InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which on the four couples chaiming tha baby with O+ blood type are possible the biological parents of it ?A. AB- and A+B. A+ and O-C. O+ and AB+D. B- and O- |
| Answer» Correct Answer - B | |
| 2. |
A couple believed that they have brought the wrong baby home from the hospital. The wife is of blood group O, her husband of group B and child of group O. could baby be theirs?A. chances are 50%B. chances are 100%C. chances are 25%D. chances are 75% |
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Answer» Correct Answer - A chances are 50% |
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| 3. |
In a hospital, on the same day-5 children were born to different couples. What is the probability of all 5 children being boys?A. `1//32`B. `1//16`C. `5//16`D. `5//32` |
| Answer» Correct Answer - A | |
| 4. |
An embryo resulting from the mating of two albino (recessive) rabbits is transplanted into the uterus of a brown rabbit. The phenoype of this transplant will most probably beA. brown theh white spotsB. allb rownC. white with brown spotsD. all white |
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Answer» Correct Answer - D all white |
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| 5. |
First child of a normal pigmented couple is albino. The possibility of a second child being an albino isA. 0.25B. 0.5C. 0.75D. 1 |
| Answer» Correct Answer - A | |
| 6. |
To a heterozygous curly (dominant) haired mother and straight haired father, 8 children are born. The ratio of curly and straight haired will beA. `6:2`B. `4:4`C. `2:6`D. `3:5` |
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Answer» Correct Answer - B `4:4` |
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| 7. |
On selfing a plant of `F_(1)`-generation with genotype "AaBbCC", the phenotypic ratio in `F_(2)`-generation will beA. `3:1`B. `1:1`C. `9:3:3:1`D. `27:9:9:9:3:3:3:1` |
| Answer» Correct Answer - A | |
| 8. |
A plant of `"F"_(1)` generation with genotype AABbCC. On selfing of this plant what is the phenotypic ratio in `"F"_(2)` generation?A. `1:1`B. `9:3:3:1`C. `1:2:1`D. `27:9:9:9:3:3:3:1` |
| Answer» Correct Answer - C | |
| 9. |
A cross of white eyed female and red eyed male drosophila gives red eyed females and white eyed males. Rarely this cross may give all white eyed females and red eyed males. This was found to be due toA. loss of a sex chromosomeB. non disjunction of X chromosomes in femaleC. mutation in female flyD. mutation in male fly |
| Answer» Correct Answer - B | |
| 10. |
A holandric gene in man causes hypertrichosis. When a man with hairy ears marrier a normal womanA. the percentage of their sons would be 100% to have hairy earB. half of daughters will have this traitC. ratio of hairy eared and normal child will be 1:2D. all correct |
| Answer» Correct Answer - A | |
| 11. |
Barr body in normal female is due to inactivation ofA. Maternally derived X chromsomeB. Paternally derived X chromosomeC. estra chromsomeD. either maternal or peternal X-chromosome |
| Answer» Correct Answer - A | |
| 12. |
If haploid number is 10, what would be the number of monosomic and tetrasomic conditionsA. 10,40B. 19,22C. 9,22D. 19,40 |
| Answer» Correct Answer - B | |
| 13. |
A male grasshopper will have a sex compliment ofA. XYB. XXC. XOD. YO |
| Answer» Correct Answer - C | |
| 14. |
Sex chromosomes are also calledA. allosomesB. heterosomesC. autosomesD. isochromosomes |
| Answer» Correct Answer - A | |
| 15. |
If husband and wife both are normal in vision but fathers of both were colour blind, the probabilityi of their first daughter to be colour blind isA. 1B. 0.5C. 0D. 0.25 |
| Answer» Correct Answer - C | |
| 16. |
Two crosses between the same pair of genotype or phenotypes in which the sources of the gametes are reversed in one cross, is known asA. back crossB. dihybrid crossC. test crossD. reciprocal cross |
| Answer» Correct Answer - D | |
| 17. |
Albinism is due to nonsynthesis (absence) of melanin on account of absence ofA. MelanaseB. luciferaseC. tyrosinaseD. lysine |
| Answer» Correct Answer - C | |
| 18. |
Which one of the following individuals can produce 16 different gametes?A. Aa Bb cc DdB. Aa Bb cc DD Ee FfC. Aa Bb Cc dd EE FFD. Aa Bb Cc DD Ee Ff |
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Answer» Correct Answer - B It is hexahybrid and, therefore, number f gametes are `(2)^(6)` but cc and DD are homozygous and hence number of gametes will be `(2)^(6-2)=(2)^(4)=16`. |
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| 19. |
A cross is made between `F_(1)` (that carries two heterozygous pairs of alleles of tall and red) and a full double recessive combination for these two genes (dwarf and white). The expected progency will haveA. all tall and redB. tall and red, tall and white, dwarf and white in 1:2:1 ratioC. tall and red: dwarf and white in 1:1 ratioD. tall and red: tall and white: dwarf and red: dwarf and white flowered plants in 1:1:1:1 ratio |
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Answer» Correct Answer - D tall and red: tall and white: dwarf and red: dwarf and white flowered plants in 1:1:1:1 ratio |
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| 20. |
If a homozygous tall pistillate plant is crossed with a dwarf staminate plant, the genotype of endosperm will beA. TTtB. ttTC. tttD. TTT |
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Answer» Correct Answer - A TTt |
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| 21. |
23 pairs of chromosomes can give rise to how many combinations?A. 8.6 millionsB. 7.6 millionC. 6.6 millionD. 5.6 million |
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Answer» Correct Answer - A `(2)^(n)`, where n=number of pairs of chromosome `=(2)^(23)=8.6` million. |
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| 22. |
Which one of the following generates new genetic combinations leading to variation ?A. Vegetative reproductionB. ParthenogenesisC. Sexual reproductionD. Nucellular polyembryony |
| Answer» Correct Answer - C | |
| 23. |
Blood group O is universal donor becauseA. it has rio antigen to clump with any antibody of recipientB. it has no antibody to clump with antigen of recipientC. both 1 and 2D. no definite answer is known |
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Answer» Correct Answer - A it has rio antigen to clump with any antibody of recipient |
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| 24. |
An individual heterozygous for two alleles (AaBb) produces two million sperms. How many of the sperms will have both recessive allelesA. 0.5 millionB. 1 millionC. 2 millionD. 0.25 million |
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Answer» Correct Answer - A The answeris 0.5 million |
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| 25. |
In which one of the following combinations (1-4) of the number of chromosomes is the present day hexaploid wheat correctly represented ?A. `{:("Combination","Mosomic","Haploid","Nullisomic","Trisomic"),(,21,28,42,43):}`B. `{:("Combination","Mosomic","Haploid","Nullisomic","Trisomic"),(,7,28,40,42):}`C. `{:("Combination","Mosomic","Haploid","Nullisomic","Trisomic"),(,21,7,42,43):}`D. `{:("Combination","Mosomic","Haploid","Nullisomic","Trisomic"),(,41,21,40,43):}` |
| Answer» Correct Answer - D | |
| 26. |
The blood of a person having group A can not be tranfused into a person of blood group B becauseA. donor has `beta`-antibodiesB. recipient has B-antigenC. both the theseD. donor has A-antigen and recipient has `alpha`-antibodies |
| Answer» Correct Answer - D | |
| 27. |
In Mirabilis, red flowered plant crossed with white flowered one resulted in all pink flowered plants. What are the chances of appearance of red flowered plant in a cross between pink and white flowered plant?A. ZeroB. 0.25C. 0.5D. 0.75 |
| Answer» Correct Answer - A | |
| 28. |
Telemere repetitive DNA sequences control the function of eukarote chromosomes because theyA. help chromosome pairingB. prevent chromosome lossC. act as repliconsD. are RNA transcription initiator |
| Answer» Correct Answer - B | |
| 29. |
In halpoids, both recessive and dominant limitations express themselves becauseA. there is single allele for each traitB. there are two alleles for each characterC. there are two genes for each characterD. there are many alleles for each trait |
| Answer» Correct Answer - A | |
| 30. |
Drosophila of plant kingdom isA. Arabidiopsis thalianaB. Aspergullus (green mould)C. MaizeD. All of the above |
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Answer» Correct Answer - A Arabidiopsis thaliana (cruciferae) is called Drosophila of plant kingdom. It is the first plant to have its entire genome sequenced. It is also known as wall cress, mouse-ear cress or thale cress. A big advantage of this plant in genetic studies is very small size of its genome. |
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| 31. |
Mendel failed to produce same result inA. Hieracium (Hawk weed)B. MangoC. DrosophilaD. None of the above |
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Answer» Correct Answer - A Hieracium shows parthenogenesis and, therefore, does not produce mendelian ratio. |
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| 32. |
Segregation of genes occurs inA. Embryo formationB. Anaphase IC. Anaphase IID. Metaphase II |
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Answer» Correct Answer - B Anaphase I |
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| 33. |
Mendel failed to get linkage becauseA. genes of seven types of traits selected by him were located on four different chromosomes and behaved independentlyB. genes selected by him were discrete and stableC. genes selected by him were located on seven non homologous chromosomesD. pea plant does not show linkage |
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Answer» Correct Answer - A genes of seven types of traits selected by him were located on four different chromosomes and behaved independently |
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| 34. |
Heterozygosity protects __________from elimination by natural selectionA. recessive allelesB. dominant allelesC. multiple factorsD. genomes |
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Answer» Correct Answer - A recessive alleles |
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| 35. |
Rh (-ve) person hasA. Rh antigens on RBCB. Rh antibodies in PlasmaC. Neither antigens nor antibodies of Rh factorD. both antigens and antibodies |
| Answer» Correct Answer - C | |
| 36. |
Which of the following disorder shows Criss-cross inheritance ?A. HaemophiliaB. ThalassemiaC. Erythroblastosis foetalisD. None of these |
| Answer» Correct Answer - A | |
| 37. |
Females are heterogametic amongstA. human beingsB. drosophilaC. both 1 and 2D. birds |
| Answer» Correct Answer - D | |
| 38. |
Slight difference in identical twins support the hypothesis thatA. dominance may be incompleteB. single gene may produce multiple effectC. the expression of genetic character is affected by environmentD. they developed from separate fertilized eggs |
| Answer» Correct Answer - C | |
| 39. |
The type of inheritance shown by Mendel in pea is:-A. monogenic inheritanceB. polygenic inheritanceC. quantitative inheritanceD. cytoplasmic inheritance |
| Answer» Correct Answer - A | |
| 40. |
Aneuploidy arises throughA. disjunctionB. nondisjunctionC. inversionD. duplication |
| Answer» Correct Answer - B | |
| 41. |
In Bugs, cockroach and roundworms, the males possessA. one chromosome less than the femaleB. two similar sex chromosomesC. one chromosome different from restD. a Y-chromosome |
| Answer» Correct Answer - A | |
| 42. |
Father of experimental genetics isA. MendelB. Hugo de ,VriesC. MorganD. Archibald garrod |
| Answer» Correct Answer - C | |
| 43. |
ZO-ZZ type of sex determination isA. opposite of XX-XO typeB. opposite of XX-XYC. opposite of ZZ-ZN typeD. gynander |
| Answer» Correct Answer - A | |
| 44. |
Antiserum used is testing blood groups hasA. antibodiesB. antigensC. leucocytesD. RBCs |
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Answer» Correct Answer - A antibodies |
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| 45. |
Agglutiongens are found inA. blood plasmaB. RBC surfaceC. WBCD. platelets |
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Answer» Correct Answer - B RBC surface |
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| 46. |
The grandsons of a colour blind male through daughter having the following probability of being colour blind is |
| Answer» Correct Answer - B | |
| 47. |
A woman has haemophilic brother and normal parents. She wants to marry a man who has no history of haemophila in his family. What is the possibility of her children having this diseaseA. 50% of the sons may be haemophilicB. 50% of the total generation will be haemophilicC. all will be haemophilicD. none of them will be haemophilic |
| Answer» Correct Answer - A | |
| 48. |
Another mutation occurring in an already mutated gene gives rise toA. multiple genesB. multiple allelesC. polygenesD. pleiotropic genes |
| Answer» Correct Answer - A | |
| 49. |
Turner syndrome is caused byA. autosomal AneuploidyB. sex chromosome aneuploidyC. polyploidyD. trisomy |
| Answer» Correct Answer - B | |
| 50. |
Genetic constitution of Klinefelter syndrome isA. 44+XXXB. 44+XOC. 42+XXXD. 44+XX |
| Answer» Correct Answer - A | |