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1.

What is the probability of being elder than 35 years of age and having at least one accident?(a) 0.41(b) 0.25(c) 0.354(d) 0.333This question was posed to me in an online quiz.This key question is from Probability & Experimental Approach in division Probability of Mathematics – Class 9

Answer»

The correct answer is (c) 0.354

To explain I would say: We can SEE that total number of events of being elder than 35 YEARS of age and having at least 1 ACCIDENT = 277 + 78 + 118 + 59

= 532

Total number of events = 1500

Hence, probability of being 18-29 years of age and having more than 1 accidents = \(\frac{532}{1500}\)

= 0.354.

2.

What is the probability of being 18-35 years of age and having more than 1 accidents?(a) 0.06(b) 0.6(c) 0.08(d) 0.1I have been asked this question in my homework.Asked question is from Probability & Experimental Approach in section Probability of Mathematics – Class 9

Answer»

Correct choice is (a) 0.06

For explanation I would SAY: We can SEE that total NUMBER of events of being 18-35 years of age and having more than 1 accidents = 90

Total number of events = 1500

Hence, PROBABILITY of being 18-35 years of age and having more than 1 accidents = \(\frac{90}{1500}\)

= 0.06.

3.

What is the probability of being 35-50 years of age and having more no accidents?(a) 0.29(b) 0.35(c) 0.09(d) 0.08I got this question during a job interview.This key question is from Probability & Experimental Approach in division Probability of Mathematics – Class 9

Answer»

The CORRECT option is (a) 0.29

Best explanation: We can see that TOTAL number of events of being 35-50 years of age and having more than 1 ACCIDENTS = 145

Total number of events = 1500

Hence, probability of being 18-29 years of age and having more than 1 accidents = \(\frac{145}{1500}\)

= 0.29.

4.

What is the probability that the student has scored more than 80?(a) 0.6(b) 0.8(c) 0.4(d) 0.5The question was asked by my school teacher while I was bunking the class.This is a very interesting question from Probability & Experimental Approach in division Probability of Mathematics – Class 9

Answer»

The correct ANSWER is (a) 0.6

Explanation: It can be SEEN that the student have scored 3 out of 5 TIMES more than 80 marks.

Therefore, probability that the student has scored more than 80 = \(\frac{number \,of \,occurrence \,of \,EVENT}{Total \,number \,of \,trials}\)

= \(\frac{3}{5}\)

= 0.6.

5.

What is the probability of getting ‘4’ as outcome?(a) 0.16(b) 0.158(c) 0.156(d) 0.131This question was addressed to me in a job interview.My query is from Probability & Experimental Approach in division Probability of Mathematics – Class 9

Answer»

Correct option is (d) 0.131

For explanation I would say: We can see from the table that we get ‘4’ 79 times out of 500 trials.

Therefore, PROBABILITY of getting ‘4’ as outcome = \(\FRAC{EVENT \,of \,occurence \,of \,getting \,’4′}{Total \,NUMBER \,of \,trials}\)

= \(\frac{79}{500}\)

= 0.158.

6.

What is the probability that the family has at least one boy?(a) 0.415(b) 0.270(c) 0.73(d) 0.315The question was asked by my school principal while I was bunking the class.The origin of the question is Probability & Experimental Approach topic in portion Probability of Mathematics – Class 9

Answer»

Right option is (c) 0.73

The EXPLANATION: In this case, having at LEAST ONE boy means one boy or two boys.

Hence, number of families having at least one boy = 415 + 315 = 730

Therefore, the probability that the FAMILY has at least one boy = \(\frac{number \,of \,families \,having \,at \,least \,one \,boy }{Total \,number \,of \,families} = \frac{730}{1000}\)

= 0.73.