Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Linked QuestionA low carbon steel bar of 147mm diameter with a length of 630mm is being turned with an uncoated carbide insert. The observed tool lives are 24min and 12min for cutting velocities of 90m/min and 120m/min respectively. The feed and depth of cut are 0.2mm/rev and 2mm respectively. Use the unmachined diameter to calculate the cutting velocity.When tool life is 20min the cutting velocity in m/min is

Answer»

Linked Question

A low carbon steel bar of 147mm diameter with a length of 630mm is being turned with an uncoated carbide insert. The observed tool lives are 24min and 12min for cutting velocities of 90m/min and 120m/min respectively. The feed and depth of cut are 0.2mm/rev and 2mm respectively. Use the unmachined diameter to calculate the cutting velocity.



When tool life is 20min the cutting velocity in m/min is



2.

A tool with side cutting edge angle of 30o and end cutting edge angle 10o is used for fine turning with a feed of 1mm/rev. Neglectign nose redius of the tool, the maximum (peak of valley) height of the surface roughness produced will be

Answer»

A tool with side cutting edge angle of 30o and end cutting edge angle 10o is used for fine turning with a feed of 1mm/rev. Neglectign nose redius of the tool, the maximum (peak of valley) height of the surface roughness produced will be

3.

A hemispherical cup of radius R is formed in a press-working operation. The radius of blank would be

Answer»

A hemispherical cup of radius R is formed in a press-working operation. The radius of blank would be

4.

A bar of 75 mm diameter is machined to reduce its diameter by orthogonal cutting. If the length of the cut chip is 73.5 mm and rake angle is 15∘, the shear plane angle is

Answer»

A bar of 75 mm diameter is machined to reduce its diameter by orthogonal cutting. If the length of the cut chip is 73.5 mm and rake angle is 15, the shear plane angle is

5.

A single-point cutting tool with 12o rake angle is used to machine a steel work-piece. The depth of cut, i.e., uncut thickness is 0.81mm. The chip thickness under orthogonal machining condition is 1.8mm. The shear angle is approximately.

Answer»

A single-point cutting tool with 12o rake angle is used to machine a steel work-piece. The depth of cut, i.e., uncut thickness is 0.81mm. The chip thickness under orthogonal machining condition is 1.8mm. The shear angle is approximately.

6.

A specimen is being grinded on a surface grinder with grinding wheel speed of 1600 m/min, and workpiece speed of 25 mm/min, grinding wheel diameter of 200 mm, grinding depth of cut of 0.025 mm. Take transverse feed of workpiece = 4.4 mm/pass and specific cutting energy = 2200J/mm3. Assume that pitch of grits at periphery of grinding wheel is 12 mm, the factor for negative rake angle of abrasive grains as 5. Mean grinding power in above operation will be___kW0.504

Answer» A specimen is being grinded on a surface grinder with grinding wheel speed of 1600 m/min, and workpiece speed of 25 mm/min, grinding wheel diameter of 200 mm, grinding depth of cut of 0.025 mm. Take transverse feed of workpiece = 4.4 mm/pass and specific cutting energy = 2200J/mm3. Assume that pitch of grits at periphery of grinding wheel is 12 mm, the factor for negative rake angle of abrasive grains as 5. Mean grinding power in above operation will be___kW
  1. 0.504
7.

Linked Data:In a orthogonal cutting experiment, an HSS tool having the following tool signature in the orthogonal reference system (ORS) has been used : 0−10−7−710−75−1Given: Width of cut =3.6mm Shear strength of workpiece material =460N/mm2; Depth of cut =0.25mm Coefficient of friction at chip tool interface =0.7Minimum power requirement (in kW) at a cutting speed of 150m/mm is

Answer»

Linked Data:

In a orthogonal cutting experiment, an HSS tool having the following tool signature in the orthogonal reference system (ORS) has been used : 0107710751

Given: Width of cut =3.6mm Shear strength of workpiece material =460N/mm2; Depth of cut =0.25mm Coefficient of friction at chip tool interface =0.7



Minimum power requirement (in kW) at a cutting speed of 150m/mm is



8.

Determine the load required to punch a 20mm diameter hole in a 2mm thick sheet. The properties of the material of the sheet are:Tensile strength −580MPaYield strength in tension −410MPaShear strength −350MPaYield strength in shear −250MPaThe load is kN is

Answer»

Determine the load required to punch a 20mm diameter hole in a 2mm thick sheet. The properties of the material of the sheet are:

Tensile strength 580MPa

Yield strength in tension 410MPa

Shear strength 350MPa

Yield strength in shear 250MPa

The load is kN is

9.

A single point cutting tool with 0° rake angle is used in an orthogonal machining process. At a cutting speed of 180 m/min, the thrust force is 490 N. If the coefficient of friction between the tool and the chip is 0.7, then the power consumption (in kW) for the machining operation is 2.1

Answer» A single point cutting tool with 0° rake angle is used in an orthogonal machining process. At a cutting speed of 180 m/min, the thrust force is 490 N. If the coefficient of friction between the tool and the chip is 0.7, then the power consumption (in kW) for the machining operation is
  1. 2.1
10.

A workpiece of 100cm length and 30cm width is machined by planning operation with a feed of 0.3mm/stroke. The machine tool executes 10 double strokes per minute. The planning time for a single pass is

Answer»

A workpiece of 100cm length and 30cm width is machined by planning operation with a feed of 0.3mm/stroke. The machine tool executes 10 double strokes per minute. The planning time for a single pass is

11.

Common Data QuestionA cup is to be drawn to a diameter of 70mm with 35mm depth from a 0.5mm thick sheet metal. The cup is drawn in one operation. Assume σu=430MPaThe required blank diameter is

Answer»

Common Data Question

A cup is to be drawn to a diameter of 70mm with 35mm depth from a 0.5mm thick sheet metal. The cup is drawn in one operation. Assume σu=430MPa



The required blank diameter is

12.

The following data relate to an orthogonal turning process: back rake angle =15deg. width of cut =2mm chip thickness =0.4mm feed rate =0.2mm/revThe shear angle is

Answer»

The following data relate to an orthogonal turning process: back rake angle =15deg. width of cut =2mm chip thickness =0.4mm feed rate =0.2mm/rev



The shear angle is

13.

Linked Data:Blind hole 10mm diameter, 50mm deep are being drilled in steel block, drilling spindle speed is 600rpm, feed 0.2mm/rev, point angle of drill is 120During the above operation, the drill wears out after producing 200 holes.Taylor's tool life equation is of the form VT0.3=C, where V= cutting speed in m/min and T= tool life in min. Taylor's constnat C will be

Answer»

Linked Data:

Blind hole 10mm diameter, 50mm deep are being drilled in steel block, drilling spindle speed is 600rpm, feed 0.2mm/rev, point angle of drill is 120



During the above operation, the drill wears out after producing 200 holes.Taylor's tool life equation is of the form VT0.3=C, where V= cutting speed in m/min and T= tool life in min. Taylor's constnat C will be



14.

An orthogonal turning operation is being carried out under the following conditions: The velocity of the tool relative to the workpiece is 3 m/sec, feed = 0.5 mm, chip thickness = 0.6 mm, The velocity of the chip relative to the tool is_________ m/sec. 2.5

Answer» An orthogonal turning operation is being carried out under the following conditions: The velocity of the tool relative to the workpiece is 3 m/sec, feed = 0.5 mm, chip thickness = 0.6 mm, The velocity of the chip relative to the tool is_________ m/sec.
  1. 2.5
15.

In orthogonal machining operation, the chip thickness and the uncut chip thickness are equal to 0.45mm. If the tool rake and is 0 deg. The shear plane angle is

Answer»

In orthogonal machining operation, the chip thickness and the uncut chip thickness are equal to 0.45mm. If the tool rake and is 0 deg. The shear plane angle is

16.

Linked Data:During orthogonal machining of a mild steel specimen with a cutting tool of zero rake angle, the following data is obtained:Uncut chip thickness =0.25mmChip thickness =0.75mmNormal force =950Nthrust force =475NThe shear angle and shear force, respectively, are

Answer»

Linked Data:

During orthogonal machining of a mild steel specimen with a cutting tool of zero rake angle, the following data is obtained:

Uncut chip thickness =0.25mm

Chip thickness =0.75mm

Normal force =950N

thrust force =475N



The shear angle and shear force, respectively, are

17.

Linked Data:A ϕ40mm job is subjected to orthogonal turning by a+10o rake angle tool at 500rev/min. By direct measurement during the cutting operation, the shear angle was found equal to 25oIf the friction angle at the tool chip interface is 58o10′ and the cutting force components measured by a dynamometer are 600N and 200N the power loss due to friction (in kNm/min) is approximately

Answer»

Linked Data:

A ϕ40mm job is subjected to orthogonal turning by a+10o rake angle tool at 500rev/min. By direct measurement during the cutting operation, the shear angle was found equal to 25o



If the friction angle at the tool chip interface is 58o10 and the cutting force components measured by a dynamometer are 600N and 200N the power loss due to friction (in kNm/min) is approximately



18.

In a shaping process, the number of double strokes per minute is 30 and the quick return ratio is 0.6. If the length of the stroke is 250mm the average cutting velocity in mm/min.

Answer»

In a shaping process, the number of double strokes per minute is 30 and the quick return ratio is 0.6. If the length of the stroke is 250mm the average cutting velocity in mm/min.

19.

The main cutting force acting on a tool during the turning (orthogonal cutting) operation of metal is 400N. The turning was performed using 2mm depth of cut and 0.1mm/rev feed rate. The specific cutting pressure (in N/mm2) is

Answer»

The main cutting force acting on a tool during the turning (orthogonal cutting) operation of metal is 400N. The turning was performed using 2mm depth of cut and 0.1mm/rev feed rate. The specific cutting pressure (in N/mm2) is

20.

During orthogonal cutting of MS with a 10deg rake angle tool, the chip thickness ratio was obtained as 0.4. The shear angle (in degrees) evaluated from this data is

Answer»

During orthogonal cutting of MS with a 10deg rake angle tool, the chip thickness ratio was obtained as 0.4. The shear angle (in degrees) evaluated from this data is

21.

In a AJM process, if Q= flow rate of abrasives and d = mean diameter of the abrasives, then MRR is proportional to

Answer»

In a AJM process, if Q= flow rate of abrasives and d = mean diameter of the abrasives, then MRR is proportional to

22.

Estimate the MRR (in cc/sec) of an alloy containing 18% cobalt. 62% nickel and 20% chromium during ECM with current of 500 ampere. The density of the alloy is 8.28 g/cc. The following date is available. Metal Gram atomic weight Velency Cobalt 58.93 2 Nickel 58.71 2 Chromium 51.99 6 Assume Faraday's constant is 96500 coulombs/mole.0.0124

Answer» Estimate the MRR (in cc/sec) of an alloy containing 18% cobalt. 62% nickel and 20% chromium during ECM with current of 500 ampere. The density of the alloy is 8.28 g/cc. The following date is available.























Metal Gram atomic weight Velency
Cobalt 58.93 2
Nickel 58.71 2
Chromium 51.99 6

Assume Faraday's constant is 96500 coulombs/mole.
  1. 0.0124
23.

In an orthogonal metal cutting process are given belowChip thickness = 0.8 mmUndeformed thickness = 0.6 mmRake angle = 15oCutting speed = 2.5 m/sMean thickness of primary shear zone 25 microns then the shear strain rate is (s−1) during the process is

Answer»

In an orthogonal metal cutting process are given below



Chip thickness = 0.8 mm

Undeformed thickness = 0.6 mm

Rake angle = 15o

Cutting speed = 2.5 m/s



Mean thickness of primary shear zone 25 microns then the shear strain rate is (s1) during the process is

24.

In an orthogonal cutting test on mild steel, the following data were obtainedCutting speed : 40m/minDepth of cut : 0.3mmTotal rake angle : +5oChip thickness : 1.5mmCutting force : 900NThrust force : 450NUsing Merchant's analysis, the friction angle during the machining will be

Answer»

In an orthogonal cutting test on mild steel, the following data were obtained

Cutting speed : 40m/min

Depth of cut : 0.3mm

Total rake angle : +5o

Chip thickness : 1.5mm

Cutting force : 900N

Thrust force : 450N

Using Merchant's analysis, the friction angle during the machining will be

25.

A steel bar 200mm in a diameter is turned at a feed of 0.25mm/rev With a depth of cut of 4mm The rotational speed of the workpiece is 160rpm. The material removal rate in mm3/s is

Answer»

A steel bar 200mm in a diameter is turned at a feed of 0.25mm/rev With a depth of cut of 4mm The rotational speed of the workpiece is 160rpm. The material removal rate in mm3/s is

26.

A milling cutter having 8 teeth is rotating at 150rpm. If the feed per tooth is 0.1mm, the speed in mm per minute is

Answer»

A milling cutter having 8 teeth is rotating at 150rpm. If the feed per tooth is 0.1mm, the speed in mm per minute is

27.

The following data relate to an orthogonal turning process: back rake angle =15deg. width of cut =2mm chip thickness =0.4mm feed rate =0.2mm/revIf the cutting force and the thrust force are 900N and 810N the shear strength in MPa

Answer»

The following data relate to an orthogonal turning process: back rake angle =15deg. width of cut =2mm chip thickness =0.4mm feed rate =0.2mm/rev



If the cutting force and the thrust force are 900N and 810N the shear strength in MPa

28.

In an orthogonal cutting test with a tool of rake angle 15 deg, the following observations were made: chip thickness ratio = 0.37, horizontal cutting force = 1000 N, vertical cutting force = 1500 N.The machining constant for the given machining operation is

Answer»

In an orthogonal cutting test with a tool of rake angle 15 deg, the following observations were made: chip thickness ratio = 0.37, horizontal cutting force = 1000 N, vertical cutting force = 1500 N.



The machining constant for the given machining operation is

29.

A metal cutting test was conducted on a lathe and the following were noted:Vertical force on the tool = 2000 Ndepth of cut = 2.00 mmFeed = 5 cuts/mmPressure of the chip cross-sectional area on the tools is______ kN/mm25

Answer» A metal cutting test was conducted on a lathe and the following were noted:

Vertical force on the tool = 2000 N

depth of cut = 2.00 mm

Feed = 5 cuts/mm

Pressure of the chip cross-sectional area on the tools is______ kN/mm2
  1. 5
30.

A through hole is drilled in an aluminum alloy plate of 15 mm thickness with a drill bit of diameter 10 mm, at a feed of 0.25 mm/rev and spindle speed of 1200 rpm. If the specific energy required for cutting this material is 0.7 N−m/mm3, the power required is_____(round off to two decimal places).274.89

Answer» A through hole is drilled in an aluminum alloy plate of 15 mm thickness with a drill bit of diameter 10 mm, at a feed of 0.25 mm/rev and spindle speed of 1200 rpm. If the specific energy required for cutting this material is 0.7 Nm/mm3, the power required is_____(round off to two decimal places).
  1. 274.89
31.

A hole of 40mm diameter is pierced in a steel sheet of 4mm thickness without shear on the tool. Shear strength of steel is 400N/mm2 and penetration is 25%. What is the expected percentage load reduction if a shear of 1mm is provided on the punch?

Answer»

A hole of 40mm diameter is pierced in a steel sheet of 4mm thickness without shear on the tool. Shear strength of steel is 400N/mm2 and penetration is 25%. What is the expected percentage load reduction if a shear of 1mm is provided on the punch?

32.

The machining time for an operation of cutting to test metal plates (much harder than both the tool material) when the tool material is changed from brass to cast steel. Metal removal rates with brass and cast steel as the tool material is given byGiven tensile strength of brass is = 135 MPaTensile strength of cast steel is = 415 MPaThe percentage change in cutting time when tool is changed from brass to cast steel will be __________QbQcs=(1+rcs1+rb)5/6Where r=Hardness of testing metalHardness of tool material -60.78

Answer» The machining time for an operation of cutting to test metal plates (much harder than both the tool material) when the tool material is changed from brass to cast steel. Metal removal rates with brass and cast steel as the tool material is given by



Given tensile strength of brass is = 135 MPa

Tensile strength of cast steel is = 415 MPa

The percentage change in cutting time when tool is changed from brass to cast steel will be __________

QbQcs=(1+rcs1+rb)5/6



Where r=Hardness of testing metalHardness of tool material


  1. -60.78
33.

A stainless steel cans of inner diameter 67 mm, thickness 3.5 mm, base thickness 5.71 mm and height 121 mm (excluding the base thickness) will be manufactured using an extrusion process. Billets used for the process have a diameter of 67 mm. The friction coefficient at the punch work piece is 0.03 and the workpiece die interface is 0.05. Assume the flow properties of the material are given as extrusion constant K=450 MPa, n = 0.16. The extrusion force is given by4857

Answer» A stainless steel cans of inner diameter 67 mm, thickness 3.5 mm, base thickness 5.71 mm and height 121 mm (excluding the base thickness) will be manufactured using an extrusion process. Billets used for the process have a diameter of 67 mm. The friction coefficient at the punch work piece is 0.03 and the workpiece die interface is 0.05. Assume the flow properties of the material are given as extrusion constant K=450 MPa, n = 0.16. The extrusion force is given by
  1. 4857
34.

A hole of 20mm diameter is to be drilled in a steel block of 40mm thickness. The drilling is performed at rotational speed of 400rpm and feed rate of 0.1mm/rev. The required approach and over run of the drill together is equal to the radius of the drill. The drilling time (in minute) is

Answer»

A hole of 20mm diameter is to be drilled in a steel block of 40mm thickness. The drilling is performed at rotational speed of 400rpm and feed rate of 0.1mm/rev. The required approach and over run of the drill together is equal to the radius of the drill. The drilling time (in minute) is

35.

In an orthogonal cutting test, the following observation were madeCutting force =1200NThrust force =500NTool rake angle =zeroCutting speed =1m/sDepth of cut =0.8mmChip thickness =1.5mmChip speed along the tool rake face will be

Answer»

In an orthogonal cutting test, the following observation were made

Cutting force =1200N

Thrust force =500N

Tool rake angle =zero

Cutting speed =1m/s

Depth of cut =0.8mm

Chip thickness =1.5mm



Chip speed along the tool rake face will be


36.

A cutting tool can be designated as:5−8−12−9−25−53−0.2 mm.(ORS) is used for machining. The normal rake angle of the tool is

Answer»

A cutting tool can be designated as:

5812925530.2 mm.

(ORS) is used for machining. The normal rake angle of the tool is

37.

Linked Data:A ϕ40mm job is subjected to orthogonal turning by +10o rake angle tool at 500rev/min. By direct measurement during the cutting operation, the shear angle was found equal to 25o.The velocity (in m/min) with which the chip flows on the tool face is

Answer»

Linked Data:

A ϕ40mm job is subjected to orthogonal turning by +10o rake angle tool at 500rev/min. By direct measurement during the cutting operation, the shear angle was found equal to 25o.



The velocity (in m/min) with which the chip flows on the tool face is



38.

Common Data:In an orthogonal machining operation:Uncut thickness =0.5mmCutting speed =20m/minRake angle =15oWidth of cut =5mmChip thickness =07mmThrust force =200NCutting force =1200NAssume Merchant's theory.The coefficient of friction at the tool-chip interface is

Answer»

Common Data:

In an orthogonal machining operation:

Uncut thickness =0.5mm

Cutting speed =20m/min

Rake angle =15o

Width of cut =5mm

Chip thickness =07mm

Thrust force =200N

Cutting force =1200N

Assume Merchant's theory.



The coefficient of friction at the tool-chip interface is



39.

For turning NiCr alloy steel at cutting speeds of 64m/min and 100m/min, the respective tool lives are 15min and 12min. The tool life for a cutting speed of 144m/min is

Answer»

For turning NiCr alloy steel at cutting speeds of 64m/min and 100m/min, the respective tool lives are 15min and 12min. The tool life for a cutting speed of 144m/min is

40.

In orthogonal turning of medium carbon steel, the specific machining energy is 2.J/mm3. The cutting velocity, feed and depth of cut are 120m/min,0.2mm/rev and 2mm respectively. The main cutting force in N is

Answer»

In orthogonal turning of medium carbon steel, the specific machining energy is 2.J/mm3. The cutting velocity, feed and depth of cut are 120m/min,0.2mm/rev and 2mm respectively. The main cutting force in N is

41.

In a machining operation, doubling the cutting speed reduces the tool life to 1/8th of the original value. The exponent n in Taylor's tool life equation VTn=C, is

Answer»

In a machining operation, doubling the cutting speed reduces the tool life to 1/8th of the original value. The exponent n in Taylor's tool life equation VTn=C, is

42.

Tool life equations for two tools under consideration are as followsHSS:VT0.2=150Carbide:VT0.3=250Where V is the cutting speed in m/min and T is the tool life in min. The breakeven cutting speed above which the carbide tool will be beneficial is

Answer»

Tool life equations for two tools under consideration are as follows

HSS:VT0.2=150

Carbide:VT0.3=250

Where V is the cutting speed in m/min and T is the tool life in min. The breakeven cutting speed above which the carbide tool will be beneficial is

43.

A lathe is used to turn a 25mm diameter bar. The value of n = 0.16 and tool life is 45 min at speed of 100 m/min. If a length of 50 mm per component is machined and the feed rate is 0.25 mm/rev. The number of pieces that can be produced between tool changes if spindle should run to obtain a tool of 5 hours is _____.1410

Answer» A lathe is used to turn a 25mm diameter bar. The value of n = 0.16 and tool life is 45 min at speed of 100 m/min. If a length of 50 mm per component is machined and the feed rate is 0.25 mm/rev. The number of pieces that can be produced between tool changes if spindle should run to obtain a tool of 5 hours is _____.
  1. 1410
44.

Common Data:A cylinder is turned on a lathe with orthogonal machining principle. Spindle rotates at 200rpm. The axial feed rate is 0.25mm per revolution. Depth of cut is 0.4mm The rake angle is 10o. In the analysis it is found that the shear angle is 27.75o.In the above problem, the coefficient of friction at the chip tool interface obtained using Earnest and Merchant theory is

Answer»

Common Data:

A cylinder is turned on a lathe with orthogonal machining principle. Spindle rotates at 200rpm. The axial feed rate is 0.25mm per revolution. Depth of cut is 0.4mm The rake angle is 10o. In the analysis it is found that the shear angle is 27.75o.



In the above problem, the coefficient of friction at the chip tool interface obtained using Earnest and Merchant theory is



45.

A batch of 500 jobs of diameter 50mm and length 100mm is to be turned at 200rev/min and feed 0.2mm/revThe number of tool changes required to machine the whole batch is

Answer»

A batch of 500 jobs of diameter 50mm and length 100mm is to be turned at 200rev/min and feed 0.2mm/rev



The number of tool changes required to machine the whole batch is



46.

A hydraulic press is used to produce circular blanks of 100mm diameter from a sheet o 2mm thickness. If the shear strength of the sheet material is 400N/mm2, the force required for producing a circular blank is

Answer»

A hydraulic press is used to produce circular blanks of 100mm diameter from a sheet o 2mm thickness. If the shear strength of the sheet material is 400N/mm2, the force required for producing a circular blank is

47.

An orthogonal turning operation is carried out under the following conditions; rake angle = 5°, spindle rotational speed = 400 rpm; axial feed = 0.4 m/min and radial depth of cut = 5 mm. the chip thickness tc, is found to be 3 mm. The shear angle (in degree) in this turning process is 18.88

Answer» An orthogonal turning operation is carried out under the following conditions; rake angle = 5°, spindle rotational speed = 400 rpm; axial feed = 0.4 m/min and radial depth of cut = 5 mm. the chip thickness tc, is found to be 3 mm. The shear angle (in degree) in this turning process is
  1. 18.88
48.

Linked Data:In a orthogonal cutting experiment, an HSS tool having the following tool signature in the orthogonal reference system (ORS) has been used : 0−10−7−7−10−75−1Given: Width of cut =3.6mmShear strength of workpiece material =460N/mm2; Depth of cut =0.25mm Coefficient of friction at chip tool interface =0.7Shear plane angle (in degrees) for minimum cutting force is

Answer»

Linked Data:

In a orthogonal cutting experiment, an HSS tool having the following tool signature in the orthogonal reference system (ORS) has been used : 0107710751

Given: Width of cut =3.6mm

Shear strength of workpiece material =460N/mm2; Depth of cut =0.25mm Coefficient of friction at chip tool interface =0.7



Shear plane angle (in degrees) for minimum cutting force is

49.

Common Data:A cylinder is turned on a lathe with orthogonal machining principle. Spindle rotates at 200rpm. The axial feed rate is 0.25mm per revolution. Depth of cut is 0.4mm The rake angle is 10o. In the analysis it is found that the shear angle is 27.75o.The thickness of the produced chip is

Answer»

Common Data:

A cylinder is turned on a lathe with orthogonal machining principle. Spindle rotates at 200rpm. The axial feed rate is 0.25mm per revolution. Depth of cut is 0.4mm The rake angle is 10o. In the analysis it is found that the shear angle is 27.75o.



The thickness of the produced chip is



50.

A non standard thread of pitch 3.175mm is to be cut on a lathe having lead screw of pitch 6mm. A change gear set provdied with the lathe has one gear each with the following number of teeth: 20,30,40,50,60,70,80,90,100,110,120,127. The correct pairs of change gears (a/b×c/d) for machining the given thread are (assuming that transmission ratio of the rest of the kinematic train between the late spindle and lead screw is equal to 1)

Answer»

A non standard thread of pitch 3.175mm is to be cut on a lathe having lead screw of pitch 6mm. A change gear set provdied with the lathe has one gear each with the following number of teeth: 20,30,40,50,60,70,80,90,100,110,120,127. The correct pairs of change gears (a/b×c/d) for machining the given thread are (assuming that transmission ratio of the rest of the kinematic train between the late spindle and lead screw is equal to 1)