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RS. 2700

Rs. 2700

RS. 30

Rs. 30

Rs. 50

SP = 125% of CP [∵ SP = {(100 + Gain%)/100} X CP]
= {125/100} x 40 
= (5/4) x 40 = 5 x 10 =Rs. 50

Rs. 2.5

100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? ---

720

Here SP = 80% of CP = 480

:. CP = 480 × 100/80 = 600.

For a profit of 20 % it should be = 600 × 120/100 = 720.

2000 Rs.

Let C.P. of each HORSE be Rs. X and C.P. of each cow be Rs. y. 

Then, 4x + 9y = 13400 -- (i)

And, 10% of 4x + 20% of 9y = 1880

2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (II)

Solving (i) and (ii), we get : x = 2000 and y = 600.

Cost price of each horse = Rs. 2000.

Rs.3068

COST of 1 kg RICE = Rs.45/-

Cost of 1 kg Wheat = Rs.36/-

Cost of 1 kg corn = Rs.28/-

:. Cost of 28 kg Rice + 23 kg Wheat + 35 kg corn = 28 x 45 + 23 x 36 + 35 x 28

= 1260 + 828 + 980 = Rs.3068.

20%

NA

25%

Let C.P. = RS. 4x. Then, S.P. = Rs. 5x

Gain = (5x - 4x) = Rs. X

Gain % = (x * 100)/ 4x = 25%.

RS. 118300

Let the COST of 1 DIGITAL camera be Rs x and that of 1 HANDY camera be Rs y.
Then15x + 21y = 354900

RS. 2800

Let the ORIGINAL PRICE be x.
∴ After 25% discount, price = 3x/4
Again 40% discount,
ie
Price = 3x/4 - 3x/4 x 40/100 = 3x/4 - 3x/10 = 9x/20
∴ 9x/20 = 1260

4% LOSS

Let CP of an article = RS. 100

MP= Rs. 120

Discount = 20%

SP = M[(100 - d%)/100] = 120(80/100) = Rs. 96

Clearly, the trader GETS 4% loss.

21%

CP of A + B + c = 2XY + 5x*2y - 2x*4Y = 20XY

profit of A = 0.2xy
profit of B = 2xy
profit of C = 2xy
Total profit = 4.2xy

% profit = (4.2xy / 20xy) X 100 = 21%

34.48 %

34.48 %

15

Given the COST price of 20 APPLES = Re 1 For 30% profit,
selling price must be RS 1.30 for 20 Apple

The SELLING PRICE is 86% of the MARKED price and is = Rs.387.

So, The marked price = 387 × 100/86 = Rs.450.

Rs 225

 LET the PRICE of the item be X 
Therefore, 700 - x = x - 400
Therefore, 2x = 1100
Therefore, x = 550
Therefore, 50% of x = 225

Rs. 500

107% of COST - 92% of cost= 75
or 15% of cost = 75
Therefore, cost = 75 x 100/15 = 500

12.5 %

12.5 %

8% PROFIT

8% profit

5 %

2 %

50 %

20 %

17%

17%

USE 900 G of weight INSTEAD of 1 kg.

Use 900 g of weight instead of 1 kg.

20% Loss

Let C.P. of each ARTICLE be Re. 1.

Then, C.P. of 50 ARTICLES = Rs. 50;

S.P. of 50 articles = Rs. 40.

Loss % = 10/50 * 100 = 20%

RS. 800

Let the VALUE of the COMMODITY be Rs. X.
∴ x/4 x 25/100 + x/8 x 40/100 + (x - x/4 - x/8) x 30/100
= 240
x/16 + x/20 + 3x/16 = 240

RS. 390

Let C.P. = Rs. X then, 425 - x = x - 355
⇒ 2X = 780
∴ x = 390

2% increase

Let original of each TOY be Rs. 100 and NUMBER originally SOLD be 100. 
∴ originally SALE proceeds = Rs. (100 x 100) = Rs. 10000

New sale proceeds = Rs. (120 x 85) = Rs. 10200
∴ Increase% = (200 x 100 / 10000)% = 2%

Rs. 4200

2 x + y = 7000 ....(i)
x + 2 y = 9800 .....(ii)
SOLVING (i) and (ii), we GET, 
y = 4200

0.25%

LOSS% ( COMMON GAIN or loss % / 10)2
= ( 5/10 )2 = 1/4 % = 0.25%

11 1/9%

GAIN% = {ERROR / (True VALUE - Error)} X 100 %
= (100/900) x 100) % 
= 11 1/9%

RS. 1000

We take CP = x

Now If i sell an article at 20% profit then what will be our SP in terms of x ?

simple 1.2x [ Because is told you percentage to DECIMAL conersion So 20% here is NOTHING but 0.2x and total SP will be x+ 0.2x = 1.2x remember add in case of profit and subtract in case of loss]

Given, he SOLD the article at 1200 Rs

So 1.2x = 1200 Rs 

So x = 1000 Rs

4%

Cost price = Rs. 78350

Marked price = 1.3*78350= 101855( I told in the Start CP is ABSOLUTE 100% so If anything is Marked or Sold Above CP by ---% You just have to add that % to 100% and Convert it into it's relative DECIMAL value)

Selling price = 101855*0.8= 81484[ Discount is calculated on MP so here MP is Absolute 100%, 20% discount that Means The PRODUCT is being Sold at 80% of MP or 0.8MP)

PROFIT = S.P - CP = 81484 - 78350 = 3134

Profit% = (Profit/CP)*100 = (3134/78350)*100 = 4%

21%

Find the C.P of 1 ORANGE that will be 10/11

Find SP of 1 orange that will be 11/10

As it's clear SP>CP hence Profit will be SP-CP = 11/10 - 10/11 = (121 - 100)/110 = 21/110

Profit % = [(profit)/CP]*100 = [(21/110)/(10/11)*100] = [(21*11)/(110*10)*100 = 21%

1500 Rs.

Take CP = X

 SP = 1200 Rs

So 0.8x = 1200

x = 1200/0.8 = 1500 Rs

So C.P is 1500 Rs.

55 %

REQUIRED PERCENTAGE PROFIT 
= 20+24/100-20 x 100
= 44x100/80
= 55%

50 %

LOSS = CP - SP

Loss = 1250 -625 = 625

Loss% = [(loss/CP)*100] = [(625/125)*100] = 50%

So we have a 50% loss here.

50%

Let the original price be 100.
After discount it is 100 - 10 = 90
He SELLS it on 35% PROFIT of original price.
So SP = 135
∴ % profit = 135-90/90 x 100 = 4500/90 = 50%

If the question can be answered using statement (II) ALONE but not statement (I) alone.

Statement (II) alone is sufficient but (I) alone is not sufficient.
From (II), COST of per dozen is RS 30.
Selling PRICE is Rs. 36 per dozen.
So % profit = 6/30 x 100 = 20%

55 %

Reparing cost = 420 x 25/100 = 525
Selling price = 525 + 126 = 651
∴ % RISE = 651 - 420/420 x 100 = 55%

RS. 49

S.P 1- C.P

RS. 17900

Loss is 25%,
IE 75% of COST PRICE is 13425
Therefore, cost price = 13425 x 100/75 = 17900

40 %

LET the marked price be x 
THEREFORE, 1ST MAN paid x - 20x/100 = 4x/5
2nd man paid x + 12x/100 = 25x + 3x/25 = 28x/25
Profit = 28x/25 - 4x/5 = 28x - 20x/25 = 8x/25
Therefore, % profit = 8x/25/4x/5 x 100 = 8x/25 x 5/4x x 100 = 40

Rs. 8500

Let the COST PRICE of the machine be X 
Therefore, x + 19x/100 = 10115

RS. 2000

CP = 2070 X 100/90 x 100/115 = Rs 2000

Rs 12372

Let the cost of ONE chair be X and that of one table be y.
∴ 21x + 35Y = 7217 ......(1)
EQN (1) x 12/7
= 21x x 12/7 + 35y x 12/7 = 7217 x 12/7
36x + 60Y = 12372

Rs. 7860

Let the SELLING PRICE = X, then
cost price = x - 25% of x = 75% of x
= 75/100 x x 
Now, 75x/100 = 5895
x = 78.6 x 100 = 7860

Rs. 48

Let the COST of item be x.
 ∴ x + x x 15/100 = 276
or, x = 27600/115 = 240
For 35% GAIN, selling price
= 240 + 240 x 35/100 = 240 + 84 = 324
∴ REQUIRED increase in price = 324 - 276 = 48

RS. 27

Selling PRICE of SUGAR = 67.50/2

17 %

TOTAL COST PRICE = 200 x 10