Explore topic-wise InterviewSolutions in Class 12.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 12 knowledge and support exam preparation. Choose a topic below to get started.

45401.

A concave lens always produces _____ images.

Answer» <html><body><p>real<br/>virtual<br/>magnified<br/>none of these</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
45402.

A ray of light passes from a medium A having refractive index 1.6 to the medium B having refractive index 1.5. The value of critical angle of medium A is ....

Answer» <html><body><p>`sin^(-1)((16)/(15))`<br/>`sin^(-1)(1/2)`<br/>`sin^(-1)<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((16)/(15))`<br/>`sin^(-1)((15)/(16))`</p>Solution :Refractive <a href="https://interviewquestions.tuteehub.com/tag/index-505893" style="font-weight:bold;" target="_blank" title="Click to know more about INDEX">INDEX</a> of medium A with <a href="https://interviewquestions.tuteehub.com/tag/respect-1186739" style="font-weight:bold;" target="_blank" title="Click to know more about RESPECT">RESPECT</a> to medium B<br/> `n_(AB)=(n_A)/(n_B)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sinc-1209122" style="font-weight:bold;" target="_blank" title="Click to know more about SINC">SINC</a>=(1)/(n_(AB))=(n_B)/(n_A)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> C=sin^(-1)((n_B)/(n_A))`<br/>`=sin^(-1)((1.5)/(1.6))=sin^(-1)((15)/(16))`</body></html>
Discussion
45403.

Draw a diagram of an illuminated p-n junction solar cell.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The diagram of an illuminated p-n <a href="https://interviewquestions.tuteehub.com/tag/junction-526696" style="font-weight:bold;" target="_blank" title="Click to know more about JUNCTION">JUNCTION</a> <a href="https://interviewquestions.tuteehub.com/tag/solar-647285" style="font-weight:bold;" target="_blank" title="Click to know more about SOLAR">SOLAR</a> cell is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> in.</body></html>
Discussion
45404.

Nuclear binding energy is equivalent to

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of proton<br/>Mass of neutron<br/>Mass of <a href="https://interviewquestions.tuteehub.com/tag/nucleus-18220" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEUS">NUCLEUS</a> <br/>Mass <a href="https://interviewquestions.tuteehub.com/tag/defect-946755" style="font-weight:bold;" target="_blank" title="Click to know more about DEFECT">DEFECT</a> of nucleus </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
45405.

Assertion:Isotopes of an element can be separated by using a mass spectrometer. Reason: Separation of isotopes is possible because of difference in electronnumber of isotopes .

Answer» <html><body><p>If both assertion and reason are true and reason is the correct explanation of assertion .<br/>If both assertion and reason are true but reason is notthe correct explanation of assertion . <br/>If assertion is true but reason is false . <br/>If both assertion and reason are false </p>Solution :Number of electrons in isotopes of an element is same. If two atoms have the same number of protons but different number of neutrons , their atomic (proton) numbers are equal but not their mass (nucleon) numbers. In mass spectrograph, the deflecting electric and magnetic fields were <a href="https://interviewquestions.tuteehub.com/tag/arranged-2443099" style="font-weight:bold;" target="_blank" title="Click to know more about ARRANGED">ARRANGED</a> so that all particles of the same mass , irrespective of their speed , were brought to a line <a href="https://interviewquestions.tuteehub.com/tag/focus-25840" style="font-weight:bold;" target="_blank" title="Click to know more about FOCUS">FOCUS</a>. When <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> of different mass were present , a series of lines, i.e., a mass spectrum , obtained on a photographic film. The relative intensities of the lines enabled an estimate to be made of the relative amounts of isotopes.</body></html>
Discussion
45406.

Explain the determination of the internal resistance of a cell using voltmeter.

Answer» <html><body><p></p>Solution :Determination of internal <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a>: The emf of cell `xi` is measured by connecting a high resistance voltmeter across it without connecting the external resistance R. Since the voltmeter draws verylittle current for <a href="https://interviewquestions.tuteehub.com/tag/deflection-17189" style="font-weight:bold;" target="_blank" title="Click to know more about DEFLECTION">DEFLECTION</a>, the circuit may be considered as open. Hence, the voltmeter <a href="https://interviewquestions.tuteehub.com/tag/reading-19542" style="font-weight:bold;" target="_blank" title="Click to know more about READING">READING</a> gives the emf of the cell. Then external resistance R is included in the circuit and current I is extablished in the circuit. The potential differenceacross R is equal to the potential difference across the cell (V). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XII_V01_C02_E01_040_S01.png" width="80%"/> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XII_V01_C02_E01_040_S02.png" width="80%"/> <br/> The potential drop across the resistor R is <br/> `V=IR "" ...(1)` <br/> Due to internal resistance r of the cell, the voltmeter reads a value V, which is less than the emf of cell `xi`. It is because, <a href="https://interviewquestions.tuteehub.com/tag/certain-407894" style="font-weight:bold;" target="_blank" title="Click to know more about CERTAIN">CERTAIN</a> amount of voltage (Ir) has dropped across the internal resistance r. <br/> Then`V=xi-Ir` <br/> `Ir=xi-V "" ...(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/dividing-957391" style="font-weight:bold;" target="_blank" title="Click to know more about DIVIDING">DIVIDING</a> equation (2) by equation (1), we get <br/> `(Ir)/(IR)=(xi-V)/(V)` <br/> `r=|(xi-V)/(V)|R"" ...(3)` <br/> Since `xi, V and R` are known, internal resistance r can be determined.</body></html>
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