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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11451. |
Integrate the following with respect to x. Cos(2x+3) |
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| 11452. |
What is the differentiation of 3x? |
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Answer» Let y=3x dy/dx=3×1x^1-1=3×1=3 therefore answer is 3 3 Hi ridhima Let y = 3x dy/ dx = d(3x)/dx = 3×1x^ 1-1 = 3× 1= 3 Answer is 3 3 |
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| 11453. |
29ApersontravelsfirsthalfwithvelocityV1andsecondhalfwithvelocityV2.findtheaveragevelocityofperson. |
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Answer» Plz type question in easy way 2/v = 1/v1 +1/v2 |
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| 11454. |
Energy of projectile |
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| 11455. |
What is principal of superposition?? |
| Answer» Considering two waves, travelling simultaneously along the same stretched string in opposite directions as shown in the figure above. We can see images of\xa0waveforms\xa0in the string at each instant of time. It is observed that the net\xa0displacement\xa0of any element of the string at a given time is the algebraic sum of the displacements due to each wave.Let us say two waves are travelling alone and the displacements of any element of these two waves can\xa0be represented by y1(x, t) and y2(x, t). When these two waves overlap, the resultant displacement can be given as y(x,t).Mathematically, y (x, t) = y1(x, t) + y2(x, t)As per the principle of superposition, we can add the overlapped waves algebraically to produce a\xa0resultant wave. Let us say the wave functions of the moving waves arey1\xa0= f1(x–vt),y2\xa0= f2(x–vt)\xa0yn\xa0= fn\xa0(x–vt)then the wave function describing the disturbance in the medium can be described asy = f1(x – vt)+ f2(x – vt)+ …+ fn(x – vt)or,\xa0y=∑ i=1 to n\xa0=\xa0fi\xa0(x−vt) | |
| 11456. |
State Bernoulli\'s theorem |
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Answer» Statement: For the streamline flow of non-viscous and incompressible liquid, the sum of potential energy, kinetic energy and pressure energy is constant.Proof: Let us consider the ideal liquid of density ρ flowing through the pipe LM of varying cross-section. Let P1\xa0and P2\xa0be the pressures at ends L and M and A1\xa0and A2\xa0be the areas of cross-sections at ends L and M respectively. Let the liquid enter with velocity V1\xa0and leave with velocity v2. Let A1\xa0> A2. By equation of continuity, Bernoulli’s principle states that The total mechanical energy of the moving fluid comprising the gravitational potential energy of elevation, the energy associated with the fluid pressure and the kinetic energy of the fluid motion, remains constant.Bernoulli’s equation formula is a relation between pressure,\xa0kinetic energy, and gravitational potential energy of a fluid in a container.The formula for Bernoulli’s principle is given as:\tp +\xa012\xa0ρ v2\xa0+\xa0ρgh =constant\tWhere,\tp is the pressure exerted by the fluid\tv is the velocity of the fluid\tρ is the density of the fluid\th is the height of the container |
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| 11457. |
Project file on collision |
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| 11458. |
A man travelled 200m in 4 second 220m in 2 second then find velocity at 7th second |
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Answer» List the main difference between mitosis and meiosis 1Q, summary of sweetest love I,Do Note Goe Let \'u\' be the initial velocity and \'a\' the acceleration.So we have the distance formulas = ut + 1/2 at^2In first 2 seconds,s = 200Put the values in the formula.200 = u x 2 + 1/2 x a x (2)^2200 = 2u + 1/2 x 4 x a200 = 2u + 2a100 = u + a -----(I)In next 4 secondsLet the distance traveled be \'y\'Time = 2+4 = 6 secSo according to the formula ,y = u x 6 + 1/2a x (6)^2y = 6u + 1/2 x 36 x ay = 6u + 18a ------(ii)Now we know that 220 cm was traveled in between 2 sec - 6 secy - 200 = 220y = 420We know y = 6u + 18a (from [ii])So, 6u + 18a = 420u + 3a = 70 ------(iii)Equating (I) and (iii)-2a = 30a = -15 cm/s^2u = 100 - (-15)u = 100 + 15 = 115 cm/secNow we know v = u + atWe have to find the "v" after 7th secondSo v = 115 + (-15) x 7v = 115 - 105v = 10 cm/sec |
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| 11459. |
Derive an expression for the maximum velocity of a car during circular motion on a level road. |
| Answer» N = mg\xa0Static friction provides the centripetal acceleration\xa0fs =< μsN\xa0mv2/r =< μsN\xa0v2 =< μsNR/m = μsmgR/m = μsRg\xa0v =< √ μsRg\xa0This is the maximum speed of a car in circular motion on a level road | |
| 11460. |
Moment of inertia of sphere.. ✍✍✍✍✍✍✍✍✍ |
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Answer» Hollow sphere is 2/3MR^2 And Solid sphere is 2/5MR^2 The moment of inertia of a sphere expression is obtained in two ways.\tFirst, we take the solid sphere and slice it up into infinitesimally thin\xa0solid cylinders.\tThen we have to sum the moments of exceedingly small thin disks in a given axis from left to right.We will look and understand the derivation below.First, we take the moment of inertia of a disc that is thin. It is given as;I = ½ MR2In this case, we write it as;dI (infinitesimally moment of inertia element) = ½ r2dmFind the dm and dv using;dm = p dVp = moment of a thin disk of mass dmdv = expressing mass dm in terms of density and volumedV = π r2\xa0dxNow we replace dV into dm. We get;dm = p π r2\xa0dxAnd finally, we replace dm with dI.dI = ½ p π r4\xa0dxThe next step involves adding x to the equation. If we look at the diagram we see that r, R and x forms a triangle. Now we will use Pythagoras theorem which gives us;r2\xa0= R2\xa0– x2Now if we substitute the values we get;dI = ½ p π (R2\xa0– x2)2\xa0dxThis leads to:I = ½ p π\xa0-R∫R\xa0(R2\xa0– x2)2\xa0dxAfter integration and expanding we get;I = ½ pπ 8/15 R5Additionally, we have to find the density as well. For that we use;p = m / Vp = m / m/v πR3If we substitute all the values;I = 8/15 [m / m/v πR3\xa0] R5I = ⅖ MR2 |
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| 11461. |
Event of horizon |
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| 11462. |
Fine the centre of mass of a triangular lamyna |
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Answer» The centre mass of the triangle always lies on the centroid of that triangle It Lies on the centroid of triangle |
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| 11463. |
Gravitational constant dimension |
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Answer» M-1L3T-2 The dimensional formula of gravitational constant is given by,M-1\xa0L3\xa0T-2Where,\tM = Mass\tL = Length\tT = Time |
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| 11464. |
Short way to understand product of scalar vectors |
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Answer» ?? Thanks Scalar products can be found by taking the component of one vector in the direction of the other vector and multiplying it with the magnitude of the other vector”. It can be defined as: Scalar product or dot product is an algebraic operation that takes two equal-length sequences of numbers and returns a single number. |
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| 11465. |
What is the difference between rotatory and circular motion |
| Answer» In rotation the body\'s centre of mass does not undergo any translation motion. In other words the centre of mass will remain at on place. Like a top spinning on its axis.In circular motion the body\'s centre of mass goes around a fixed centre maintaining a constant distance from it. Which means the centre of mass is actually going through a translation motion. For example an ant sitting on the circumference of the spinning top in the above example. | |
| 11466. |
Happy\' Diwali to all my dear friends??? |
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Answer» You to Happy deepawali |
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| 11467. |
What is kinematics. ...? |
| Answer» The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as\xa0kinematics.Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.These equations link five kinematic variables:\tDisplacement (denoted by Δx)\tInitial velocity (v0)\tFinal velocity (denoted by\xa0v)\tTime interval (denoted by\xa0t)\tConstant acceleration (denoted by\xa0a) | |
| 11468. |
what is the difference between mN, nm and Nm |
| Answer» mN means milli newton, 1 mN = {tex}{{10}^{-3}}{/tex} N.Nm means Newton-metre.nm means nanometer, 1 nm = {tex}{{10}^{-9}}{/tex} m. | |
| 11469. |
Define center of mass of a system |
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Answer» It is centre of body where mass of whole body concerntrated The centre of mass of a body or a system of particles is defined as “A single point at which the whole mass of the body or system is imagined to be concentrated and all the applied forces acts at that point.” |
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| 11470. |
How to understand physics well |
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Answer» Physics wallah alakh pandey by reading and practicing and with the help of teachers physics wallah in YouTube Increase your calculation and learning power and learn all formulas related to chapters and try at least 1. Question each it help to under stand physics |
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| 11471. |
The relation between pressure and mean kinetic energy of a gas |
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| 11472. |
Application of principle of conservation of linear momentum? |
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Answer» Ok ? I dont know lekin mai jesa hu mujhe bhi nhi pata and actually I never think for myself. Aur baate to hai pehle bhi thi aaj bhi hai personal hai |
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| 11473. |
Principal of conservation of linear momentum? |
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Answer» Sometimes it feels like bs !!! Ok ? Linear momentum is conserved .. isse zada nhi aata |
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| 11474. |
Equation of motion by calculas and graphical method |
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| 11475. |
State the number of significant figures 0.000040027 |
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Answer» 5 5 The number of significant figures in 0.000040027 m2\xa0is 5.If the number is less than one, then the zeroes on the right of the decimal point (but left to the first non-zero) are insignificant. Hence, all four zeroes appearing before 4 are not significant figure. All zero between two non-zero digit are always significant. Hence, the remaining five digits are significant figures. |
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| 11476. |
State the theorem of perpendicular axis. |
| Answer» The perpendicular axis theorem states that the moment of inertia of a planar lamina about an axis perpendicular to the plane of the lamina is equal to the sum of the moments of inertia of the lamina about the two axes at right angles to each other, in its own plane intersecting each other at the point where the perpendicular axis passes through it. | |
| 11477. |
Why the value of g is maximum at poles? |
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Answer» Min distance max force The\xa0value of \'g\' that is\xa0gravity\xa0is greater at the\xa0poles\xa0because the gravitational pull is\xa0maximum\xa0at the\xa0poles\xa0and decreases as it comes down toward the\xa0equator.\xa0Because the force due to gravitational attraction between two bodies (the Earth and the object being weighed) varies inversely with the square of the distance between them, an object at the Equator experiences a weaker gravitational pull than an object at the\xa0poles. |
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| 11478. |
Define elasticity.. ✍✍✍✍✍ |
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Answer» Elasticity\xa0is that property of the object by virtue of which it regain its original configuration after the removal of the deforming force. the ability of an object or material to resume its normal shape after being stretched or compressed; stretchiness. |
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| 11479. |
Explain hookes law |
| Answer» \tRobert Hooke was the scientist who gave Hooke’s law.\tHooke’s law states that within the elastic limit, stress developed is directly proportional to the strain produced in a body.\tConsider a scenario where we apply external force to the body. As a result stress develops in the body due to this stress there will be a strain produced in the body which implies that there will be some deformation in the body.\tBecause of stress, strain is produced.\tAccording to Hooke’s law, if strain increases the stress will increase and vice-versa.\tThe Hooke’s law is applicable to all elastic substances.\tIt does not apply to plastic deformation.\tMathematically :\tstress ∝ strain\tstress = k × strain\tWhere k is the proportionality constant and is known as modulus of elasticity. | |
| 11480. |
Check the dimensionally accuracy of the relation s=U+at2 where symbol have their usual meaning |
| Answer» To check $$S=u+at²$$ .$$S=[L]$$$$(u+at²)= ([L¹T-¹]+[L¹T-² T²])=[L¹T-¹]$$ Hence it is dimensionally incorrect | |
| 11481. |
What are the three modes of heat transfer? Define each of them with suitable example. |
| Answer» There are three modes of heat transfer.\tConduction:\xa0Heat conduction is a process in which heat is transferred from the hotter part to the colder part in a body without involving any actual movement of the molecules of the body. Heat transfer takes place from one molecule to another molecule as a result of the vibratory motion of the molecules. Heat transfer through the process of conduction occurs in substances which are in direct contact with each other. It generally takes place in solids.\tConvection:\xa0In this process, heat is transferred in the liquid and gases from a region of higher temperature to a region of lower temperature. Convection heat transfer occurs partly due to the actual movement of molecules or due to the mass transfer.\xa0For example. Heating of milk in a pan.\tRadiation: It is the process in which heat is transferred from one body to another body without involving the molecules of the medium. Radiation heat transfer does not depend on the medium.\xa0For example: In a microwave, the substances are heated directly without any heating medium. | |
| 11482. |
Explain the expression of simple pendulum? |
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Answer» Tnq? Simple PendulumA simple pendulum is defined as an object that has a small mass (pendulum bob), which is suspended from a wire or string having negligible mass. \tWhenthe pendulum bob is displaced it oscillates on a plane about the vertical line through the support.\tSimple pendulum can be set into oscillatory motion by pulling it to one side of equilibrium position and then releasing it.In the above image one end of a bob of mass m is attached to a string of length L and another to a rigid support executing simple harmonic motion. |
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| 11483. |
Find the relative error z if z=a^3b^6/√dc |
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Answer» Hlo $$3(\\frac{\\Delta a}{a})+6(\\frac{\\Delta b}{b})+\\frac{1}{2}(\\frac{\\Delta d}{d})+1(\\frac{\\delta c}{c})$$ $$3(\\frac{∆a}{a})+6(\\frac{∆b}{b})+\\frac{1}{2}(\\frac{∆d}{d})+1(\\frac{∆c}{c})$$ |
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| 11484. |
Calculate the angular momentum |
| Answer» Angular momentum is defined as:The property of any rotating object given by moment of inertia times angular velocity.It is the property of a rotating body given by the product of the moment of inertia and the angular velocity of the rotating object. It is a\xa0vector quantity, which implies that here along with magnitude, the direction is also considered.\tSymbolThe angular momentum is a vector quantity, denoted by\xa0L⃗\xa0UnitsIt is measured using SI base units: Kg.m2.s-1Dimensional formulaThe dimensional formula is: [M][L]2[T]-1\tYou may also want to check out these topics given below! | |
| 11485. |
Derive the formula s=ut + 1/2at^2 |
| Answer» Consider the linear motion of a body with an initial velocity u. Let the body accelerate uniformly and acquire\xa0a final velocity v after time t. The velocity–time graph is a straight line AB as shown below.\xa0At t = 0, initial velocity = u = OA\xa0At t = t, final velocity = v = OCThe distance S travelled in time t = area of the trapezium OABDs = (1/2)\xa0x\xa0(OA + DB) × ODs =\xa0(1/2)\xa0x\xa0(u + v) × t Since v = u + at,s =\xa0(1/2)\xa0x\xa0(u + u + at) × ts = ut +\xa0(1/2) at2 | |
| 11486. |
What is called artificial satellites,?what type of satellites? |
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Answer» Yes it\'s correct Artificial satellite is a man-made device orbiting around the earth, moon or another planet transmitting to earth scientific information or used for communication.These satellite revolve around the planets and prvided all the information about planet through satellite imagery.Two types of artificial satellites :1) Weather satellite : Help to predict weather. ex. TIROS, COSMOS2) Communication satellite :\xa0Allow telephone and data conversations to be relayed through satellite .\xa0ex. Telstar, Intelsat. |
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| 11487. |
What is work? |
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Answer» Work is said to be done when a force acts on a body and cause displacement.Work = F s cos tetaIt is a vector quantity. Work is said to be done when a force applied to an object moves that object.We can calculate work by multiplying the force by the movement of the object.W = F × dThe SI unit of work is the joule (J) \tWorkDefinitionWork is said to be done when a force applied to an object moves that object.FormulaWe can calculate work by multiplying the force by the movement of the object. \xa0W = F × dUnitThe SI unit of work is the joule (J)\t |
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| 11488. |
Derive an expression for centripetal acceleration in uniform circular motion |
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| 11489. |
Any reason behind constant temperature of debye temperature |
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| 11490. |
Ans pls jullet |
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| 11491. |
What is projecticle motion?? |
| Answer» When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called\xa0projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.In a Projectile Motion, there are two simultaneous independent rectilinear motions:\tAlong the x-axis:\xa0uniform velocity, responsible for the\xa0horizontal\xa0(forward)\xa0motion\xa0of the particle.\tAlong y-axis:\xa0uniform acceleration, responsible for the\xa0vertical\xa0(downwards)\xa0motion\xa0of the particle. | |
| 11492. |
Find the value of int int_(0)^(x)Fdx; where F=kx |
| Answer» $$\\int\\limits _{0}^{x} F dx \\\\ \\int\\limits _{0}^{x} kxdx \\\\ k \\int\\limits _{0}^{x}xdx \\\\ k \\displaystyle [\\dfrac{x^2}{2}]^x _0 \\\\ k \\displaystyle [\\dfrac{x^2}{2} - \\dfrac{0}{2}] \\\\ \\dfrac{kx^2}{2} $$ | |
| 11493. |
how impulse is related to momentum |
| Answer» The impulse experienced by the object equals the change in momentum of the object. In equation form, F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the change in momentum. | |
| 11494. |
Write a dimension of velocity Where V= l/t and |
| Answer» The dimensional formula of Velocity is given by,M0\xa0L1\xa0T-1Where,\tM = Mass\tL = Length\tT = Time | |
| 11495. |
Newton universal law of gravitation full define |
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Answer» G=(m1×m2)/r²This is called universal law of gravitation Newton’s Law of Universal Gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of the masses and inversely proportional to the square of the distance between them Any two bodies in the universe attract each other with a force is called Newton universal law of gravitation\xa0. It is only attractive force. Newton’s Law of Universal Gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of the masses and inversely proportional to the square of the distance between them. |
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| 11496. |
Suggest best utube channel for physics?? |
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Answer» Tmko physics wallah ka jab nhi samagh aata.. tab kisi ka nhi aayega ?... Carryminiti Ooo...baaki to meko nahi pata....kyuki main humanities se hun..mere science waale frnds wahi dekhte hain..isliye Maine suggest kiya? Dhruv meko unka smjh nata bhut bde lectures rhte Physics wallah |
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| 11497. |
Subract 63.54 kg from 187.2 from significant figures |
| Answer» 187.2 - 63.54 = 123.66Rounding off to 4 significant digits,Answer = 123.7 | |
| 11498. |
Write a note on venturimeter,hence derive expression for the speed of incompressible liquid. |
| Answer» Venturimeter is based on Bernoulli\'s theorem. It consists of a two truncated tubes connected by a pipe at narrow ends. The pipe connecting the two tubes is called throat as shown in figure.The venturimeter tube is positioned horizontally and the liquid is made to enter in it at end A and after passing through throat BC, it leaves tube at end D. Let at A, the area of cross-section of tube be a1, pressure of liquid be P1\xa0and velocity be v1\xa0And at the throat, the area of cross-section of tube be a2\xa0pressure of liquid be P2\xa0and velocity be v2 | |
| 11499. |
Obtain relation between linear and angular velocity. |
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Answer» Gbh Relation between linear velocity and angular velocityLet us consider the randomly shaped body undergoing a rotational motion as shown in the figure below. The linear velocity of the particle is related to the angular velocity. While considering the rotational motion of a rigid body on a fixed axis, the extended body is considered as a system of particles moving in a circle lying on a plane that is perpendicular to the axis, such as the center of rotation lies on the axis.In this figure, the particle P has been shown to rotate over a fixed axis passing through O. Here, the particle represents a circle on the axis. The radius of the circle is the perpendicular distance between point P and the axis. The angle indicates the\xa0angular displacement\xa0Δθ of the given particle at time Δt. The average angular velocity in the time Δt is Δθ/Δt. Since Δt tends to zero, the ratio Δθ/Δt reaches a limit which is known as the instantaneous angular velocity dθ/dt. The instantaneous angular velocity is denoted by ω.From the knowledge of circular motion, we can say that the magnitude of the linear velocity of a particle traveling in a circle relates to the angular velocity of the particle ω by the relation υ/ω= r, where r denotes the radius. At any instant, the relation v/ r = ω applies to every particle that has a rigid body.If the perpendicular distance of a particle from a fixed axis is ri, the linear velocity at a given instant v is given by the relation,Vi\xa0= ωriSimilarly, we can write the expression for the linear velocity for n different particles comprising the system. From the expression, we can say that for particles lying on the axis, the tangential velocity is zero as the radius is zero. Also, the angular velocity ω is a vector quantity which is constant for all the particles comprising the motion. |
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| 11500. |
State two conditions for dynamic equilibrium |
| Answer» Both the net force and net torque must be zero | |