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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

Who produces the cellulase in the intestine of ungulates?(a) Bacteria(b) Mosses(c) Lichens(d) ProtozoaI have been asked this question in an interview.This key question is from Population Interactions-1 in portion Organisms and Populations of Biology – Class 12

Answer»

Right ANSWER is (a) Bacteria

Easy explanation: VARIOUS BACTERIAL species PRODUCE the cellulase in the intestine of ungulates. Since many of them are herbivores the gut-bacteria help in the digestion of cellulose. Most of the gut-bacteria are anaerobic in nature.

52.

What kind of interaction is mutualism?(a) Negative Interspecific(b) Positive Intraspecific(c) Negative Intraspecific(d) Positive InterspecificI got this question during an online exam.I would like to ask this question from Population Interactions-1 in portion Organisms and Populations of Biology – Class 12

Answer» CORRECT choice is (d) Positive Interspecific

Best explanation: MUTUALISM is a positively directed interspecific RELATIONSHIP. It is a biological interaction between ORGANISMS of different species in which each INDIVIDUAL receives the benefit.
53.

What happens to two species in mutualism?(a) Only one is benefited(b) Both live differently(c) Both are benefited(d) Only one is harmedI have been asked this question during an interview.My query is from Population Interactions-1 topic in section Organisms and Populations of Biology – Class 12

Answer» RIGHT answer is (c) Both are benefited

Easiest explanation: Mutualism is a biological interaction between organisms of different SPECIES in which each individual receives a benefit. It is a positively DIRECTED relationship SINCE both organisms are benefited.
54.

What is a biological interaction between organisms of different species in which each individual receives benefit known?(a) Parasitism(b) Competition(c) Commensalism(d) MutualismI got this question at a job interview.My enquiry is from Population Interactions-1 in division Organisms and Populations of Biology – Class 12

Answer» RIGHT answer is (d) Mutualism

To ELABORATE: Mutualism is a BIOLOGICAL interaction between ORGANISMS of different species in which each individual receives a benefit. It is a positively DIRECTED relationship since both organisms are benefited.
55.

What is a competition between the individuals of two separate species for sharing the same resources in the same area known?(a) Apparent competition(b) Interspecific competition(c) Interference competition(d) Intraspecific competitionThe question was asked during an online exam.My question is taken from Population Interactions-1 in chapter Organisms and Populations of Biology – Class 12

Answer»

Right choice is (b) INTERSPECIFIC COMPETITION

For explanation: Interspecific competition is the competition between the individuals of two separate SPECIES for sharing the same resources in the same area. An example is tigers and lions living in the same area competing for the same prey.

56.

In which two species apparent competition occurs indirectly?(a) Compete for space(b) Fight for the same resources and mate(c) Have a common prey(d) Share the same resources in a territoryThe question was posed to me in an internship interview.Origin of the question is Population Interactions-1 in division Organisms and Populations of Biology – Class 12

Answer»

Right ANSWER is (c) Have a common prey

For explanation: The APPARENT competition occurs INDIRECTLY between two species that fight for the same prey. In this, both the species may serve as prey for a common predator. It is an indirect negative INTERACTION.

57.

Where exploitation competition does occur indirectly?(a) One individual prevents the survival and reproduction of others(b) Two species have common prey(c) Two separate species compete for different resources and space(d) Organisms compete for common spaceI had been asked this question in exam.My query is from Population Interactions-1 in section Organisms and Populations of Biology – Class 12

Answer»

Right option is (d) Organisms compete for common space

For EXPLANATION I would say: The exploitation COMPETITION occurs INDIRECTLY when organisms compete for common RESOURCES like space or territory, food or prey. It RESULTS in depletion in the availability and amount of resources.

58.

Where the interference competition does occur directly between individuals?(a) Two species have a common prey(b) One individual prevents the reproduction of others(c) Organism compete for space(d) Two separate species compete for the same resources and spaceThe question was asked during an interview.Question is from Population Interactions-1 in portion Organisms and Populations of Biology – Class 12

Answer» RIGHT option is (b) One individual prevents the reproduction of others

To explain I would say: The interference COMPETITION is where one individual prevents the reproduction of others. Along with this, the survival of other species is also PREVENTED. It can occur via aggression and is thought to stabilize consumer-resource systems.
59.

In which curve the population density shows a sudden crash?(a) M-shaped(b) N-shaped(c) J-shaped(d) S-shapedThe question was posed to me at a job interview.I need to ask this question from Growth Models topic in division Organisms and Populations of Biology – Class 12

Answer» RIGHT choice is (c) J-shaped

To explain I would say: The population density shows a sudden crash in the J-shaped curve. In this, there is no STATIONARY phase and the ENVIRONMENTAL RESISTANCE operates.
60.

Who gave the following sentence “Two closely related species competing for the same resources cannot co-exist indefinitely and the competitively inferior will be eliminated eventually”?(a) Gause’s competitive exclusion principle(b) Mutation Theory(c) Theory of Special Creation(d) Theory of Organic EvolutionI have been asked this question during an interview.My question is from Population Interactions-1 in division Organisms and Populations of Biology – Class 12

Answer»

The correct choice is (a) Gause’s competitive exclusion principle

To elaborate: The above sentence is given by Gause’s competitive exclusion principle. It states that TWO species having the same resources cannot live together at CONSTANT POPULATION values. The INFERIOR species will be eliminated with TIME due to natural selection.

61.

What is the interaction between species in which the fitness of one overpowers the presence and fitness of another called?(a) Competition(b) Mutualism(c) Parasitism(d) CommensalismThe question was posed to me during an interview.I want to ask this question from Population Interactions-1 in portion Organisms and Populations of Biology – Class 12

Answer» CORRECT CHOICE is (a) Competition

To EXPLAIN: In competition interaction, the fitness of ONE organism overpowers the presence and fitness of another. In these organisms of same or different species, living in the same or different COMMUNITY fights for the same resources.
62.

In which growth the environmental resistance suddenly occurs?(a) Logistic growth(b) Sigmoidal growth(c) S-shaped growth curve(d) Exponential growthI had been asked this question in quiz.I need to ask this question from Growth Models topic in portion Organisms and Populations of Biology – Class 12

Answer»

The correct OPTION is (d) EXPONENTIAL growth

To explain: The ENVIRONMENTAL RESISTANCE suddenly occurs in exponential growth. In this, there is no stationary phase and population density shows a sudden crash due to environmental resistance.

63.

In which phase is the stationary phase absent?(a) Sigmoidal growth(b) Exponential growth(c) Decreasing growth(d) Deacceleration growthThe question was asked in an international level competition.My doubt stems from Growth Models in chapter Organisms and Populations of Biology – Class 12

Answer»

Right choice is (b) Exponential growth

The EXPLANATION: The STATIONARY phase is absent in exponential growth. Exponential growth is observed when resources in the population are unlimited. The population grows in GEOMETRIC fashion and RESULTS in a J-shaped CURVE.

64.

Which shape does the exponential growth curve show?(a) J-shape(b) U-shape(c) W-shape(d) M-shapeThis question was posed to me in an interview for internship.This question is from Growth Models topic in portion Organisms and Populations of Biology – Class 12

Answer»

Right answer is (a) J-shape

To explain I would SAY: An exponential growth is observed when resources in the population are UNLIMITED. The population grows in GEOMETRIC fashion and RESULTS in a J-shaped curve.

65.

Which of the following is a S-shaped growth curve?(a) Exponential growth(b) Logistic growth curve(c) J-shaped curve(d) Geometric curveI had been asked this question in my homework.My question is from Growth Models topic in portion Organisms and Populations of Biology – Class 12

Answer»

The correct choice is (B) Logistic growth curve

The best explanation: The logistic growth curve is also known as the sigmoid / S-shaped growth curve. It is CONSIDERED to be a realistic curve. It is obtained DUE to the FINITE and limited source of RESOURCES in a population. It is also called a Verhulst-Pearl Logistic Growth curve.

66.

Exponential growth is observed in which fashion?(a) Geometric(b) Algebraic(c) Declining(d) SteadyThe question was posed to me in my homework.The question is from Growth Models topic in section Organisms and Populations of Biology – Class 12

Answer»

Right ANSWER is (a) Geometric

Best explanation: The exponential growth is in which the POPULATION continues to MULTIPLY in a geometric FASHION. It results in a J-shaped curve. It is obtained when the resources in the population are UNLIMITED.

67.

When responses in a population are unlimited which growth is observed?(a) Logistic growth(b) Decreasing growth(c) Lag phase growth(d) Exponential growthI have been asked this question in an international level competition.This interesting question is from Growth Models topic in division Organisms and Populations of Biology – Class 12

Answer»

Right ANSWER is (d) Exponential GROWTH

For explanation: An exponential growth is observed when resources in the population are unlimited. The population grows in GEOMETRIC FASHION and results in a J-shaped curve.

68.

When responses in a population are limiting which growth is observed?(a) Increasing growth(b) Logistic growth(c) Decreasing growth(d) Stationary growthI got this question in examination.My enquiry is from Growth Models topic in division Organisms and Populations of Biology – Class 12

Answer»

The correct option is (B) Logistic growth

Explanation: Logistic growth is seen when resources in a population are limiting. It has 5 PHASES. It is ALSO known as the sigmoid/ S-shaped growth CURVE. It is a more realistic growth model.

69.

Which letter is used to designate the carrying capacity of a population?(a) A(b) S(c) K(d) NI have been asked this question in examination.The query is from Growth Models in portion Organisms and Populations of Biology – Class 12

Answer»

Right option is (C) K

Explanation: The carrying CAPACITY of a population is DESIGNATED by the letter ‘K’. The resources in a given habitat can be used by the MAXIMUM possible NUMBER of a population; beyond this, no further growth is seen in a population. This is known as the carrying capacity of that species in that habitat.

70.

In which phase population achieves zero growth?(a) Growing phase(b) Stationary phase(c) Lag phase(d) Log phaseI got this question during an interview for a job.The above asked question is from Growth Models topic in section Organisms and Populations of Biology – Class 12

Answer»

The CORRECT choice is (b) Stationary phase

To explain: The population achieves zero growth in the stationary phase. It is the last phase of logistic growth. It is due to many reasons such as EXHAUSTION of resources, aging, ETC.

71.

What happens in the negative down acceleration phase?(a) Grows at a faster rate(b) Growth gradually increase(c) Organisms growth gradually reduce(d) DeathI have been asked this question in an online quiz.My query is from Growth Models topic in division Organisms and Populations of Biology – Class 12

Answer» RIGHT answer is (C) Organisms growth gradually reduce

The best explanation: The negative down acceleration phase is the FOURTH phase of a sigmoid/ logistic/ S-shaped growth curve. In this phase the population density gradually REDUCES.
72.

What happens in the deacceleration phase?(a) Grow at a faster rate(b) Tend to adapt(c) Death(d) Organisms increase slowlyI got this question in my homework.The above asked question is from Growth Models in portion Organisms and Populations of Biology – Class 12

Answer»

The CORRECT option is (d) Organisms increase SLOWLY

For explanation: In the deacceleration phase, the organisms increase slowly. This happens due to LIMITED resources. It is the THIRD phase of a sigmoid/ logistic/ S-shaped growth curve.

73.

Which is the third phase in the logistic growth curve of the population?(a) Log phase(b) Deacceleration phase(c) Lag phase(d) Negative phaseThis question was posed to me during an interview.The origin of the question is Growth Models in portion Organisms and Populations of Biology – Class 12

Answer»

Correct ANSWER is (C) Lag phase

The best EXPLANATION: The third phase in the LOGISTIC growth of the population is the deacceleration phase. In this phase, the organisms increase SLOWLY. This happens due to limited resources.

74.

Which is the second phase of the sigmoidal growth curve?(a) Deceleration phase(b) Log phase(c) Exponential phase(d) Stationary phaseI have been asked this question in an interview for job.The doubt is from Growth Models in section Organisms and Populations of Biology – Class 12

Answer»

Right OPTION is (b) Log phase

Easy EXPLANATION: The second phase of the sigmoid (logistic) growth curve is the log phase. It is the logarithmic, exponential growth phase in which ORGANISMS MULTIPLY at a faster rate.

75.

In which of the following phase do organisms in a population multiply at a faster rate?(a) Deceleration phase(b) Stationary phase(c) Exponential phase(d) Log phaseI got this question during an interview for a job.The doubt is from Growth Models in division Organisms and Populations of Biology – Class 12

Answer» RIGHT choice is (d) LOG phase

Explanation: The ORGANISMS multiply at a faster RATE in the log phase. It is the second phase of the sigmoid (logistic) GROWTH curve. And the maximum growth of the population is observed in this phase.
76.

Which of the following initial phase is slow?(a) Declaration phase(b) Stationary phase(c) Lag phase(d) Log phaseThe question was asked during an interview.Asked question is from Growth Models in section Organisms and Populations of Biology – Class 12

Answer»

The CORRECT option is (C) Lag phase

To elaborate: The lag phase is initial and SLOW. It is the phase in which the population increases slowly and TENDS to adopt the new environment. The population DENSITY increases in the positive acceleration phase.

77.

What do organisms in a population do in the lag phase?(a) Grow at a slower rate(b) Grow at a faster rate(c) Death(d) Tend to adaptThe question was asked in final exam.My question is based upon Growth Models in chapter Organisms and Populations of Biology – Class 12

Answer» CORRECT option is (d) TEND to adapt

For explanation: The lag phase is the initial phase of a growth CURVE in which the population INCREASES slowly. In this phase, the population tries to ADOPT the new environment. The population density increases in the positive acceleration phase.
78.

How many phases does a logistic growth curve have?(a) 5(b) 8(c) 1(d) 4I got this question by my school teacher while I was bunking the class.I need to ask this question from Growth Models in division Organisms and Populations of Biology – Class 12

Answer»

The correct choice is (a) 5

Easiest explanation: A logistic (SIGMOIDAL) growth CURVE has 5 phases. They are lag PHASE, log phase, deacceleration phase, NEGATIVE down acceleration phase, and stationary phase.

79.

Which is the initial phase in logistic growth?(a) Log phase(b) Lag phase(c) Declining phase(d) Stationary phaseThis question was posed to me at a job interview.Question is from Growth Models topic in division Organisms and Populations of Biology – Class 12

Answer»

The correct answer is (b) Lag phase

For explanation: The initial phase of logistic growth is the lag phase. It has 5 phases. It is the phase in which the population increases SLOWLY and tends to adopt the NEW environment. The population DENSITY increases in the positive ACCELERATION phase.

80.

What is a sigmoid growth curve called?(a) Exponential growth curve(b) Logistic growth curve(c) Declining growth curve(d) Interacting curveThe question was posed to me during an interview for a job.This intriguing question comes from Growth Models in portion Organisms and Populations of Biology – Class 12

Answer»

Correct choice is (b) Logistic GROWTH curve

The explanation: A sigmoid growth curve is ALSO called a logistic growth curve. It is CONSIDERED to be a realistic curve. It is obtained DUE to the finite and limited SOURCE of resources in a population. It is also called a Verhulst-Pearl Logistic Growth curve.

81.

If in a population the natality is 25 and mortality is 55, in a span of 10 years. What is the growth rate (GR) of that population?(a) -3(b) 100(c) 28(d) -38I have been asked this question in a national level competition.Enquiry is from Population Growth in portion Organisms and Populations of Biology – Class 12

Answer»

The CORRECT ANSWER is (a) -3

Explanation: As per the FORMULA, GR = \(\frac{Natality – MORTALITY}{Unit \, time} = \frac{25 – 55}{10}\) = -3

The growth rate of the given area is -3 in 10 years.

82.

If in a population the natality is 50 and mortality is 80, in a span of 10 years. What is the growth rate (GR) of that population?(a) 28(b) 100(c) 10(d) -3I got this question by my college director while I was bunking the class.My doubt stems from Population Growth topic in portion Organisms and Populations of Biology – Class 12

Answer»

The correct option is (d) -3

The best explanation: As per the FORMULA, GR = \(\frac{NATALITY – Mortality}{Unit \, TIME} = \frac{50 – 80}{10}\) = -3

The growth rate of the given area is -3 in 10 years.

83.

If in a population the natality is 30 and mortality is 5, in a span of 10 years. What is the growth rate (GR) of that population?(a) 0(b) 2.5(c) 10(d) -10This question was addressed to me by my college professor while I was bunking the class.My query is from Population Growth in portion Organisms and Populations of Biology – Class 12

Answer» CORRECT option is (B) 2.5

Explanation: As per the formula, GR = \(\FRAC{NATALITY – Mortality}{Unit \, time} = \frac{30 – 5}{10}\) = 2.5

The growth rate of the given AREA is 2.5 in 10 years.
84.

If in a population the natality is 20 and mortality is 10, in a span of 10 years. What is the growth rate (GR) of that population?(a) 0(b) 20(c) 1(d) -10I have been asked this question in an online interview.Question is taken from Population Growth in portion Organisms and Populations of Biology – Class 12

Answer»

The correct answer is (c) 1

The EXPLANATION: As per the formula, GR = \(\frac{NATALITY – Mortality}{UNIT \, time} = \frac{20 – 10}{10}\) = 1

The growth rate of the given area is 1 in 10 years.

85.

The 95 individuals are dying per year in a population, and the mid-year population is 7000. What is the death rate of that area?(a) 200(b) 13.6(c) 100(d) 395This question was addressed to me by my school principal while I was bunking the class.My question comes from Population Growth topic in chapter Organisms and Populations of Biology – Class 12

Answer»

The correct answer is (b) 13.6

Easy EXPLANATION: As per the FORMULA, Natality = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, population}\) x 1000 = \(\frac{95}{7000}\)1000 = 13.6

The BIRTH rate of the given area is 13.6 per year.

86.

The 75 individuals are dying per year in a population, and the mid-year population is 7000. What is the death rate of that area?(a) 13(b) 30(c) 10.7(d) 39I got this question in class test.My question comes from Population Growth topic in portion Organisms and Populations of Biology – Class 12

Answer»

The correct answer is (c) 10.7

To explain I would say: As per the FORMULA, Natality = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, POPULATION}\) X 1000 = \(\frac{75}{7000}\)1000 = 10.7

The BIRTH rate of the given AREA is 10.7 per year.

87.

The 25 individuals are dying per year in a population, and the mid-year population is 7000. What is the death rate of that area?(a) 13(b) 30(c) 2(d) 3.6This question was addressed to me in an international level competition.My question is taken from Population Growth in section Organisms and Populations of Biology – Class 12

Answer»

Correct choice is (d) 3.6

The best I can explain: As PER the formula, Natality = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, population}\) X 1000 = \(\frac{25}{7000}\)1000 = 3.6

The birth RATE of the given AREA is 3.6 per year.

88.

The 80 individuals are born per year in a population, and the mid-year population is 5000. What is the birth rate of that area?(a) 20(b) 16(c) 4(d) 2I got this question in exam.This intriguing question comes from Population Growth in section Organisms and Populations of Biology – Class 12

Answer»

Correct CHOICE is (b) 16

To explain I would SAY: As per the formula, Natality = \(\frac{NUMBER \, of \, deaths \, per \, year}{Mid-year \, population}\) X 1000 = \(\frac{80}{5000}\)1000 = 16

The birth rate of the given area is 16 per year.

89.

The 20 individuals are dying per year in a population, and the mid-year population is 7000. What is the death rate of that area?(a) 13(b) 30(c) 2.8(d) 29I have been asked this question in unit test.This question is from Population Growth topic in division Organisms and Populations of Biology – Class 12

Answer»

The CORRECT choice is (c) 2.8

For explanation: As per the formula, Natality = \(\frac{Number \, of \, DEATHS \, per \, YEAR}{Mid-year \, population}\) X 1000 = \(\frac{20}{7000}\)1000 = 2.8

The birth RATE of the given area is 2.8 per year.

90.

The 100 individuals are born per year in a population, and the mid-year population is 5000. What is the birth rate of that area?(a) 2(b) 1.0(c) 20(d) 2The question was asked in an online quiz.I need to ask this question from Population Growth topic in section Organisms and Populations of Biology – Class 12

Answer» CORRECT option is (C) 20

For explanation I WOULD say: As per the formula, NATALITY = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, population}\) x 1000 = \(\frac{100}{5000}\)1000 = 20

The birth rate of the given area is 20 per year.
91.

The 20 individuals are born per year in a population, and the mid-year population is 5000. What is the birth rate of that area?(a) 20(b) 1.0(c) 4(d) 2This question was posed to me during an interview for a job.Enquiry is from Population Growth topic in chapter Organisms and Populations of Biology – Class 12

Answer» CORRECT answer is (c) 4

The explanation: As per the FORMULA, Natality = \(\frac{Number \, of \, DEATHS \, per \, year}{Mid-year \, population}\) x 1000 = \(\frac{20}{5000}\)1000 = 4

The BIRTH rate of the given area is 4 per year.
92.

The 10 individuals are born per year in a population, and the mid-year population is 5000. What is the birth rate of that area?(a) 20(b) 1.6(c) 4(d) 2This question was posed to me during an online interview.This key question is from Population Growth in portion Organisms and Populations of Biology – Class 12

Answer» CORRECT option is (d) 2

Easiest explanation: As per the formula, Natality = \(\FRAC{Number \, of \, DEATHS \, per \, YEAR}{Mid-year \, POPULATION}\) x 1000 = \(\frac{10}{5000}\)1000 = 2

The birth rate of the given area is 2 per year.
93.

Which of the following formula correctly defines growth rate (GR)?(a) GR = \(\frac{Natality – Mortality}{Unit time}\)(b) GR = \(\frac{Natality – Natality}{Unit time}\)(c) GR = \(\frac{Mortality – Natality}{Unit time}\)(d) GR = \(\frac{Mortality – Mortality}{Unit time}\)The question was posed to me in an online quiz.Query is from Population Growth in chapter Organisms and Populations of Biology – Class 12

Answer»

Correct option is (a) GR = \(\frac{NATALITY – Mortality}{Unit time}\)

For explanation I WOULD say: The growth RATE. It is the increase in POPULATION due to an actual NUMBER of individuals added to the population. Usually in India, the growth rate is calculated every 10 years.

94.

Which of the following formula correctly defines mortality?(a) Mortality = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, population}\) x 1000(b) Mortality = \(\frac{Number \, of \, births \, per \, year}{Mid-year \, population}\) x 1000(c) Mortality = Number of deaths x 1000(d) Mortality = Number of births x 1000The question was posed to me during an interview for a job.My question comes from Population Growth in chapter Organisms and Populations of Biology – Class 12

Answer»

Right answer is (a) Mortality = \(\frac{Number \, of \, deaths \, per \, YEAR}{Mid-year \, population}\) x 1000

Easy EXPLANATION: The growth rate is the INCREASE in population due to an actual number of INDIVIDUALS added to the population. Usually in India, the growth rate is calculated EVERY 10 years.

95.

Which of the following formula correctly defines natality?(a) Natality = \(\frac{Number \, of \, deaths \, per \, year}{Mid-year \, population}\) x 1000(b) Natality = \(\frac{Number \, of \, births \, per \, year}{Mid-year \, population}\) x 1000(c) Natality = \(\frac{Number \, of \, births + Number \, of \, deaths}{Mid-year \, population}\) x 1000(d) Natality = Births – Deaths x 1000I have been asked this question in quiz.The origin of the question is Population Growth in chapter Organisms and Populations of Biology – Class 12

Answer»

The correct choice is (B) Natality = \(\frac{Number \, of \, births \, PER \, year}{Mid-year \, population}\) x 1000

Explanation: The natality is also KNOWN as the birth rate. It is the number of individuals born in a population at a specific time. For humans, it is described as a number of individuals born per 1000 of the population per year.

96.

What does Nt define?(a) The population diversity at time t(b) The birth rate at time t(c) The death rate at time t(d) The population density at time tI got this question during an interview.The above asked question is from Population Growth in division Organisms and Populations of Biology – Class 12

Answer»

Correct answer is (d) The population density at time t

To explain I WOULD say: Nt defines the population density at time t. The DEATH rate, BIRTH rate, IMMIGRATION, and emigration are the factors influencing population density.

97.

In which year does the first population count of India start?(a) 1885(b) 1891(c) 1900(d) 2001I got this question in quiz.Origin of the question is Population Growth topic in portion Organisms and Populations of Biology – Class 12

Answer»

Correct ANSWER is (B) 1891

For explanation I WOULD say: The first population count of India started in the year 1891. It was conducted by the British raj under the supervision of Jervoise Athelstane Baines. The last CENSUS of India was carried out in 2011 while NEXT will be carried out in 2021.

98.

Which one of the following causes a population explosion?(a) The decrease in infant mortality rate and an increase in the death rate(b) The decrease in death rate, maternal and infant mortality rate(c) The decrease in infant mortality rate(d) Increase in maternal mortality rate and decrease in the death rateI had been asked this question in my homework.My question is taken from Population Growth topic in portion Organisms and Populations of Biology – Class 12

Answer» RIGHT answer is (c) The DECREASE in infant mortality rate

To explain: The decrease in death rate, maternal and infant mortality rate is the cause of POPULATION explosion. This leads to a LARGE and sudden INCREASE in the rate of population.
99.

What is the relative proportion of individuals of various age groups in the population called?(a) Growth rate(b) Density(c) Diversity(d) Age structureThis question was posed to me during an online interview.My question is taken from Population Growth topic in section Organisms and Populations of Biology – Class 12

Answer»

The correct CHOICE is (d) Age structure

The best explanation: The relative proportion of individuals of VARIOUS age GROUPS in the population is called the age structure of the population. It is the distribution of a population in terms of the proportions of individuals at DIFFERENT life stages.

100.

What does coming new of individuals to a population from outside called?(a) Community(b) Density(c) Emigration(d) ImmigrationThe question was asked in my homework.Enquiry is from Population Growth in division Organisms and Populations of Biology – Class 12

Answer»

Correct CHOICE is (c) Emigration

Explanation: It is an ACT of coming into a different country of which they are not natives and RESIDE permanently. It is RESPONSIBLE for an INCREASE in population density.