InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
Does mol have any dimension or it is dimension less? |
| Answer» I know it is dimension less but I was confused.<br>No , it is dimension less , if u not believe me u can checkout in Google ??<br>But in many searches I saw its dimension as \'mol\'.<br>Dimension less | |
| 252. |
Gravitational force is weak but still important. Justify |
| Answer» Because it is found in our daily life .people can see that from the moon to all the object which is placed on earth every body affected by the gravitational force due to its high range for distinct ares<br>Beacause it bind the earth moon and galaxies | |
| 253. |
If A is the angle between unit vectors A and B then (1-A.B)/1+A.B is equal to |
| Answer» | |
| 254. |
Formula of coefficient of viscosity |
| Answer» Δt=time , displacement =ΔxTherefore, shearing stress =Δx/l where l= lengthStrain rate=Δx/lΔtη=shearing stress/strain rate(F/A)/(Δx/lΔt) = (Fl)/vA where Δx/t=vTherefore η=(Fl)/ vA | |
| 255. |
Change 20 neuton into new system in which the mass is 10g length is beta and time is 30 sec |
| Answer» Sorry for if wrong<br>20(1kg by 10g)(1m by 10cm)(1sec by 30sec)^-220(100g)(10cm)(900sec)1.8×10^6MLT^-2 | |
| 256. |
In 1 newton there are how many dyne |
| Answer» 10 to the power 5 dynes !<br>1 N = 10 power 5 dyne..<br>HELLO IN 1 N 10TO THE POWER 5 DYNES | |
| 257. |
What are the important points in ch _ laws of motion |
| Answer» | |
| 258. |
A body acted upon by three forces F1 F2 F3 is under equilibrium. F1= 10 N F2= 6N . Find F3 |
| Answer» F1 + F2 +F3 = 010N+6N+F3=016N+F3=0F3=-16N | |
| 259. |
Value of angstorm |
| Answer» 10 power -10<br>10 power minus 10m<br>10^-10 m | |
| 260. |
Unit of velocity gradient |
| Answer» Sec ^-1 | |
| 261. |
Dimensional formula of gravitational constant |
| Answer» {tex}= \\left[ M ^ { - 1 } T ^ { - 2 } L ^ { 3 } \\right]{/tex} | |
| 262. |
Convert 1 joule into erdge?? |
| Answer» Solve krke send kro<br>1 J = 10^7 erg | |
| 263. |
What is coefficient of elasticity |
| Answer» | |
| 264. |
What is fundamental change |
| Answer» The centripital force of a body is dependent on mass of body velocity of body and radius of circle derive an expression for centripital force dimensionaly (k=1) | |
| 265. |
How to find the direction of vectors |
| Answer» It can be calculated by the formula : tan bita = Bsintheta ÷ A + Bcostheta . | |
| 266. |
Clear the product rule and addition rule |
| Answer» | |
| 267. |
Length of a sheet is 17.3+/_ 0.3 cm and breadth is3.12+/_0.08cm .calculate the percentage error |
| Answer» | |
| 268. |
Plot the graph between kinetic energy and potential energy in case of pendulum |
| Answer» | |
| 269. |
How to convert erg into Joule |
| Answer» 1 joule = 10⁷erg ..................it take so much time to convert it .so, I can\'t write here | |
| 270. |
Ten application of Physics in society |
| Answer» | |
| 271. |
Define measurement,physical quantity and unit. |
| Answer» | |
| 272. |
Triangl law of vector addition |
| Answer» if two vector are reperstented by two side of triangle then their resultant is given by third side of triangle | |
| 273. |
What is integration and differentiation ? |
| Answer» Integration -when we make large parts by joining small parts. Differentation-when we divide large parts of things in small parts for convenience of measuring | |
| 274. |
Ncert question pg no. 14 question no.1.7 |
| Answer» The industrial revolution\xa0starts in England and Western Europe in mid-18th\xa0Century. Its main contributions are inventions to perform work in effective and efficient manner. Some of them are,1. Blast FurnaceIt is the closed type of furnace which is capable of generating high temperatures. It is used to convert Iron into steel which is most widely used element nowadays.2. Cotton JenneyIt is said to be a most valuable invention in the 18thcentury because it reduces time to collect cotton from cotton flowers. It is almost 300 times efficient than a normal hand.3. Steam engineSteam engine invented by James Watt. It revolutionizes the transport system which ultimately leads to connectivity between countries. So, different peoples, cultures and their ideas mingle to form revolutionary products and inventions to the modern world.Fig. Steam Engine James Watt_1784There are many other inventions that are outcomes of the industrial revolution which pave the path for modern technology. | |
| 275. |
Applications of bernoullis principle ventri metre |
| Answer» Thank u for the answer<br>The flow speed of a fluid can be measured using a device such as a Venturi meter or an orifice plate, which can be placed into a pipeline to reduce the diameter of the flow. For a horizontal device, the continuty plate shows that for an incompressible fluid, the reduction in diameter will cause an increase in the fluid flow speed. Subsequently Bernoulli\'s principle then shows that there must be a decrease in the pressure in the reduced diameter region. This phenomenon is known as the Venturi effect. | |
| 276. |
From which book we can understand concept quickly |
| Answer» Pradeep for chemistry SL arora for Physics | |
| 277. |
What is bernoulli s principal with proof |
| Answer» Thanks<br>Bernoulli’s Principle\tFor a streamline fluid flow, the sum of the pressure (P), the kinetic energy per unit volume (ρv2/2) and the potential energy per unit volume (ρgh) remain constant.\tMathematically:- P+ ρv2/2 + ρgh = constant\twhere P= pressure ,E./ Volume=1/2mv2/V = 1/2v2(m/V) = 1/2ρv2E./Volume = mgh/V = (m/V)gh = ρgh\t\tDerive: Bernoulli’s equationAssumptions:\tFluid flow through a pipe of varying width.\tPipe is located at changing heights.\tFluid is incompressible.\tFlow is laminar.\tNo energy is lost due to friction:applicable only to non-viscous fluids.\tMathematically: -\tConsider the fluid initially lying between B and D. In an infinitesimal timeinterval Δt, this fluid would have moved.\tSuppose v1= speed at B and v2= speedat D, initial distance moved by fluid from to C=v1Δt.In the same interval Δtfluid distance moved by D to E = v2Δt.P1= Pressureat A1, P2=Pressure at A2.Work done on the fluid atleft end (BC) W1 = P1A1(v1Δt).Work done by the fluid at the other end (DE)W2 = P2A2(v2Δt)\t\t\tNet work done on the fluid is W1 – W2 = (P1A1v1Δt− P2A2v2Δt)\tBy the Equation of continuity Av=constant.\tP1A1 v1Δt - P2A2v2Δt where A1v1Δt =P1ΔV and A2v2Δt = P2ΔV.\t\t\tTherefore Work done = (P1− P2) ΔVequation (a)\tPart of this work goes in changing Kinetic energy, ΔK = (½)m (v22 – v12) and part in gravitational potential energy,ΔU =mg (h2 − h1).\t\t\tThe total change in energy ΔE= ΔK +ΔU = (½) m (v22 – v12) + mg (h2 − h1). (i)\tDensity of the fluid ρ =m/V or m=ρV\tTherefore in small interval of time Δt, small change in mass Δm\tΔm=ρΔV (ii)\t\t\tPutting the value from equation (ii) to (i)\tΔE = 1/2 ρΔV (v22 – v12) + ρgΔV (h2 − h1) equation(b)\tBy using work-energy theorem: W = ΔE\tFrom (a) and (b)(P1-P2) ΔV =(1/2) ρΔV (v22 – v12) + ρgΔV (h2 − h1)P1-P2 = 1/2ρv22 - 1/2ρv12+ρgh2 -ρgh1(By cancelling ΔV from both the sides).\t\t\tAfter rearranging we get,P1 + (1/2) ρ v12 + ρg h1 = (1/2) ρ v22 + ρg h2\tP+(1/2) ρv2+ρg h = constant.\tThis is the Bernoulli’s equation. | |
| 278. |
Relation between G,M,R in terms of v |
| Answer» | |
| 279. |
What is difference between one Armstrong and one atomic mass unit |
| Answer» Armstrong nhi avogram ya auston hoga dono same hai koi difference nhi hai | |
| 280. |
V=at3 |
| Answer» | |
| 281. |
Calculate the dimension of force and impulse take velocity density and frequency as basic quantities |
| Answer» | |
| 282. |
Convert 9.8 m/s into cm/s |
| Answer» No ques is right i have find the ans Th answ is 980cm/s<br>980 cm/s<br>9.8×10^3×6 itna hoga mere ko lgta hai ques galat hai ques phir se dekho sec ,sec me change ni hota hai | |
| 283. |
Explain the dual nature of light. |
| Answer» The light has wave and particle nature.<br>Wave n particle nature | |
| 284. |
What are the types of vector???? |
| Answer» | |
| 285. |
What is equal vector |
| Answer» No which also follow traingular law of vector addition<br>Whose magnitude and direction is same | |
| 286. |
Write SI unit of luminous intensity and temperature |
| Answer» Candela(cd) = luminous objectKelvin(k)=Temperature<br>SI unit of luminous intensity is Candela and temperature is Kelvin.<br>Candela luminous intensity and temperature : kelvin | |
| 287. |
Expand using binomial (1+3x)⁵ upto the term having x³ |
| Answer» | |
| 288. |
Find the dimension of force |
| Answer» M*1L*1T*-2<br>F=m×aF=m×velocity ÷timeF=m×displacement ÷time ×timeF=m×l÷t^2F=m^1L^1T^-2 | |
| 289. |
Dimensional of torque |
| Answer» M*1L*1T*-2 | |
| 290. |
What is fluids and hydroulic brake |
| Answer» | |
| 291. |
What is final theory |
| Answer» There is no final theory in physics | |
| 292. |
What is the physical quantities of force |
| Answer» Force is a derived quantity so it is having the dimensional formula MLT-2 ... | |
| 293. |
Which additional book is best for physics? |
| Answer» Ncert ya praddep se padho<br>Thanks<br>H C Verma is a must-have and the go-to book for Class 12 Physics. | |
| 294. |
Law\'s of conservarion of mass |
| Answer» It states that energy can neither be created nor be destroyed but it can converted from one form to another<br>The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system\'s mass cannot change, so quantity can neither be added nor be removed. | |
| 295. |
Hlow gyesssssss |
| Answer» Hlo guys.....m. How r u all....may god bless u ..... Be happy....<br>Hello<br>How r u muskan<br>Hlo | |
| 296. |
In physics where is realative error dervation |
| Answer» | |
| 297. |
When is the value of g is positive and when it is negative |
| Answer» If you choose downward direction to be positive and upward to be negative (generally used convention) then, g will be positive if the object is stationary or moving downwards. g will be negative if the object is moving upwards.<br>+ve tb hota h jb koi cheej earth ki trf gir rhi hoAur -ve tb hota h jb kisi cheej ko earth se faiki jaye | |
| 298. |
d/dx e tanx2 |
| Answer» | |
| 299. |
Laws of periods definition |
| Answer» | |
| 300. |
Define strategy of approximation |
| Answer» The strategy orlf approximation turned out to be very successful. (i) Most observed phenomena in daily life are rather complicated manifestations of the basic laws.(ii)Scientists recognised the importance of extracting the essential features of a phenomenon from its less significant aspects.(iii)It is not practical to take into account all the complexities of a phenomena in one go.(iv)A good strategy is to focus first on the essential features of a phenomena and discover the basic principles and then introduce corrections to build a more refined theory.(v)During study for free fall under gravity we assume air resistance to be zero.Similarly in mechanics we take moving objects as point objects.<br>The strategy of approximation can be explained as -[1]Speculation (talking about future results of experiments) and conjecture ( a approximation)have an important role to play during the procedure of scientific method of describing a phenomena, but must be verified by experiments.For example (i) The circular orbits as assumed by Nicolaus Copernicus in the heliocentric theory was replaced after certain inspections and experiments carried by Johannes Kepler.(ii)Paul Dirac in 1930, theoretically introduced the concept of antiparticle,which was later experimentally verified by Carl Anderson. [ii] Sometimes physical constants had to be assumed , their values later experimentally verified. The Universal gravitational constant G and constant in the coulombian force 1/4πε_0 were earlier assumed and later evaluated by using torsion balance.<br>Approximation theory is a branch of mathematics, a quantitative part of functional analysis. Approximation usually occurs when an exact form or an exact numerical number is unknown. | |