InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If in solution containing `Cl^(-) & Bt^(-)` ions, `AgNO_(3)` is added then initial precipitate of which colour will be formed ? |
| Answer» Correct Answer - Yellow | |
| 2. |
The ion most difficult to removes as precipitate isA. `Ag^(+)`B. `NH_(4)^(+)`C. `Fe^(+2)`D. `Co^(+2)` |
| Answer» Correct Answer - B | |
| 3. |
If silver nitrate solution is added to a salt solution and a yellow precipitate is obtained the salt may containA. `Br^(-)`B. `l^(-)`C. `Cl^(-)`D. `F^(-)` |
| Answer» Correct Answer - A::B | |
| 4. |
In the fifth group, `(NH_4)_2 CO_3` is added to precipitate out the carbonates, we do not add `Na_2 CO_3` becauseA. `MgCO_(3)` is soluble in `Na_(2)CO_(3)`B. `Na_(2)CO_(3)` increases the solubility of fifth group carbonatesC. `MgCO_(3)` will also be precipitated out in fifth groupD. `Na_(2)CO_(3)` will decrease the solubility product of `MgCO_(3)` |
| Answer» Correct Answer - C | |
| 5. |
The compound responsible for deep yellow colour isA. `FeCl_(3)`B. `CoCl_(3)`C. `MnCl_(2)`D. `NaCl` |
| Answer» Correct Answer - A | |
| 6. |
The compound responsible for red colour isA. `Fe(SCN)_(3)`B. `Co(CNS)_(6)^(-4)`C. `Mn(CNS)_(6)^(-4)`D. `NaSCN` |
| Answer» Correct Answer - A | |
| 7. |
A black mineral (A) on heating in presence of air gives a gas (B). The mineral (A) on reaction with dilute `H_(2)SO_(4)` gives a gas (C) and a solution of a compound (D) on passing the gas (C) into an aqueous solution of (B), a white turbidity is obtained. The aqueous solution of (D) on reaction with potassium ferricyanide gives a blue compound (E). Identify (A) to (E) and give chemical equations for the reaction involved. |
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Answer» `ArarrFeS` `B rarr SO_(2)` `C rarr H_(2)S` `D rarr FeSO_(4)` `E rarr KFe [Fe(CN)_(6)]` |
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| 8. |
The compound A may beA. `FeSO_(4)`B. `CoSO_(4)`C. `MnSO_(4)`D. `Na_(2)S_(2)O_(7)` |
| Answer» Correct Answer - A | |
| 9. |
A compound (X) on heating with an excess of NaOH solution gives a gas (Y) which gives white fumes on exposure to HCl. Heating is continued to expel the gas completely. The resultant alkaline solution again liberates the same gas (Y) when heated with Zn powder. However, when the compound (X) is heated alone does not give nitrogen. Identify (X) and (Y). |
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Answer» `X rarr NH_(4)NO_(3)` `Y rarr NH_(3)` `underset((X))(NH_(4)NO_(3)) overset(NaOH)rarr NaNO_(3)+underset((Y))(NH_(3))+H_(2)O` `NH_(3)+HCl rarr NH_(4)Cl uarr "(white fumes)"` `NH_(4)NO_(3) overset(Delta)rarr N_(2)O+2H_(2)O` |
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| 10. |
Which of the following compound will not turn black on adding `NH_(4)OH` to it ?A. `ZnSO_(4)`B. `Hg_(2)Cl_(2)`C. `AgCl`D. `CuSO_(4)` |
| Answer» Correct Answer - A::C::D | |
| 11. |
The gas C may beA. `SO_(2)`B. `CO_(2)`C. `Cl_(2)`D. `H_(2)S` |
| Answer» Correct Answer - D | |
| 12. |
Which among the following will be soluble in excess of `NaOH`?A. `FeCl_(3)`B. `CrCl_(3)`C. `AlCl_(3)`D. `ZnCl_(2)` |
| Answer» Correct Answer - C::D | |
| 13. |
A colourless water soluble solid (X) on heating gives equimolar quantities of (Y) and (Z). Y gives dense white fumes with HCl and Z does so with `NH_(3)`. Y gives brown ppt. with `K_(2)Hgl_(4)` (Nesslers reagent) and Z gives white precipitate with nitrates of `Ag^(+), Pb^(2+) and Hg^(+)`. What is X ? |
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Answer» Y is `NH_(3)` and Z is HCl Hence X must be `NH_(4)Cl` `underset((X))(NH_(4)Cl)overset("Heat")rarr underset((Y))(NH_(3))+underset((Z))(HCl)` |
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| 14. |
The salt A may beA. `MnSO_(4)`B. `ZnS`C. `CuSO_(4)`D. `Al_(2)(SO_(4))_(3)` |
| Answer» Correct Answer - B | |
| 15. |
Which of the following sulphates are soluble in water?A. `CuSO_(4)`B. `PbSO_(4)`C. `Ag_(2)SO_(4)`D. `BaSO_(4)` |
| Answer» Correct Answer - A::C | |
| 16. |
STATEMENT - 1 : `SO_(2)` turns acidified `K_(2)Cr_(2)O_(7)` green. AndSTATEMENT - 2 : `SO_(2)` converts `Cr_(2)O_(7)^(2-)` ion to `Cr^(+3)` which gives green colour.A. Statement-1 is True, Statement-2, is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2, is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 17. |
Which among the following sulphates is insoluble in water ?A. `CuSO_(4)`B. `CdSO_(4)`C. `PbSO_(4)`D. `Bi_(2)(SO_(4))_(3)` |
| Answer» Correct Answer - C | |
| 18. |
Which of the following salts will not give borax bead test ?A. `Al(NO_(3))_(3)`B. `CoCl_(2)`C. `CoC_(2)O_(4)`D. `K_(2)C_(2)O_(4)` |
| Answer» Correct Answer - A::D | |
| 19. |
Concentrated HCl cannot be used as group reagent in first group precipitation. Why ? |
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Answer» The conc. HCl is avoided because ions in high concentration increases the solubility of precipitate of group I chlorides through the formation of soluble complex ions `AgCl+2Cl^(-) rarr AgCl_(3)^(2-)` `PbCl_(2)+2Cl^(-) rarr PbCl_(4)^(2-)` |
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| 20. |
A solid laboratory reagent (A) give following reactions. (i) It impart green colour of flame : (ii) Its solution does not give ppt. on passong `H_(2)S`. (iii) When it is heated with `K_(2)Cr_(2)O_(7)` and conc. `H_(2)SO_(4)`, a red gas (B) is evolved. The gas when passed in aq. NaOH solution turns it yellow (C). Identify (A), (B), (C) giving chemical reactions. |
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Answer» `A rarr BaCl_(2)` `B rarr CrO_(2)Cl_(2)` `C rarr Na_(2)CrO_(4)` |
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| 21. |
Match the following `{:(" Column I"," Column II"),("(A) "FeSO_(4)overset(Delta)rarr,"(p) A gas which gives green colour with acidified "K_(2)Cr_(2)O_(7)),("(B) "NaNO_(2)overset(dil)rarrA"(gas)" overset(air)rarrB" (gas)","(q) A gas which form oleum with "H_(2)SO_(4)),("(C) "Na_(2)SO_(3)overset(dil(HCl))rarrP" (gas)","(r) A gas which is mixed anhydride of "HNO_(2) and NHO_(3)),("(D) "NaCl overset(conc. H_(2)SO_(4))rarrP" (gas)","(s) A gas which is also given by "AlCl_(3)" in moist air"),(,"(t) Green colour"):}` |
| Answer» Correct Answer - A(p, q, t), B(r), C(p, t), D(s) | |
| 22. |
Which of the following will not give positive chromyl chloride test?A. `CuCl_(2)`B. `HgCl_(2)`C. `ZnCl_(2)`D. `C_(6)H_(5)NH_(3)^(+)Cl^(-)` |
| Answer» Correct Answer - B | |
| 23. |
Hydrogen sulphide is not a group reagent for (basic radical)A. `2^(nd)` group radicalsB. `3^(rd)` group radicalsC. `4^(th)` group radicalsD. `5^(th)` group radicals |
| Answer» Correct Answer - B::D | |
| 24. |
`FeCl_(3)` is acidic towards litmus. On treatment with excess of `NH_(4)SCN` it gives red coloured compound (A) and on treatment with excess of `K_(2)Cr_(2)O_(7)` in the presence of conc. `H_(2)SO_(4)`, it evolves deep red vapours of (B) on passing the vapours of (B) into `NaOH`, then adding a solution of acetic acid and lead acetate it gives yellow ppt. of compound of chromium (C) What is the hybridisation of chromium in compound (C) ?A. `sp^(3)d`B. `sp^(3)`C. `dsp^(2)`D. `sp^(2)` |
| Answer» Correct Answer - B | |
| 25. |
`FeCl_(3)` is acidic towards litmus. On treatment with excess of `NH_(4)SCN` it gives red coloured compound (A) and on treatment with excess of `K_(2)Cr_(2)O_(7)` in the presence of conc. `H_(2)SO_(4)`, it evolves deep red vapours of (B) on passing the vapours of (B) into `NaOH`, then adding a solution of acetic acid and lead acetate it gives yellow ppt. of compound of chromium (C)The compound B isA. `NO_(2)`B. `Br_(2)`C. `CrO_(2)Cl_(2)`D. `CrOCl_(4)` |
| Answer» Correct Answer - C | |
| 26. |
`PbCl_(2)+Klrarr underset("Yellow ppt")([A])+KCl` `underset("Yellow ppt")([A])+underset("excess")(Kl) rarr underset("Soluble")([B])` Compound [A] and [B] areA. `Pbl_(4) and K_(2)[Pbl_(4)]` respectivelyB. `K_(2)[Pbl_(4)] and Pbl_(4)` respectivelyC. `Pbl_(2) and K_(2)[Pbl_(4)]` respectivelyD. `Pbl_(2) and K_(2)[Pbl_(2)]` respectively |
| Answer» Correct Answer - C | |
| 27. |
Which of the following radicals evolve gas or vapour when treated with dil HCl?A. `SO_(3)^(2-)`B. `C_(2)O_(4)^(2-)`C. `CH_(3)COO^(-)`D. `HCO_(3)^(-)` |
| Answer» Correct Answer - A::C::D | |
| 28. |
Match the complex with its oxidation state of central metal `{:(" Column I"," Column II"),("(A) Chromyl chloride test","(p) "S^(2-)),("(B) Ring test","(q) "NO_(3)^(-)),("(C) Smell of vinegar","(r) "CH_(3)COO^(-)),("(D) Smell of rotten eggs","(s) "Cl^(-)):}` |
| Answer» Correct Answer - A(s), B(q), C(r), D(p) | |
| 29. |
STATEMENT - 1 : `H_(2)S` in acidic medium is the group reagent for `II^(nd)` group in basic radical. STATEMENT - 2 : `K_(sp)` of suphides of `II^(nd)` group ions is less. STATEMENT - 3 : All sulphides of `II^(nd)` group element are coloured.A. FTFB. TTTC. FFFD. TTF |
| Answer» Correct Answer - B | |
| 30. |
During detection of P we get canary yellow ppt on addition of ammonium molybdate. The number of element in `sp^(3)` hybridisation from `15^(th)` group is ______________. |
| Answer» Correct Answer - 4 | |
| 31. |
STATEMENT - 1 : All `Pb^(+2)` form white ppt with dil. HCl in estimation. STATEMENT - 2 : `Al^(+3)` form white ppt with `NH_(4)OH//NH_(4)Cl`. STATEMENT - 3 : `Fe(OH)_(3)` is soluble in excess `NaOH`.A. TTFB. TTTC. FTTD. FTF |
| Answer» Correct Answer - C | |
| 32. |
Match the Following : `{:(" Column I"," Column II"),(" (Addition of dil. HCl/dil "H_(2)SO_(4)")"," (Observation)"),("(A) "S_(2)O_(3)^(2-),"(p) Gas evolved turns lime water milky"),("(B) "SO_(3)^(2-),"(q) Gas turns lead acetate paper black"),("(C) "CO_(3)^(2-),"(r) Gas turns acidified "K_(2)Cr_(2)O_(7)" solution green"),("(D) "S^(2-),"(s) Gives white turbidity"):}` |
| Answer» Correct Answer - A(p, r, s), B(p, r), C(p), D(q, r) | |
| 33. |
The brown ring complex compound is formulated as `[Fe(H_(2)O)_(5)NO]SO_(4)`. The oxidation state of `Fe` isA. `+1`B. `+2`C. `+3`D. `+4` |
| Answer» Correct Answer - A | |
| 34. |
STATEMENT - 1 : `NaNO_(2)` on treatment with dil. HCl gives brown coloured gas directly. STATEMENT -- 2 : `[Fe(CN)_5NO]^(+2)` is used for the detection of of `S^(-2)`. STATEMENT - 3 : Precipitate of Agl are of yellow colourA. FTFB. FTTC. TTFD. TTT |
| Answer» Correct Answer - B | |
| 35. |
STATEMENT - 1 : CdS and `As_(2)S_(3)` are coloured compounds. and STATEMENT - 2 - : CdS and `As_(2)S_(3)` can be separated by ammonium sulphide.A. Statement-1 is True, Statement-2, is True, Statement-2 is a correct explanation for Statement-3B. Statement-1 is True, Statement-2, is True, Statement-2 is NOT a correct explanation for Statement-3C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - B | |
| 36. |
How can you distinguish between (i) `CO_(3)^(-2) and SO_(3)^(-2)` ions? (ii) `NO_(3)^(-)` ion and `NO_(2)^(-)` ion ? |
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Answer» (i) Sulphite ion `(SO_(3)^(-2))` will give `SO_(2)` gas which converts orange coloured `K_(2)Cr_(2)O_(7)` solution into green. Carbonate `(CO_(3)^(-2))` will give `CO_(2)` gas which do not given green colour with `K_(2)Cr_(2)O_(7)` solution. (ii) `NO_(2)^(-)` gives brown `NO_(2)` gas with dil. and acid but `NO_(3)^(-)` does not. |
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| 37. |
Complete the following reaction. (i) `CaCO_(3) overset(Delta)rarr [A]+underset("gas")([B])` (ii) `[A]+H_(2)O rarr [C]` (iii) `[C]+[B] rarr CaCO_(3)+H_(2)O` (iv) `NH_(4)Cl+[C] overset(Delta)rarr underset("gas")([E])+CaCl_(2)+H_(2)O` (v) `E+H_(2)O+[B]rarr[F]` (vi) `NaCl+[F]rarr [G]+NH_(4)Cl` (vii) `[G] overset(Delta)rarr Na_(2)CO_(3)+H_(2)O+[B]` |
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Answer» (i) `CaCO_(3)overset(Delta)rarr underset((A))(CaO)+underset((B))(CO_(2))` (ii) `underset((A))(CaO)+H_(2)O rarr underset((C))(Ca(OH)_(2))` (iii) `Ca(OH)_(2)+CO_(2) rarr CaCO_(3) darr +H_(2)O` (iv) `2NH_(4)Cl+underset((C))(Ca(OH)_(2)) overset(Delta)rarr underset((E))(2NH_(3))+CaCl_(2)+2H_(2)O` (v) `underset((E))(NH_(3))+H_(2)O+underset((B))(CO_(2))rarr underset((F))(NH_(4)HCO_(3))` (vi) `NaCl+underset((F))(NH_(4)HCO_(3))rarr underset((G))(NaHCO_(3))+underset((D))(NH_(4)Cl)` (vii) `2NaHCO_(3) overset(Delta) rarr Na_(2)CO_(3)+H_(2)O+underset((B))(CO_(2))` |
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| 38. |
A salt which gives `CO_2` with hot `H_2 SO_4` and also decolourizes acidified `KMnO_4` on warming isA. `HCO_(3)^(-)`B. `CO_(3)^(2-)`C. Oxalate ionD. Acetate ion |
| Answer» Correct Answer - C | |
| 39. |
The brown ring test for `NO_(3)^(-)` is due to the formation of the complex ion with formulaA. `[Fe(H_(2)O)_(6)]^(2+)`B. `[Fe(NO(CN)_(5)]^(2-)`C. `[Fe(H_(2)O)_(5)NO]^(2+)`D. `[Fe(H_(2)O)(NO)_(5)]^(2+)` |
| Answer» Correct Answer - C | |