InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Medel selected Pisum sativum for hybridisation experiments because ofA. Clear contrasting characters and short life spanB. Long life span and non-fertile hybridsC. Presence of unisexual flowersD. Infertile hybrids and production of large number of seeds by each plant |
| Answer» Correct Answer - A | |
| 102. |
How many pairs of contrasting characters in pea plants were studied by Mendel in his experiments?A. EightB. SevenC. FiveD. Six |
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Answer» Correct Answer - B Seven pairs of contrasting characters in pea plants were studied by Mendel in his experiments. |
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| 103. |
Number of linkage groups in pisum sativum isA. 4B. 5C. 7D. 10 |
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Answer» Correct Answer - C Linkage groups: A linkage group is a group of linked gene and corresponds to the genome of organism, like human has 23 linkage groups, pea and Neurospora has 7 linkage groups, Drosophila has 4 linkage groups. |
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| 104. |
Number of linkage group in Pisum sativum is or How many pairs of contrasting charaters in pea planets were studied by mendal in his experimentsA. 2B. 5C. 7D. 9 |
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Answer» Correct Answer - C (c) The garden pea plant has seven pairs of chromosome and the same number of linkage group. |
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| 105. |
Among of the following characters, which one was not considered by Mendal in his experiments on peaA. Stem- Tall of DwarfB. Trichomes-Glandular or non-glandularC. Seed- Green or YellowD. Pod-Inflated or Constricted |
| Answer» Correct Answer - C | |
| 106. |
The colour blindness is more likely to occur in males than in females becauseA. The Y-chromosomes of males have the genes for distinguishing coloursB. Genes for characters are located on the X-chromosomesC. The trait is dominant in males and recessive in femalesD. None of these |
| Answer» Correct Answer - B | |
| 107. |
Triticale, the first man-made cereal, crop has been obtained by crossing wheat withA. BarleyB. RyeC. Pearl milletD. Sugarcane |
| Answer» Correct Answer - B | |
| 108. |
Among the following characters, which one was not considered by Mendel in his experiment on peaA. Trichomes-Glandular or non-glandularB. Seed-Green or yellowC. Pod-Inflated or constrictedD. Stem-Tall or dwarf |
| Answer» Correct Answer - A | |
| 109. |
Sex-linked characters areA. DominantB. RacessiveC. LethalD. Not inherited |
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Answer» Correct Answer - B Genes for sex linked characters occurs in both segments of X and Y-chromosomes. Many sex linked characters (about 120 ) are found in man , Such characters are mostly recessiove. |
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| 110. |
If mother is a carrier for colour blindess and father is normal, then in the offsprings this disease may be seem omA. All the sonsB. All the daughtersC. `50%` sons and `50%` daughters (carrier)D. All the sons and not in daughters |
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Answer» Correct Answer - C Carrire mother is heterogametic for recessive colour blindness gene. |
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| 111. |
This pedigree is of a rare trait, in which children have extra fingers and toes. Which one of the following patterns of inheritance is consistent with this pedigree A. Autosomal recessiveB. Autosomal dominantC. Y-linkageD. Sex linked recessive |
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Answer» Correct Answer - C Y - linked disorder are caused by mutations on the Y- chromosome from the their father, every son of a an affected father will be affacted. Because femlas inherit an X-chromosome from their father, female offspring of affected fathes are never affected. |
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| 112. |
Sickle cell anamia has not been eleiminated from African polulation asA. It is controlled by dominant genesB. It is controlled by recessive genesC. It is not a fatal diseaseD. It provides immunity against malaria |
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Answer» Correct Answer - D Sickle cell anaemia has not been eliminated from African population as it provides immunity against malaria. |
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| 113. |
A colour blind man marries with a daughter of colour blind father, generation will beA. there will be no daughter colour blindB. all sons will be colour blindC. all daughters will be colour blindD. half sons will be colour blind |
| Answer» Correct Answer - D | |
| 114. |
In a plant, red fruit ( R ) is dominant over yellow fruit ( r ) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that a rrtt:A. 25% will be tall with red fruitB. 50% will be tall with red fruitC. 75% will be tall with red fruitD. All of the offspring will be tall with red fruits |
| Answer» Correct Answer - D | |
| 115. |
Assertion: `Hb^(S) Hb^(S)` is homozygous condition of sickle cell anaemia. Reason: It occurs due to substitution of glutamic acid by valine at sixth position in `beta`-chain of haemoglobin. |
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Answer» Correct Answer - B `Hb^(S)Hb^(S)` is homozygous condition of sickle cell anaemia. It occurs due to substitution of glutamic acid by valine at sixth position in `beta`-chain of haemoglobin. |
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| 116. |
Mendel was born inA. `17^(th)` centuryB. `18^(th)` centuryC. `19^(th)` centuryD. `8^(th)` century |
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Answer» Correct Answer - C (c ) Mendel born in 1822 and died in 1884. |
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| 117. |
Which one of the following techniques is employed in human genetic counsellingA. Serological techniqueB. PolyploidyC. Pedigree analysisD. Amniocentesis. |
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Answer» Correct Answer - C The technique employed in human genetic counselling is pedigree analysis. |
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| 118. |
Assertion: Mendelian disorders are transmitted to offspring on the same lines as in the principles of inheritance. Reason: The pattern of inheritance of Mendelian disorders cannot be traced in a family by the pedigree analysis.A. If both assertion and reasons are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If both assertion and reason are false. |
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Answer» Correct Answer - C Mendelian disorders are transmitted to offspring on the same lines as in the principles of inheritance. The pattern of inheritance of Mendelian disorders can be traced in a family by the pedigree analysis. |
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| 119. |
Mark the odd one (w.r.t. `F_(2)` generation of Mendelian dihybrid cross)A. Frequency of TIRR genotype `= 12.5%`B. Frequency of ttrr genotype `= 6.25%`C. Frequency of TTRR genotype `= 6.25%`D. Frequency of TTRR genotype `= 25%` |
| Answer» Correct Answer - D | |
| 120. |
ln `F_(2)` generation of a Mendelian dihybrid cross `("TTRR" xx ttrr)`A. Tall plants and violet flowered plants are obtained in 1 : 1 frequencyB. Ratio of parental and non-parental plants is `1 : 15`C. Recombinant plants are obtained in `1 : 1` frequencyD. More than one option is correct |
| Answer» Correct Answer - D | |
| 121. |
In incomplete dominance, the ratio which not deviates from the Mendelian monohybrid cross?A. Genotypic ratioB. Phenotypic ratioC. Both A and BD. Either A or B |
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Answer» Correct Answer - A Here the genotype ratios were exactly as we would expect in any Mendelian monohybrid cross, but the phenotype ratios had changed from the 3:1 dominant : recessive ratio. |
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| 122. |
State the mendelian principle which can be derived from a dihybrid cross and not from monohybrid cross |
| Answer» Law of independent assortment. | |
| 123. |
After crossing two plants, the progenies are found to be male sterile. The phrnomenon is found to be maternally inherited and is due to some genes which reside inA. NucleusB. ChloroplastC. MitochondriaD. Cytoplasm |
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Answer» Correct Answer - D (d) Cytoplasmic inheritance is due to extranuclear genes present in mitochondria and chloroplasts. These genes do not follow Mendelian inheritance. |
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| 124. |
Plasmids so found in bacteria isA. Extra nuclear DNAB. Food particlesC. Deas protoplasmic partsD. None of these |
| Answer» Correct Answer - A | |
| 125. |
Besides activating the egg, another role of a sperm is to carry to eggA. RNAB. MitochondriaC. DNAD. Ribosomes |
| Answer» Correct Answer - C | |
| 126. |
Sickle cell anemia is an example of (i) Menedelian disorder (ii) Genetic disorder (iii) Chromosomal disorder (iv) Inborn error of metabolism (v) Point mutation (vi) Frame-Shift mutation (vii) Sex-linked disease (viii) Recessive disorder (ix) Qualitative disorder (x) Quantitative disorder (xi) Autosomal disorderA. i, ii, iv, v, viii, x, xiB. i, v, viii, ix, xiC. i, ii, v, viii, ix, xiD. ii, iii, v, vii, ix |
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Answer» Correct Answer - C Sickle cell anemia is an example of Mendelian disorder, genetic disorder, point mutation, recessive disorder, qualitative disorder and autosomal disorder. |
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| 127. |
The offspring produced from a mariiage have only O or A blood groups. Of the genotypes given below, the posiible genotypes of the parents would beA. `I^(A)I^(A) and I^(A)I^(O)`B. `I^(O)I^(O) and I^(O)I^(O)`C. `I^(A)I^(A) and I^(O)I^(O)`D. `I^(A)I^(O) and I^(O)I^(O)` |
| Answer» Correct Answer - D | |
| 128. |
In a dilhybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow (YY) and seed colour green (yy) weith seed shapewrikled (rr) the number of green colo0ured seeds (yy) among sixteen products of `F_(2)` generation will beA. 2B. 4C. 6D. 8 |
| Answer» Correct Answer - B | |
| 129. |
The genotypes of offspring in a gentic cross is called graphical reprwsrntion to calculate the probability of all possibleA. Pedigree analysisB. KaryotoyeC. Punett squareD. Chromosome map |
| Answer» Correct Answer - C | |
| 130. |
The graphical representation to calculate the probability of all possible genotypes of offspring in a genetic cross is calledA. Pedigree analysisB. Punnet squareC. Chromosome mapD. Genotypic ratio |
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Answer» Correct Answer - B The graphical representation to calculate the probability of all possible genotypes of offspring in a genetics cross is called punnet square. |
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| 131. |
A chromosome, in which the centromere is situated is situated close to its end so that one arm is very short and other vey long isA. AcroentricB. MetacentricC. Sub-metacentricD. Telecentric |
| Answer» Correct Answer - A | |
| 132. |
Explain the mechanism of sex determination in insects like Drosophila and grasshopper. |
| Answer» A large number of insects show XO type of sex determination while some of the sperms bear an X chromosome and other do not have an X chromosome becoomes female and thoses fertilized by sperms that lacks X chromosome becomes male. Rest of the chromosomes are named autosomes. In Drosophila melanogaslar and human beings, the male have XY chromosomes & females have XX chromosomes. | |
| 133. |
Plan an experiment and prepare a flow chart of the steps that you would follow to ensure that the seeds are formed only from the desired sets of pollen grains.Name the type of experiment that you carried out . ( b) Write the importance of such experimets. |
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Answer» (a) Through proces of artificial hydridization, desired seeds are obtained. `{:("Selection of flowers from desired plants."),(" "darr),("Anthers are removed (emasculation)"),(" "darr),("Emescalated flowers are covered with butter paper bags"),(" "darr),("Dusting of pollen grains on the stigma of emasculated, bagged flowers"),(" "darr),("Flowers are rebagged"),(" "darr),("Fruits are rebagged"),(" "darr),("Desired seeds are obtained"):}` (b) Importance of hybridization : (i) It helps in the production of commercially superior varieties of crops. (ii) It helps to produce hybrids. (ii) It helps to improve crop yield. |
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| 134. |
Mendel proposed something was being stably passed down unchanged from parents to offspring calledA. GenesB. GenotypeC. FactorsD. Alleles |
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Answer» Correct Answer - C Mendel proposed something was being stably passed down unchanged from parents to offspring called factors (now called genes). |
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| 135. |
Different forms of a gene located at the same locus of chromosomes are calledA. Multiple allelesB. PolygenesC. NucleusD. Chlorplast |
| Answer» Correct Answer - A | |
| 136. |
Genetic identity of human male is known byA. NucleolusB. Cell organellesC. AutosomesD. Sex chromosomes |
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Answer» Correct Answer - D Genetic identity of human male is known by sex chromosomes. |
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| 137. |
Genetic identity of a human male is determined byA. Sex-chromosomeB. Cell organellesC. AutosomeD. Nucleolous |
| Answer» Correct Answer - A | |
| 138. |
A female fruitfly heterozygous for sex linked genes is mated with normal male fruitfly mlae specific chromosome will enter the egg cells in proportion ofA. `3:1`B. `7:1`C. `1:1`D. `2:1` |
| Answer» Correct Answer - C | |
| 139. |
A fruit fly heterozygous for sex-linked genes, is mated with normal female fruit fly. Male specific chromosome will enter egg cell in the proportionA. `1 : 1`B. `2 : 1`C. `3 : 1`D. `7 : 1` |
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Answer» Correct Answer - A Genes which are present on sex chromosomes are called sex linked genes. Male Drosophila contains XY sex chromosome, while female contains XX-chromosomes. During gamete formation male produces 50% male specific gametes and 50% female specific gametes while female produces only one type of gametes, i.e. female specific. As male produces two types of gametes in equal proportion. There is an equal opportunity to getting a male or female offspring. |
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| 140. |
In a certain species of animal, genes T, U,V and W occur on the same chromosome.The following table give their crossover values (COVs) Which of the following option shows the appropriate order of the genes on the chromosomesA. V,W,T,UB. T,V,W,UC. T,W,U,VD. V,T,W,U |
| Answer» Correct Answer - D | |
| 141. |
In phenylketonuriaA. Break down of phenylatanine is rapidB. Accumulation of phenylalanine in bodyC. Chromosomes constitution of patient changesD. TSD gene situated on chromosomes 15 undergoes mutation |
| Answer» Correct Answer - B | |
| 142. |
How many types of gametes will be produced by a female Drosophilla having following arrangement of two genes (`y^(+)` and `w^(+)`) on X-chromosome ? A. 2B. 4C. 1D. 8 |
| Answer» Correct Answer - A | |
| 143. |
A polygenic trait is controlled by 3 genes A, B and C. In a cross AaBbCc `xx` AaBbCc, the phenotypic ratio of the offsprings was observed as : `1:6xx:20xx:6:1` what is the possibe value of x?A. 3B. 9C. 15D. 25 |
| Answer» Correct Answer - C | |
| 144. |
Crossing over in diploid organisms is responsible forA. Dominance of genesB. Linkage between genesC. Recombination of linked genesD. Segregation of alleles |
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Answer» Correct Answer - C Crossing over in diploid organisms is responsible for recombination of linked genes. |
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| 145. |
In a complimentary gene interaction calculate the number of phenotype and genotype produced in a cross AaBb `xx` aaBBA. 1 phenotype, 2 genotypesB. 2 phenotypes, 4 genotypesC. 4 phenotypes, 4 genotypesD. 2 phenotypes, 2 genotypes |
| Answer» Correct Answer - B | |
| 146. |
Number of phenotypes possible from AaBbCc `xx` AaBbCc isA. 16B. 9C. 8D. 27 |
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Answer» Correct Answer - C No. of phenotypes = `2^(n)` For trihybrid cross, n = 3 So, no. of phenotyes = `2^(3) = 8`. |
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| 147. |
Genotypic ratio of a dihybrid cross isA. `1:4:6:4:1`B. `9:3:3:1`C. `1:2:1`D. `1:2:2:4:1:2:1:2:1` |
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Answer» Correct Answer - D Genotypic ratio of a dihybrid cross is `1:2:2:4:1:2:1:2:1.` |
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| 148. |
Identify the pheonomenon in the following example- 'Sickle cell anaemia is an autosomal receissive trait. It is caused by the substituation of amoni acid glutamic acid (Glu) by vlaine (val at the sixt position of the beta globin of haemoglobin. This substituatio of amino acid occurs due to a phenomenon is which the sixth codon of beta globinc gene is. transformed from GAAG t GUG' |
| Answer» The phenomenon is point mutation that substituation of a single nitorgenuous base in DAN. | |
| 149. |
Male XX and female XY sometime occur due to :A. DeletionB. Transfer of segments in X and Y chromosomeC. AneuploidyD. Hormonal imbalance |
| Answer» Correct Answer - B | |
| 150. |
Human blood groups are example of aA. GradulismB. ClineC. Gradient of diplodiyD. Polymorphism |
| Answer» Correct Answer - D | |