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1.

Which of these is the vibrational rate equation?(a) \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)(b) τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\)(c) evib = τ(e\(_{vib}^{eq}\) – evib)(d) \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)I had been asked this question in an online quiz.This intriguing question originated from Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics

Answer»

Correct choice is (a) \(\frac {de_{VIB}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{EQ}\) – evib)

Best explanation: The vibrational rate equation gives a RELATION between evib which is the time rate change with the difference between the equilibrium and the local instantaneous NON – equilibrium value (e\(_{vib}^{eq}\) – evib). It is given by the following relation which is a differential equation:

\(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)

2.

What is the value of equilibrium constant based on concentrations if the forward and reverse rate constant of a non – equilibrium reaction are 1.85 × 10^-4 and 2.34 × 10^-5?(a) 6.45(b) 7.91(c) 8.43(d) 2.31I got this question during an interview.My doubt is from Chemical Equilibrium in High Temperature Air in section Properties of High Temperature Gases of Aerodynamics

Answer»

The correct ANSWER is (b) 7.91

To elaborate: Given, KF = 1.85 × 10^-4 , kb= 2.34 × 10^-5

The EQUILIBRIUM constant based on concentrations for non – equilibrium is same as derived for the equilibrium condition SINCE it relates the forward and reverse rate constants. It is given by:

kc = \(\frac {k_f}{k_b}\)

Substituting the values, we get,

kc = \(\frac {1.85 × 10^{- 4}}{2.34 × 10^{- 5}}\) = 7.91

3.

What does the product of collision frequency and transition probability yield?(a) Number of transitions per particle per second(b) Number of collisions per second(c) Number of collisions per second per particle(d) Transitions per collisionThis question was posed to me in examination.My question is based upon Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics

Answer»

The CORRECT OPTION is (a) Number of transitions PER particle per second

Explanation: The COLLISION frequency (Z) when multiplied with the transition probability (Pi, i + 1) yield the number of transitions per particle per second. Since the collision frequency is the number of collisions taking place per particle and the transition probability gives the number of transitions taking place per collision per particle.

4.

For which condition is collision theory low?(a) Low temperature and pressure(b) High temperature and pressure(c) Low temperature, high pressure(d) High temperature, low pressureThe question was asked by my school principal while I was bunking the class.This interesting question is from Introduction to Nonequilibrium Systems topic in chapter Properties of High Temperature Gases of Aerodynamics

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Right option is (d) High TEMPERATURE, low pressure

Best explanation: Molecular collision FREQUENCY is directly proportional to the pressure of the molecule and inversely proportional to the square root of the temperature. Therefore, for OBTAINING low collision frequency, the pressure should be low and the temperature should be high.

5.

Which of these reactions is not carried out for the formation of nitric oxide?(a) Dissociation reaction of oxygen molecule(b) Dissociation reaction of nitrogen molecule(c) Shuffle reaction of nitric oxide molecule(d) Dissociative – recombination reaction of nitrogen and oxygenI got this question during a job interview.This intriguing question originated from Chemical Equilibrium in High Temperature Air topic in section Properties of High Temperature Gases of Aerodynamics

Answer»

Correct answer is (d) Dissociative – recombination reaction of nitrogen and oxygen

Easy explanation: The reaction taking place below 9000 K for the formation of nitric OXIDE are dissociation reaction and BIMOLECULAR exchange reaction ALSO KNOWN as shuffle reaction. They are as follows:

6.

In case of translation-vibration transfers, there can be an increase or decrease in kinetic energy.(a) True(b) FalseThis question was posed to me by my college director while I was bunking the class.My enquiry is from Vibrational Rate Equations topic in section Properties of High Temperature Gases of Aerodynamics

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Correct ANSWER is (a) True

For explanation: When a molecule undergoes a translation-vibration transfer also known as T – V transfer, molecules tend to lose or gain vibrational energy. This energy is reflected in the form of an increase or DECREASE in the KINETIC energy of the molecule UNDERGOING collision.

7.

If the temperature increases, what happens to the molecular collision frequency?(a) Increases(b) Decreases(c) No change(d) First increases then decreasesThis question was posed to me in an interview.I would like to ask this question from Introduction to Nonequilibrium Systems in section Properties of High Temperature Gases of Aerodynamics

Answer»

Correct choice is (B) Decreases

Explanation: The molecular COLLISION frequency (Z) is given by the relation:

Z ∝ \(\FRAC {p}{\sqrt {T}}\)

THEREFORE, molecular collision frequency is inversely proportional to the square root of temperature which means that as the temperature INCREASES, collision frequency decreases.

8.

Time taken for the number of collisions depends on which of these parameters?(a) Molecular collision frequency(b) Molar density(c) Number of moles(d) Boltzmann constantThe question was asked in final exam.Query is from Introduction to Nonequilibrium Systems in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

The CORRECT CHOICE is (a) Molecular COLLISION frequency

To EXPLAIN: The amount of time taken by the molecules for collision depends on the molecular collision frequency. Thus parameter tells how many collisions take PLACE with a neighboring particle in a second for a single particle.

9.

Which of these parameters affect the number of collisions?(a) Pressure of the setup(b) Kinetic energy between the molecules(c) Density of the apparatus(d) Temperature of the apparatusThe question was asked in class test.This interesting question is from Introduction to Nonequilibrium Systems topic in chapter Properties of High Temperature Gases of Aerodynamics

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Right choice is (b) Kinetic ENERGY between the molecules

The EXPLANATION is: For a molecule to become vibrationally excited, it has to undergo several NUMBER of collisions which is affected by the kinetic energy PRESENT between these colliding particles. HIGHER kinetic energy results in higher gas temperature which eventually leads to lesser number of collisions required for the molecule to become vibrationally excited.

10.

What is chemical equilibrium?(a) Change in temperature spontaneously(b) No change in chemical composition spontaneously(c) Change in pressure(d) Equilibrium between mole fractionsThe question was posed to me during an interview for a job.Enquiry is from High Temperature Gases topic in division Properties of High Temperature Gases of Aerodynamics

Answer»

Right option is (b) No change in chemical composition spontaneously

To EXPLAIN: In a mixture of gases (AIR), when there is no SUDDEN change in the chemical composition spontaneously or over a short period of TIME, the SYSTEM is known to be in chemical equilibrium. There are no changes in temperature, velocity, pressure in the system.

11.

How does the probability of finding molecule in an energy state vary?(a) Parabolic(b) Exponential(c) Hyperbolic(d) LinearThis question was addressed to me by my college director while I was bunking the class.I would like to ask this question from Boltzmann Distribution topic in division Properties of High Temperature Gases of Aerodynamics

Answer» RIGHT choice is (b) Exponential

For explanation I would say: On observing the equation of finding the molecule in a particular energy state as given by BOLTZMANN distribution LAW, we see that the graph varies exponentially as energy εj divided by kT (where k is the Boltzmann CONSTANT).
12.

At 4000 K what happens to the gas?(a) Oxygen is dissociated completely(b) Nitrogen is dissociated completely(c) Oxygen is dissociated completely, nitrogen begins to dissociate(d) Ionization of both oxygen and nitrogenThe question was posed to me in a job interview.This question is from Microscopic Description of Gases topic in portion Properties of High Temperature Gases of Aerodynamics

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Right ANSWER is (c) Oxygen is dissociated COMPLETELY, nitrogen begins to dissociate

The explanation: Up to 2500 K, there is no reaction taking place and oxygen starts to dissociated. At 4000 K, oxygen gets completely dissociated and nitrogen begins the PROCESS of DISSOCIATION. The reaction is as follows:

13.

In a boson particle, how many elementary particles are present inside a molecule?(a) Odd number(b) Even number(c) Zero(d) Imaginary numberThe question was asked in homework.My question is based upon Microscopic Description of Gases topic in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

The correct answer is (b) Even number

To explain: There are certain atoms and molecules which have even number (2, 4, 6, ..) of ELEMENTARY particles (quarks, leptons) that OBEY Bose – Einstein statistical distribution. These particles are KNOWN as Bosons.

14.

For a single atom what is the total energy a sum of?(a) Translation and rotational energy(b) Electrical and vibrational energy(c) Translation and electronic energy(d) Rotational, electronic and translation energyI had been asked this question during an interview for a job.My question is from Microscopic Description of Gases topic in section Properties of High Temperature Gases of Aerodynamics

Answer» RIGHT option is (C) Translation and electronic energy

For explanation I would say: For a molecule, the TOTAL energy is a SUMMATION of rotational, translation, vibrational and electronic energy. But for a single ATOM, the total energy is a sum of only translation and electronic energy.
15.

What is Dalton’s law?(a) Total temperature is equal to sum of partial temperatures(b) Total entropy is equal to sum of partial entropies(c) Total pressure is equal to sum of partial pressures(d) Total number of moles is equal to sum of mole fractionsThe question was posed to me by my college director while I was bunking the class.I'm obligated to ask this question of High Temperature Gases topic in portion Properties of High Temperature Gases of Aerodynamics

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Right choice is (c) Total pressure is EQUAL to sum of partial pressures

The EXPLANATION: Dalton’s LAW of partial pressure was formulated to FIND out the total pressure of the chemically reactive mixture. This is the sum of partial pressures of individual components in the mixture. Dalton’s law is only applicable or perfect gases which means that the INTERMOLECULAR forces between individual molecules is negligible.

16.

What happens to a reaction when reaction quotient is equal to the equilibrium constant?(a) Forward reaction(b) Equilibrium(c) Reverse reaction(d) No changeThe question was asked in homework.Question is taken from High Temperature Gases topic in section Properties of High Temperature Gases of Aerodynamics

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The correct answer is (C) Reverse reaction

Easiest explanation: The reaction quotient gives the same expression as the equilibrium constant for a reaction that is at CHEMICAL equilibrium. But, for a reaction when the reaction quotient (Q) is GREATER than the equilibrium constant (k), there’s more PRODUCT than the reactant and reverse reaction takes place.

17.

At low temperature, low – lying states close to the ground energy levels are overly populated.(a) True(b) FalseI had been asked this question in an online interview.This interesting question is from Boltzmann Distribution topic in section Properties of High Temperature Gases of Aerodynamics

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The correct choice is (a) True

For EXPLANATION I would say: At higher temperatures, the MOLECULES are spread over different STATES in several energy levels but the same trend is not observed at lower temperatures. At temperatures below 5K, molecules are NEAR or at the ground STATE thus making it overly populated.

18.

At high temperature, there’s presence of only oxygen and nitrogen molecules in the air.(a) True(b) FalseThe question was asked during an internship interview.Question is from High Temperature Gases topic in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

Correct option is (b) False

To EXPLAIN: While analyzing the chemical composition of AIR at normal temperature and pressure, the major composition is of oxygen and nitrogen molecules. Presence of water vapor, argon, helium ETC. are very less THUS they can be neglected. Although, at higher temperature (2500K – 9000K), oxygen and nitrogen undergo chemical reaction and there is presence of O, N, NO, NO^+ etc.

19.

What is specific heat a function of at high temperatures?(a) Time(b) Temperature(c) Entropy(d) DensityThe question was asked in an online quiz.My doubt is from Microscopic Description of Gases in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

Right option is (b) Temperature

Explanation: The vibrational motion of the molecules becomes significant by absorbing some of the energy that would otherwise GO into the translational and rotational molecular motion as the temperature of a diatomic or polyatomic GAS is raised above normal conditions. The EXCITATION of vibrational energy, ALLOWS the specific heat to become a function of temperature function making it THERMALLY perfect rather than calorically perfect.

20.

What is a partition function Q a function of?(a) Volume(b) Temperature(c) Temperature and volume(d) Volume and massThis question was addressed to me during an interview.My question is taken from Boltzmann Distribution topic in portion Properties of High Temperature Gases of Aerodynamics

Answer»

Correct option is (c) Temperature and volume

Best EXPLANATION: The partition function Q is ALSO known as the state sum. It is defined by the formula:

Q = ∑jgje\(^{- \frac {ε_j^{‘}}{KT}}\)

This partition function has its USE in statistical thermodynamics and is a function of both temperature and volume.

21.

What is a ground state?(a) Energy when gas is at absolute zero(b) Energy when gas is at 273.15 K(c) State where energies are non – existent(d) State where only translation energy existsI have been asked this question in an interview for job.The origin of the question is Microscopic Description of Gases in section Properties of High Temperature Gases of Aerodynamics

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Correct option is (a) Energy when GAS is at ABSOLUTE zero

The explanation: The MOLECULE’s ground state refers to the energy that the molecule WOULD have if the gas were theoretically at absolute zero temperature. Therefore, the values for the translational, rotational, vibrational, and electronic modes are often referred to as zero – point ENERGIES.

22.

The source of electronic energy is kinetic energy due to translation motion.(a) True(b) FalseI had been asked this question during an interview.My query is from Microscopic Description of Gases topic in chapter Properties of High Temperature Gases of Aerodynamics

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Right ANSWER is (a) True

Best explanation: Electrons revolve around the NUCLEUS of an atom which makes up the molecule. This molecule POSSESSES ELECTRICAL energy. This is a result of TWO factors – kinetic energy due to translation motion and potential energy.

23.

What is the value of transition probability?(a) 0(b) More than 1(c) Less than 1(d) 1I got this question in examination.My question is taken from Vibrational Rate Equations topic in division Properties of High Temperature Gases of Aerodynamics

Answer»

The correct option is (C) Less than 1

Explanation: Transition PROBABILITY is the probability that a molecule will jump to ANOTHER i + 1 level after the molecular COLLISION. The transition of the molecule moving to a higher energy level requires several number of collisions. This probability value is ALWAYS less than 1.

24.

At high temperatures, what does dissociation of molecule mean?(a) Atoms break away from molecular structure(b) Electrons break away from the atom(c) Protons and neutrons break away(d) Electrons jump to the higher energy stateI had been asked this question in unit test.Asked question is from Microscopic Description of Gases in division Properties of High Temperature Gases of Aerodynamics

Answer»

Right answer is (a) ATOMS break away from molecular structure

Easiest explanation: At HIGHER temperature molecules dissociate or ionize depending on the temperature RANGE. Dissociation is a process where the atoms which are a part of the molecule break away from the molecular structure. This leads to the gas BECOMING highly chemically reactive.

25.

What is the master equation for vibrational relaxation?(a) \(\frac {dN_i}{dt}\) = ki + 1, i ZNi + 1 + ki – 1, i ZNi – 1 – ki, i + 1 ZNi – ki, i – 1 ZNi(b) \(\frac {dN_i}{dt}\) = ki + 1, i Ni + 1 + ki – 1, i Ni – 1 – ki, i + 1Ni – ki, i – 1 Ni(c) \(\frac {dN_i}{dt}\) = ZNi + 1 + ZNi – 1 – ZNi, i – 1 – ZNi(d) \(\frac {dN_i}{dt}\) = Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1This question was addressed to me in an international level competition.My doubt stems from Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics

Answer» CORRECT choice is (b) \(\frac {dN_i}{DT}\) = ki + 1, i Ni + 1 + ki – 1, i Ni – 1 – ki, i + 1Ni – ki, i – 1 Ni

To explain: In the formula derived to obtain then net rate of change of population of the i^th level, the product of TRANSITION probability and collision frequency is expressed in the form of a new variable known as vibrational rate constant ki + 1, i = PI + 1, i Z (this is an example of ONE of the transitions). Thus the formula is reduced from \(\frac {dN_i}{dt}\) = Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 – Pi, i + 1 ZNi – Pi, i – 1 ZNi to:

\(\frac {dN_i}{dt}\) = ki + 1, i Ni + 1 + ki – 1, i Ni – 1 – ki, i + 1Ni – ki, i – 1 Ni
26.

What is the formula to compute net rate change of the population of the i^th level?(a) \(\frac {dN_i}{dt}\) = Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 – Pi, i + 1 ZNi – Pi, i – 1 ZNi(b) \(\frac {dN_i}{dt}\) = – Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 + Pi, i + 1 ZNi + Pi, i – 1 ZNi(c) \(\frac {dN_i}{dt}\) = Pi + 1, i ZNi + 1 – Pi, i + 1 ZNi(d) \(\frac {dN_i}{dt}\) = + Pi – 1, i ZNi – 1 – Pi, i – 1 ZNiThe question was asked by my college professor while I was bunking the class.Query is from Vibrational Rate Equations topic in division Properties of High Temperature Gases of Aerodynamics

Answer»

The correct option is (a) \(\FRAC {dN_i}{DT}\) = Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 – Pi, i + 1 ZNi – Pi, i – 1 ZNi

The EXPLANATION: The rate of CHANGE of population of the molecules in i^th level is computed by adding rate of increase of NI (population of i^th level) and rate of decrease of Ni. Thus the formula is:

\(\frac {dN_i}{dt}\) = Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 – Pi, i + 1 ZNi – Pi, i – 1 ZNi

Where, Pi + 1, i ZNi + 1 + Pi – 1, i ZNi – 1 is the rate of increase of population in i^th level due to the molecules jumping up from i – 1 and down from i + 1 levels.

Pi, i + 1 ZNi – Pi, i – 1 ZNi is the rate of decrease of population in the i^th level due to the molecules jumping from i^th level to i + 1 and i – 1 levels.

27.

At higher temperatures, the assumption of a calorically perfect gas is valid.(a) True(b) FalseThe question was posed to me by my college director while I was bunking the class.My query is from Microscopic Description of Gases in section Properties of High Temperature Gases of Aerodynamics

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The correct answer is (b) False

The EXPLANATION: For studying MODERN compressible flow, the ASSUMPTION of calorically perfect has is not valid at high temperature because the gases become highly reactive. The molecules of the gas vibrate as the temperature rises causing deviation from the calorically perfect gas BEHAVIOR.

28.

Which of these methods is not used in describing the composition of air which is at a chemical equilibrium?(a) Partial pressure(b) Partial temperature(c) Mass fraction(d) Mole – mass ratioThis question was posed to me during an online exam.The question is from High Temperature Gases topic in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

Right choice is (b) Partial temperature

For explanation I would say: There are several WAYS to describe the composition of air which is at a CHEMICAL equilibrium. These are – partial fraction, CONCENTRATION, mole fraction, mole – mass fraction and mass fraction. These HELP in determining the composition of the reacting GAS.

29.

2H2 + O2 → 2H2O is an elementary chemical reaction.(a) True(b) FalseThe question was asked during an interview for a job.This key question is from Chemical Equilibrium in High Temperature Air in division Properties of High Temperature Gases of Aerodynamics

Answer»

Correct option is (B) False

To explain I WOULD say: The reaction between hydrogen and oxygen molecule to form water molecule involves a SERIES of chemical reactions instead of one single step. THUS, it is not an elementary chemical reaction.

30.

What does Boltzmann distribution tell us?(a) Energy levels(b) Distribution of molecules at different energy levels(c) Distribution of electrons in a molecule(d) Magnitude of different energy levels of a moleculeThis question was addressed to me in examination.I would like to ask this question from Boltzmann Distribution in section Properties of High Temperature Gases of Aerodynamics

Answer»

The correct choice is (B) Distribution of molecules at DIFFERENT ENERGY levels

To ELABORATE: The Boltzmann distribution is a probability distribution of how molecules are at different energy levels. It is given by:

N\(_j^*\) = N\(\frac {g_j e^{- \frac {ε_j^{‘}}{kT}}}{∑_jg_j e^{ – \frac {ε_j^{‘}}{kT}}} \)

Where, ε\(_j^{‘}\) is total energy

gj are the degenerate states

N are the number of molecules

31.

What are the particles which obey Fermi – Dirac statistics called?(a) Bosons(b) Fermions(c) Leptons(d) QuarksI got this question during a job interview.Asked question is from Microscopic Description of Gases in chapter Properties of High Temperature Gases of Aerodynamics

Answer» RIGHT choice is (b) FERMIONS

Explanation: Molecules and ATOMS whose elementary particles PRESENT are in odd number usually follow a DIFFERENT statistical distribution known as Fermi – Dirac statistics. These atoms and molecules are commonly referred to as Fermions.
32.

The chemical and vibrational process occur due to molecular collision.(a) True(b) FalseThe question was posed to me in an internship interview.I need to ask this question from Introduction to Nonequilibrium Systems topic in section Properties of High Temperature Gases of Aerodynamics

Answer» CORRECT choice is (a) True

To explain I WOULD say: All the vibrational and CHEMICAL PROCESSES occur by the process of molecular COLLISION. When the molecules collide, there is a change between the vibrational energy before and after the collision which is dependent on the temperature and kinetic energy.
33.

Boltzmann distribution tells us the distribution of molecules in an unsteady system.(a) True(b) FalseThe question was posed to me in class test.The query is from Boltzmann Distribution topic in portion Properties of High Temperature Gases of Aerodynamics

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The correct ANSWER is (B) False

To explain: Boltzmann distribution helps in ANALYZING the ENERGY state εj in which the molecule or atom lies within a system of N – molecules. This distribution is provided for a system of molecules/atoms which is in thermodynamic equilibrium.

34.

How many thermal degrees of freedom is there for a diatomic molecule having translation energy?(a) 2(b) 3(c) 4(d) 6This question was posed to me in an online interview.Question is taken from Microscopic Description of Gases in chapter Properties of High Temperature Gases of Aerodynamics

Answer»

Right choice is (b) 3

The explanation is: For a diatomic molecule having translation ENERGY, there are three thermal degrees of freedom. This energy is at the center of mass PRESENT due to the translation kinetic energy. The velocity components are in X, y, Z direction of the Cartesian space.

35.

How many degrees of freedom is there for a CO2 molecule with rotational kinetic energy?(a) 1(b) 2(c) 3(d) 6The question was asked in a national level competition.The above asked question is from Microscopic Description of Gases in portion Properties of High Temperature Gases of Aerodynamics

Answer»

The correct OPTION is (b) 2

The best explanation: CO2 is a linear POLYATOMIC molecule that has similar properties as the diatomic molecule having rotational kinetic energy. The MOMENT of inertia for the molecule in z – axis is negligible SMALL compared to x and y – axis. Due to this reason, diatomic and even linear polyatomic molecules have only two thermal degrees of freedom.