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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Directions: Anil started from city X at 10:00 AM and travelled towards city Y. After one hour, Sunil started from Y and travelled towards X. The total time taken by Anil and Sunil for their journey are (k + 2) hours and k hours respectively. They met each other at 7:00 PM. The speed of Sunil is 7 km/h more than that of Anil.What is the distance between X and Y?1). 1134 km2). 952 km3). 1024 km4). 1008 km |
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Answer» The ratio of SPEEDS of Anil and SUNIL = 8 : 9 and the difference between their speeds is 7km/h Therefore their speeds are 56 KM/h and 63 km/h RESPECTIVELY ∴ Required total distance = 63 × 16 = 1008 km. |
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| 2. |
What is the approximate percentage of the boys who have participated in Kho-Kho out of the total number of boys?1). 19%2). 23%3). 16%4). 27% |
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Answer»
∴ The approximate PERCENTAGE of the boys PARTICIPATED in Kho-Kho out of the total boys = (28/147) × 100 ≈ 19% |
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| 3. |
He sold ten kg of apples, eight kg of bananas and four kg of oranges, both on Monday and Friday each, what is the total amount he earned?1). Rs. 9562). Rs. 9873). Rs. 1,1244). Rs. 1,198 |
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Answer» On Monday Bananas = Rs. 12 per kg Oranges = Rs. 28 per kg SP of 10 kg of apples, 8 kg of bananas and 4 kg of oranges = 10 × 40 + 8 × 12 + 4 × 28 = Rs. 608 On Friday Apples = Rs. 30 per kg Bananas = Rs. 30 per kg Oranges = Rs. 34 per kg SP of 10 kg of apples, 8 kg of bananas and 4 kg of oranges = 10 × 30 + 8 × 30 + 4 × 34 = Rs. 676 Total = 608 + 676 = Rs. 1,284 |
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| 4. |
What is the total number of girls who have participated in Badminton and chess together?1). 1122). 1333). 1434). 150 |
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| 5. |
Direction: A company produces four different products uiz., Mobile Phones, Televisions, Refrigerators, and Computers. Each of the products has two categories, uiz., Category - A and Category B. The total number of all the products is 900. 25% of the total number of products is Computers and one - third of the total number of products is Televisions. 32% of the total products are Refrigerators. 50%, each of the total number of Televisions as well as the total number of Refrigerators is of Category - A. 40% of the total number of Computers is of Category - B. One - third of the total number of Mobile Phones is of Category - B.What is the respective ratio between the number of Televisions of Category - B and the number of Computers of Category - A?1). 10 : 192). 10 : 93). 1 : 94). 1 : 19 |
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Answer» For Category A, Computer = 135 For Category B, TELEVISION = 150 ∴ Required RATIO = 150 : 135 = 10 : 9 |
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| 6. |
The selling price of R is what per cent of the cost price of Q?1). 120%2). 140%3). 180%4). 220% |
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Answer» Cost PRICE of Q = 100 + 10 = 110 Selling price of R = 250 + 20 + 5 = 275 ∴ Required % = 275/110 × 100 = 250% |
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| 7. |
What is the overall percentage change in the value of the stocks?1). 1%2). 2%3). 4%4). 5% |
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Answer» MONEY invested in stocks = 3.75 lakhs Money after 1 YEAR = 3.75 × (110/100) = 4.125 lakhs Money after 2 years = 4.125 × (105/100) = 4.33125 lakhs Money after 3 years = 4.33125× (90/100) = 3.898 lakhs Percentage INCREASE in price of stocks = (3.898 - 3.75 )/3.75 × 100 = 3.95 = 4% |
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| 8. |
If the loss on P is 5%, then its selling price is what percentage less than the selling price of T?1). 95%2). 45%3). 83.7%4). 77.5% |
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Answer» SELLING price of T = 400 + 6% of 400 + 40 = 464 Selling price of P = 80 – 5% of 80 = 76 ∴ REQUIRED % = (464 - 76)/464 × 100 = 83.7% |
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| 9. |
Directions: Anil started from city X at 10:00 AM and travelled towards city Y. After one hour, Sunil started from Y and travelled towards X. The total time taken by Anil and Sunil for their journey are (k + 2) hours and k hours respectively. They met each other at 7:00 PM. The speed of Sunil is 7 km/h more than that of Anil.Find the total time taken by Anil for his journey?1). 16 hours2). 14 hours3). 20 hours4). 18 hours |
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Answer» LET the distance between the two cities be ‘d’ km. The distance TRAVELLED by ANIL for ONE hour = d/(k + 2) Remaining distance = d[1 – 1/(k + 2)] = d[(k + 1)/(k + 2)] km Given, ⇒ [(k + 1)/(k + 2)]/[d/(k + 2) + d/k] = 8 ⇒ k/2 = 8 ⇒ k = 16 ∴ Required number of hours taken by Anil = 16 + 2 = 18 hours |
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| 10. |
Direction: |
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Answer» Required PERCENTAGE of boys = $(\frac{{\left[ {\left( {\frac{1}{3}} \right){\rm{\;}} \TIMES {\rm{\;}}\left( {\frac{3}{8}} \right){\rm{\;}} \times {\rm{\;}}\left( {\frac{5}{9}} \right){\rm{\;}} \times {\rm{\;}}1008} \right]}}{{\left[ {\left( {\frac{3}{8}} \right){\rm{\;}} \times {\rm{\;}}1008} \right]}} \times 100)$ ⇒ 18.5 |
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| 11. |
1). On Wednesday by Rs. 242). On Thursday by Rs. 243). On Wednesday by Rs. 364). On Thursday by Rs. 36 |
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Answer» On Wednesday Apples = Rs. 42 per kg BANANAS = Rs. 16 per kg Oranges = Rs. 22 per kg SP of 12 kg of apples, 18 kg of bananas and 16 kg of oranges = 12 × 42 + 18 × 16 + 16 × 22 = Rs. 1,144 On THURSDAY Apples = Rs. 32 per kg Bananas = Rs. 24 per kg Oranges = Rs. 22 per kg SP of 12 kg of apples, 18 kg of bananas and 16 kg of oranges = 12 × 32 + 18 × 24 + 16 × 22 = Rs. 1,168 Thus, he earns more on Thursday by 1168 -1144 = Rs. 24 |
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| 12. |
Note: 3.84% = 1/26 of fraction.The Average Speed of train in September to February is 195 km/h and March to August is 260 km/h. Then find the ratio of the cost of travel in March to August cycle to September to February Cycle of travelling in train.1). 3 : 82). 1 : 23). 3 : 44). 1 : 7 |
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Answer» DISTANCE travelled by TRAIN = 2600[1 - (1/26) - (1/52)] = 2450 Km Time TAKEN in MARCH to August cycle = 2450/260 Cost in March to August cycle = 2450 × 130/260 Time taken in September to February cycle = 2450/195 Cost in September to February cycle = 2450 × 78/195 ∴ Required Ratio = 5 : 4 |
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| 13. |
So, either boxers can be in attacking mode or defensive mode at a time.Probability of a certain boxer X attacking his opponent is 100%. In his bout with Mike Tyson what is the probability that an attacking moves from boxer X encountering a defensive move from Mike Tyson?1). 0.432). 0.633). 0.734). 0.53 |
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Answer» PROBABILITY of Mike TYSON attacking with a left jab = 0.16 Probability of Mike Tyson attacking with a right jab = 0.29 Probability of Mike Tyson attacking with a left hook = 0.12 Probability of Mike Tyson attacking with a right hook = 0.10 Probability of Mike Tyson attacking = 0.16 + 0.29 + 0.12 + 0.10 = 0.67 Probability of Mike Tyson being on defensive mode = 1 – 0.67 = 0.33 ? The Boxer X ATTACKS all the TIME, the probability of both the boxers going for an attacking mode would be totally dependent on Mike Tyson’s likeliness of going for a defensive move. ∴ The probability that an attacking moves from boxer X encountering a defensive move from Mike Tyson is equal to the probability of Mike Tyson MAKING a defensive move = 0.33 |
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| 14. |
1). 1502). 6003). 3004). 495 |
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| 15. |
Direction: A, B & C together invested a total of Rs. D in the ratio 5 : 8 : 2 for X, Y and Z months respectively. Then answer as directed - Given X : Y : Z = 4 : 1 : 7, X + Y + Z = 1 year and D = 120% of the total profit earned. If A gets Rs. 300 as profit, find D.1). Rs. 7162). Rs. 7263). Rs. 7364). Rs. 746 |
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Answer» As, profit ratio = investment ratio × time ratio ∴ Profit ratio A : B : C = (4 × 5) : (1 × 8) : (2 × 7) = 10 : 4 : 7 ∴ Total profit = (10 + 4 + 7) × 300/10 = 630 ⇒ D = 120% of P = 1.2P = 1.2 × 630 = 12 × 63 = Rs. 756 |
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| 16. |
Note: 3.84% = 1/26 of fraction.Find the average Speed in km/h of the train for the whole journey.1). 120 km/h2). 110 km/h3). 140 km/h4). 130 km/h |
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Answer» Distance TRAVELLED by TRAIN = 2600[1 - (1/26) - (1/52)] = 2450 Km Time TAKEN by train = 2450/196 = 12.5 Hours Additional time = 5 hours ∴ AVERAGE Speed = 2450/(12.5 + 5) = 140 km/h |
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