InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
Ankit was given an increment of 10% on his salary. His new salary is Rs3575. What was his salary before increment? |
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Answer» New salary of Ankit = Rs.3575 Percentage increase in salary = 10% Let original salary of Ankit is = Rs. X Hence, Salary of Ankit before increment \(={X}\times\frac{110}{100}\) = 3575 \(={X}=\frac{3575\times100}{110}\) = Rs. 3250 ∴ Original salary of Ankit = Rs. 3250 |
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| 202. |
In the new budget, the price of petrol rose by 10%. By how much percent must one reduce the consumption so that the expenditure does not increase? |
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Answer» Percentage increase in price of petrol = 10% Hence, Reduction in consumption while having same expenditure \(=\frac{\text%increase}{100+{\text%increase}}\times{100}\) \(=\frac{10}{100+10}\times{100}\) \(=\frac{1000}{110}={9}\frac{1}{11}\text%\) |
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| 203. |
Mohan’s income is Rs 15500 per month. He saves 11% of his income. If his income increases by 10%, then he reduces his saving by 1%, how much does he save now? |
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Answer» Mohan monthly income is = Rs 15500 Mohan savings is = 11% of 15500 = 15500 × 11/100 = Rs 1705 Monthly income increases by = 10% New monthly income is = 15500 + 10/100 × 15500 = 15500 + 1550 = Rs 17050 When savings reduced by 1% will result in = 11 – 1 = 10% of 17050 New savings = (10/100) × 17050 = Rs 1705 ∴ Savings is Rs 1705, which remains the same even after increment. |
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| 204. |
A metal bar weighs 8.5 kg. 85% of the bar is silver. How many kilograms of silver are in the bar? |
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Answer» Total weight of the metal = 8.5 kg Percentage of silver in the metal = 85% Weight of silver in the metal = 85% of total weight = \(\frac{85}{100}\) x 8.5 kg = 7.225 kg 7.225 kg of silver are in the bar. |
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| 205. |
x is 5% of y, y is 24% of z. If x = 480, find the values of y and z. |
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Answer» Given x = 480 Ans, x is 5% of y. So, we write it as: x = \({y}\times\frac{5}{100}\) \({480}=\)\({y}\times\frac{5}{100}\) solving for y, we get, \({y} =\frac{480\times100}{5}\) or y = 900 Now, It is also given that: y is 24% of z Therefore, we can write it as: \({y} ={z}\times\frac{24}{100}\) or 9600 = 24z/ 100 Solving it for z we get, z = 960000/24 z = 40000 |
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| 206. |
Stephen invested Rs 10,000 in a savings bank account that earned 2% simple interest. Find the interest earned if the amount was kept in the bank for 4 years. |
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Answer» Principal (P) = Rs 10,000 Rate of interest (r) = 2% Time (n) = 4 years ∴ Simple Interest I = \(\frac{pnr}{100}\) = \(\frac{10000\times4\times2}{100}\) = Rs 800 Stephen will earn Rs 800 |
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| 207. |
Thendral saved one fourth of her salary. Her savings percentage is (i) \(\frac{3}{4}\)(ii) \(\frac{1}{4}\) %(iii) 25 %(iv) 1 % |
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Answer» (iii) 25 % \(\frac{1}{4}\) x \(\frac{100}{100}\) = \(\frac{1}{4}\) x 100 % = 25 % |
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| 208. |
A picture of dart board is given. Find the percentage of white coloured portion and black coloured portion. |
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Answer» Total sector = 20 White coloured sector = 10 Black coloured sector = 10 Percentage of white : \(\frac{10}{20}\) x \(\frac{100}{100}\) = \(\frac{10}{20}\) x 100 % = 50 % Decimal : \(\frac{10}{20}\) x 100 % = 50 % Percentage of black colour : \(\frac{10}{20}\) x \(\frac{100}{100}\) = \(\frac{10}{20}\) x 100 % = 50 % Decimal : \(\frac{10}{20}\) x 100 % = 50 % |
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| 209. |
Kavin scored 15 out of 25 in a test. The percentage of his marks is (i) 60% (ii) 15% (iii) 25% (iv) \(\frac{15}{25}\) |
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Answer» (i) 60% \(\frac{15}{25}\) x \(\frac{100}{100}\) = \(\frac{15}{25}\) x 100 % = 60 % |
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| 210. |
Anbu scored 436 marks out of 500 in his exams. What was the percentage he scored? |
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Answer» Total marks = 500 Anbu’s Score = 436 Percentage = \(\frac{436}{500}\) x \(\frac{100}{100}\) = \(\frac{436}{500}\) x 100 % = 87.2 % Anbu’s Score = 87.2 % |
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| 211. |
In an election, Candidate X secured 48% of votes. What fraction will represent his votes? |
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Answer» Percentage of votes x secured = 48% = \(\frac{48}{100}\) Fraction of votes x secured = \(\frac{12}{25}\) |
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| 212. |
In a mixture of two liquids A and B, 35% is liquid B. If the total quantity of the mixture is 20 kg, find the quantity of A, by weight. |
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Answer» Total quantity of A and B = 20 kg Quantity of B = 35% of 20 = 35/100 x 20 = 7kg Quantity of A = Total quantity – Quantity of B = 20 kg – 7 kg = 13 kg Hence, quantity of A = 13 kg. |
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| 213. |
Mrs. Sharma went to the market with Rs 800 in her purse. When she returned to her home, Rs 240 were still left in her purse. What percent of her money did she spend in the market ? |
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Answer» Money in her purse = Rs 800 Balance in her purse = Rs 240 Money spent = Rs 800 – Rs 240 = Rs 560 Percentage of money spent = 560/800 x 100 = 70% |
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| 214. |
A fruit-seller had some apples. He sells 40% of them and still has 420 apples. Find the number of apples he had originally. |
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Answer» Assume that the fruit seller had 100 apples initially. He sell 40% of them = 40 apples Left out apples = (100 – 40) = 60 In initial amount of apples if 60 of them are remaining = 100 In initial amount of apples if 1 of them is remaining = (100/60) In initial amount of apples if 420 of them are remaining = (100/60) × (420) = (100 ×7) = 700 ∴the fruit seller originally had 700 apples. |
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| 215. |
Find the following:(i) 8 is 4% of which number?(ii) 6 is 60% of which number?(iii) 6 is 30% of which number?(iv) 12 is 25% of which number? |
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Answer» (i) Let x be the required number Given that 4% of x = 8 (4/100) × x = 8 x = (800/4) x = 200 (ii) Let the required number be x Given that 60% of x = 6 (60/100) × x = 6 x = (60/6) x = 10 (iii) Let the required number be x Given that 30% of x = 6 (30/100) × x = 6 x = (6 × 100)/30 x = 20 (iv) Let the required number be x Given that 25% of x = 12 (25/100) × x = 12 x = (12 × 100)/25 x = 48 |
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| 216. |
A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in(i) Sixes(ii) 4’s(iii) 2’s(iv) singles |
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Answer» Total runs scored by cricketer = 62 (i) Run scored in 3 sixes = 3×6 = 18 Percentage of runs scored in sixes \(=\frac{18}{62}\times100\)=29.03% (ii) Run scored in 8 fours = 8×4 = 32 Percentage of runs scored in fours (iii) Run scored in 2 two’s = 2×2 = 4 Percentage of runs scored in two’s \(=\frac{4}{62}\times100\)=6.45% (iv) Run scored in singles = 8 Percentage of runs scored in singles \(=\frac{4}{62}\times{100}\) =12.9% |
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