308 + Interview Questions in NUMBER SYSTEM in Quantitative Aptitude Page 1 InterviewSolution

1.	In a row of boys, if A who is 10th from the left and B who is 9th, from the right, interchange their positions, A becomes 15th from left. How many boys are there in the row ?1. 232. 313. 284. 27
Answer» Correct Answer - Option 1 : 23 Calculation: Position of A from left = 10th Position of B from right = 9th After interchanging positions, Position of A from left = 15th Total number of students in the row = (15 + 9)–1 ⇒ 24–1 ⇒ 23 ∴ Boys in the row is 23

1.

In a row of boys, if A who is 10th from the left and B who is 9th, from the right, interchange their positions, A becomes 15th from left. How many boys are there in the row ?1. 232. 313. 284. 27

Answer» Correct Answer - Option 1 : 23

Calculation:

Position of A from left = 10th

Position of B from right = 9th

After interchanging positions, Position of A from left = 15th

Total number of students in the row = (15 + 9)–1

⇒ 24–1

⇒ 23

∴ Boys in the row is 23

Discussion

2.	The highest common factor and least common multiple of two numbers are 35 and 525 respectively. If one of them is 175, then other number is1. 752. 853. 954. 105
Answer» Correct Answer - Option 4 : 105 Given: HCF = 35 LCM = 525 One number = 175 Concept: Product of two numbers = HCF× LCM Calculation: Let the other number be x. ⇒ Product of two numbers = HCF× LCM ⇒ 175× x = 35× 525 ⇒ x = (35× 525)/175 = 105 Hence, the other number is 105.

2.

The highest common factor and least common multiple of two numbers are 35 and 525 respectively. If one of them is 175, then other number is1. 752. 853. 954. 105

Answer» Correct Answer - Option 4 : 105

Given:

HCF = 35

LCM = 525

One number = 175

Concept:

Product of two numbers = HCF× LCM

Calculation:

Let the other number be x.

⇒ Product of two numbers = HCF× LCM

⇒ 175× x = 35× 525

⇒ x = (35× 525)/175 = 105

Hence, the other number is 105.

Discussion

3.	Find the highest common factor of 0.9, 0.48 and 0.525.1. \(\dfrac{3}{400}\)2. \(\dfrac{3}{150}\)3. \(\dfrac{3}{200}\)4. \(\dfrac{3}{100}\)
Answer» Correct Answer - Option 3 : \(\dfrac{3}{200}\) Concept used: HCF of fractions = HCFof numerators ÷ LCMof denominators Calculation: We can write 0.9as 9/10 Similarly, 0.48 = 48/100 = 12/25 And, 0.525 = 525/1000 = 21/40 Now, we can write 9as 1× 3× 3 Similarly, we can write 12as 1× 3× 4 And, 21 as 1× 3× 7 So, HCFof 9, 12 and 21= 3 We can write 10as 2× 5 Similarly, we can write 25as 5× 5 And, we can write 40 as 2× 2× 2× 5 So, LCMof 10, 25, 40 =2×2× 2× 5× 5 = 200 So, HCFof 0.9, 0.48and 0.525is 3/200 ∴LCM of 0.9, 0.48and 0.525is 3/200.

3.

Find the highest common factor of 0.9, 0.48 and 0.525.1. \(\dfrac{3}{400}\)2. \(\dfrac{3}{150}\)3. \(\dfrac{3}{200}\)4. \(\dfrac{3}{100}\)

Answer» Correct Answer - Option 3 : \(\dfrac{3}{200}\)

Concept used:

HCF of fractions = HCFof numerators ÷ LCMof denominators

Calculation:

We can write 0.9as 9/10

Similarly, 0.48 = 48/100 = 12/25

And, 0.525 = 525/1000 = 21/40

Now, we can write 9as 1× 3× 3

Similarly, we can write 12as 1× 3× 4

And, 21 as 1× 3× 7

So, HCFof 9, 12 and 21= 3

We can write 10as 2× 5

Similarly, we can write 25as 5× 5

And, we can write 40 as 2× 2× 2× 5

So, LCMof 10, 25, 40 =2×2× 2× 5× 5 = 200

So, HCFof 0.9, 0.48and 0.525is 3/200

∴LCM of 0.9, 0.48and 0.525is 3/200.

Discussion

4.	The speed of a bike is 15 m/s. Find its speed in km/hr.1. 362. 543. 454. 63
Answer» Correct Answer - Option 2 : 54 Given: Speed of the bike = 15 m/s Formula used: 1 m/s = 18/5 km/hr Calculation: 1 m/s = 18/5 km/hr ⇒ 1× 15 m/s = (18/5)× 15 km/hr ⇒ 15 m/s = 54 km/hr ∴ The speed of the bike in km/hr is 54.

4.

The speed of a bike is 15 m/s. Find its speed in km/hr.1. 362. 543. 454. 63

Answer» Correct Answer - Option 2 : 54

Given:

Speed of the bike = 15 m/s

Formula used:

1 m/s = 18/5 km/hr

Calculation:

1 m/s = 18/5 km/hr

⇒ 1× 15 m/s = (18/5)× 15 km/hr

⇒ 15 m/s = 54 km/hr

∴ The speed of the bike in km/hr is 54.

Discussion

5.	A tennis player before playing a major tournament had a win ratio of 2 : 3. Win ratio is defined as the ratio of the number of matches won to the total number of matches played by a player. The player won 4 out of 5 matches played in the Australian Open and his win ratio after it is more than 69 : 100. What could be the maximum total number of matches played by the player including the matches played in the Australian Open?1. 222. 263. 244. 30
Answer» Correct Answer - Option 2 : 26 Calculation: Let the number of matches played by the player before the Australian Open be 3n. The number of matches won by him be 2n so that his win ratio is 2:3. After the Australian Open, ⇒ (2n + 4)/(3n + 5) > 69/100 ⇒ 200n + 400 > 207n + 345 ⇒ 7n < 55 ⇒ The maximum value of n is 7. The maximum number of matches played by the player before the Australian Open is 3n which is 21. The maximum number of matches played by the player after the Australian Open is ⇒ 21 + 5 ⇒ 26 The maximum total number of matches played by the player including the matches played in the Australian Open is 26.

5.

A tennis player before playing a major tournament had a win ratio of 2 : 3. Win ratio is defined as the ratio of the number of matches won to the total number of matches played by a player. The player won 4 out of 5 matches played in the Australian Open and his win ratio after it is more than 69 : 100. What could be the maximum total number of matches played by the player including the matches played in the Australian Open?1. 222. 263. 244. 30

Answer» Correct Answer - Option 2 : 26

Calculation:

Let the number of matches played by the player before the Australian Open be 3n.

The number of matches won by him be 2n so that his win ratio is 2:3.

After the Australian Open,

⇒ (2n + 4)/(3n + 5) > 69/100

⇒ 200n + 400 > 207n + 345

⇒ 7n < 55

⇒ The maximum value of n is 7.

The maximum number of matches played by the player before the Australian Open is 3n which is 21.

The maximum number of matches played by the player after the Australian Open is

⇒ 21 + 5

⇒ 26

The maximum total number of matches played by the player including the matches played in the Australian Open is 26.

Discussion

6.	If log125729 = x, then what is the value of log815625?1. 2x/(4 - x)2. (4 - x)/2x3. (4 + x)/2x4. 2x/(4 + x)
Answer» Correct Answer - Option 3 : (4 + x)/2x Calculation: log125729 = x ⇒ loga729/loga125 = x ⇒ loga(9)3/loga(5)3= x ⇒ 3loga9/3loga5= x ⇒ loga9/loga5 = x ⇒ log59=x ⇒ log95 = 1/x ⇒ log35 = 2/x Now, log815625 ⇒ log81(625× 9) ⇒ log81625 + log819 ⇒ log(3)4(5)4+ log(9)2(9) ⇒ log35 + 1/2 ⇒ 2/x + 1/2 ⇒ (4 + x)/2x The value of log815625 is (4 + x)/2x. loga(MN) = logaM + logaN logMN = logaN/ logaM loga(M)b= b× logaM loga(a) = 1 If loga(b) = x then, logb(a) = 1/x

6.

If log125729 = x, then what is the value of log815625?1. 2x/(4 - x)2. (4 - x)/2x3. (4 + x)/2x4. 2x/(4 + x)

Answer» Correct Answer - Option 3 : (4 + x)/2x

Calculation:

log125729 = x

⇒ loga729/loga125 = x

⇒ loga(9)3/loga(5)3= x

⇒ 3loga9/3loga5= x

⇒ loga9/loga5 = x

⇒ log59=x

⇒ log95 = 1/x

⇒ log35 = 2/x

Now,

log815625

⇒ log81(625× 9)

⇒ log81625 + log819

⇒ log(3)4(5)4+ log(9)2(9)

⇒ log35 + 1/2

⇒ 2/x + 1/2

⇒ (4 + x)/2x

The value of log815625 is (4 + x)/2x.

loga(MN) = logaM + logaN

logMN = logaN/ logaM

loga(M)b= b× logaM

loga(a) = 1

If loga(b) = x then, logb(a) = 1/x

Discussion

7.	If one-seventh of a number is 55 then 40% of that number = ?
Answer» 154 Let the no. be X ,

7.

If one-seventh of a number is 55 then 40% of that number = ?

Answer»

154

Let the no. be X ,

Discussion

8.	In a 150-litre mixture of milk and water, the percentage of milk is 84%. How much water should be added so that the percentage of milk becomes 52.5% ?
Answer» 90 LITRE In 150 litre, milk is 84% ie 150 x 84/100 = 126 litre Let us add x litres of water Therefore, the quantity of mixture = 150 + x ∴ 52.5% of (150 + x) = 126 litres 150 + x = 126x100/52.5 = 240 litres ∴ x = 240 - 150 = 90 litres

8.

In a 150-litre mixture of milk and water, the percentage of milk is 84%. How much water should be added so that the percentage of milk becomes 52.5% ?

Answer»

90 LITRE

In 150 litre, milk is 84%
ie 150 x 84/100 = 126 litre
Let us add x litres of water
Therefore, the quantity of mixture = 150 + x
∴ 52.5% of (150 + x) = 126 litres
150 + x = 126x100/52.5 = 240 litres
∴ x = 240 - 150 = 90 litres

Discussion

9.	What should be the least number to be added to the 51234 number to make it divisible by 9?
Answer» 3 The least number to be ADDED to the numbers to MAKE them divisible by 9 is equal to the difference of the least MULTIPLE of 9 GREATER than the sum of the digits and sum of the digits. Sum of digits = 15. Nearest multiple of 9 greater than sum of digits = 18. Hence 3 has to be added.

9.

What should be the least number to be added to the 51234 number to make it divisible by 9?

Answer»

3

The least number to be ADDED to the numbers to MAKE them divisible by 9 is equal to the difference of the least MULTIPLE of 9 GREATER than the sum of the digits and sum of the digits.

Sum of digits = 15.

Nearest multiple of 9 greater than sum of digits = 18.

Hence 3 has to be added.

Discussion

10.	If the sum of 4 consecutive odd numbers is 104, what will be the third number if they are arranged in ascending order ?
Answer» 27 Let the consecutive odd number be x, x + 2, x + 4 and x + 6 respectively. According to the QUESTION x + x + 2 + x + 4 + x + 6 = 104

10.

If the sum of 4 consecutive odd numbers is 104, what will be the third number if they are arranged in ascending order ?

Answer»

27

Let the consecutive odd number be x, x + 2, x + 4 and x + 6 respectively.
According to the QUESTION x + x + 2 + x + 4 + x + 6 = 104

Discussion

11.	The average of five consecutive even numbers A, B, C, D and E is 54. What is the product of'B' and 'E' ?
Answer» 3016 Because, The EVEN NUMBERS are consecutive and their average is 54. ∴ The NUMBER C will be 54. ∴ A = 50, B = 52, D = 56, E = 58 B x E = 52 x 58 = 3016

11.

The average of five consecutive even numbers A, B, C, D and E is 54. What is the product of'B' and 'E' ?

Answer»

3016

Because, The EVEN NUMBERS are consecutive and their average is 54.
∴ The NUMBER C will be 54.
∴ A = 50, B = 52, D = 56, E = 58
B x E = 52 x 58 = 3016

Discussion

12.	What is the difference between the local value of 7 and 5 in the number 2574?
Answer» 430 500 – 70 = 430

12.

What is the difference between the local value of 7 and 5 in the number 2574?

Answer»

430

500 – 70 = 430

Discussion

13.	What is 25/2% of 482 times of 183 ?
Answer» 11025.75 25/2% of [482 X 183] = 25/2% of 88206 = 25/2 x 88206 / 100 = 88206 / 8 = 11025.75

13.

What is 25/2% of 482 times of 183 ?

Answer»

11025.75

25/2% of [482 X 183]
= 25/2% of 88206
= 25/2 x 88206 / 100
= 88206 / 8
= 11025.75

Discussion

14.	Look at this series: 2, 6, 18, 54, ... What number should come next?
Answer» 162 This is a SIMPLE multiplication series. Each NUMBER is 3 TIMES more than the PREVIOUS number.

14.

Look at this series: 2, 6, 18, 54, ... What number should come next?

Answer»

162

This is a SIMPLE multiplication series. Each NUMBER is 3 TIMES more than the PREVIOUS number.

Discussion

15.	A shopkeeper purchased 200 bulbs for Rs. 10 each. However, 5 bulbs were fused and had to be thrown away. The remaining were sold at Rs. 12 each. What will be percentage profit?
Answer» 17 12

15.

A shopkeeper purchased 200 bulbs for Rs. 10 each. However, 5 bulbs were fused and had to be thrown away. The remaining were sold at Rs. 12 each. What will be percentage profit?

Answer»

17

12

Discussion

16.	A number exceeds by 25 from its 3/8 part. Then the number is?
Answer» 40 X – 3/8 x = 25 x = 40

16.

A number exceeds by 25 from its 3/8 part. Then the number is?

Answer»

40

X – 3/8 x = 25

x = 40

Discussion

17.	64% of 2650+40% 0f 320=?
Answer» 1824 1824

17.

64% of 2650+40% 0f 320=?

Answer»

1824

Discussion

18.	The difference between 78% of a number and 59% of the same number is 323. What is 62% of that number ?
Answer» Rs. 1054 Let the number be X. 78% of x - 59% of x = 323 = 78X - 59x/100 = 323 = 19x/100 = 323 ∴ x = 323 x 100/19 = 1700 = 62% of 1700 = 1700 x 62/100 = 1054

18.

The difference between 78% of a number and 59% of the same number is 323. What is 62% of that number ?

Answer»

Rs. 1054

Let the number be X.
78% of x - 59% of x = 323
= 78X - 59x/100 = 323
= 19x/100 = 323
∴ x = 323 x 100/19 = 1700
= 62% of 1700 = 1700 x 62/100 = 1054

Discussion

19.	63.602 + 153.756 + 94.754 - 84.321 - 122.204 = ?
Answer» 141.587 ? = 312.112 - 170.525 = 141.587

19.

63.602 + 153.756 + 94.754 - 84.321 - 122.204 = ?

Answer»

141.587

? = 312.112 - 170.525 = 141.587

Discussion

20.	The population of a town increases by 15% in the first year and decreases by 25% in the second year. If its current population is 168480 then what will be its population after two years ?
Answer» 145314 Population of the TOWN = 168480 X 115/100 x 75/100 = 145314

20.

The population of a town increases by 15% in the first year and decreases by 25% in the second year. If its current population is 168480 then what will be its population after two years ?

Answer»

145314

Population of the TOWN
= 168480 X 115/100 x 75/100
= 145314

Discussion

21.	20% of the total number of students in a school play football. How many students do not play football if the total number of students in the school is 7600 ?
Answer» 6080 20% of 7600 = 1520 Therefore, STUDENTS who do not PLAY FOOTBALL = 7600 - 1520 = 6080

21.

20% of the total number of students in a school play football. How many students do not play football if the total number of students in the school is 7600 ?

Answer»

6080

20% of 7600 = 1520
Therefore, STUDENTS who do not PLAY FOOTBALL = 7600 - 1520 = 6080

Discussion

22.	Two third of three- fifth of one fourth of a number is 24, what is 30% of that number?
Answer» 72 x * 2/3 * 3/5 * 1/4 = 24 x = 240 240 * 30/100 = 72

22.

Two third of three- fifth of one fourth of a number is 24, what is 30% of that number?

Answer»

72

x * 2/3 * 3/5 * 1/4 = 24

x = 240

240 * 30/100 = 72

Discussion

23.	The peresent age of the father and the son are in the ratio of 8:3. After 12 years the ratio of their ages will be 2:1. What is the sum of the present age of the father and the son ?
Answer» 66 years Let the present age of the father be 'x' and that of the son be 'y'. Then x/y = 8/3 ∴ 3X = 8Y Further, x + 12/y + 12 = 2/1 ∴ x + 12 = 2y + 24

23.

The peresent age of the father and the son are in the ratio of 8:3. After 12 years the ratio of their ages will be 2:1. What is the sum of the present age of the father and the son ?

Answer»

66 years

Let the present age of the father be
'x' and that of the son be 'y'. Then x/y = 8/3
∴ 3X = 8Y
Further, x + 12/y + 12 = 2/1
∴ x + 12 = 2y + 24

Discussion

24.	Find the nearest to 25268 which is exactly divisible by 467?
Answer» 25218 NA

24.

Find the nearest to 25268 which is exactly divisible by 467?

Answer»

25218

NA

Discussion

25.	If the sum of four consecutive numbers is 370, which the following is the third lowest number among them
Answer» 92 Let the four consecutive NUMBERS be X, (x + 1), (x + 2), (x + 3) then x + (x + 1) + (x + 2) + (x + 3) = 370 = 4x + 6 = 370 ∴ x = 364/4 = 91 ∴ THIRD lowest number among them = x + 1= 91 + 1 = 92

25.

If the sum of four consecutive numbers is 370, which the following is the third lowest number among them

Answer»

92

Let the four consecutive NUMBERS be
X, (x + 1), (x + 2), (x + 3) then
x + (x + 1) + (x + 2) + (x + 3) = 370
= 4x + 6 = 370
∴ x = 364/4 = 91
∴ THIRD lowest number among them = x + 1= 91 + 1 = 92

Discussion

26.	Look at this series: U32, V29, __, X23, Y20, ... What number should fill the blank?
Answer» W26 In this SERIES, the LETTERS progress by 1; the numbers DECREASE by 3.

26.

Look at this series: U32, V29, __, X23, Y20, ... What number should fill the blank?

Answer»

W26

In this SERIES, the LETTERS progress by 1; the numbers DECREASE by 3.

Discussion

27.	The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is:
Answer» 72 Let the second NUMBER be x. Then, FIRST number = 2X and third number = 2x/3. 2x + x + 2x/3 = 264 11x/3 = 264 x = 72

27.

The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is:

Answer»

72

Let the second NUMBER be x. Then, FIRST number = 2X and third number = 2x/3.

2x + x + 2x/3 = 264

11x/3 = 264

x = 72

Discussion

28.	The sum of two numbers is 25 and their difference is 13. Find their product.
Answer» 114 Let the NUMBERS be X and y. Then x + y = 25 and x - y = 13. x = 19; y = 6 xy = 19 * 6 = 114

28.

The sum of two numbers is 25 and their difference is 13. Find their product.

Answer»

114

Let the NUMBERS be X and y.

Then x + y = 25 and x - y = 13.

x = 19; y = 6

xy = 19 * 6 = 114

Discussion

29.	Find the average of the following set of scores 450, 1050, 12, 390, 143, 286, 550, 999
Answer» 485 Required AVERAGE SCORE

29.

Find the average of the following set of scores 450, 1050, 12, 390, 143, 286, 550, 999

Answer»

485

Required AVERAGE SCORE

Discussion

30.	In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient?
Answer» 20 Number = (12 * 35) = 420 Correct QUOTIENT = 420/21 = 20

30.

In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient?

Answer»

20

Number = (12 * 35) = 420

Correct QUOTIENT = 420/21 = 20

Discussion

31.	1051.64 - 159.42 - 96.84 + 162.37 - 940.26 + 504 = ?
Answer» 521.49 ? = 1718.01 - 1196.52 = 521.49

31.

1051.64 - 159.42 - 96.84 + 162.37 - 940.26 + 504 = ?

Answer»

521.49

? = 1718.01 - 1196.52 = 521.49

Discussion

32.	9 3/4 + 7 2/17 - 9 1/15 = ?
Answer» 7 817/1020 Given sum = 9 + 3/4 + 7 + 2/17 - (9 + 1/15) = (9 + 7 - 9) + (3/4 + 2/17 - 1/15) = 7 + (765 + 120 - 68)/1020 = 7 817/1020

32.

9 3/4 + 7 2/17 - 9 1/15 = ?

Answer»

7 817/1020

Given sum = 9 + 3/4 + 7 + 2/17 - (9 + 1/15)

= (9 + 7 - 9) + (3/4 + 2/17 - 1/15)

= 7 + (765 + 120 - 68)/1020 = 7 817/1020

Discussion

33.	The sum and the product of two numbers are 25 and 144 respectively, the difference of the number is?
Answer» 7 x + y = 25 xy = 144 (x- y)2 = (x + y)2 – 4xy (x- y)2 = 625 – 576 => (x – y) = 7

33.

The sum and the product of two numbers are 25 and 144 respectively, the difference of the number is?

Answer»

7

x + y = 25

xy = 144

(x- y)2 = (x + y)2 – 4xy

(x- y)2 = 625 – 576 => (x – y) = 7

Discussion

34.	Look at this series: 7, 10, 8, 11, 9, 12, ... What number should come next?
Answer» 10 This is a simple ALTERNATING ADDITION and SUBTRACTION series. In the first pattern, 3 is ADDED; in the second, 2 is SUBTRACTED.

34.

Look at this series: 7, 10, 8, 11, 9, 12, ... What number should come next?

Answer»

10

This is a simple ALTERNATING ADDITION and SUBTRACTION series.
In the first pattern, 3 is ADDED; in the second, 2 is SUBTRACTED.

Discussion

35.	On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:
Answer» 47619 By HIT and TRAIL, we FIND that 47619 * 7 = 333333. 7) 333333 (47619

35.

On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:

Answer»

47619

By HIT and TRAIL, we FIND that

47619 * 7 = 333333.

7) 333333 (47619

Discussion

36.	If the of a two-digit number are interchanged, the number so obtained is greater than the original number by 18. If the sum of the two digits of the number is 14. What is the original number ?
Answer» 68 Let the no. be 10x + y. No. formed by the interchange of digits = 10Y + x We have y - x = 2 .........(i) y + x = 14

36.

If the of a two-digit number are interchanged, the number so obtained is greater than the original number by 18. If the sum of the two digits of the number is 14. What is the original number ?

Answer»

68

Let the no. be 10x + y.
No. formed by the interchange of digits = 10Y + x
We have y - x = 2 .........(i)
y + x = 14

Discussion

37.	If 70% of an equal to 40% of b, then ratio between a and b is?
Answer» 4: 7 70 a = 40 B a: b = 4: 7

37.

If 70% of an equal to 40% of b, then ratio between a and b is?

Answer»

4: 7

70 a = 40 B

a: b = 4: 7

Discussion

38.	If (182)² is added to the square of a number, the answer so obtained is 47765. What is the number ?
Answer» 121 Let the no. be x Therefore x² + (182)² = 47765 Therefore x² = 47765 - (182)2

38.

If (182)² is added to the square of a number, the answer so obtained is 47765. What is the number ?

Answer»

121

Let the no. be x
Therefore x² + (182)² = 47765
Therefore x² = 47765 - (182)2

Discussion

39.	Let R = qs—4. When s=8, R=16. When s=10, R is equal to
Answer» 21 21

39.

Let R = qs—4. When s=8, R=16. When s=10, R is equal to

Answer»

21

Discussion

40.	4.78% of 1255 + 3.24% of 440=0.5% of ?
Answer» 14849 0.5 X ?/100 = 4.78 x 1255/100 + 3.24 x 440/100 = 59.989 + 14.256 ∴ ? = 74.245 x 100/0.5 = 14849

40.

4.78% of 1255 + 3.24% of 440=0.5% of ?

Answer»

14849

0.5 X ?/100 = 4.78 x 1255/100 + 3.24 x 440/100
= 59.989 + 14.256
∴ ? = 74.245 x 100/0.5 = 14849

Discussion

41.	576÷ ? x114=8208
Answer» 8 8

41.

576÷ ? x114=8208

Answer»

8

Discussion

42.	7.8% of 12.5 + 2.5% of 161 = ?
Answer» 5 7.8 X 12.5/100 + 2.5 x 161/100 = 0.975 + 4.025 = 5

42.

7.8% of 12.5 + 2.5% of 161 = ?

Answer»

5

7.8 X 12.5/100 + 2.5 x 161/100
= 0.975 + 4.025
= 5

Discussion

43.	If the following fractions 7/6, 6/7, 5/3, 8/13 and 6/5 are arranged in descending order, which will be the last in the series?
Answer» 8/13 7/6 = 1.166, 6/7 = 0.857, 5/3 = 1.66, 8/13 = 0.615, 6/5 = 1.2 Therefore, 5/3 > 6/5 > 7/6 > 6/7 > 8/13

43.

If the following fractions 7/6, 6/7, 5/3, 8/13 and 6/5 are arranged in descending order, which will be the last in the series?

Answer»

8/13

7/6 = 1.166,
6/7 = 0.857,
5/3 = 1.66,
8/13 = 0.615,
6/5 = 1.2
Therefore, 5/3 > 6/5 > 7/6 > 6/7 > 8/13

Discussion

44.	The sum of five consecutive numbers is 190. What is the sum of the largest and the smallest number ?
Answer» 76 x + x + 1 + x + 2 + x + 3 + x + 4 = 190 = 5x + 10 = 190 = 5x = 190 - 10 = 180 = x = 180/5 = 36 The largest number = 36 + 4 = 40 ∴ Required SUM = 36 + 40 = 76

44.

The sum of five consecutive numbers is 190. What is the sum of the largest and the smallest number ?

Answer»

76

x + x + 1 + x + 2 + x + 3 + x + 4
= 190
= 5x + 10 = 190
= 5x = 190 - 10 = 180
= x = 180/5 = 36
The largest number = 36 + 4 = 40
∴ Required SUM = 36 + 40 = 76

Discussion

45.	In how many different ways can be the letters of the word PENCIL be arranged among themselves ?
Answer» 720 Total six LETTERS are there and HENCE the number of arrangements = 6!

45.

In how many different ways can be the letters of the word PENCIL be arranged among themselves ?

Answer»

720

Total six LETTERS are there and HENCE the number of arrangements = 6!

Discussion

46.	If HKUJ means FISH, what does UVCD mean ?
Answer» STAB STAB

46.

If HKUJ means FISH, what does UVCD mean ?

Answer»

STAB

Discussion

47.	What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?
Answer» 43983 74330 Largest 30347 SMALLEST ------------- 43983

47.

What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?

Answer»

43983

74330 Largest

30347 SMALLEST

-------------

43983

Discussion

48.	8988 / 8 / 4 = ?
Answer» 280.875 8988 * 1/8 * 1/4 = 2247/8 = 280.875

48.

8988 / 8 / 4 = ?

Answer»

280.875

8988 * 1/8 * 1/4 = 2247/8 = 280.875

Discussion

49.	50% of 8/15 of 9/4 of 5/3 of 333 = ?
Answer» 333 50% of [8x9x5/15x4x3 X 333] = 50% of 666 = 333

49.

50% of 8/15 of 9/4 of 5/3 of 333 = ?

Answer»

333

50% of [8x9x5/15x4x3 X 333]
= 50% of 666
= 333

Discussion

50.	In how many different ways can the letters of the word CORPORATION be arranged ?
Answer» 3326400 CORPORATION = 11 letters 'O' COMES THRICE,'R' twice. ∴ total no. of ways = 111/3121 = 3326400

50.

In how many different ways can the letters of the word CORPORATION be arranged ?

Answer»

3326400

CORPORATION = 11 letters
'O' COMES THRICE,'R' twice.
∴ total no. of ways = 111/3121 = 3326400

Discussion

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