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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
How many 3-letter words can be formed using a, b, c, d, e if (i) repetition of letters is not allowed? (ii) repetition of letters is allowed? |
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Answer» Correct Answer - (i) 60 (ii) 125 (i) Total number of 3-letter words is equal to the number of ways of filling 3 places. First place can be filled in 5 ways by any of the given five letters. Second place can be filled in 4 ways by any of the remaining 4 letters and the third place can be filled in 3 ways by any of the remaining 3 letters. So, the required number of 3-letter words `=(5xx4xx3)=60.` (ii) When repetition of letters is allowed, each place can be filled by any of the 5 letters in 5 ways. `therefore " the required number of ways "=(5xx5xx5)=125.` |
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| 2. |
How many 4-letter word, with or without meaning, can be formed out of theletters of the word, ‘LOGARITHMS’, if repetition of letters is not allowed? |
| Answer» Total possible ways=`10*9*8*7=5040` | |