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501.

In the descending order of a group in the periodic table which of the following would be true 1) All the atoms have the same number of valence electrons 2) Gram atomic volume increases 3) Electronegativity decreases 4) Metallic character decrease and basic nature of their oxides decreases Select the correct answer using the codesA. 1, 2 and 4B. 1 , 3 and 4C. 1 ,2 and 3D. 2 , 3 and 4

Answer» Correct Answer - C
502.

Which of the following represents second ionization potential ?A. `Mg^(-) (g) rarr Mg(g) `B. `Mg^(2+)(g) rarr Mg^(3+) (g)`C. `Mg^(-) (g) rarr Mg^(+)(g)`D. `Mg^(+) (g) rarr Mg^(2+) (g)`

Answer» Correct Answer - D
503.

Which equation represents the first ionization of calcium?A. `Ca(s) rarr Ca^(+)(g)+e^(-)`B. `Ca(g) rarr Ca^(+)(g)+e^(-)`C. `Ca^(+)(g)+Ca^(2+)(g)+e^(-)`D. `Ca^(2+)(g)+e^(-) rarr Ca^(+)(g)`

Answer» Correct Answer - B
504.

Which list gives the symbols of the element in the order of increasing first ionization energy?A. `F,Ne,Na`B. `AI,Mg,Na`C. `Sr,Ca,Mg`D. `CI,Br,I`

Answer» Correct Answer - C
505.

The material used in solar cells containsA. AsB. GeC. PD. Si

Answer» Correct Answer - D
506.

Which pair of symbols identifies two elements that are metalloids?A. Si and GeB. Mg and SiC. P and AsD. Ti and V

Answer» Correct Answer - A
507.

Which one of the following is correct order of the size of iodine species ?A. `I gt I^(-) gt I^(+)`B. `I^(+) gt I^(-) gt I`C. `I gt I^(+) gt I^(-)`D. `I^(-) gt I gt I^(+)`

Answer» Correct Answer - D
508.

Which one is the correct order of the size of the iodine species ?A. `I gt I^(+) gt I^(-)`B. `I gt I^(-) gt I^(+)`C. `I^(+) gt I^(-) gt I`D. `I^(-) gt I gt I^(+)`

Answer» Correct Answer - D
509.

Which of the following pairs of ions have the same electronic configurationA. `Cr^(+3),Fe^(+3)`B. `Fe^(+3),Mn^(+2)`C. `Fe^(+3),Co^(+3)`D. `Sc^(+3),Cr^(+3)`

Answer» Correct Answer - B
510.

Which set represents isoelectronic species ?A. `Na^(+), Mg^(2+),Al^(3+), Cl^(-)`B. `Na^(+), Ca^(2+), Sc^(3+), F^(-)`C. `K^(+), Cl^(-), Mg^(2+), Sc^(3+)`D. `K^(+), Cl^(-), Ca^(2+), Sc^(3+)`

Answer» Correct Answer - D
511.

Separation of lanthanides from their mixture is not easy because ofA. Shielding effectB. Pentetrating effectC. Consequences of lanthanide contractionD. Inert pair effect

Answer» Correct Answer - C
512.

`O^(2-)` and `Si^(4+)` are isoelectronic ions. If the ionic radius of `O^(2-)` is `1A^(0)`, the ionic radius of `Si^(4+)` will beA. `1.4A^(0)`B. `0.41A^(0)`C. `2.8A^(0)`D. `1.5A^(0)`

Answer» Correct Answer - B
513.

Covalent radius of `Li`is ` 123 pm` .The crystal radius of Li will be:A. `gt 123` pmB. `lt 123` pmC. `+123` pm`D. `=(123)/(2)`pm

Answer» Correct Answer - B
514.

The number of species among the following , having insert gas configuration is ____ . `K^(+), Ca^(2+), S^(2-), Br^(-), Se^(2-), H^(+), H^(-), Mn^(2+)`

Answer» Correct Answer - 6
515.

The number of elements among the following atomic numbers that are p block elements is ______. 83,79,42,64,37,54,34

Answer» Correct Answer - 3
516.

Which bond in each pair is more polar (a) `P-CI` or `P - Br` (b) `S -CI` or `S-O` (c) `N-O` or `N-F`

Answer» Correct Answer - `[(a) P-CI (b) S-O, (C) N-F]`
[Bond polarity `prop (DeltaEN)`
517.

The `As-CI` bond distance in `AsCI_(3)` is `2.20 Å`. Estimate the SBCR (single bond covalent radius) of As. (Assume EN of both to be same and radius of `CI = 0.99 Å)`.A. `1.21 Å`B. `1.31 Å`C. `1.41Å`D. `1.51Å`

Answer» Correct Answer - A
518.

The As-CI bond distance in `AsCI_(3)` is `2.20 Å`. Estimate the SBCR (single bond covalent radius) of As. (Assume EN of both to be same and radius of `CI = 0.99 Å)`.

Answer» Correct Answer - `[1.21Å]`
`[d_(As-Cl) = r_(As) + r_(Cl)`
`2.20 = r_(As) + 0.99`
`r_(As) = 1.21 Å`]
519.

Which one of the following statements is/are incorrect :A. Atomic radius of Be is larger than that of Al.B. `Delta_(eg)H` of Se is -195 kJ/mol where as that of O is -141 KJ/mol.C. First ionization energy of N is greater than that of NeD. CO, NO and `N_(2)O` are neutral oxides.

Answer» Correct Answer - A::C
520.

Poor shielding of nuclear charge by `d` or `f`-orbital electrons is responsible for which of the following facts?A. Atomic radius of Nb (4d -series) is comparable to Ta (5d-series)B. The 1 st ionisation enregy of copper is less than that of zinc.C. The value of electron gain enthalpy is more negative for sulphur than for oxygen.D. The 1 st ionization energy for gold is greater than that of silver.

Answer» Correct Answer - A::D
521.

Arrange `S,O and Se` in acending order of electron affinity?A. `O lt S lt Se`B. `S lt O lt Se`C. `O lt S gt Se`D. `Se lt O gt S`

Answer» Correct Answer - C
Atomic size of Se is very large.
522.

Stabitlity order of +3 and +1 states of boron family element isA. `Ga^(3+) lt In^(3+) lt Tl^(3+)`B. `Ga^(+) gt In^(+) gt Tl^(+)`C. `Ga^(+) lt In^(+) lt Tl^(+)`D. `Ga^(3+) gt Ga^(+)`

Answer» Correct Answer - C::D
523.

The electronegativity of carbon from the following data is nearly `E_(H - H) = 104.2 "kcal" mol^(-1)`, `E_(C-C) = 83.1` kcal `mol^(-1)` , `E_(C-H) = 98.8` kcal `mol^(-1) , X_(H) = 2.1`A. `3.0`B. `2.1`C. `2.5`D. `3.1`

Answer» Correct Answer - C
524.

For the gaseous reaction `K+F rarrK^(o+)+F^(ɵ)` `Delta H = 19 kcal mol^(-1)` under the condition when cations and anions are prevented by electrostatic separation from combining with each other. The `IE_(1)` of `K` is `4.3 eV`. Calculate `Delta_("eg")H^(ɵ)` of `F`.

Answer» Correct Answer - `[3.467 eV]`
`[1eV = 23 Kcal//mol DeltaH = I_(E) +E_(A), E.A = 347eV]`
525.

The increasing order of electron affinity values of `O,S` and `Se` isA. `O gt S gt Se`B. `S gt Se gt O`C. `Se gt O gt S`D. `S gt O gt Se`

Answer» Correct Answer - 2
O has exceptionally smaller value of electron affinity `(-141kJ^(-1)mol)` due to smaller atomic size than sulphur ( weaker electron-electron repulsion in `3p-` subshell). It is less tha Se and Te also.
526.

Metal exhibiting higher oxidation state is in which block ?A. pB. sC. dD. f

Answer» Correct Answer - C
527.

In which group all the elements do not have same number of valence electrons?A. ZeroB. FirstC. SecondD. Seventh

Answer» Correct Answer - A
528.

The reference element in Paulings scale of Electronegativity isA. HB. OC. ND. `Cl`

Answer» Correct Answer - A
529.

The values that are useful in writing chemical formulae and in calculation of oxidation states areA. Ionisation potentialB. Electron affinityC. ElectronegativityD. Metallic character

Answer» Correct Answer - C
530.

Electronegativity is the property related toA. Isolated atom in gaseous stateB. Isolated atom is solid stateC. Inert gasD. Bonded atoms in a molecule

Answer» Correct Answer - D
531.

Electronegativity is the property related toA. Isolated atom in gaseous stateB. Isolated atom is solid stateC. Inert gas D. Bonded atoms in a molecule

Answer» Correct Answer - D
532.

Select the correct statement(s)A. The value of electron gain enthalpy of an element can be -ve or +ve .B. In the perodic table , metallic character of the elements increases down the group and decreases across the periodC. the `Cl^(-)` & `S^(2-)` are isoelectronic species but first one is not smaller in size than the secondD. Ionization enthalpy of an atom is equal to electron gain enthalpy of its cation .

Answer» Correct Answer - A::B::D
533.

The order of decreasing atomic radii for `Be, Na` & `Mg` isA. `Na gt Mg gt Be`B. `Mg gt Na gt Be`C. `Be gt Na gt Mg`D. `Be gt Mg gt Na`

Answer» Correct Answer - A
534.

Which of the following has the largest sizeA. `N^(-3)`B. `O^(-2)`C. `K^(+1)`D. `Ca^(+2)`

Answer» Correct Answer - A
535.

Of the folowing, the one with largest size isA. `Cl^(-)`B. `Ar`C. `K^(+)`D. `Ca^(2+)`

Answer» Correct Answer - A
536.

The radii of `F,F^(-),O` and `O^(-2)` are in the order ofA. `O^(2-) gt F^(-) gt O gt F`B. `O^(2-) gt F^(-) gt F gt O`C. `F^(-) gt O^(2-) gt F gt O`D. `O^(2-) gt O gt F^(-) gt F`

Answer» Correct Answer - A
537.

Identify the correct order in which the ionic radius of the following ions increases (I) `F^(-)` (II) `Na^(+)` (III) `N^(3-)`A. III, I, IIB. I, II, IIIC. II, III, ID. II, I, III

Answer» Correct Answer - D
538.

According to I.C slater effective nuclear charge, `Z^(**)`, due to screening, is not exactly equal to the actual nuclear charge Z of the nucleus of the atom. `Z^(**)` depends on the type of orbitals in which the electron is housed, and on the ability of other electrons in more penetrating orbitals to screen the electron in question from the nucleus. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is `s gt p gt f` . The effective nuclear charge `Z^(**)` due to screening is given by `Z^(**)=Z-sigma`, where Z is the atomic atomic number and `sigma` is the slater screening constant values `0 lt sigma lt Z` Screening effect of one electron in the outermost orbitals, is not considered in calculate of `sigma`. What is the value of `Z^(**)` for Rb(37) ?A. 1.7B. 1.3C. 2.2D. 34.8

Answer» Correct Answer - C
539.

According to I.C slater effective nuclear charge, `Z^(**)`, due to screening, is not exactly equal to the actual nuclear charge Z of the nucleus of the atom. `Z^(**)` depends on the type of orbitals in which the electron is housed, and on the ability of other electrons in more penetrating orbitals to screen the electron in question from the nucleus. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is `s gt p gt f` . The effective nuclear charge `Z^(**)` due to screening is given by `Z^(**)=Z-sigma`, where Z is the atomic atomic number and `sigma` is the slater screening constant values `0 lt sigma lt Z` Screening effect of one electron in the outermost orbitals, is not considered in calculate of `sigma`. In which of the following cases the concept of `Z^(**)` is applicable?A. Ionisation energy increases as `Z^(**)` increasesB. Electronegativity of the atom increases as `Z^(**)` increasesC. The ionisation energy of `Na, K^(-), Rb^(-)` , are comparable because of equal `Z^(**)`D. All of the above

Answer» Correct Answer - C
540.

According to I.C slater effective nuclear charge, `Z^(**)`, due to screening, is not exactly equal to the actual nuclear charge Z of the nucleus of the atom. `Z^(**)` depends on the type of orbitals in which the electron is housed, and on the ability of other electrons in more penetrating orbitals to screen the electron in question from the nucleus. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is `s gt p gt f` . The effective nuclear charge `Z^(**)` due to screening is given by `Z^(**)=Z-sigma`, where Z is the atomic atomic number and `sigma` is the slater screening constant values `0 lt sigma lt Z` Screening effect of one electron in the outermost orbitals, is not considered in calculate of `sigma`. What is the value of `Z^(**)` for Rb(37) ?A. 1.7B. 1.3C. 2.2D. 34.8

Answer» Correct Answer - C
541.

According to I.C slater effective nuclear charge, `Z^(**)`, due to screening, is not exactly equal to the actual nuclear charge Z of the nucleus of the atom. `Z^(**)` depends on the type of orbitals in which the electron is housed, and on the ability of other electrons in more penetrating orbitals to screen the electron in question from the nucleus. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is `s gt p gt f` . The effective nuclear charge `Z^(**)` due to screening is given by `Z^(**)=Z-sigma`, where Z is the atomic atomic number and `sigma` is the slater screening constant values `0 lt sigma lt Z` Screening effect of one electron in the outermost orbitals, is not considered in calculate of `sigma`. what is `Z^(**)` for Cu(29) ?A. 29B. 24.8C. 2.2D. 4.2

Answer» Correct Answer - C
542.

According to I.C slater effective nuclear charge, `Z^(**)`, due to screening, is not exactly equal to the actual nuclear charge Z of the nucleus of the atom. `Z^(**)` depends on the type of orbitals in which the electron is housed, and on the ability of other electrons in more penetrating orbitals to screen the electron in question from the nucleus. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is `s gt p gt f` . The effective nuclear charge `Z^(**)` due to screening is given by `Z^(**)=Z-sigma`, where Z is the atomic atomic number and `sigma` is the slater screening constant values `0 lt sigma lt Z` Screening effect of one electron in the outermost orbitals, is not considered in calculate of `sigma`. In which of the following cases the concept of `Z^(**)` is applicable?A. Ionisation energy increases as `Z^(**)` increasesB. Electronegativity of the atom increases as `Z^(**)` increasesC. The ionisation energy of `Na, K^(-), Rb^(-)` , are comparable because of equal `Z^(**)`D. All of the above

Answer» Correct Answer - C
543.

Be and Mg have zero values of electron affinity becauseA. Their 2s and 3s-orbitals are fully occupiedB. Their first ionisation - energies are very smallC. Their electronegativity are very highD. Their electro- affinity are very high in `Mg^(2+)` and `Be^(2+)`

Answer» Correct Answer - A
544.

The long form of periodic table is nothing but just a graphical representation of ______principle.A. AufbauB. PhosphorousC. CobaltD. Aluminium

Answer» Correct Answer - A
545.

The element present in the IIIA group and 3 period in the periodic table isA. CarbonB. PhosphorousC. CobaltD. Aluminium

Answer» Correct Answer - D
546.

Why are the electron affinities of alkaline earth metals positive? `M_((g))+e^(-) to M^(-)`_((g)) DeltaH =+ ("Electron affinity")

Answer» All the electrons present in alkaline earth metals
are paired. Therefore to add one extre electron to
these atoms, work has to be done against the force
of repulsion. Hence, electron affinity of an alkaline
earth metal is a positive.
547.

Most of the d block elements are known as:A. alkali metalsB. alkaline earth metalsC. innertransition elementsD. transition elements

Answer» Correct Answer - D
548.

Which of the following represents the electronic configuration of a transition element?A. `1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),4s^(2)`B. `1s^(2),2s^(2),2p^(6),3s^(2),3p^(6) 3d^(2),4s^(2)`C. `1s^(2),2s^(2)2p^(6),3s^(2)3p^(6)3d^(10),4s^(2)4p^(2)`D. `1s^(2),2s^(2)2p^(6),3s^(2)3p^(6)3d^(10),4s^(2)4p^(1)`

Answer» Correct Answer - B
549.

Which of the following represents the electronic configuration of d-block elementsA. `(n-1) s^(2)nd^(1-10)`B. `(n-1)d^(1-10) ns^(1-2)`C. `(n-1)s^(2) p^(6), ns^(1)`D. `ns^(2) p^(2) d^(1)`

Answer» Correct Answer - B
550.

The general configuration `(n-1)d^(3)ns^(2)` indicates that particular element belongs to the following groupA. VBB. IVBC. VIBD. IIIB

Answer» Correct Answer - A