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Energy is defined as ability to do work.

Mathematically,Energy = Work.Dimensional formula of Work = M1L2T-2Putting these values in above equation we get,Dimensional Formula of Energy = M1L2T-2SI unit of Energy is Joule (J)

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it travel 12m distance in vx

I don't understood that 44=...,.... step

replyyyyy

s = ut + 1/2 at^2 Substitute in that the values.

but s will be then total distance or just the distance travel in 2 sec

how u can take time 2 sec

it is the time at which it travel 14 m from top

ya u are right

I understood now

⇒ the time taken by both balls at point P has same time ' t ' seconds .

⇒ for first ball , that is in the diagram from A to P

S = ut + 1/2 at²

we know that u = 0 and a = g

⇒ ( 100 - x ) = (0)t + 1/2 gt²------------(1)

now, for the second ball from B to P in the diagram ,

S = t + 1/2 at²

where u = 50 m/s and a = -g

therefore, x = 50(t) - 1/2gt² ------------------(2)

by adding equation (1) and (2) we will get ,

100 = 50 t

implies, t = 100 / 50

therefore t = 2 sec .

therefore the time that they cross each other is 2 seconds.

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answer of this question is 2 second

In traditional railway construction, rails are laid down over sleepers, clamped to them and then fastened to one another by means of fishplates. These fishplates not only help the whole track structure to maintain its integrity, but also ensure that a certain (small) distance between rails is kept. This is due to thermal expansion.

All solids expand (increase in size) in a certain measure when subjected to high temperatures — and contract when cooled. This is a basic thermodynamic fact: molecules always vibrate and when heated, this vibration increases, slightly expanding the bulk of the material. When the main dimension of a solid is linear (like in rails) we talk of linear thermal expansion. This effect can be modeled with a constant coefficient for ambient temperatures. Rails are made of a steel which has a linear thermal expansion coefficient of around 12 µm/(m·K). That is: each meter of rail expands 0,012 millimeters for each degree of temperature increase.

On joining OF , the resultant of OF +OB , will be OA

=> OF + OB = OA=> OF = OA - OB = a-b

1.5V meansthat there is a potential energy difference of1.5joules per coulomb between the points where that potential difference is measured. Similar for 9V, 12V, or 480,000V.

Batteriesare based on certain electrochemical reactions and those reaction all produce a voltage in the region of1.5to 3.0voltspercell.

In mathematics,the dot productorscalar productis an algebraic operation that takestwoequal-length sequences of numbers (usually coordinate vectors) and returns a single number. ... Geometrically, it isthe productoftheEuclidean magnitudes ofthe twovectors andthecosine oftheangle between them

In mathematics,the dot productorscalar productis an algebraic operation that takestwoequal-length sequences of numbers (usually coordinate vectors) and returns a single number. ... Geometrically, it isthe productoftheEuclidean magnitudes ofthe twovectors andthecosine oftheangle between them.

Dot Product



A way of multiplying two vectors:

a · b= |a| × |b| × cos(θ)

Where || means "the magnitude (length) of"And θ is the angle between the vectors

Example: the lengths of two vectors are 3 and 4, and the angle between them is 60°So the dot product is:

a · b= 3 × 4 × cos(60°) = 3 × 4 × 0.5 = 6

like for like........

Supplementary unitsare the dimensionlessunitsthat are used along with the baseunitsto form derivedunitsin the International system. The class ofsupplementarycontains only two purely geometricalunits, that is the radian and the steradian.

u = 0, v = 72 km/hr = 72*5/18 = 20 m/s, s = 100 m

Using,v = u + atat = 20......... (1)

Now,s = ut + 1/2 at^2100 = 0 + 1/2*(at)*t100 = 1/2*20*tt = 100/10 = 10 s

From eq(1)a*10 = 20a = 20/10 = 2 m/s^2

Force exerted by engine= mass*acceleration = 500*2 = 1000 N

v=72km/h=72*5/18=20m/su=0 s=100m v^2-u^2=2asa=v^2-u^2/2s =20^2-0^2/2*100 =400-0/200 =400/200 =2m/s^2m=500kga=2m/s^2F=ma =500*2 =1000N

at first u=initial velocity=0 using v=u+at a=1/15 m/s2. then using s= ut + 1/2 at2 . s=3 km

TheSI unitof kilogram per cubic metre (kg/m3) and thecgs unitof gram per cubic centimetre (g/cm3) are probably the most commonly usedunitsfordensity.1,000 kg/m3equals 1 g/cm3. (The cubic centimeter can be alternately called a millilitre or a cc.)

The power factor of an LCR circuit is defined as the ratio of the real power (W) consumed by a circuit to the apparent power (VA) consumed by the same circuit.It is the cosine of the phase angle between voltage and current. The power factor can get values in the range from 0 to 1.

kilowatthour=3.6×10^6J.1J=1Kgms^-2×m=1Kgm^2s^-2.therefore3.6×10^6J=3.6×10^6Kgm^2s^-2.so3.6×106Kgm^2s^2=ngcm^2s^-2.orn=3.6×10^6(Kgg)mcm^2ss^-2.orn=3.6×10^61000g1g100cm1cm21-2.orn=3.6×10^13.Therefore1Kilowatthour=3.6x10^13erg/sec

Ohm's Law is a mathematical equation that shows the relationship between electric voltage (V), current (I) and impedance (Z). Ohm's Law is often seen with impedance replaced by resistance, which is fine for electricians wiring a house with only resistance in the circuits. However, in nondestructive testing the circuits also have inductive reactance and capacitance which also impede the flow of electricity. Therefore, impedance is used in this version of Ohm's Law. Ohm's Law can be expressed in the following three ways.

V = I x Z

Z = V / I

I = V / Z

Ohm's law is used in eddy current testing to determine the change in impedance caused by some change in the material or loading of the test coil. Eddy current instruments typically apply a constant AC current and monitor the voltage or visa versa. A change in the voltage (or current) in an eddy current test system can be directly related to a change in impedance.

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For a consumer a most economical power factor will be between 0 to 1it may be 0.85 laggingas most of the appliances are in lagging nature

approximately 8.85The permittivity of free space (a vacuum) is a physical constant equal to approximately 8.85 x 10-12 farad per meter (F/m). It is symbolized o. In general, permittivity is symbolized and is a constant of proportionality that exists between electric displacement and electric field intensity in a given medium.

find the dimentions of permittivity of vacuum. In brife

wrong aahe

If the density of cone is p, then mass of cone = density x volume=p1/3π(2R)²= 16/3π(R)³pThis mass is concentrated at a height from O= h/4 =4R/h = R

Mass of the sphere= m₂= density x volume= 12p x 4/3π(R)³= 16πR³p= m3

This mass is concentrated at O2, i.e. at a distance of 4R+R=5Rfrom O.Hence centre of mass of whole system will beYcm = m1y1 + m2y2/m1 + m2=mR + 3m(5R)/ m + 3m= 16mR/ 4m=4R

hence, option (C) is correct.

options d hoga answer

Relative permittivity= €/€°

option a hoga.

(d) is a correct answer

a answer create hoga

The refrigerator is just the reverse of a heat engine. In this the working substance extracts an amount of heat Q2 from the sink and after doing work rejects an amount of heat Q1 to the source which is at a higher temperatureT1

Increase in length = coefficient of linear expansion*original length*temperature change= 17*(10^-6)* 10*30= 0.0051m

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Option ATake an element of length dr.

mass per unit length= m/l dr

Tension=integral mw2rdr/L=mw2r2/2L

Given,Angular Displacementtheta = at^2 + bt + c

Angular velocity is given byd(theta)/dt = 2at + b

Therefore,For t = 1Angular velocity = 2a*1 + b= 2a + b

(a) is correct option

thanx

y kaise aaya please explain

wrong answer

Lets suppose each square lamina has a mass of 1 kg. having COM at (1/2, 1/2) (3/2, 1/2) (1/2, 3/2)

COM of L shaped lamina will bex= m1x1 + m2x2 + mx3/ m1 + m2 + m3by putting the values we will get x= 5/6m

y = m1y1 + m2y2+ m3y/ m1 + m2 + m3y= 5/6 m

note I have consider reference pt to be bottom left corner since it was not mentioned in question but probably they have taken it center so their value is 5/6,5/6. so don't worry about it. position is still same while coordinates are different.