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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
In vulcanisation of rubber,A. sulphur reacts to form new compoundB. sulphur cross-links are introducedC. sulphur forms a very thin protective layer over rubberD. all the statements are correct |
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Answer» Correct Answer - B |
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| 852. |
Assertion : Nylon-6, 6, is a polymade Reason : In Nylon 6, 6 the monomers are adipic acid and hexxamethylene diamineA. If both assertion and reason are correct and reason is correct explanation for assertionB. If both assertion and reason are correct but reason is not correct explanation for assertionC. If assertion is correct but reason is incorrectD. If assertion and reason are both incorrect |
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Answer» Correct Answer - B Correct explanation. In Nylon-66, the monomer units are linked by amide `(-CO - NH -)` linkage |
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| 853. |
A natural linear polymer of 2-methyl-1, 3-butadiene becomes hard on treatment with sulphur between 373 to 415 K and —S—S— bonds are formed between chains. Write the structure of the product of this treatment? |
| Answer» Vulcanised rubber. | |
| 854. |
A natural linear polymer of 2 methyl -1,3 - butadiene becomes hard on treatment with suphur between 373 to 415 K and -s - s- bonda are formed between chains.Write the structure of the product of this treatment? |
| Answer» The process is known as vulcanisation of rubber. | |
| 855. |
A natural linear polymer of 2-methyl-1, 3-butadiene becomes hard on treatment with sulphur between 373 to 415 K and -S-S- bonds are formed between chains. Write structure of the product ofthis treatment. |
| Answer» Correct Answer - Vulcanized rubber | |
| 856. |
Artificial silk is aA. polypeptideB. polysaccharidesC. PolyethyleneD. polyvinyl chloride . |
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Answer» Correct Answer - B Chemically -treated cellulose (a polysaccharide ) is called artificial silk . |
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| 857. |
Artificial silk is aA. polypeptideB. polysaccharideC. polytheneD. polyvinyl chloride |
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Answer» Correct Answer - B Chemically treated cellulose (polysaccharide) is called silk. |
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| 858. |
Artificial silk is:A. nylon-6B. rayonC. nylon-66D. none of these |
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Answer» Correct Answer - C |
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| 859. |
Which of the following statements is false?A. Artificial silk is derived from celluloseB. Nylon-6,6 is an example of elastomerC. The repeat unit in natural rubber is isopreneD. Both starch and cellulose arc polymers of glucose |
| Answer» Correct Answer - B | |
| 860. |
Is `(-CH_(2) - underset(Cl)underset(|)(C))_(n)` a homopolymer or copolymer ? |
| Answer» Correct Answer - It is a homopolymer | |
| 861. |
Caprolactum is used to prepare which of the following polymer?A. TeflonB. teryleneC. nylon 6, 6D. nylon 6 |
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Answer» Correct Answer - D Caprolactum is used in the manufacture of nylon-6. |
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| 862. |
Caprolactum is used to prepare which of the following polymer?A. Nylon-66B. MalamineC. Nylon-6D. PMMA |
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Answer» Correct Answer - B |
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| 863. |
Is `[-CH_(2)-CH(C_(6)H_(5)-)]_(n)`a homopolymer or a copolymer? |
| Answer» It is a homopolymer and the monomer from which it is obtained is styrene`C_(6)H_(5)CH=CH_(2)`. | |
| 864. |
Mark out the most unlike form of polymerization of `H_(2)C=CH-CH=CH_(2)`A. B. C. D. |
| Answer» Correct Answer - D | |
| 865. |
Is `-[CH_(2)-CH(C_(6)H_(5))-]_(n)`-homopolymer or a copolymer ? |
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Answer» `-[CH_(2)-CH(C_(6)H_(5))-]_(n)` is polystrene .It us a homopolymer. It is formed by the polymerisation of single monomer styrene. `(C_(6)H_(5)-CH=CH_(2))` |
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| 866. |
Is `[CH_(2)-CH(C_(6)H_(5))]_("n")` a homopolymer or a copolymer? |
| Answer» It is a homopolymer and the monomer from which it is obtained is styrene `C_(6)H_(5)CH = CH_(2)`. | |
| 867. |
What is `[--CH_(2)-CH-(C_(6)H_(5))--]_(n)` ?A. HomopolymerB. CopolymerC. Both (a) and (b)D. Neither (a) nor (b) |
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Answer» Correct Answer - A `[--CH_(2)-CH(C_(6)H_(5))--]_(n)` is a homopolymer and its monomeric unit is styrene , `(C_(6)H_(5)CH=CH_(2))` . |
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| 868. |
Which of the following dose not come under the classification of polymer on the basis of source ?A. NaturalB. AdditionC. CondensationD. Both (b) and (c) |
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Answer» Correct Answer - D On the basis of source polymers can be classified as natural , semi-synthetic and synthetic. |
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| 869. |
Among the following , the wrong statement isA. PMMA is plexiglassB. SBR is natural rubberC. PTFE is teflonD. LDPE is low density polythene |
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Answer» Correct Answer - B SBR (styrene-butadiene ) is a synthetic rubber. |
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| 870. |
Which is true for terpolymers ?A. A polymer of acrylonitrile, butadiene and styreneB. Contains three monomers.C. ABS plasticD. All of the above |
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Answer» Correct Answer - D All the given properties are of terpolymers. |
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| 871. |
Which of the following polymers does not involve cross-linkages ?A. Vulcanised rubberB. MelamineC. bakeliteD. Polystyrene |
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Answer» Correct Answer - D Polystyrene contains only linear chains. |
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| 872. |
Which of the following polymers does not involve cross-linkages ?A. Vulcanised rubber B. MelamineC. bakeliteD. Polystyrene |
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Answer» Correct Answer - D Polystyrene contains only linear chains. |
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| 873. |
Which of the following polymers involves cross-linkages?A. PolytheneB. BakeliteC. MelamineD. Vulcanized rubber |
| Answer» Correct Answer - A::B::C | |
| 874. |
The number of disulphide linkages present in insulin areA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - B Insulin is composed of two peptide chains referred to chains A and B. Chain A of 21 residues and chain B of 30 residues are cross-liked by two disulphide bridges. |
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| 875. |
A regular copolymer of ethylene and vinyl chloride contains alternate monomers of each type. What is the weight percent of ethylene in this copolymer? |
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Answer» The weight percent of ethylene in this copolymer [28/(28+62.5)]*100 30.93% Acid polymerisation 4.C6H10 = NOH → A → B Give the products A& B. A=€‐ Aminocaproic acid B = nylon‐6 |
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| 876. |
In rubber industry, natural rubber is processed using sulphur.What is the need of processing rubber in this way? Name this process.What is the monomer unit of natural rubber? |
Answer»
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| 877. |
Fill in the blanks: Table Polymers Monomer(a) PVC(i) …………(b) Terylene(i) …………c() Buna-N(iii) ………(d) …………(iv) 2-Chloro-1,3- butadiene |
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Answer» 1. Vinyl chloride 2. Glyptal 3. 1,3-butadiene and acrylonitrile 4. Neoprene |
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| 878. |
What are the monomeric repeating units of Nylon-6 and Nylon-6,6? |
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Answer» The monomeric repeating unit of nylon 6 is [NH – (CH2)5 – CO], which is derived from caprolactam. The monomeric repeating unit of nylon 6, 6 is [NH – (CH2)6 - NH - CO - (CH2)4 - CO], which is derived from hexamethylene diamine and adipic acid. |
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| 879. |
1. Give the monomeric repeating units of nylon 6 and nylon 6, 6.2. Differentiate between addition polymerisation and condensation polymerization. |
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Answer» 1. monomeric repeating units: 1. Nylon – 6 – Caprolactam 2. Nylon – 66 – Adipic acid, Hexamethylene diamine 2. Difference between addition polymerisation and condensation polymerization: Addition polymer: Simple monomer units combine together to form polymer. Example: polythene. Condensation polymer: Simple monomer units combine together to form polymer followed by the removal of small molecules like H2O, NH3 etc. Example: Nylon-6,6, |
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| 880. |
Identify the monomer in the following polymeric structure : `[-CH_(2) - CH = CH - CH_(2) - CH_(2) - overset(CN)overset(|)(CH)-]_(n)` (i) On the basis of force between their molecules in a polymer to which class does neoprene belong ? (ii) Can both addition and condensation polymerization result in the formation of a copolymer ? |
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Answer» (i) The monomers are : `CH_(2) = CH - CH = CH_(2)` (Buta -1, 3-diene) and `CH_(2) = CHCN` (Acrylonitrile) (ii) Neporene belongs to the class of elastomers since the intermolecular forces present in the monomer units (chloroprene) are quite weak. (iii) Yes, it is in possible. |
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| 881. |
Nylon is:A. polyamideB. polyesterC. polytheneD. regenerated |
| Answer» Correct Answer - A | |
| 882. |
Classify these polymers on the basis of mode of polymerization: Buna-S, Dacron,Nylon-6, Polythene. |
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Answer» Addition Polymerisation: Polythene, Buna-S Condensation Polymerisation: Dacron, Nylon-6 |
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| 883. |
Which of the following represents nylon 6 ?A. `(-underset(O)underset(||)C-(CH_2)_4-underset(O)underset(||)C-NH-(CH_2)_(6)-NH-)_n`B. `(-CH_2-underset(Cl)underset(|)(CH)=CH_2-underset(Cl)underset(|)(CH))n`C. `(-CH_2-underset(Cl)underset(|)(CH)-CH_2-underset(Cl)underset(|)CH)n`D. `{OC-(CH_(2))_(5)-NH-}_(n)` |
| Answer» Correct Answer - D | |
| 884. |
How is Dacron obtained from ethylene glycol and terephthalic acid?A. GlyptalB. KevlarC. DacronD. Bakelite |
| Answer» Correct Answer - 3 | |
| 885. |
How is dacron obtained from ethylene glycol and terephthalic acid? |
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Answer» It is the condensation product of ethylene glycol and terephthalic acid carried out at 420 to 460K in the presence of catalyst mixture of zinc acetate and antimony trioxide. |
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| 886. |
Which of the following represent terylene (or dacron)?A. `(-OCH_2-CH_2O-overset(O)overset(||)C-C_6-H_5-overset(O)overset(||)C-)n`B. `(-CH_2-CH=CH-CH_2-CH-CH_2-)n`C. `(-CH_2-underset(Cl)underset(|)(C )=CH-CH_2-underset(Cl)underset(|)(CH)-CH_2-)n`D. `(-CH_2-underset(C_6H_5)underset(|)(CH)-CH_(2)-underset(C_(6)H_(5))underset(|)(C)H-)n` |
| Answer» Correct Answer - A | |
| 887. |
Explain copolymerization with an example . |
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Answer» Copolymers : A polymer which is formed by the polymerisation of two (or) more chemically different types of monomer units is called copolymer .E.g: Bunadiene -styrene polymer (Buna-S The process of formation of copolymer is called copolymerisation. E.g.: Buna -S Buna -S is thecopolymer which is formed by the polymerisation of 2,3 - Butadiene and styrene. `{:(n(CH_2=CH-CH=CH_2)+n(CH_2=CH-C_6H_5)rarr"("-CH_2-CH=CH-CH_2-CH_2-overset(C_6H_5)overset(|)CH-")"_n),(" ""1,3-Butadiene " " ""Styrene " " "Buna" -S):}` |
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| 888. |
Define the term polymerisation. |
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Answer» Polymerisation is the process of forming high molecular mass (103-107u) macromolecules, which consist of repeating structural units derived from monomers. In a polymer, various monomer units are joined by strong covalent bonds. |
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| 889. |
In which classes, the polymers are classified on the basis of molecular forces? |
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Answer» On the basis of magnitude of intermolecular forces present in polymers, they are classified into the following groups:
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| 890. |
Write chemical name of (Ziegler‐Natta catalyst). |
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Answer» Triethylaluminium and titanium tetrachloride |
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| 891. |
What are the products in the following sequence of reaction Poly (F) is:A. Nylon-6,6B. Nylon-6,10C. Nylon-6D. Nylon-5 |
| Answer» Correct Answer - A | |
| 892. |
What is the cross linking agent used in the manufacture of tyre rubber ? |
| Answer» In the manufacture of tyre rubber 5% sulphur I used as cross linking agent . | |
| 893. |
Name the different types of molecular masses of polymers . |
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Answer» The different types of important molecular masses of polymers are 1)Number average molecular mass `(bar(M)_n)_(2)`Weight average molecular mass `(bar(M)_w)` |
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| 894. |
What is PDI (Poly Dispersity Index ) ? |
| Answer» Poly Dispersity Index (PDI) : The ratio between weight average molecular mass `(bar(M)_w)` and the number avetage molecular mass `(bar(M)_n)` of a polymer is called poly Dispersity Index (PDI). | |
| 895. |
Which of the following statement about polymers in correct?A. The number - average molecular `overline(M_(n))` and the weight - average molecular mass, `overline(M_(w))` are expressed by the equations `overline(M_(n)) = (sum N_(i) M_(i))/(sum N_(i))` and `overline(M_(w)) = (sum N_(i) M_(i)^(2))/(sum N_(i) M_(i))` where `N_(i)` is the number of molecular mass `M_(i)` of the species `i`.B. Some physical properties such as freezing point, vapor pressure and osmoric pressure are related directly to `overline(M_(n))` whereas some other physical properties lie light - scattering, sedimantation and difusion constant are related direclty to `overline(M_(w))`C. The ration of the weight - average and number - average molecular masses, `overline(M_(w))//overline(M_(n))` is called poly dispersity index `(PDI)`,D. All of these |
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Answer» Correct Answer - D `overline(M_(n)) = (sum N_(i) M_(i))/(sum N_(i))` `overline(M_(w)) = (sum N_(i) N_(i)^(2))/(sum N_(i) N_(i))` `PDI = (overline (M_(w)))/(overline(M_(n)))` |
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| 896. |
`PHBV` is a copolymer ofA. 2 - hydroxybutanoic acid and 3 - hydroxypentatonic acidB. 3- hydroxybutanoic acid and 3 - hydroxypentatonic acidC. 3 - hydroxybutanoic acid and 2 - hydroxypentatonic acidD. 2 - hydroxybutanoic acid and 2 - hydroxypentatonic acid |
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Answer» Correct Answer - B `{:(underset(3-"Hydroxybutanoic acid")(CH_(3)-overset(OH)overset(|)(CH)-CH_(2)-COOH)+CH_(3)-underset(3-"Hydroxypentanoic acid")(CH_(3)-overset(OH)overset(|)(CH)-CH_(2)-COOH)),(" "darr-(2n-1)H_(2)O),(" "(O-underset(R)underset(|)(CH)-CH_(2)-underset(O)underset(||)(C)-O-underset(R)underset(|)(CH)-CH_(2)-underset(O)underset(||)(C))):}` `R=CH_(3)^(-), C_(2)H_(5)^(-)` |
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| 897. |
The poly dispersity index `(PDI)` is for - natural polymersA. unitB. higher than unityC. smaller than unityD. higher of smaller than unity depending the nature of monomer |
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Answer» Correct Answer - A The `PDI` is unity (i.e., `overline(M_(w)) = overline(M_(n)))` for natural polymers as they are monodispersed. In synthetic polymers, which are always polydispersed, the `PDI` is greater than unity because `overline(M_(w))` is greater than unity |
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| 898. |
On the basis of the mode of their formation the polymers can be classified:A. as addition polymers onlyB. as condensation polymers onlyC. as copolymersD. both as addition and condensation polymers |
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Answer» Correct Answer - D During addition polymerisation , there is no byproduct . The addition is due to double bond or rearrangement . Whereas in condensation polymerisation , there will be byproduct . |
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| 899. |
On the basis of the mode of their formation the polymers can be classified:A. as addition polymer onlyB. as condensation polymers onlyC. as copolymersD. both as addition and condensation polymers |
| Answer» Correct Answer - D | |
| 900. |
Polymers can be classified on the basis of:A. originB. structureC. mechanismD. synthesis |
| Answer» Correct Answer - A::B::C::D | |