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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1051. |
The strongest acid among the following isA. concentrated `H2SO_4 `B. concentrated `H_3PO_4 `C. concentrated HCID. solid oxalic acid |
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Answer» Correct Answer - A Conc. `H_2SO_4` is stonger as dissociation is more |
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| 1052. |
Why sulphurous acid and sulphites are reducing in nature. |
| Answer» Correct Answer - B::C::D | |
| 1053. |
Sulphurous acid is reducing agent due toA. absence of hydrogen bondingB. presence of lone pair of electrons of sulphurC. absence of bonding between oxygen atomsD. presence of only three oxygen atoms |
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Answer» Correct Answer - B Sulphurous acid is reducing agent due to presence of lone `e^-` pair on S `[O=underset(OH)underset|overset(* *)S-OH]` |
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| 1054. |
The hybridisation of sulphur in `SF_(6)` isA. `sp^3d^2`B. `sp^3d`C. `sp^3`D. `sp^2d` |
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Answer» Correct Answer - A S is `sp^3d^2` hybridised in `SF_6` |
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| 1055. |
The hybridisation of sulphur in `SF_(4)` isA. `sp^3d^2`B. `sp^3 d`C. `sp^3`D. `sp^2d` |
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Answer» Correct Answer - B S in `SF_4` is `sp^3d` hybridised |
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| 1056. |
Among the group 16 elements the only element which does not exist as octa-atomic solid isA. SulphurB. SeleniumC. OxygenD. Tellurium |
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Answer» Correct Answer - C oxygen is diatomic `(O_2)` |
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| 1057. |
The chemical formula of baryte, the salt of sulphur isA. `CaSO_4. 2H_2O`B. `MgSO_4 . 7H_2O`C. `BaSO_4`D. `CuFeS_2` |
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Answer» Correct Answer - C Buryte is `BaSO_4` |
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| 1058. |
S-S bond is present inA. `S_2O_7^(2-)`B. `S_3O_9`C. `S_2O_4^(2-)`D. `S_2O_3^(2-)` |
| Answer» Correct Answer - C | |
| 1059. |
The chemical formula of baryte, the salt of sulphur isA. `CaSO_4 . 2H_2O`B. `MgSO_4 . 7H_2O`C. `BaSO_4`D. `CuFeS_2` |
| Answer» Correct Answer - C | |
| 1060. |
The reaction, which forms nitric oxide, isA. `C` and `N_(2)O`B. `Cu` and `N_(2)O`C. `Na` and `NH_(3)`D. `Cu` and `HNO_(3)` |
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Answer» Correct Answer - D Copper react with Conc.nitric acid to form a nitric oxide. |
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| 1061. |
Which is used in the Haper process for the manufacture of `NH_(3)`?A. `Pt`B. `Fe+Mo`C. `CuO`D. `Al_(2)O_(3)` |
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Answer» Correct Answer - B In the Haber process for the manufacture of `NH_(3)`,Fe is used catalyst and MO as a promoter. |
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| 1062. |
Which is most acidic in nature?A. `Na_2O`B. `NO_2`C. `Al_2O_3`D. CaO |
| Answer» Correct Answer - B | |
| 1063. |
The oxide of nitrogen used as an anaesthetic for minor operation by dentists isA. `N_2O`B. `N_2O_4`C. NOD. `N_2O_3` |
| Answer» Correct Answer - A | |
| 1064. |
Which one of the following can be used as an anaesthetic?A. `N_(2)O`B. `NO`C. `NCl_(3)`D. `NO_(3)` |
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Answer» Correct Answer - A `N_(2)O` on account of stimulating effect on nervous system. |
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| 1065. |
Which one of the following can be used as an anaesthetic?A. `N_2O`B. `NO`C. `NCl_3`D. `NO_2` |
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Answer» Correct Answer - A Property and uses of `N_2O` |
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| 1066. |
The brown ring test for `NO_2^-` and `NO_3^-` is due to the formation of complex ion with a formula -A. `[Fe(H_2O)_6]^(2+)`B. `[Fe(NO)(CN)_5]^(2+)`C. `[Fe(H_2O)_5NO]^(2+)`D. `[Fe(H_2O)(NO)_5]^(2+)` |
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Answer» Correct Answer - C Reaction of brown ring test |
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| 1067. |
The inert compound toward water would be:A. `SiCl_(4)`B. `C Cl_(4)`C. `BCl_(3)`D. `PCl_(3)` |
| Answer» Correct Answer - B | |
| 1068. |
Select the correct statement regarding `B_(2)H_(6)`.A. It has only `2c-2e^(-)` bondB. It is planarC. It does not react with `NH_(3)`D. Hybridisation of boron is `sp^(3)` |
| Answer» Correct Answer - D | |
| 1069. |
Select the correct statement regarding `B_(2)H_(6)`.A. Each B atom undergoes `sp^(3)` hybridisation.B. There is tetrahedral environment around each B atom.C. Hb-Bu-Hb bond angle is ` 122^(@)`D. These are four hydrogen bridged bonds. |
| Answer» All the three statements are correct. | |
| 1070. |
Which is incorrect statement regarding `B_(2)H_(6)` ?A. It is a strong reducing agentB. On heating, gives amorphous boronC. It is a planar moleculeD. With excess `(CH_(3))_(3)N`, undergo symmetrical cleavage |
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Answer» Correct Answer - C |
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| 1071. |
All of the following gives orthoboric acid axceptA. `B_(2)H_(6) + H_(2)O rarr`B. `B_(2)H_(6) + HCl rarr`C. `Na_(2)B_(4)O_(7) + H_(2)SO_(4)(aq) rarr`D. `Ca_(2)B_(6)O_(11) + SO_(2)(aq) rarr` |
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Answer» Correct Answer - B |
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| 1072. |
The correct statement (s) for orthoboric acid is/areA. It behaves as a weak acid in water due to self ionisationB. Acidity of its aqueous solution increases upon addition of ethylene glycolC. It has a three-dimensional structure due to hydrogen bondingD. It is a weak electrolyte in water |
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Answer» Correct Answer - B::D |
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| 1073. |
Assertion: `[Al(NH_(3))_(6)]^(3+)` does not exist in aqueous solution. Reason: `Al^(3+)` being smaller ion posseses high degree of hydration. `[Al(NH_(3))_(6)]^(3+)+6?H_(2)O to [Al(H_(2)O)_(6)]^(3+)+6NH_(3)`A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - A `Al^(3+)` ions being smaller posses high degree of hydration and therefore, the ligand `H_(2)O` takes position of `NH_(3)`. |
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| 1074. |
Assertion: `[Al(NH_(3))_(6)]^(3+)` does not exist in aqueous solution. Reason: `Al^(3+)` being smaller ion posseses high degree of hydration. `[Al(NH_(3))_(6)]^(3+)+6?H_(2)O to [Al(H_(2)O)_(6)]^(3+)+6NH_(3)`A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. Ifassertion is false but reason is true. |
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Answer» Correct Answer - A `Al^(3+)` ions being smaller posses high degree of hydration and therefore, the ligand `H_(2)O` takes position of `NH_(3)`. |
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| 1075. |
Halogens belong to group ………………. In the modern periodic table.A. 15B. 16C. 17D. 18 |
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Answer» Correct Answer - C Halogens (Cl,Br, I) belongs to group 17. |
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| 1076. |
`Mg_3 N_2` on reaction with water gives off `NH_3`, but `MgCl_2` on reaction with water does not give `HCl` at room temperature. |
| Answer» Correct Answer - A::B::C::D | |
| 1077. |
Write balanced equation for the following : Phosphorus is treated with concentrated nitric acid. |
| Answer» Correct Answer - B::C::D | |
| 1078. |
Boron, the first member of group 13 (p-block) is a typical non-metal. H exists in two allotropic forms. The compounds of boron are mainly electron deficient as well as Lewis acids. For example, all the trihalides of boron `(BX_(3))` are Lewis acids. The expected order of acidic strength based on the electro negativity of halogen atoms is : `BF_(3)gtBC l_(3)gtBBr_(3)gtBl_(3)`. But the actual order is the reverse. This is explained with the help of the concept of back bonding `(p pi- p pi)` . Among the hydrides of boron. diborane has a bridged structure. Among the halides of the elements of group 13, the one which is most acidic is:A. `BF_(3)`B. `AlCl_(3)`C. `BCl_(3)`D. `BBr_(3)`. |
| Answer» `BBr_(3)` is maximum acidic because `p pi- p pi` back bonding is the minimum. | |
| 1079. |
Boron, the first member of group 13 (p-block) is a typical non-metal. H exists in two allotropic forms. The compounds of boron are mainly electron deficient as well as Lewis acids. For example, all the trihalides of boron `(BX_(3))` are Lewis acids. The expected order of acidic strength based on the electro negativity of halogen atoms is : `BF_(3)gtBC l_(3)gtBBr_(3)gtBl_(3)`. But the actual order is the reverse. This is explained with the help of the concept of back bonding `(p pi- p pi)` . Among the hydrides of boron. diborane has a bridged structure. Which of the following statements of group 13, the one which is most acidic is:A. `BCl_(3)` is a covalent compoundB. `BCl_(3)` acts as a Lewis acidC. `BCl_(3)` does not form a dimerD. In `BCl_(3)`, the B-Cl bond length is greater thatn the bond length of single covalent b ond. |
| Answer» B-Cl bond length is lesser than that of actual bond length of a pure single bond because the bond has a partial double bond character on account of back bonding. | |
| 1080. |
Which is the correct statement for the given acids ?A. Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acidB. Phosphinic acid is a diprotic acid while phosphonic acid is a monoprotic acidC. Both are diprotic acidsD. Both are triprotic acids |
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Answer» Correct Answer - A Phosphinic aicd, `H_(3)PO_(2)` (monoprotic), phosphonic acid, `H_(3)PO_(3)` (diprotic), |
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| 1081. |
The reaction of the type `2X_2 + S to SX_4` is shown by sulphur when X isA. fluorine and chlorineB. chlorineC. chlorine and bromineD. F,Cl,Br |
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Answer» Correct Answer - A Fluorine and chlorine are more electronegative than sulphur , so they can displace it form its salt. |
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| 1082. |
The structural formula of lithium tetrahydrido-aluminate isA. `Al[LiH_(4)]`B. `Al_(2)[LiH_(4)]_(3)`C. `Li[AlH_(4)]`D. `Li[AlH_(4)]_(2)` |
| Answer» Correct Answer - C | |
| 1083. |
The repeating structural unit is silicone isA. `SiO_(2)`B. `-underset(R ) underset(l)overset(R )overset(|)(Si)-O-`C. `overset(R )overset(|)(O)-underset(R )underset(|)(Si)-O-`D. `-underset(R )underset(|)overset(|)(S)-O-O-R` |
| Answer» Correct Answer - B | |
| 1084. |
The white pigment used under the name pearl white isA. BiOClB. `BiCl_3`C. `PCl_3`D. `AsCl_3` |
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Answer» Correct Answer - A Pearl white is BiOCl (informative) |
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| 1085. |
Which of the following metals does not dissolve in concentrated `HNO_(3)` ?A. `Pb`B. `Cu`C. `Au`D. `Hg` |
| Answer» Correct Answer - C | |
| 1086. |
Statement-1 : Bismith does not form a pentoxides. Statement-2 : The stability of the highest oxidation states decreases on descending the group due to inert pair effect.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-6B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-7C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
| Answer» Correct Answer - A | |
| 1087. |
The stability of `+5` oxidation state decreases down the group `15` of the periodic table.Explain this observation giving appropriate reasons. |
| Answer» All the elements of group `15` have five electrons in the valence shell, two in the `s`-subshell and three in the `p`-subshell.Therefore, among others, they can show positive oxidation states of `+3` (due to participation of only `p`-electrons) and `+5` (due to the participation of both `s-` and `p-`electrons of the valence shell).Now `N` does not have `d`- or `f`-electrons but all other elements have either `d`- and `f`-electrons in the inner shells. Since `d` and `f` electrons shield the `s`-electrons of the valence shell more effectively than the `p`-electrons, therefore, on moving down the group, tendency of `s`-electrons to participate in bond formation decreases while that of `p`-electrons increases.In other words, among heavier elements of group `15`, the electron pair in `s`-orbital of the valence shell bonds shows reductance to participate in bond formation.In other words, among heavier elements, only `p`-electrons participate in bond formation and hence show an oxidation state of `+3`.This is called inert pair effect.Further, as the number of `d-` and `f-` electrons increases down the group, the inert pair effect becomes more and more pronounced. In other words, down the group from `As` to `Bi`, the stability of `+3` oxidation state increases while that of `+5` oxidation state decreases. | |
| 1088. |
Nitric acid usually turns yellow on standing.This is due toA. absorption of yellow wavelengthB. slow decomposition of `HNO_(3)` into `NO_(2)`C. its oxidation by atmospheric airD. absorption of moisture by it |
| Answer» Correct Answer - B | |
| 1089. |
Following are neutral oxides except :A. `NO`B. `N_(2)O`C. `CO`D. `NO_(2)` |
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Answer» Correct Answer - D `2NO_(2)+H_(2)OtoHNO_(3)+HNO_(2)` It is a mixed anhydride of `HNO_(2)` and `HNO_(3)` |
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| 1090. |
`HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is :A. `NO_(2)`B. `N_(2)O_(3)`C. `N_(2)O_(4)`D. `N_(2)O_(5)` |
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Answer» Correct Answer - D `4HNO_(3)+P_(4)O_(10)overset(250 K)to 4HPO_(3) + N_(2)O_(5)` (anhydrid of `HNO_(3)`) |
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| 1091. |
`HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is :A. `N_(2)O`B. `N_(2)O_(3)`C. `NO_(2)`D. `N_(2)O_(5)` |
| Answer» Correct Answer - D | |
| 1092. |
Assertion : `HNO_(3)` makes iron passive. Reason : `HNO_(3)` forms a protective layer of ferric nitrate on the surface of iron.A. Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.B. Both assertion is and reason are correct statements, but reason is not the correct explanation of the assertion.C. Assertion is correct, but reason is wrong statement.D. Assertion is wrong but reason is correct statement. |
| Answer» Correct reason `HNO_(3)` forms a protective layer of ferrosoferric oxide on the surface of iron. | |
| 1093. |
Assertion (A) `HNO_(3)` makes iron passive. Reason (R ) `HNO_(3)` forms a protective layer of ferric nitrate on the surface of iron.A. Both Assertion and Reason are correct statements , and Reason is the correct explation of the Assertion.B. Both Assertion and Reason are correct statements , and Reason is not the correct explanation of the Assertion.C. Assertion is correct, but Reason is wrong statement.D. Assertion is wrong but Reason is correct statement. |
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Answer» Assertion is true, but reason is false. `HNO_(3)` makes iron passive due to formation of passive form of oxide on the surface. Hence, Fe does not dissolve in conc `HNO_(3)` solution. |
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| 1094. |
Which is incorrectly matched ?A. `CsBr_(3) iff Cs^(+)+Br_(3)^(-)`B. `I_(4)O_(9) iff I^(3+)+(IO_(3)^(-))_(3)`C. `AgBrO_(3) iff Ag^(+)+BrO_(3)^(-)`D. `I_(2)O_(4) iff IO_(2)^(-)+IO_(2)^(+)` |
| Answer» Correct Answer - D | |
| 1095. |
One mole of calcium phosphide on reaction with excess of water give:A. one mole of phosphineB. two moles of phosphoric acidC. two mole of phosphineD. one mole of phosphorus penta- oxide |
| Answer» Correct Answer - C | |
| 1096. |
When `PH_(3)` absorbed in `HgCl_(2)` solution the corresponding phosphide is obtained:A. `Hg_(2)P_(3)`B. `Hg_(3)P_(2)`C. `Hg_(3)(PO_(4))_(2)`D. none of these |
| Answer» Correct Answer - B | |
| 1097. |
`P_4 O_(10)` is not used to dry `NH_3` gas becauseA. `P_4O_10` reacts with moisture in `NH_3`B. `P_4O_10` is not a drying agentC. `P_4O_10` is acidic and `NH_3` is basicD. `P_4O_10` is basic and `NH_3` is acidic |
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Answer» Correct Answer - C `P_4O_10` is acidic oxide, hence reacts with `NH_3` with is basic in nature |
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| 1098. |
Brown colour in `HNO_3` can be removed byA. adding Mg powderB. boiling the acidC. passing `NH_3` through acidD. passing air through warm acid |
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Answer» Correct Answer - D Colour is due to presence of `NO_2` in the solution. Removed by passing air . `NO_2` gets removed along with air. |
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| 1099. |
Aluminium phosphide (cellphos) is used as fumigant (killing insects and pests) because in the presence of moisture it givesA. `HNO_3`B. `H_3PO_4`C. `PH_3`D. White phosphorus |
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Answer» Correct Answer - C `AlP+3H_2O to Al(OH)_3 + PH_3` |
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| 1100. |
Which of the elements listed below occurs in allotropic forms?A. IodineB. CopperC. SulphurD. Silver |
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Answer» Correct Answer - C Sulphur (1)monoclinic (2) Rhombic (3) Plastic |
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