InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4301. |
7. Two identical metal spheres A and B have equaland similar charges. They repel each other witha force 103 N, when they are placed 10 cm apartin a medium of dielectric constant 7. Determinethe charge on each sphere. Ans. 28-3 x 10-6 CI |
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| 4302. |
which of the following does not deplete ozone leyer?(1)NO(2)N2O(3)CO2(4)CFC |
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Answer» cfc is that gas which seplate ozone layer The answer is OPTION 1: Nitric oxide(NO) |
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| 4303. |
raatus(T15. Express the relation for solid angle. |
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| 4304. |
2. What is the solid angle subtended bya hemisphere at its centre?(b) 2π steradian(d) 4π steradian(a) n steradian(c) 3π steradian |
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Answer» Angle made Solid angle |
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| 4305. |
) mass volume number O1 IHolecti1: Al (s) + Fe2O3 (s)A12()3 (s) +Fe(→ |
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| 4306. |
(d)Give the rules for assigning oxidation number. |
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Answer» Rules for Assigning Oxidation Numbers: 1) The oxidation number for an atom of any free (uncombined) element is ZERO.Examples: Na, Ca have zero oxidation number. 2) The oxidation number of an element in self-combination is always ZERO.Examples: H2, O2, P4 have zero oxidation number. 3) In most hydrogen containing compounds, oxidation number of hydrogen is + 1.(Exception is when H combines with alkali metals or alkaline earth to form hydrides of metals such as: NaH, LiH, CaH2. Then, the oxidation number of H is -1). 4) In compounds involving the alkali metals, the elements are assigned oxidation number of +1. 5) In compounds involving the alkaline earth metals, the elements are asasigned oxidation number of +2. 6) Oxygen is usually assigned an oxidation number of -2 for oxides. It has an oxidation number of -1 in peroxides (H2O2). 7) Fluorine always has oxidation number of -1 in compounds. The other elements in that group is usually -1 in compounds with elements of low electronegativity. 8) The sum of oxidation numbers of all the atoms in the formula for a neutral compound is ZERO. 9) The sum of oxidation numbers of an ion or complex ion is the same as the charge on that ion. |
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| 4307. |
Ol Name the divice which is used for measuringcarrena - Ans = AMMetre |
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Answer» ammetre and its unit is ampere ammeter and galvanometer Ametre the device which is used for measuring Carron. ammeter measure strength of current , galvanometer measure potential difference between two end. ammeter is the right answer and its unit is ampere Ammetre is the correct answer amppears measuring of current ammetre is best answer Ammeter(Amperemeter) is the device which is used for measuring the current. |
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| 4308. |
5X2-10Answer any FIVE of the following:11. If at + bt2 where X is in metre and t in second, what are the units of a and b? |
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| 4309. |
6. Where are poles of a bar magnet located?hefranscacte |
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Answer» thank you so much |
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| 4310. |
6. Where are poles of a bar magnet located? |
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Answer» they r located at the ends of bar magnet |
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| 4311. |
7. The units which are used for measurement offundamental quantities i.e., mass, length and time areknown as(a) scalar units (b) basic units (c) derived units(d) secondary units |
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Answer» These are called basic units as from these we can measure others |
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| 4312. |
DPPs BOOKLET-2wo persons, pull each other through a massless rope in 'tug of war gameWho will win?(A) one whose weight is more(B) one who pulls the rope with a greater force)one who applies more friction force (shear force) on ground(D) one(C)who applies more normal force (compressive force) on ground |
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| 4313. |
Two equal point charges A and B are R distanceapart. A third point charge placed on theperpendicular bisector at a distance d from thecentre will experience maximum electrostatic forcewhenĺ°ş2) d22V2(3) d RV2(4)de2V2R |
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Answer» ans is 1 I think d |
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| 4314. |
DPPs BOOKLET-28.wo persons, pull each other through a massless rope in 'tug of war' gamneWho will win?(A) one whose weight is more(B) one who pulls the rope with a greater force(C) one who applies more friction force (shear force) on ground(D) one who applies more normal force (compressive force) on ground |
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Answer» option c) the team pushes the ground more harder, more the reaction force it gets, and wins the game. Actually, this is based on newton's 3 rd law which states that action and reaction are equal and opposite. The more you push the ground, the more backward force you get, that means your team will move backwards, forcing other team to cross the line and lose the game. not in theory do it numerically bro |
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| 4315. |
2Asthe temperature of a metallic resistor is increased the product of resistivity & conductivitye increases.e decreases.e remains constant.changes.aro force ineion of an uniform field Then the [1l |
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Answer» As the temperature of a metallic resistor is increased the product of its resistivity and conductivity remains constant. |
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| 4316. |
9. Two charges 4q and -q are placed a distancer apart. A charge Q is placed exactly mid-way between them. What will be the valueof Q so that charge 4q experiences no netforce ? |
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| 4317. |
1) Define vector product of two vectors. State thecharacteristics of vector product. |
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| 4318. |
C) a.UE3. The modulus of the vector product of two vectors istimes their scalar product. The angle between vectors is362 |
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| 4319. |
Ans.A person applies some force on an almirah but it does not move. Why |
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Answer» Because the force applied by the person isn't greater than the inertia of that almirah.Means that the almirah is applying the sane force the person is applying and as we know only unbalanced force cause motion. |
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| 4320. |
.7) Match the following elements correctly with their ores:elementoreZinLead CalamineBauxiteAluminiunlena |
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Answer» Zinc-CalamineLead-GajenaAluminium-Bauxite |
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| 4321. |
.. G- UlliVersal gravitátional constantQ11. Findthe value o Guniversai gravitational constant. |
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Answer» Thegravitational constant(also known as the "universal gravitational constant", the "Newtonian constant of gravitation", or the "Cavendish gravitational constant"[1]), denoted by the letterG, is anempiricalphysical constantinvolved in the calculation ofgravitationaleffects inSir Isaac Newton'slaw of universal gravitationand inAlbert Einstein'sgeneral theory of relativity. In Newton's law, it is the proportionality constant connecting thegravitational forcebetween two bodies with the product of theirmassesand theinverse squareof theirdistance. In theEinstein field equations, it quantifies the relation betweenspacetime topologyandenergy–momentum. The measured value of the constant is known with some certainty to four significant digits. InSI unitsits value is approximately6.674×10^−11N·kg–2·m2. |
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| 4322. |
43. The potential energy, i.e., U(x)canbeassumedzenowhen(a) x0(b) gravitational force is constant(c) infinite distance from the gravitational source(d) All of the above |
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Answer» when X is equal to zero, gravitational force is constant |
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| 4323. |
A=5i+6j-7kB=6j-7k |
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Answer» i j k5 6 -70 6 -7 = i(-42+42) -j(-35+0) +k(30+0) =35j+30k ans. |
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| 4324. |
1.03 GRAVITATIONAL CONSTANT |
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Answer» Thegravitational constant(also known as the "universal gravitational constant", the "Newtonian constant of gravitation", or the "Cavendish gravitational constant"), denoted by the letterG, is anempiricalphysical constantinvolved in the calculation ofgravitationaleffects inSir Isaac Newton'slaw of universal gravitationand inAlbert Einstein'sgeneral theory of relativity |
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| 4325. |
8. A transformer has turns ratio of 10:1. Find the secondary voltage if the primary isconnected to 220V supply.(Ans: 22V) |
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Answer» V1/V2= N1/N2so220/V2= 10/1V1= 22 v |
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| 4326. |
8. A transformer has turns ratio of 10:1. Find the secondary voltage if the primary isconnected to 220V supply(Ans: 22V) |
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Answer» Ns/Np=Vs/Vp=a a=turn ratio 10:1=Vs/22010=Vs/220Vs=220*10=2200V |
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| 4327. |
9. A transformer has turns ratio of 5:1 and if secondary voltage is 40V/50Hz. Find the(Ans: Vp= 2007. f = 50Hz.)primary voltage and the frequency of supply. |
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Answer» The input and output frequencies are the same. Turns ratio (the number of primary turns divided by the number of secondary turns) is approximately equal to the ratio of primary to secondary voltage. Therefore if secondary voltage is 40V, the primary voltage will be approximately equal to 200V |
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| 4328. |
The input and output voltages of a transformer are220 V and 44 V respectively. Find (a) the turnsratio, (b) the current in input circuit if the outputcurrent is 2 A.Ans. (a) 1:5 (b) 0.4 A |
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Answer» we know thatV₁/V₂= I₂/I₁= N₁/N₂current = 0.4A turns ratio will be N1/N2= 220/441/5 |
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| 4329. |
CHAPTER PRACTICE PROBLEMTwo blocks of mass m = 5 kg and M-10 kg are connected by a string passingover a pulley B as shown. Another string connects the centre of pulley B to thefloor and passes over another pulley A as shown. An upward force F is appliedat the centre of pulley A. Both the pulleys are massless.Find the acceleration of blocks m and M if F is(a) 100 N(b) 300 N(c) 500 N (take g 10 m/s?) |
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Answer» (b) for F= 300 N similarly, find for other magnitudes of force |
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| 4330. |
8. An object is placed at a distance 3f72 from a concave mirror of focal length 'f'. Findand inverted, h = -5 cmnosition of image in terms of t. What is the magnification and nature of image 10od |
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Answer» u=-3f/2 after sign conventionsv=?f=-fby mirror formula:1/f=1/v+1/u1/v=1/f-1/u=-1/f-2/3f=(-3+2)/3f=-1/3fv=-3f image is beyond Cthus, m=-v/u=+3f/(-3f/2)=-2m=-2Image is real, inverted and magnified. |
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| 4331. |
A convex lens has a focal length of 30cm. At which distance should the object be placed from the lens to obtain an image at 60cm distance on other side of the lens? Find the magnification produced by the lens. |
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| 4332. |
a concave lens has focal length of 15cm.at what distance should the object from the lens be placed.so that it forms an image at 10cm from the lens?also find the magnification produced by the lens? |
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| 4333. |
(4)24JIf a spring extends by x on loading then energystored by the spring is :- (T is tension in the spring,K spring const.)222k(3) 2(42T22x2k (3) |
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Answer» option (2) |
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| 4334. |
Example 7.11 What is the moment ofinertia of a rod of mass M, length l aboutan axis perpendicular to it through oneend? |
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Answer» use parallel axis theorem. requuired MI= ml^2/12 + m(l/2)^2 =ml^2/3. (1/2) kaise aya bro explain me bro ho gya bro |
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| 4335. |
2. Write a note on parallel axis and perpendicular axis theorem for moment ofinertia. |
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Answer» sahi he kya |
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| 4336. |
lhat |
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Answer» Physics is the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms. hello mujha pata ha Yar 1st time download Kiya hu check Kar Raha hu bar bar pata nahi kaise Chala ja Raha ha |
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| 4337. |
A thin wire of length /and mass m is bent in the formof a semicircle. The moment of inertia about an axisperpendicular to its plane and passing through theend of the wire is2m/2(2) 2m2(3) m/2(4) 2m/22 |
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| 4338. |
pole?5cl The earth's field, it is claimed, roughly approximates the teedue to a dipole of magnetic moment 8 x 1022 JT locacentre. Check the order of magnitude of this number in sonewayits |
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| 4339. |
3A stone is allowed to fall from from the top of a tower and covers half the height of the tower in the last second ofits journey. The time taken by the stone to reach the foot of the tower is[CPMT-99][1] (2-V2)s[2] (2 +2) s4] (2+2)s[3] 4shndlhat was the initial |
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| 4340. |
From the top of a tower a stone is dropped. If it covers 25 m in the last second of its motion, find theheight of the tower. (g 10 m/s)15. |
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| 4341. |
An object dropped from a tower covers half height in 2 seconds. The height oftower will be: (g-9.8 ms2)(a) 9-8 m2.(b) 19-6 m(c) 20 m(d) 39.2 m. |
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Answer» please send me book name |
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| 4342. |
3.Find the power of a concave lens of focal length 2 m. |
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| 4343. |
lens.3. Find the power of a concave lens of focal length 28 |
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Answer» Thank u miss |
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| 4344. |
(which(u=1.5)Two similar thin equi-convex lenses, of focal lengthfeach, are kept coaxially in contact with each othersuch that the focal length of the combination isF . When the space between the two lenses isfilled with glycerin (which has the same refractiveindex (u = 1.5) as that of glass) then the equivalentfocal length is F,. The ratio F:F, will be(1) 2:33:42:1(4) 1:2for |
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Answer» 3) is the correct answer |
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| 4345. |
14. The masses m1,m2, m of three bodies shown in fig.calculate tension T,T2,T, when (i) the whole system ismoving with an acceleration of 2m/s'(ii) the whole system is stationary. (118 N, 59N,35.4 N,98N,49N, 29.4 N) |
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Answer» I guess the question is not complete.. because I can't see m3 in the figure as well as the weight of all masses otherwise the answer would be in the form of m |
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| 4346. |
\frac{d}{d x}\left(x^{4}-2 \sin x+3 \cos x\right)(A) 4x3 -2 cos x +3 sin x(B) 3x2+ 2 cosx + 3 sin x(C) 4x3+2 cosx-3 sin x(D) 4x3 -2 cos x- 3 sin xQ.1ax |
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Answer» option (D) |
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| 4347. |
2) State and explain Newton's law of gravitation. Give any two examp |
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Answer» Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Ex : force between planets, an objects falls in Earth as it attracts that object |
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| 4348. |
าภ<t01xm fall in the fort kumidirection when a moving busbrakes to a stop and fallbackwards when it acceleratesfrom rest?Why do |
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Answer» We fall in forward direction when a moving bus apply brakes because when the bus was moving, our upper part of body and the bus both are in motion, and when the bus apply brakes our body tries to be in motion because of inertia of motion and experiences a forward push. And when a bus at rest accelerates from rest , the passengers fall backwards, as initially both bus and our upper part of body is in state of rest and when it's starts moving our body tries to be in state of rest due to inertia of red rest and the passengers feel a backward push. Note - Inertia is the inability of the body to change its state of rest or motion by itself. |
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| 4349. |
g A concave mirror forms a real image four times thesize of the object which itself is placed 10 cm awayfrom the mirror. Find the position of the image andalso, the radius of curvature |
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Answer» u= -10 cm(negative as per sign convention) m= -4(real image) m= -v/u so, v = -40cm therefore image is located 40 cm in front of concave mirror since v is negative therefore image formed is real and inverted |
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| 4350. |
What do you mean by saturated and unsaturated vapours? |
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Answer» Saturated Water Vapour : When you add moisture (by water spray) to the dry air then it becomes water vapour. Now, consider you add moisture continuously. After period of some time we can not add moisture in the dry air because there is amaximum amount of moisture added,so this is called the saturated water vapour. Unsaturated Water Vapour : When you can add the moisture in the dry air till it reach to the saturation state then it's called unsaturated water vapour. |
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