for Binary Subtraction are : 0 – 0 = 0 0 – 1 = 1 ( BORROW 1) 1 – 0 = 1 1 – 1 = 0

Discussion

37.	Perform binary addition: 101101 + 011011 = ?(a) 011010(b) 1010100(c) 101110(d) 1001000This question was posed to me during an online exam.Asked question is from Arithmetic Operation topic in section Number System and Codes of Digital Circuits
Answer» Right option is (d) 1001000 The EXPLANATION is: The rules for Binary Addition are : 0 + 0 = 0 0 + 1 = 1 1 + 0 = 1 1 + 1 = 0 ( CARRY 1)

Discussion

38.	Binary subtraction of 100101 – 011110 is?(a) 000111(b) 111000(c) 010101(d) 101010I got this question in an interview for job.I want to ask this question from Arithmetic Operation in chapter Number System and Codes of Digital Circuits
Answer» Right OPTION is (a) 000111 Best EXPLANATION: The rules for Binary SUBTRACTION are : 0 – 0 = 0 0 – 1 = 1 ( BORROW 1) 1 – 0 = 1 1 – 1 = 0

Discussion

39.	What is the addition of the binary numbers 11011011010 and 010100101?(a) 0111001000(b) 1100110110(c) 11101111111(d) 10011010011I have been asked this question in an interview for internship.The origin of the question is Arithmetic Operation topic in chapter Number System and Codes of Digital Circuits
Answer» Correct OPTION is (c) 11101111111 The best I can EXPLAIN: The rules for BINARY Addition are : 0 + 0 = 0 0 + 1 = 1 1 + 0 = 1 1 + 1 = 0 ( CARRY 1)

Discussion

40.	Convert binary to octal: (110110001010)2 =?(a) (5512)8(b) (6612)8(c) (4532)8(d) (6745)8This question was addressed to me during an interview for a job.I'd like to ask this question from Number System in chapter Number System and Codes of Digital Circuits
Answer» CORRECT option is (b) (6612)8 For explanation: The binary equivalent is segregated into groups of 3 bits, starting from left. And then for each GROUP, the respective digit is written. THUS, the octal equivalent is obtained. (110110001010)2 = (6612)8.

Discussion

41.	Octal to binary conversion: (24)8 =?(a) (111101)2(b) (010100)2(c) (111100)2(d) (101010)2I have been asked this question in exam.My doubt is from Number System in chapter Number System and Codes of Digital Circuits
Answer» Right OPTION is (B) (010100)2 The explanation is: Each digit of the OCTAL NUMBER is expressed in terms of group of 3 bits. Thus, the binary equivalent of the octal number is obtained. (24)8 = (010100)2.

Discussion

42.	Convert the binary number (01011.1011)2 into decimal.(a) (11.6875)10(b) (11.5874)10(c) (10.9876)10(d) (10.7893)10I got this question in class test.Enquiry is from Number System in portion Number System and Codes of Digital Circuits
Answer» Right choice is (a) (11.6875)10 The best I can explain: BINARY to Decimal conversion is obtained by MULTIPLYING 2 to the power of base INDEX along with the VALUE at that index POSITION. (01011)2 = 0 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 1 * 2^0 = 11 (1011)2 = 1 * 2^-1 + 0 * 2^-2 + 1 * 2^-3 + 1 * 2^-4 = 0.6875 So,(01011.1011)2 = (11.6875)10.

Discussion

43.	Convert (0.345)10 into an octal number.(a) (0.16050)8(b) (0.26050)8(c) (0.19450)8(d) (0.24040)8This question was posed to me during an interview.Origin of the question is Number System topic in chapter Number System and Codes of Digital Circuits
Answer» The correct choice is (B) (0.26050)8 For explanation: Converting decimal fraction into OCTAL number is ACHIEVED by multiplying the fraction part by 8 everytime and COLLECTING the integer part of the result, UNLESS the result is 1. 0.3458 = 2.762 0.7608 = 6.086 00.088 = 0.640 0.6408 = 5.125 0.120*8 = 0.960 So, (0.345)10 = (0.26050)8.

Discussion

44.	(170)10 is equivalent to ____________(a) (FD)16(b) (DF)16(c) (AA)16(d) (AF)16The question was posed to me in a job interview.The origin of the question is Number System in chapter Number System and Codes of Digital Circuits
Answer» CORRECT option is (c) (AA)16 Easy explanation: Hexadecimal equivalent of decimal number is OBTAINED by dividing the number by 16 and collecting the remainders in reverse order. 16 \| 170 16 \| 10 – 10 Hence, (170)10 = (AA)16.

Discussion

45.	Convert (214)8 into decimal.(a) (140)10(b) (141)10(c) (142)10(d) (130)10This question was posed to me in a job interview.I'd like to ask this question from Number System topic in portion Number System and Codes of Digital Circuits
Answer» The CORRECT choice is (a) (140)10 To explain I WOULD say: Octal to Decimal conversion is obtained by multiplying 8 to the power of base index along with the value at that index position. (214)8 = 2 * 8v + 1 * 8^1 + 4 * 8^0 = 128 + 8 + 4 = (140)10.

Discussion

46.	The octal equivalent of the decimal number (417)10 is _____(a) (641)8(b) (619)8(c) (640)8(d) (598)8This question was addressed to me by my school teacher while I was bunking the class.This intriguing question comes from Number System topic in section Number System and Codes of Digital Circuits
Answer» Correct OPTION is (a) (641)8 Explanation: Octal equivalent of decimal NUMBER is obtained by dividing the number by 8 and collecting the remainders in reverse order. 8 \| 417 8 \| 52 — 1 8 \| 6 – 4 So, (417)10 = (641)8.

Discussion

47.	Convert the hexadecimal number (1E2)16 to decimal.(a) 480(b) 483(c) 482(d) 484I had been asked this question during an interview for a job.This interesting question is from Number System topic in section Number System and Codes of Digital Circuits
Answer» Correct choice is (C) 482 Easy explanation: HEXADECIMAL to Decimal conversion is obtained by multiplying 16 to the power of base index along with the value at that index position. (1E2)16 = 1 * 16^2 + 14 * 16^1 + 2 * 16^0 (Since, E = 14) = 256 + 224 + 2 = (482)10.

Discussion

48.	The given hexadecimal number (1E.53)16 is equivalent to ____________(a) (35.684)8(b) (36.246)8(c) (34.340)8(d) (35.599)8I had been asked this question in my homework.Question is taken from Number System in section Number System and Codes of Digital Circuits
Answer» The correct option is (b) (36.246)8 To ELABORATE: First, the hexadecimal number is converted to it’s equivalent binary form, by writing the binary equivalent of each digit in form of 4 bits. Then, the binary equivalent bits are GROUPED in terms of 3 bits and then for each of the 3-bits, the respective digit is written. Thus, the octal equivalent is obtained. (1E.53)16 = (0001 1110.0101 0011)2 = (00011110.01010011)2 = (011110.010100110)2 = (011 110.010 100 110)2 = (36.246)8.

Discussion

49.	The octal number (651.124)8 is equivalent to ______(a) (1A9.2A)16(b) (1B0.10)16(c) (1A8.A3)16(d) (1B0.B0)16The question was posed to me in an international level competition.I'd like to ask this question from Number System topic in portion Number System and Codes of Digital Circuits
Answer» Right choice is (a) (1A9.2A)16 The best I can explain: First, the OCTAL number is converted to it’s equivalent binary form, by WRITING the binary equivalent of each DIGIT in form of 3 bits. Then, the binary equivalent bits are grouped in terms of 4 bits and then for each of the 4-bits, the respective digit is written. Thus, the HEXADECIMAL equivalent is obtained. (651.124)8 = (110 101 001.001 010 100)2 = (110101001.001010100)2 = (0001 1010 1001.0010 1010)2 = (1A9.2A)16.

Discussion

50.	The quantity of double word is ________(a) 16 bits(b) 32 bits(c) 4 bits(d) 8 bitsThe question was posed to me in homework.My enquiry is from Number System in division Number System and Codes of Digital Circuits
Answer» The correct choice is (B) 32 bits For explanation I would say: ONE word means 16 bits, Thus, the quantity of double word is 32 bits.

Discussion

Explore topic-wise InterviewSolutions in .

How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?(a) 12(b) 14(c) 16(d) 18I had been asked this question in an interview.My question is taken from Binary Coded Decimal(BCD) topic in chapter Number System and Codes of Digital Circuits

Carry out BCD subtraction for (68) – (61) using 10’s complement method.(a) 00000111(b) 01110000(c) 100000111(d) 011111000This question was addressed to me during an online exam.This interesting question is from Binary Coded Decimal(BCD) in division Number System and Codes of Digital Circuits

The decimal number 10 is represented in its BCD form as __________(a) 10100000(b) 01010111(c) 00010000(d) 00101011I had been asked this question in an interview for internship.My enquiry is from Binary Coded Decimal(BCD) in chapter Number System and Codes of Digital Circuits

Add the two BCD numbers: 1001 + 0100 = ?(a) 10101111(b) 01010000(c) 00010011(d) 00101011The question was posed to me in final exam.My doubt stems from Binary Coded Decimal(BCD) in chapter Number System and Codes of Digital Circuits

For arithmetic operations only _________(a) 1’s complement is used(b) 2’s complement(c) 10’s complement(d) 9’s complementThe question was asked in semester exam.Query is from 1’s, 2’s, 9’s & 10’s Complements in division Number System and Codes of Digital Circuits

Which one is used for logical manipulations?(a) 2’s complement(b) 9’s complement(c) 1’s complement(d) 10’s complementThis question was posed to me in examination.Enquiry is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits

The 1’s complements requires _________(a) One operation(b) Two operations(c) Three operations(d) Combined OperationsThis question was posed to me in final exam.This key question is from 1’s, 2’s, 9’s & 10’s Complements in chapter Number System and Codes of Digital Circuits

1’s complement can be easily obtained by using _________(a) Comparator(b) Inverter(c) Adder(d) SubtractorI got this question in an interview for internship.My enquiry is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits

Logic circuitry is used to detect _________(a) Underflow(b) MSD(c) Overflow(d) LSDThis question was posed to me during an interview.This intriguing question comes from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits

An overflow occurs in _________(a) MSD position(b) LSD position(c) Middle position(d) Signed BitI have been asked this question in an interview for internship.I would like to ask this question from 1’s, 2’s, 9’s & 10’s Complements topic in portion Number System and Codes of Digital Circuits

An overflow is a _________(a) Hardware problem(b) Software problem(c) User input problem(d) Input Output ErrorThe question was asked in homework.My question comes from 1’s, 2’s, 9’s & 10’s Complements topic in division Number System and Codes of Digital Circuits

On subtracting +28 from +29 using 2’s complement, we get ____________(a) 11111010(b) 111111001(c) 100001(d) 1I had been asked this question in an interview.My question is from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits

On addition of -46 and +28 using 2’s complement, we get ____________(a) -10010(b) -00101(c) 01011(d) 0100101I had been asked this question in an online quiz.This interesting question is from 1’s, 2’s, 9’s & 10’s Complements in portion Number System and Codes of Digital Circuits

On addition of +38 and -20 using 2’s complement, we get ____________(a) 11110001(b) 100001110(c) 010010(d) 110101011The question was asked in examination.This intriguing question comes from 1’s, 2’s, 9’s & 10’s Complements in division Number System and Codes of Digital Circuits

On subtracting (001100)2 from (101001)2 using 2’s complement, we get ____________(a) 1101100(b) 011101(c) 11010101(d) 11010111I got this question in semester exam.This question is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits

On subtracting (01010)2 from (11110)2 using 1’s complement, we get ____________(a) 01001(b) 11010(c) 10101(d) 10100I have been asked this question in examination.Question is taken from 1’s, 2’s, 9’s & 10’s Complements in section Number System and Codes of Digital Circuits

2’s complement of 11001011 is ____________(a) 01010111(b) 11010100(c) 00110101(d) 11100010I got this question during an interview.My doubt is from 1’s, 2’s, 9’s & 10’s Complements in section Number System and Codes of Digital Circuits

1’s complement of 1011101 is ____________(a) 0101110(b) 1001101(c) 0100010(d) 1100101I got this question during an online exam.This key question is from 1’s, 2’s, 9’s & 10’s Complements topic in chapter Number System and Codes of Digital Circuits

Binary subtraction of 101101 – 001011 = ?(a) 100010(b) 010110(c) 110101(d) 101100This question was addressed to me in an international level competition.This intriguing question originated from Arithmetic Operation in division Number System and Codes of Digital Circuits

Divide the binary numbers: 111101 ÷ 1001 and find the remainder.(a) 0010(b) 1010(c) 1100(d) 0111This question was posed to me in an interview.The above asked question is from Arithmetic Operation in portion Number System and Codes of Digital Circuits

On multiplication of (10.10) and (01.01), we get ____________(a) 101.0010(b) 0010.101(c) 011.0010(d) 110.0011I had been asked this question in an online interview.I need to ask this question from Arithmetic Operation topic in section Number System and Codes of Digital Circuits

100101 × 0110 = ?(a) 1011001111(b) 0100110011(c) 101111110(d) 0110100101This question was addressed to me in a national level competition.I'd like to ask this question from Arithmetic Operation topic in chapter Number System and Codes of Digital Circuits

Perform multiplication of the binary numbers: 01001 × 01011 = ?(a) 001100011(b) 110011100(c) 010100110(d) 101010111The question was asked during an interview.The origin of the question is Arithmetic Operation in portion Number System and Codes of Digital Circuits

Perform binary subtraction: 101111 – 010101 = ?(a) 100100(b) 010101(c) 011010(d) 011001I have been asked this question in unit test.My query is from Arithmetic Operation in chapter Number System and Codes of Digital Circuits

Perform binary addition: 101101 + 011011 = ?(a) 011010(b) 1010100(c) 101110(d) 1001000This question was posed to me during an online exam.Asked question is from Arithmetic Operation topic in section Number System and Codes of Digital Circuits

Binary subtraction of 100101 – 011110 is?(a) 000111(b) 111000(c) 010101(d) 101010I got this question in an interview for job.I want to ask this question from Arithmetic Operation in chapter Number System and Codes of Digital Circuits

Convert binary to octal: (110110001010)2 =?(a) (5512)8(b) (6612)8(c) (4532)8(d) (6745)8This question was addressed to me during an interview for a job.I'd like to ask this question from Number System in chapter Number System and Codes of Digital Circuits

Octal to binary conversion: (24)8 =?(a) (111101)2(b) (010100)2(c) (111100)2(d) (101010)2I have been asked this question in exam.My doubt is from Number System in chapter Number System and Codes of Digital Circuits

Convert the binary number (01011.1011)2 into decimal.(a) (11.6875)10(b) (11.5874)10(c) (10.9876)10(d) (10.7893)10I got this question in class test.Enquiry is from Number System in portion Number System and Codes of Digital Circuits

Convert (0.345)10 into an octal number.(a) (0.16050)8(b) (0.26050)8(c) (0.19450)8(d) (0.24040)8This question was posed to me during an interview.Origin of the question is Number System topic in chapter Number System and Codes of Digital Circuits

(170)10 is equivalent to ____________(a) (FD)16(b) (DF)16(c) (AA)16(d) (AF)16The question was posed to me in a job interview.The origin of the question is Number System in chapter Number System and Codes of Digital Circuits

Convert (214)8 into decimal.(a) (140)10(b) (141)10(c) (142)10(d) (130)10This question was posed to me in a job interview.I'd like to ask this question from Number System topic in portion Number System and Codes of Digital Circuits

The octal equivalent of the decimal number (417)10 is _____(a) (641)8(b) (619)8(c) (640)8(d) (598)8This question was addressed to me by my school teacher while I was bunking the class.This intriguing question comes from Number System topic in section Number System and Codes of Digital Circuits

Convert the hexadecimal number (1E2)16 to decimal.(a) 480(b) 483(c) 482(d) 484I had been asked this question during an interview for a job.This interesting question is from Number System topic in section Number System and Codes of Digital Circuits

The given hexadecimal number (1E.53)16 is equivalent to ____________(a) (35.684)8(b) (36.246)8(c) (34.340)8(d) (35.599)8I had been asked this question in my homework.Question is taken from Number System in section Number System and Codes of Digital Circuits

The octal number (651.124)8 is equivalent to ______(a) (1A9.2A)16(b) (1B0.10)16(c) (1A8.A3)16(d) (1B0.B0)16The question was posed to me in an international level competition.I'd like to ask this question from Number System topic in portion Number System and Codes of Digital Circuits

The quantity of double word is ________(a) 16 bits(b) 32 bits(c) 4 bits(d) 8 bitsThe question was posed to me in homework.My enquiry is from Number System in division Number System and Codes of Digital Circuits