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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
Following compound is an example of isA. Aromatic compoundB. Heterocyclic compoundC. AnnuleneD. Xanthates. |
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Answer» Correct Answer - C Factual question. |
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| 402. |
The IUPAC name of the compound A. 4-Mehtylcyclopent-1-en-2-01B. 2-Methylcyclopent-4-en-1-01C. 3-Methylcyclopent-1-en-2-01D. 5-Methylcyclopent-2-en-01 |
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Answer» Correct Answer - D Similar to Q. 45. |
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| 403. |
The correct IUPAC name ofA. IsopropylbenzeneB. CumeneC. PhenylisopropeneD. None of these |
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Answer» Correct Answer - A Factual question. |
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| 404. |
In the IUPAC system, `PhCH_(2)CH_(2)CO_(2)H` is namedA. 3-phenylpropanoic acidB. benzylacetic acidC. carboxyethyl benzeneD. 2-phenylpropanoic acid |
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Answer» Correct Answer - A `underset("3-Phenylpropanoic acid")(Phoverset(3)(C)H_(2)overset(2)(C)H_(2)overset(1)(C)OOH)` |
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| 405. |
The correct IUPAC name of `(C_(2)H_(5))_(4)C` isA. Tetraethyl methaneB. 2-EthylpentaneC. 3, 3-diethylpentaneD. None of the above |
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Answer» Correct Answer - C `underset("3, 3-Diethylpentane")underset()(overset(5)CH_(3)-overset(4)CH_(2)-overset(C_(2)H_(5))overset(2|)underset(C_(2)H_(5))underset(|)C-overset(2)CH_(2)-overset(1)CH_(3))` |
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| 406. |
Which is the most stable resonating structure?A. B. C. D. |
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Answer» Correct Answer - B Negative charge on more electronegative atom is more stable. |
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| 407. |
The IUPAC name of the following compound is A. 1, 2-Dimethylbut-2-en-1-01B. 3-Methylpent-3-en-2-01C. 3, 4-Dimethylbut-2-en-4-01D. 2,3-Dimethylpent-3-en-1-01 |
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Answer» Correct Answer - B `underset("3-Methylpent-3-en-2-1")underset()(overset(1)CH_(3)-overset(OH)overset(2|)CH-overset(CH_(3))overset(3|)C=overset(4)CH-overset(5)CH_(3))` |
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| 408. |
The compound `CH_(2)=CH[CH_(2)]_(2)CH_(3)` is named asA. `alpha`-PentyleneB. AmyleneC. Pent-1-eneD. All A, B, C are correct. |
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Answer» Correct Answer - D `underset("Pent-1-ene or a-Pentylene or Amylene")(CH_(2)=CH-CH_(2)-CH_(2)-CH_(3))` |
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| 409. |
Resonance effect involves:A. Delocalisation of `pi`-electrons along a conjugated system.B. Delocalization of lone pair along a conjugated system.C. Delocalisation of negative charge along a conjugated system.D. All are correct. |
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Answer» Correct Answer - D This is fact. |
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| 410. |
Two volatile liquids A and B differ in their boiling points by 15K. The process which can be used to separate them isA. fractional distillationB. steam distillationC. distillation under reduced pressureD. simple distillation |
| Answer» Correct Answer - A | |
| 411. |
The boiling point difference the two liquids is not much then..........method used to separate themA. Simple distillationB. Distillation under reduced pressureC. steam distillationD. fractional distillation |
| Answer» Correct Answer - D | |
| 412. |
Resonance effect involves:A. Delocalization of `pi`-electrons along a conjugated systemB. Delocalization of n-electrons along a conjugated systemC. Delocalization of `sigama`-electrons into an adjacent `pi`-bondD. All are correct. |
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Answer» Correct Answer - D Refer Comprehensive Review. |
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| 413. |
Which of the following is an aromatic species ?A. B. C. D. None of the above |
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Answer» Correct Answer - B (B) Tropylium cation is planar with 6 `pi`-electrons which are completely delocalised over the entire cyclic system and hence aromatic. |
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| 414. |
Hyperconjugation involvesA. Delocalization of `sigma`-electrons into an adjacent `pi`-bondB. Delocalization of n-electrons into an adjacent double bondC. Delocalization of `pi`-electrons into an adjacent `pi`-bondD. All are true. |
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Answer» Correct Answer - A Hyperconjugation involves delocalisation of `alpha` electrons into an adjacent `pi`-bond. |
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| 415. |
Mesomeric effect involvesA. delocalisation of `pi`-electronsB. delocalisation of `sigma`-electronsC. partial displacement of electronsD. delocalisation of `pi" and "sigma`-electrons. |
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Answer» Correct Answer - A (A) Mesomeric or resonance effect involves delocalisation of `pi`-electrons and lone pairs of electrons. |
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| 416. |
Which of the following has `+R (or +M)` effect?A. `-CN`B. `-CHO`C. `-NH_(2)`D. `NO_(2)` |
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Answer» Correct Answer - C `-overset(cupcup)(NH)_(2)` has + R effect while all others have -R effect. |
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| 417. |
Which of the following series contains atoms/groups having only-M(mesomeric) effect ?A. `COR,OR,COOR`B. `Cl,CHO,NH_(2)`C. `NO_(2),CN,SO_(3)H`D. `OH,NR_(2),SR` |
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Answer» Correct Answer - C `-NO_(2),-CN,-SO_(3)` H have - M effect. |
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| 418. |
Among the following The correct order of reactivity of chloride isA. `IgtIIgtIII`B. `IIIgtIIgtI`C. `IIgtIgtIII`D. `IIgtIIIgtI` |
| Answer» Correct Answer - D | |
| 419. |
In the given anion,-ve charge is delocalized on A. One atomB. Three atomC. Four atomD. Five atom |
| Answer» Correct Answer - C | |
| 420. |
The compounds areA. Chain isomersB. MetamersC. Positions isomersD. Both 1 and 2 |
| Answer» Correct Answer - D | |
| 421. |
Which one of the following is a benzenoid aromatic compound ?A. FuranB. ThiopheneC. PyridineD. Aniline |
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Answer» Correct Answer - D Aniline, i.e., option (d) is correct since it contains a benzene ring. |
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| 422. |
Tropolone is an example ofA. benzenoid aromatic compoundB. non-benzenoid aromatic compoundC. alicyclic compoundD. acyclic compound |
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Answer» Correct Answer - B Tropolone is an example of non-benzenoid aromatic compound |
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| 423. |
Which isomer of hexane has only two different sets of structurally equivalent hydrogen atoms?A. 2,2-dimethyl butaneB. 2-methyl pentaneC. 3-methyl pentaneD. 2,3-dimethyl butane. |
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Answer» Correct Answer - D (D) option has a primary and 2-tertiary hydrogen atoms |
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| 424. |
Which isomer of hexane has only two different sets of structurally equivalent hydrogen atoms ?A. 2, 2-dimethylbutaneB. 2-methylpentaneC. 3-methylpentaneD. 2, 3-dimethylbutane |
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Answer» Correct Answer - D `{:(" "CH_(3)" "CH_(3)),(" |"" |"),(CH_(3)-CH-CH-CH_(3)):}` 2, 3-Dimethylbutane has two sets of structure-rally equivalent hydrogens (twelve `1^(@)` and two `3^(@)`) |
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| 425. |
An organic reaction occurs through making and breaking of bonds. The breaking of bonds may occur either homolytically leading to the formation of radicals or heterolytically generating positively and negatively charged species. The neutral species (free radicals, carbenes, nitrenes, etc.) and positively charged species being electron deifcient are collectively called electrophiles while neutral and negatively charged species which are electron rich are called nucleophiles. An organic reaction usually involves the attack of a reagent (radicals, positively and negatively charged species) on the substrate molecule). The substrate molecule, although as a whole electrically neutral, has centres of low and high electron density due to displacement of bonding electrons. These electrons displacements occur through inductive, electromeric occur through inductive, electromeric, resonance and hyperconjugation effects. Whereas inductive effects involve displacement transfer of n-and `pi`-electrons along a conjugated system. Hypercongation effects, on the other hand, involve `sigma-pi`-conjugation. Both inductive and hyperconjugation effects can be used to explain the stability of carbocations and free radicals which follow the stability order: `3^(@) gt 2^(@) gt 1^(@)`. The stability of carbanions, however, follows opposite order. The stability of a molecule can be judged on the basis of contribution of its resonance structures. Resonance structures have same position of nuclei and have same number of unpaired electrons. Among resonance structures, the one which has greater number of covalent bonds, has less separation of opposite Charges, a negative charge on more electronegative and a positive charge on a more electropostive atom are more stable than others. Out of the following, the one containing only nucleophiles isA. `NH_(3), CN^(-), CH_(3)OH`B. `AlCl_(3), BF_(3), NH_(3)`C. `AlCl_(3), NH_(2)^(-), H_(2)O`D. `RNH_(2), :CX_(2), H^(-)` |
| Answer» Correct Answer - A | |
| 426. |
An organic reaction occurs through making and breaking of bonds. The breaking of bonds may occur either homolytically leading to the formation of radicals or heterolytically generating positively and negatively charged species. The neutral species (free radicals, carbenes, nitrenes, etc.) and positively charged species being electron deifcient are collectively called electrophiles while neutral and negatively charged species which are electron rich are called nucleophiles. An organic reaction usually involves the attack of a reagent (radicals, positively and negatively charged species) on the substrate molecule). The substrate molecule, although as a whole electrically neutral, has centres of low and high electron density due to displacement of bonding electrons. These electrons displacements occur through inductive, electromeric occur through inductive, electromeric, resonance and hyperconjugation effects. Whereas inductive effects involve displacement transfer of n-and `pi`-electrons along a conjugated system. Hypercongation effects, on the other hand, involve `sigma-pi`-conjugation. Both inductive and hyperconjugation effects can be used to explain the stability of carbocations and free radicals which follow the stability order: `3^(@) gt 2^(@) gt 1^(@)`. The stability of carbanions, however, follows opposite order. The stability of a molecule can be judged on the basis of contribution of its resonance structures. Resonance structures have same position of nuclei and have same number of unpaired electrons. Among resonance structures, the one which has greater number of covalent bonds, has less separation of opposite Charges, a negative charge on more electronegative and a positive charge on a more electropostive atom are more stable than others. The C-C bond length in propene s little shorter (1.49 Å) than the C-C bond length (1.54 Å) in ethane. This is due toA. `+I` effect of `CH_(3)` groupB. mesomeric effectC. electromeric effectD. hyperconjugation effect |
| Answer» Correct Answer - D | |
| 427. |
Which of the following is not true for maleic acid and fumaric acids?A. Configurational isomersB. StereoisomersC. `Z` and `E` isomersD. Optical isomers |
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Answer» Correct Answer - D Malic and fumaric acid are `GI` isomers not `OI`. |
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| 428. |
Assertion : A free radical is paramagnetic species. Reason : A free radical is formed in homolytic fission of covalent bond.A. If both assertion and Reason are true, and reason is the true explanation of the assertion.B. If both assertion and reason are true, but reason is not the true explanation of the assertion.C. If assertion is true, but reason is falseD. If both assertion and reason are false |
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Answer» Correct Answer - B Correct explanation. Free radicals have odd number of electrons in the valence shell and hence are paramagnetic. |
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| 429. |
Why it is necessary to use acetic acid and not sulphuric acid for acidification of sodium extraction for testing sulphur by lead acetate test ? |
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Answer» For testing sulphur, the sodium extract is acidified with acetic acid because lead acetate is soluble and does not interfere with the test. If `H_(2)SO_(4)` were used, lead acetate itself will react with `H_(2)SO_(4)` to form white ppt. of lead sulphate which will interfere with the test. `underset("Lead acetate")(Pb(OCOCH_(3))_(2) )+H_(2)SO_(4) rarr underset("(White ppt.)")(PbSO_(4)darr) + 2CH_(3)COOH` |
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| 430. |
The hydrocarbon used for welding purpose isA. ethaneB. ethyneC. etheneD. beczene |
| Answer» he hydrocarbon used for welding purposes is acet ylene (ethyne) since oxyacetylene flame produces a high temperature of `3800^@C`. | |
| 431. |
Which of the following statements are correct ?A. `R - overset(+)(C) = overset(..)(O):` and `R - C -= overset(+)(O):` are resonance structuresB. Methyl carbanion is both isostructural and isoelectronic with ammoniaC. In `overset(4)(C)H_(2)=overset(3)(C)H - overset(2)(C)H=overset(1)(O)`, nucleophilic centre is position 4 while electrophilic centre position 1.D. `SnCl_(4)` acts as an electrophile |
| Answer» Correct Answer - A::B::C::D | |
| 432. |
How many σ and π bonds are present in each of the following molecules? (a) `HCequiv"CC"H=CHCH_(3)` (b) `CH_(2)=C=CHCH_(3)` |
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Answer» `(a) sigma_(C-C):4,sigma_(C-H):6,pi_(C=C):1,piCequivC:2` `(b)sigma_(C-C):3,sigma_(C-H):6,pi_(C=C):2` |
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| 433. |
Which of the following is most stable carbocation?A. `CH_(3)overset(o+)(C)H_(2)`B. `CH_(3)overset(o+)(C)=O`C. `overset(o+)(C)H_(3)-overset(o+)(C)=NH`D. `CH_(2)=overset(o+)(C)H` |
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Answer» Correct Answer - C Electron releasing `(+M)` effect of nitrogen stabilise the carbocation. |
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| 434. |
Which of the following is most stable carbocation?A. `CH_(3)-overset(o+)(C)H_(2)`B. `overset(o+)(C)H_(2)-CHCl_(2)`C. `overset(o+)(C)H_(2)-CH_(2)-Cl`D. `overset(o+)(C)H_(2)-C Cl_(3)` |
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Answer» Correct Answer - A Electron withdrawing `(-I)` effect decreases the stability of carbocations. |
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| 435. |
Tautomerism is exhibited byA. `(Me_(3)C CO)_(3)CH`B. C. D. |
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Answer» Correct Answer - A::B::D Only option (c) does not have a `alpha`-H on a saturated carbon and hence does not exhibit tautomerism while all others do. |
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| 436. |
Classify the following transformation according to the reaction type. (a) `H_(3)C-CH=CH-CH_(3) + Br_(2) rarr H_(3)C - CHBr - CHBr - CH_(3)` (b) `(H_(3)C)_(2)C = C(CH_(3))_(2) + Br_(2) rarr (H_(3)C)_(2)C = C(CH_(3))CH_(2)Br + HBr` (c) `H_(2)C = CH - CH_(2)CH_(3) rarr H_(3)C - CH = CH - CH_(3)` (d) `C_(6)H_(5)CHO + CH_(3)COCH_(3) rarr C_(6)H_(5)CH(OH)CH_(2)COCH_(3)` (e) `(CH_(3))_(3)C Cl + HO^(-) rarr (CH_(3))_(2)C = CH_(2)` (f) `{:(CH_(3)-C=N-OH+H_(3)O^(+) rarr CH_(3)-C=O),(" |"" |"),(" "Ph" "NHPh):}` |
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Answer» (a) Electrophilic addition (b) Free radical substitution (c) Isomerisation (d) Condensation (e) `beta`-Elimination reaction (f) Rearrangement |
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| 437. |
With proper justification, arrange the following in order of increasing stability `CH_(3)CH_(2)^(-), CH -= C^(-), CH_(2) = CH^(-)`. |
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Answer» In acetylide ion `CH -= C^(-)`, the carbon atom carrying the -ve charge is sp-hybridized and has 50% s-character : in `CH_(2) = CH^(-)` ion, the carbon atom is `sp^(2)`-hybridized and has 33.3% s-character while in `CH_(3)CH_(2)^(-)` ion, the carbon atom bearing the -ve charge is `sp^(3)`-hybridized and has 25% s-character. Since s-electrons, on the average, are closer to the nucleus than p-electrons, therefore, a carbon atom with greater s-character can accommodate or stabilize the negative charge better than a carbon atom with smaller s-character. In other words, the stability of the carbanion increases as the s-character of the carbon atom carrying the negative charge increases. Now since the s-character of the carbon decreases as we move from sp to `sp^(2)` to `sp^(3)`-carbon, therefore, the relative stability of the three carbanions follows the sequence: `CH -= C^(-) gt CH_(2) = CH^(-) gt CH_(3)CH_(2)^(-)`. |
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| 438. |
Give the IUPAC names of the following : |
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Answer» (i) 4-Cyclopentylbut-1-ene, (ii) Cyclohexylcyclohexane (iii) 2-Hydroxycyclohexanecarbonyl chloride, (iv) 2-(2-Methylcyclobut-1-enyl) ethanal (v) 4-Cyclobutylbut-3-en-2-one, (vi) 2-Ethyl-1, 4-dimethylcyclohexane (vii) 1-(4-hydroxycyclohexyl) pentane-1, 5-diol, (viii) 2-Isoproyl-5-methylcyclohexanol (ix) 4-(4-Nitrocyclohexyl) benzaldehyde, (x) 2-Nitrocyclohexanecarboxamide. |
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| 439. |
IUPAC name of compound `{:(" "CH_(3)),(" |"),(H_(3)C-C-CH=C-CH_(3)),(" |"" |"),(" "CH_(3)" "CH_(3)):}` isA. 2, 2, 4-Trimethylpent -2-eneB. 2, 4, 4-Trimethylpent-2-eneC. 2, 2, 4-Trimethylpent-3-eneD. 2, 2, 4-Trimethylpent-1-ene |
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Answer» Correct Answer - B is the correct answer. |
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| 440. |
Write the IUPAC names of the following compounds. |
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Answer» (i) 2-Phenylethanol, (ii) 1, 1, 1-Trichloro-2, 2-diphenylethane (iii) 2-Phenylethanamine, (iv) 2- (Chloromethyl) chlorobenzene (v) 3, 3-Diphenylbutan-2-ol, (vi) 1, 2-bis (4-chlorophenyl) ethane (vii) 2, 4-Dinitrobenzenamine, (viii) 4-Nitroso-N-dimethylbenzenamine (ix) Benzene 1, 4-dicarboxylic acid, (x) 1-Phenylpropanone. |
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| 441. |
The correct decreasing order for the function groups of organic compounds in the IUPAC system of nomenclature isA. `-CONH_(2), -CHO, -SO_(3)H, -COOH`B. `-COOH, -SO_(3)H, -CONH_(2), -CHO`C. `-SO_(3)H, -COOH, -CONH_(2), -CHO`D. `-CHO, -COOH, -SO_(3)H, -CONH_(2)`. |
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Answer» Correct Answer - B is the correct sequence. |
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| 442. |
The IUAPC name of the following compound is A. 4-Bromo-3-cyanophenolB. 2-Bromo-3-hydroxybromobenzeneC. 2-Cyano-4-hydroxybromobenzeneD. 6-Bromo-3-hydrocybenzonitrile. |
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Answer» Correct Answer - B is the correct IUPAC name. |
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| 443. |
What is the IUPAC name of `H- overset(O)overset(||)(C)-CH_(2)-CH_(2)-OCH_(3)`?A. 2-FormylmethoxyethaneB. MethoxypropanalC. 2-MethoxpropanalD. 3-Methoxypropanal |
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Answer» Correct Answer - D `{:(" "O),(" ||"),(H-overset(1)(C-)overset(2)(C)H_(2)-overset(3)(C)H_(2)-OCH_(3)):}` 3-Methoxypropanal |
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| 444. |
Out of following, the alkane that exhibit optical isomerism isA. `3`-methyl-`2`-penteneB. `4`-methyl-`1`-penteneC. `3`-methyl-`1`-penteneD. `2`-methyl-`2`-pentene |
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Answer» Correct Answer - C Optical isomerism is shown by the carbonm, hence it shows optical isomerism. `CH_(3)-CH_(2)-overset(H)overset(|)underset(("It has one chiral centre"))underset("3-methyl-1-pentane")underset(CH_(3))underset(|)(C^(**))-CH=CH_(2)` |
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| 445. |
Pick out the alkane which differs from the other members of the groupA. 2,2-DimethylpropaneB. PentaneC. 2-MethylbutaneD. 2,2-Dimethylbutane |
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Answer» Correct Answer - D Choice (D) has six carbon atoms whereas other three are pentanes. |
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| 446. |
The correct IUPAC name of the spiro compound, A. 2, 7-dimethyl-5-Oxospiro[3. 4] octaneB. 3,7-dimethyl-l-Oxospiro[4. 3] octaneC. 3 7-dimethyl-5-0xospiro[3. 4] octaneD. 2, 7-dimethyl-1-0xospiro [3. 4] octane. |
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Answer» Correct Answer - A Factual questions. |
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| 447. |
Write structural formulae for compounds names as- (a) 1-Bromoheptane (b) 5-Bromoheptanoic acid |
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Answer» `underset("1-Bromoheptane")(overset(7)(C)H_(3)-overset(6)(C)H_(2)-overset(5)(C)H_(2)-overset(4)(C)H_(2)-overset(3)(C)H_(2)-overset(2)(C)H_(2)-overset(1)(C)H_(2)Br)` (b) `{:(overset(7)(C)H_(3)-overset(6)(C)H_(2)-overset(5)(C)H-overset(4)(C)H_(2)-overset(3)(C)H_(2)-overset(2)(C)H_(2)-overset(1)(C)-OH),(" |"" ||"),(" "Br" "O),(" 5-Bromoheptanoic acid"):}` |
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| 448. |
Write structural formulae for compounds named as (a) 1-Bromoheptane (b) 5-Bromoheptanoic acid |
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Answer» (a) `overset(7)(CH_(3))-overset(6)(CH_(2))-overset(5)(CH_(2))-overset(4)(CH_(2))-overset(3)(CH_(2))-overset(2)(CH_(2))-overset(1)(CH_(2))-Br` (b) `overset(7)(CH_(3))-overset(6)(CH_(2))-underset(Br)underset(|)overset(5)(C)H-overset(4)(CH_(2))-overset(3)(CH_(2))-overset(2)(CH_(2))-overset(1)(C)OOH` |
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| 449. |
Write the structures of the following : (i) But-2-en-1-ol (ii) 2-Aminoethan-1-ol (iii) 2, 4-Dimethylhexan-3-one (iv) 1, 3-Diaminopropane (v) 4-Ethyl-2, 4-dimethylhexane (vi) 5-(1, 2-Dimethylpropyl) nonane. |
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Answer» (i) `CH_(3)-CH=CH-CH_(2)-OH` (ii) `HO-CH_(2)-CH_(2)-NH_(2)` (iii) `{:(" "O),(" ||"),(CH_(3)-CH-C-CH-CH_(2)-CH_(3)),(" |"" |"),(" "CH_(3)" "CH_(3)):}` (iv) `H_(2)N-CH_(2)-CH_(2)-CH_(2)-NH_(2)` (v) `{:(" "CH_(3)),(" |"),(CH_(3)-CH-CH_(2)-C-CH_(2)-CH_(3)),(" |"" |"),(" "CH_(3)" "C_(2)H_(5)):}` (vi) `{:(CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH-CH_(2)-CH_(2)-CH_(2)-CH_(3)),(" |"),(" "CH-CH_(3)),(" |"),(" "CH-CH_(3)),(" |"),(" "CH_(3)):}` |
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| 450. |
The `IUPAC` name of neopentane isA. 2-methylbutaneB. 2, 2 dimethyl propaneC. 2-methyl propaneD. 2, 2-dimethyl butane. |
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Answer» Correct Answer - B `underset("IUPAC name 2,2,dimethyl propane")underset()("neopentane "H_(3)C-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-CH_(2))` |
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