InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
I have my physics exam tomorrow please tell me important topic for ray optics i have not done that |
| Answer» •Lens Maker formula•Total intarnal reflection•Compound macroscope and astronomical macroscope•Numericals on lens combination•Prism and dispersion This will be enough... | |
| 852. |
Why it is easier to pull a body then push |
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| 853. |
Important topics of all chapters |
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| 854. |
Guys how many of you are expecting more than 60 marks out of 70 in your Physics exam today |
| Answer» Come on Neha what\'s that it was not your life exam | |
| 855. |
Newton\'s law of cooling |
| Answer» Rate of heat lose by a high temperature body is directly proportional to the heat transferred b/w body and surrounding.<br>The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. | |
| 856. |
Bernaulli theorem |
| Answer» This theorem states that the sum of pressure energy per unit mass , kinetic energy per unit mass , potential energy per unit mass is always remains constant<br>It states that the sum of pressures(P),the kinetic energy(K.E) per unit volume,potential energy(P.E) per unit volume of fluid non-viscous,incompressible and flowing through streamline remains constant. | |
| 857. |
Solar method,radar method, eco method, parallax method |
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| 858. |
Prove it that 1/u + 1/v = 1/f for concave mirror |
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| 859. |
2016-2017 final solved question pape |
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| 860. |
What is geometrical interpretation of SHM |
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| 861. |
Kisi ka physics final exam hogaya ho toh batao ki paper tough aaya tha ya easy? |
| Answer» Thermal properties k kuch important topics h jinpr dhyaan dena i.e Newton\'s law of cooling. Thermal resistance in series. Relation in types of expansion. lekin ek baar sb padh lena. Marks k baare m mughe correctly kuch nhi pata.<br>aur thermal properties of matter se maximum kitte marks ka tha ?mera exam 22 feb ko hai.. iam so tensed about it ?<br>long ques kon se chapters se the ??<br>Aj hua mera exam. It was good maximum derivations aaye the conceptual questions bhi the. Sb padh kr gyi thi to sb easy hi lga aur sb kr ke aayi hu. Ab bss wish k achee marks bhi aa jae | |
| 862. |
Define accceleration due to gravity |
| Answer» Any object placed in the field of the gravitational pull of the Earth experiences the gravitational force. Acceleration due to gravity is defined as the acceleration gained by an object because of the force of gravity acting on it. It is represented by ‘g’ and is measured in terms of m/s2. Acceleration due to gravity is a vector quantity, that is, it possesses both magnitude as well as direction.<br>The force of gravity acting on unit mass of a body placed on or near the surface of the earth | |
| 863. |
Whats up guys ready for the exam today of Physics |
| Answer» All done now.<br>In which school you study<br>Yes | |
| 864. |
Application of simple harmonic motion |
| Answer» Harmonic ossilatore | |
| 865. |
Application of SHM |
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| 866. |
Work energy theorem derived |
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| 867. |
Dimensions formula of cofecitint of viscosity |
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| 868. |
What is elasticc collison |
| Answer» A type of collision based on energy conservation in which coefficient of restitution =1 i-e; initial velocity = final velocity and( k.e)initial = (k.e) final | |
| 869. |
Pressure exerted by gas molecules. |
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| 870. |
What is 2nd law of thermodynamics |
| Answer» Kelvin planks statement : There is no engine which can work in such a way that the whole given energy is converted into work done without any loss of energy . Thus , according to this statement there is no engine with efficiency 100% . THANKS !!<br>Clausis statement= it is imposible to construct a device that transfers heat from colder body to a hotter body without an external work on the device | |
| 871. |
What is rolling without skidding? |
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| 872. |
What is the length of second pendulum |
| Answer» Approx. 1m<br>O.994 m<br>99.3 | |
| 873. |
Derive the derivation for Doppler effect |
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| 874. |
Derivation of thin lens equation |
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| 875. |
What is electric flux |
| Answer» Is it in our syllabus??<br>a force present in magentic area when any of a metal object is moved in it the there is a change in flux so this flux generates a electric charge which gives rise to electrical energy | |
| 876. |
Economical importance of algae |
| Answer» algae are used for commercial purposes like for making agar, gelidium helps in the preparation of ice-cream and jelly | |
| 877. |
Any body can make time tablefor study of class 12 to get good marks . |
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| 878. |
When are velocity and acceleration is same direction in SHM |
| Answer» | |
| 879. |
When are displacement and velocity in the same direction in SHM |
| Answer» Between mean and extreme positions | |
| 880. |
Bernouilli theorm |
| Answer» Pressure+kinetic energy+potential energy=constant | |
| 881. |
Friends what are most probable questions of dimensional analysis asked in CBSE exams. |
| Answer» Error analysis | |
| 882. |
Describe a method for measuring the molecular size of oleic acid |
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| 883. |
1°54\'=? |
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| 884. |
Find an expeession for the weight of a body at the centre of the body |
| Answer» W=mg in the centre g is 0 so,W=m×0=0 | |
| 885. |
Dued how many of you are having physics exam tomorrow.?? |
| Answer» Mine is tomorrow....only few hours are left?<br>Mine is on 12 march<br>Mine is on 21st<br>my exam on 22 feb | |
| 886. |
Which ques are imp for 5 marks |
| Answer» Doppler effect ,projectile, refrigerator,heat engine | |
| 887. |
What is dopplers effect |
| Answer» \tDoppler Effect is the phenomenon of motion-related frequency change.\tConsider if a truck is coming from very far off location as it approaches near our house, the sound increases and when it passes our house the sound will be maximum. And when it goes away from our house sound decreases.\tThis effect is known as Doppler Effect.\tA person who is observing is known as Observer and object from where the sound wave is getting generated it is known as Source.\tWhen the observer and source come nearer to each other as a result waves get compressed. Therefore wavelength decreases and frequency increases. | |
| 888. |
Tell me imp que of physicd |
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| 889. |
A soap bubble of radius R and filled thickness is t (t |
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| 890. |
When temperature equal in kelvin and celcius |
| Answer» kriti sharma from which stream you are maths or bio<br>0degree<br>-40 | |
| 891. |
How to solve numericals on resolution of vectors |
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| 892. |
Tips to gets marks in pointwise? |
| Answer» Dued it is the best way of giving marks by teachers .you need to write the question stepwise step what follows after what ok even if you forget the last step you will be awarded marks of all the steps you did .it increases the possiblitiy of getting good marks . | |
| 893. |
Hey share the important questions of physics that your teachers had shared with you. |
| Answer» Tomorrow is my last exam................computer science.....???<br>I know bahut time lagta hai yaar i am greatly thankfull to you.<br>Thanks sanidhya so much. What is your next exam now<br>4)Describe Carnot\'s reversible heat engine and obtain an expression for its efficiency............5) state and prove bournolli\'s theorem and mentio its application .............6) if the earth stops rotating about it\'s axis ,what will be the effect on the value of g? will this effect be same at all places?...........<br>Hey Kriti these are some theoretical questions and numericals which came in my exam............1) the velocity of an aeroplane is doubled (i) what will happen to the momentum? Will the momentum remain conserved?(ii)what will happen to the kinetic energy?will the energy remain conserved?................2) Establish the displacement equation of a plane progressive wave...............3) Two sprongs of force constant k1 and k2 are joined ene to end and suspended from a support.A body of mass m is attached to the lower end .Find out the period of oscillation of the body......................... yaar bahut der lagti he type karne main isliye or nhi daal paunga questions wi isse bhi bade he .......hope this may help u.............? | |
| 894. |
How much external force is required to move a body with uniform velocity along a straight line |
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| 895. |
What is wark energy theorem |
| Answer» The workdone by force is equal to change in its kinetic energy. w=1/2mv^2-1/2mu^2 | |
| 896. |
What is torcelli theorem |
| Answer» The velocity with which the liquid flows out from a narrow hole , is equal to that which a freely falling body would acquire in the falling through a vertical distance equal to the depth of orifice below the free surface of liquid | |
| 897. |
What is thurmodymaic |
| Answer» Koi mahan vyakti lag rhe ho ap<br>Branch of science which deals with study of flow of heat<br>Pahle thermodynamic ka spelling sikh lo Then ask | |
| 898. |
bernoalli\'s thoram |
| Answer» Let us consider two different regions in the above diagram. Let us name the first region as BC and the second region as DE. Now consider the fluid was previously present in between B and D. However, this fluid will move in a minute (infinitesimal) interval of time (∆t).If the speed of fluid at point B is v1 and at point D is v2. Therefore, if the fluid initially at B moves to C then the distance is v1∆t. However, v1∆t is very small and we can consider it constant across the cross-section in the region BC.Similarly, during the same interval of time ∆t the fluid which was previously present in the point D is now at E. Thus, the distance covered is v2∆t. Pressures, P1 and P2, will act in the two regions, A1 and A2, thereby binding the two parts. The entire diagram will look something like the figure given below.Bernoulli\'s equationFinding the Work DoneFirst, we will calculate the work done (W1) on the fluid in the region BC. Work done isW1 = P1A1 (v1∆t) = P1∆VMoreover, if we consider the equation of continuity, the same volume of fluid will pass through BC and DE. Therefore, work done by the fluid on the right-hand side of the pipe or DE region isW2 = P2A2 (v2∆t) = P2∆VThus, we can consider the work done on the fluid as – P2∆V. Therefore, the total work done on the fluid isW1 – W2 = (P1 − P2) ∆VThe total work done helps to convert the gravitational potential energy and kinetic energy of the fluid. Now, consider the fluid density as ρ and the mass passing through the pipe as ∆m in the ∆t interval of time.Hence, ∆m = ρA1 v1∆t = ρ∆VChange in Gravitational Potential and Kinetic EnergyNow, we have to calculate the change in gravitational potential energy ∆U.Bernoulli\'s equation.Similarly, the change in ∆K or kinetic energy can be written asBernoulli\'s equation.Calculation of Bernoulli’s EquationApplying work-energy theorem in the volume of the fluid andDividing each term by ∆V andRearranging the equation will yieldBernoulli\'s equation.The above equation is the Bernoulli’s equation. However, the 1 and 2 of both the sides of the equation denotes two different points along the pipe. Thus, the general equation can be written asBernoulli\'s equation.Thus, we can state that Bernoulli’s equation state that the Pressure (P), potential energy (ρgh) per unit volume and the kinetic energy (ρv2/2) per unit volume will remain constant. | |
| 899. |
Prove F=ma |
| Answer» According to the Newton’s 2nd Law of motion, the rate of change of linear momentum of a body is directly proportional to the applied external force and in the direction of force.It means that the linear momentum will change faster when a bigger force is applied.Consider a body of mass ‘m’ moving with velocity v.The linear momentum of a body is given by:P= mvNow According to Newton’s 2nd Law of Motion:Force is directly proportional to rate of change of momnetum, that isF α dp/dtF = k dp/dtF = k d(mv)/dtF = k md(v)/dtF = k maExperimentally k =1F = k maWhich is the required equation of force. | |
| 900. |
Derive lens maker formula |
| Answer» | |