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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2001. |
The two types of bonds present in diborane are `"………….."` and `"………….."`. |
| Answer» Correct Answer - Covalent, (i.e, `2c-2e`) bonds, three centre two elecron `(3c-2e)` bonds | |
| 2002. |
Which one of the following statements is not true regarding diborane?A. It has two bidging hydrogens and four terminal hydrogenB. When methylated, the product is `Me_(4)B_(2)H_(2)`.C. The bridging hydrogens are in aplane perpendicular to the rest.D. All the `B-H` bond distances are equal. |
| Answer» Correct Answer - D | |
| 2003. |
In diboraneA. 4-Bridged hydrogens and two terminal hydrogens are presentB. 2-Bridged hydrogens and four terminal hydrogens are presentC. 3-Bridged and three terminal hydrogens are presentD. None of the above |
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Answer» Correct Answer - B In diborane `(B_(2)H_(6))` there are two bridged H atoms and four terminel H atoms which along with two B atoms lie in plane perpendicular to each other. |
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| 2004. |
Stability of trivalent and mono valent cation of group 13 (Boron family) will be in order :A. `Ga^(3+)ltIn^(3+)ltTI^(3+)`B. `Ga^(3+)gtIn^(3+)gtTI^(3+)`C. `Ga^(+)gtIn^(+)ltTI^(+)`D. `Ga^(+)ltIn^(+)ltTI^(+)` |
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Answer» Correct Answer - B,D By inert pair effect stability of `+3` state decreases and that of `+1` state increases along a group. |
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| 2005. |
Which oxide of nitrogen is `not` a common pollutant introduced into the atmosphere both due to natural and human activity?A. `N_(2)O_(5)`B. `NO_(2)`C. `N_(2)O`D. `NO` |
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Answer» Correct Answer - A Nitrous oxides `(N_(2)O)` occurs naturally in environment. In automobile engine, when fossil is burnt dinitrogen & dioxygen combine to yield `NO & NO_(2)`. |
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| 2006. |
A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. `H_(2)SO_(4)`. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will beA. `1.4`B. `3.0`C. `2.8`D. `4.4` |
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Answer» Correct Answer - C `Hunderset(0.05)(COO)Hoverset(H_(2)SO_(4))(rarr)underset(0.05)(H_(2)O)+underset(0.05)(CO)+underset(0.05)(CO)` `H_(2)underset(0.05)(C_(2))O_(4)overset(H_(2)SO_(4))(rarr)underset(0.05)(H_(2)O)+underset(0.05)(CO)+underset(0.05)(CO_(2))` Total moles of `CO=0.05+0.05=0.10` `KOH` absorbs `CO_(2)(g)` :. Mass of `CO=0.1xx28=2.8 g`. |
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| 2007. |
The number of lone pairs of electrons present in central atom of `CIF_3` is: |
| Answer» Correct Answer - 2 | |
| 2008. |
What products are expected from the desproprtionation reactin of hypochorous acid ?A. `HClO_3 and Cl_2O`B. `HClO_2 and HClO_4`C. `HCl and Cl_2O`D. `HCl and HCIO_3` |
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Answer» Correct Answer - 4 |
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| 2009. |
Explain why fluorine forms only one oxoacid, HOF.A. high electronegativityB. small sizeC. low electronegativity and large sizeD. Both (a) and (b) |
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Answer» Correct Answer - D Due to high electronegativity and small size , fluroine forms only one oxoacid , HOF known as fluoric (I) acid or hypofluorous acid . |
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| 2010. |
Consider following statements: (I): In diamond, each carbon atom is linked tetrahedrally to four other carbon atoms by `sp^(3)` bonds. (II): Graphite has planar hexagonal layers of carbone atoms held together by weak Van der Waals forces. (III): Silicon exists only in diamonds structure due to its tendacy to form `p pi- p pi` bonds to itself. In this.A. Only I and II are correctB. Only I is correctC. Only II and III are correctD. All are correct statement |
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Answer» Correct Answer - A Only `I` and `II` are correct |
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| 2011. |
Conidier following statements : I : In diamond, each carbon atom is linked tetrahedrally to four other carbon atoms by `sp_(3)` bonds. II : Graphite has planer hexagonal layers of carbon atoms held together by weak vander Walls forces III : Silicon exists only in diamond structure due to its tendency to form `p_(p)-p_(p)` bonds to itself. In this :A. Only I and II are correctB. Only I is correctC. Only II and III are correctD. All are correct statements |
| Answer» Correct Answer - D | |
| 2012. |
Newly shaped glass articles when cooled suddenly become brittle, these are cooled slowly, this process is known asA. temperingB. galvanisingC. quenchingD. annealing |
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Answer» Correct Answer - D The phenomenon of very slow regulated homogenous cooling of glass of relieve strain is called annealing. |
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| 2013. |
Water glass is:A. sodium silicateB. sodium, calcium silicateC. calcium silicateD. magnesium silicate |
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Answer» Correct Answer - A Water glass is sodium silicate. |
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| 2014. |
The name of the structure of silicates in which three oxygen atoms of `[SiO_(4)]^(4-)` are shared isA. PyrosilicateB. Sheet silicateC. Linear chain silicateD. Three dimensional sheet silicate |
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Answer» Correct Answer - B Two dimensional sheet structures are formed when three oxygen atoms of each `[SiO_(4)]^(4-)` tetrahedral are shered. |
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| 2015. |
The name of the structure of silicates in which three oxygen atoms of `[SiO_(4)]^(4-)` are shared isA. pyrosilicateB. sheet silicateC. linear chain silicateD. three dimensional silicate |
| Answer» (b) Sheet silicates are formed when three oxygen atoms ( bridging O- atoms) of each `(SiO_(4))^(4-)` units are shared | |
| 2016. |
The name of the structure of silicates in which three oxygen atoms of `[SiO_(4)]^(4-)` are shared isA. PyrosilicateB. Linear chain silicateC. Sheet silicateD. Three-dimensional sheet silicate |
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Answer» Correct Answer - C Two dimensional sheet structures are formed when three oxygen atoms of each `[SiO_(4)]^(4-)` tetrahedral are shered. |
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| 2017. |
The name of the structure of silicates in which three oxygen atoms of `[SiO_(4)]^(4-)` are shared isA. pyrosilicateB. sheet silicateC. linear cahin silicateD. three dimensional silicate. |
| Answer» The structure is known as sheet silicate. | |
| 2018. |
The name of the structure of silicates in which three oxygen atoms of `[SiO_(4)]^(4-)` are shared isA. pyrosilicateB. sheet silicateC. linear chain silicateD. three-dimensional silicate |
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Answer» Correct Answer - A |
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| 2019. |
The reaction of zinc with dilute and concentrated nitric acid, respectively producesA. `N_(2)OandNO_(2)`B. `NO_(2)andNO`C. `NOandN_(2)O`D. `NO_(2)andN_(2)O` |
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Answer» Correct Answer - A `4Zn+10HNO_(3)(dil.)to4Zn(NO_(3))_(2)+N_(2)O+5H_(2)O` `Zn+4HNO_(3)(conc.)toZn(NO_(3))_(2)+2H_(2)O` |
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| 2020. |
When copper is heated with conc. `HNO_(3)` it producesA. `Cu(NO_(3))_(2),NOandNO_(2)`B. `Cu(NO_(3))_(2)andN_(2)O`C. `Cu(NO_(3))_(2)andNO_(2)`D. `Cu(NO_(3))_(2)andNO` |
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Answer» Correct Answer - C `Cu+4HNO_(3)(conc.)toCu(NO_(3))_(2)+2NO_(2)+2H_(2)O` |
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| 2021. |
Illustrate how copper metal can give different products on reaction with `HNO_(3)`. |
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Answer» On heating with dil. `HNO_(3)`, copper gives copper nitrate and nitric oxide. `3Cu+8HNO_(3)(dil)overset("Heat")to3Cu(NO_(3))_(2)+4H_(2)O+underset("Nitric oxide")(2NO)` With conc. `HNO_(3)`, instead of `NO,NO_(2)` is evolved. `Cu+4HNO_(3)(conc)overset("Heat")toCu(NO_(3))_(2)+2H_(2)O+underset("Nitrogen dioxide")(2NO_(2))` |
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| 2022. |
The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)`A. can be prepared by reaction of `P_(4)andHNO_(3)`B. is diamaganeticC. contains N-N bondD. reacts with Na-metal producing brown gas |
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Answer» Correct Answer - B::D `4HNO_(3)+P_(4)O_(10)to4HPO_(3)+2N_(2)O_(5)` `N_(2)O_(5)` cannot be prepared by action of `HNO_(3)` on `P_(4)` but gives `H_(3)PO_(4)` `P_(4)+10HNO_(3)to4H_(3)PO_(4)+20NO_(2)+4H_(2)O` `N_(2)O_(5)` has 54 electrons `(2xx7+5xx8)` and hence is diamagnetic `N_(2)O_(5)` does not contain N-N bond. Refer to structure is Table 11.14, page 11//120. `N_(2)O_(5)` reacts with Na producing `NO_(2)` `Na+N_(2)O_(5)toNaNO_(3)+NO_(2)` (brown gas) Thus, option (b) and (d) are correct. |
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| 2023. |
Complete the following reaction? `HNO_(3)overset(P_(4)O_(10),Delta)to`? |
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Answer» `P_(4)O_(10)` being a strong dehydrating agent, eliminates a molecule of `H_(2)O` from two molecules of `HNO_(3)` giving dinitrogen pentoxide `((N_(2)O_(5))`. `4HNO_(3)+P_(4)O_(10)overset(Delta)to2N_(2)O_(5)+4HPO_(3)` |
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| 2024. |
Is `H_(3)BO_(3)` a tribasic acid? |
| Answer» Correct Answer - No, it is monobasic | |
| 2025. |
When dipped in conc. `HNO_3`, metals like iron, chromium, nickel, aluminium, base become passive. This is due toA. reduction of metalsB. formation of corresponding nitratesC. evolution of nitrogen dioxideD. formation of layer of metal oxide on the surface of metal |
| Answer» Correct Answer - D | |
| 2026. |
Why `N(CH_(3))_(3)` is more basic than `N(SiMe_(3))_(3)` ? |
| Answer» This is because the lone pair of electron of `N` (present in the2p orbital ) is transferred to the empty d-orbital of Si (`ppi-dpi` overlapping) and hence it is not available for protonation . As a result, `N(SiMe_(3))_(3)` is a weaker base than `N(CH_(3))_(3)` or `N(SiH_(3))_(3)` is a stronger base than `N(CH_(3))_(3)`. | |
| 2027. |
Dry powder fire extinguisher containsA. SandB. Sand and `Na_(2)CO_(3)`C. Sand and `NaHCO_(3)`D. Sand and `K_(2)CO_(3)`. |
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Answer» Correct Answer - C Mixture of sand and baking soda is used in dry powder fire extinguisher. |
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| 2028. |
`PbCl_(4)` exists but `PbBr_(4)` and `PbI_(4)` do not because ofA. inability of bromine and iodine to oxidise `Pb^(2+)` to `Pb^(4+)`B. `Br^(-)` and `I^(-)` ions are bigger in sizeC. More electronegative nature of bromina and iodineD. Chlorin e is a gas. |
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Answer» Correct Answer - A Inability of bromine and iodine to oxidise `Pb^(2+)` to `Pb^(4+)`. |
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| 2029. |
`PbCl_(4)` exists but `PbBr_(4)` and `PbI_(4)` do not because ofA. bromine and iodine are more electronegative these chlorine.B. iodine and bromine are smaller in size.C. larger iodine and bromine are able to reduce `Pb^(4+)` to `Pb^(2+)` or `Pb`.D. the statement is incorrect |
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Answer» Correct Answer - C `Pb^(4+)` has higher polarising power and `Br^(-)` and `I^(-)` being larger in size can easily give the electrons to `Pb^(4+)`, i.e. as compared to `Cl^(-),Br^(-)` and `I^(-)` are good reducing agents. |
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| 2030. |
Account for the following : (i) `PbX_(2)` is more stable than `PbX_(4) (X = Cl, Br)` (ii) `PbCl_(4)` is more stable than `SnCl_(4)` but `PbCl_(2)` is more stable than `SnCl_(2)`, (iii) `PbCl_(4)` is less stable than `SnCl_(4)` ? |
| Answer» (i) Due to inert pair effect, the +2 oxidation state of Pb is more stable than `+4`. Hence, `PbX_(2)` is more stable than `PbX_(4)`. (ii) Stability of `+4` oxidation state decreases down the group while that of `+2` oxidation state increases due to inert pair effect. (iii) Same as (ii). | |
| 2031. |
Assertion. `PbI_(4)` is a stable than `PbCl_(4)`. Reason. Iodide ion stabilizes higher oxidation state.A. If both assertion and reason are true, and reason is the true explanation of the assertion.B. If both assertion and reason are true, but reason not is the true explanation of the assertion.C. If assertion is true, but reason is false.D. If both assertion and reason are false. |
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Answer» Correct Answer - D Correct assertion. `PbI_(4)` is unstable. Correct reason. `I^(-)` being a reducing agent, reduces `Pb^(4+)` to `Pb^(2+)` or `Pb^(4+)` being an oxidising agent oxidises `I^(-)` to `I_(2)`. |
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| 2032. |
Nitric acid is a strong oxidizing agent and attacks most metals, non-metals and metalloids. Which of the following process is/are incorrect ?A. `Mn overset(2%HNO_(3))rarrH_(2)uarr`B. `Zn overset(70%HNO_(3)) rarrNO_(2)`C. `Sn overset(20% HNO_(3))rarrNOuarr`D. `Cu overset(6% HNO_(3))rarr NH_(4)NO_(3)` |
| Answer» Correct Answer - C::D | |
| 2033. |
Assertion: `PbCl_(2)` is more stable more stable than `PbCl_(4)` Reason: `PbCl_(4)` is strong oxidizing agent.A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - A Both assertion and reason are true and the reason is the correct explanation of the assertion. |
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| 2034. |
Which of the following attacks glass?A. `HCl`B. `HF`C. `HI`D. `HBr` |
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Answer» Correct Answer - B Glass being a mixture of sodium and calcium silicates reacts with hydrofluoric and forming sodium and calcium fluorosilicates respectively. `{:(Na_(2)SiO_(3)+3H_(2)F_(2)toNa_(2)SiF_(4)+3H_(2)O),(CaSiO_(3)+3H_(2)F_(2)toCaSiF_(4)+3H_(2)O):}` The etching of glass is based on these reactions. |
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| 2035. |
Assertion: Benzene is reactive while inorganic benzene is unreactiveA. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
| Answer» Correct Answer - D | |
| 2036. |
Which of the following has the minimum heat of dissociation?A. `[(CH_(3))_(3)NtoB(CH_(3))_(3)]`B. `[(CH_(3))_(3)NtoB(CH_(3))F_(2)]`C. `[(CH_(3))_(3)NtoB(CH_(3))_(2)F]`D. `[(CH_(3))_(3)NtoBF_(3)]` |
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Answer» Correct Answer - A The tendency of trimethyl boron to act as Lewis acid decreases due to `+IE` of `CH_(3)` group and thus, coordination becomes weaker. |
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| 2037. |
Assertion: `C_(3)O_(2)` has linear structure. Reason: Each carbon atom in `C_(3)O_(2)` in `sp` -hydridized.A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - A `C_(3)O_(2)` is `O=C=C=O` geometry. |
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| 2038. |
Which of the following has the minimum heat of dissociation?A. `[(CH_(3))_(3)NtoBF_(3)]`B. `[(CH_(3))_(3)NtoB(CH_(3))F_(2)]`C. `[(CH_(3))_(3)NtoB(CH_(3))_(2)F]`D. `[(CH_(3))_(3)NtoBF_(3)]` |
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Answer» Correct Answer - D The tendency of trimethyl boron to act as Lewis acid decreases due to `+IE` of `CH_(3)` group and thus, coordination becomes weaker. |
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| 2039. |
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increased atomic number. Explain. |
| Answer» This is explanied on the basis of inert pair effect which becomes more effective as we downwards in the elements of both 13 and 14 groups. | |
| 2040. |
Corundum isA. `Al_(2)(SO_(4)_(3)`B. `Al_(2)O_(3).H_(2)O`C. `al_(2)O_(3)2H_(2)O`D. `Al_(2)O_(3)` |
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Answer» Correct Answer - D Corundum is `Al_(2)O_(3)`. |
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| 2041. |
Which inert gas has abnormal behaviour on liquefaction ?A. XeB. HeC. ArD. Kr |
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Answer» Correct Answer - B |
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| 2042. |
`(CH_(3))_(3)SiCl` is used during polymerisation of organosilicones becauseA. the chaing length of organosilicon polymers can be controlled by adding `(CH_(3))_(3)SiCl`B. `(CH_(3))_(3)SiCl` improves the quality and yields of the polymerC. `(CH_(3))_(3)SiCl` does not block the end terminal of silicone polymerD. `(CH_(3))_(3)SiCl` acts as a catalyst during polymerisation |
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Answer» Correct Answer - A `(CH_(3))_(3)SiCl` is used to control the length of the polymer chain. |
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| 2043. |
`Me_(3)SiCl` is used during polymerisation of organosilicones becauseA. the chain lengths of organosilicone polymers can be controlled by adding `Me_(3)SiCl`B. `Me_(3)SiCl` blocks the end terminal of silicone polymerC. `Me_(3)SiCl` improves the quality and yield of the polymerD. `Me_(3)SiCl` acts as a catalyst during polymeriation |
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Answer» Correct Answer - A::B `Me_(3)SiCl` is used to control the length of silicone polymers by blocking the end terminal of the silicone polymer. Thus, options (a) and (b) are correct. |
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| 2044. |
On controlled hydrolysis and condensation, `R_(3)SiCl` yieldsA. `R_(3)Si-O-SiR_(3)`B. C. `R_(3)SiOH`D. |
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Answer» Correct Answer - A `R_(3)SiCl` on hydrolysis forms only a dimer. `R_(3)SiOH+HOSiR_(3)rarrR_(3)Si-O-SiR_(3)`. |
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| 2045. |
`"………….."` is produced by action of conc. `H_(2)SO_(4)` on potassium ferrocyanide. |
| Answer» Correct Answer - `CO` | |
| 2046. |
With respect to graphite and diamond, which of the statements given below are correct? (1) Graphite is harder than diamond. (2) Graphite has higher electrical conductivity than diamond. (3) Graphite has higher thermal conductivity than diamond.(4)Graphite has higher `C-C` bond order than diamond.A. Graphite is harder than diamondB. Graphite has higher electrical conductivity than diamond.C. Graphite has higher thermal conductivity than diamond.D. Graphite has higher `C-C` bond order than diamond |
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Answer» Correct Answer - B::D |
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| 2047. |
The `C-C` bond lengt in diamond is `"………….."`while in graphite it is `"………….."`. |
| Answer» Correct Answer - `154` pm and `141.5` pm | |