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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous `NaCl` to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The final solution containsA. `[Pb(NH_(3))_(4)]^(2+)` and `[CoCl_(4)]^(2-)`B. `[Al(NH_(3))_(4)]^(3+)]` and `[Cu(NH_(3))_(4)]^(2+)`C. `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)`D. `[Ag(NH_(3))_(2)]^(+)` and `[Ni(NH_(3))_(6)]^(2+)` |
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Answer» Correct Answer - C |
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| 2. |
`(NH_(4))_(2)Cr_(2)O_(7)` on heating gives a gas which is also given byA. Heating `NH_(4)NO_(2)`B. Heating `NH_(4)NO_(3)`C. `Mg_(3)N_(2)+H_(2)O`D. `Na(comp.)+H_(2)O` |
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Answer» Correct Answer - A |
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| 3. |
A sodium salt on treatment with `MgCl_(2)` gives white precipitate only on heating. The anion of sodium salt isA. `HCO_(3)^(-)`B. `CO_(3)^(2-)`C. `NO_(3)^(-)`D. `SO_(4)^(2-)` |
| Answer» Correct Answer - A | |
| 4. |
To a metal nitrate, when KI solution is added, a black precipitate is produced at first , on additing excess of KI, orange solution is produced. Identify the meatl ionA. `Hg^(2+)`B. `Bi^(3+)`C. `Cu^(2+)`D. `Pb^(2+)` |
| Answer» Correct Answer - A | |
| 5. |
A metal nitrate reacts with `KI` to give a black precipitate which on addition of excess of `KI` convert into orange colour solution. The cation of metal nitrate isA. `Hg^(2+)`B. `Bi^(3+)`C. `Sn^(2+)`D. `Pb^(2+)` |
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Answer» Correct Answer - B |
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| 6. |
A metal nitrate reacts with `KI` to give a black precipitate which on addition of excess of `Kl` is converted into orange colour solution.The cation of the metal nitrate is :A. `Hg^(2+)`B. `Bi^(3+)`C. `Pb^(2+)`D. `Cu^(+)` |
| Answer» Correct Answer - B | |
| 7. |
Assertion : Change in colour of the acidic solution of breath is used as a test for drunken driver. Reason : Change in colour is due to complexation of alcohol with potassium dichromate. |
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Answer» Correct Answer - C Change in colour is due to reduction of dichromate and organge red dichromate changes to green coloured `Cr^(3+)`. |
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| 8. |
`S_(1) :` Silver iodide is fairly soluble in hypo solution. `S_(2) :` Heavy metal chloride like `AgCl,HgCl_(2)` etc. also respond to Chromyl chloride test. `S_(3) :` Bromine reacts with `KI` liberating violet vapours of iodine. `S_(4) :` Diphenylamine reagent test is also given by nitrites chlorates, bromates, iodates, etc. in addition to `NO_(3)^(-)`A. `T T T F`B. `T F T T`C. `T T F F `D. `F F T T ` |
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Answer» Correct Answer - B `S_(2) :` do not respond as they are partially dissociated. |
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| 9. |
Statement I Sulphate is extimated as `BaSO_(4)`, not as `MgSO_(4)`. Statement II Ionic radius of `Mg^(2+)` is smaller than that of `Ba^(2+)`. |
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Answer» Correct Answer - B Sulphate is estimated as `BaSO_(4)` because of its insolubility in water . `BaSO_(4)` forms white precipitate. |
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| 10. |
Addition of excess of sodium hydroxide solution to stannous chloride solution, we obtain:A. Al and BiB. Al and ZnC. Zn and MgD. Al,Bi and Zn |
| Answer» Correct Answer - 1 | |
| 11. |
A colouless solution of a compound gives a precipitate with `AgNO_(3)` solution but no precipitate with a solution of `Na_(2)CO_(3)`. The action of concentrated `H_(2)SO_(4)` on the compound liberates a suffocating reddish brown gas. The compound is `:`A. `Ba(CH_(3)COO)_(2)`B. `CaCl_(2)`C. `Nal`D. `NaBr` |
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Answer» Correct Answer - D `Ag^(+)+Br to AgBr darr ("pale yellow"),NaBr+Na_(2)CO_(3) to` No reaction. `2NaBr+2H_(2)SO_(4) to Br_(2) uarr ("reddish brown") +SO_(2)+SO_(4)^(2-)+2Na^(+)+2H_(2)O` |
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| 12. |
Aqua regia isA. WhiteB. RedC. GreenD. Yellow |
| Answer» Correct Answer - A | |
| 13. |
A colouless solution of a compound gives a precipitate with `AgNO_(3)` solution but no precipitate with a solution of `Na_(2)CO_(3)`. The action of concentrated `H_(2)SO_(4)` on the compound liberates a suffocating reddish brown gas. The compound is `:`A. `Ba(CH_(3)COO)_(2)`B. `CaCl_(2)`C. `NaI`D. `NaBr` |
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Answer» Correct Answer - 4 `Ag^(+)+Br^(-)rarrAgBrdarr("paly yellow")" "," "NaBr+Na_(2)CO_(3)rarr"No reaction"` `2NaBr+2H_(2)SO_(4)rarrBr_(2)uarr(" reddish brown")+SO_(2)+SO_(4)^(2-)+2Na^(+)+2H_(2)O.` |
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| 14. |
`H_(2)S` in the presence of `HCl` precipitates `II` group but not `IV` group because:A. Ionisation of `H_(2)S` is increasedB. Ionisation of `H_(2)S` is decreasedC. Precipitation of `Pb^(+2)` is avoidedD. Precipitated of `Mn^(+2)` as sulphide is facilitated |
| Answer» Correct Answer - 2 | |
| 15. |
`H_(2)S` in the presence of HCl precipitates II group but not IV group because `:`A. HCl activates `H_(2)S`B. `HCl` increases concentration of `Cl^(-)`C. `HCl` decreases concentration of `S^(2-)`D. `HCl` lowers the solubility of `H_(2)S` in solution |
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Answer» Correct Answer - 3 `H_(2)ShArr 2H^(+)+S^(2-),HClhArrH_(2)^(+)+Cl^(-)`. Due to common ion effect, the ionisation of `H_(2)S` is suppressed and thus low concentration of `S^(2-)` ions is obtained. This much of `S^(2-)` ions concentration is enough to precipitate only `II^(nd)` group cations `(` because of the low `K_(SP)` of `II^(nd)` group sulphides ). |
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| 16. |
`H_(2)S` in the presence of `HCl` precipitates `II` group but not `IV` group because:A. `HCl` activates `H_(2)S`B. `HCl` increase concentration of `Cl^(-)`C. `HCl` decreases concentration of `S^(2-)`D. `HCl` lowers the solubility of `H_(2)S` in solution. |
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Answer» Correct Answer - C `H_(2)S hArr2H^(+)+S^(2-),HClhArrH_(2)^(+) +Cl^(-)` Due to common ion effect, the ionisation of `H_(2)S` is suppressed and thus low concentration of `S^(2-)` ions is obtained This much of `S^(2-)` ions concentration is enough to precipitate only `II^(nd)` group cations (because of the low `K_(SP)` of `II^(nd)` group sulphides) |
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| 17. |
Sometimes yellow turbidity appears while passing `H_(2)S` gas even in slightly acidic medium in the absence of `II` group radicals. This is because:A. sulphur is present in the mixture as impurity.B. `IV` group radicals are precipitated as sulphidesC. of the oxidation of `H_(2)S` gas by some acid radicalsD. `III` group radicals are precipitated as hydroxides. |
| Answer» Correct Answer - C | |
| 18. |
Sometimes yellow turbidity appears while passing `H_(2)S` gas even in the absence of II group radicals. This is because ofA. sulphur is present in the mixture as impurityB. IV group radicals are precipitated as sulphides.C. the oxidation of `H_(2)S` gas by some acid radicalsD. III group radicals are precipitated as hydroxides |
| Answer» Correct Answer - 3 | |
| 19. |
Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute hydrochloric acid ?A. `Bi^(3+) , Sn^(4+)`B. `Al^(3+) , Hg^(2+)`C. `Zn^(2+) , Cu^(2+)`D. `Ni^(2+) , Cu^(2+)` |
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Answer» Correct Answer - A Both belong to same group i.e. `II^(nd)` group and their `K_(SP)` values are low, so both are precipitated according to the following reactions. `{:(2Bi^(3+),+,3S^(2-),to,Bi_(2)S_(3),darr,("black")),(Sn^(4+),+,2S^(2-),to,SnS_(2),darr,("yellow")):}` |
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| 20. |
Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute HCl ?A. `Bi^(3+),Sn^(4+)`B. `Al^(3+),Hg^(2+)`C. `Zn^(2+),Cu^(2+)`D. `Ni^(2+),Cu^(2+)` |
| Answer» Correct Answer - 1 | |
| 21. |
Distinguishing reagent between silver and load salts isA. `H_(2)S` gasB. dil HCl solutionC. `NH_(4)Cl` ( solid) `+NH_(4)OH` solutionD. `NH_(4)Cl`( solide) `+(NH_(4))_(2)CO_(3)` solution |
| Answer» Correct Answer - 2 | |
| 22. |
A white powder (A) on heating gave a non-combustible gas and a residue (B). The white compound A on reaction with `H_(2)S` in alkaline medium forms a precipitate (C ) which dissolves in dil. `CH_(3)COOH`. (B) can be disssolved in dil HCl to prepare a solution which gives a white precipitate with `K_(4)[Fe(CN)_(6)]`. Compound A isA. `CaCO_(3)`B. `CoCO_(3)`C. `CuCO_(3)`D. `ZnCO_(3)` |
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Answer» Correct Answer - D `ZnCO_(3)overset(Delta)(rarr)underset((B))(ZnO)+CO_(2)` yellow when hot but white when cold |
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| 23. |
A solid compound X on heating gives `CO_(2)` gas and a residue. The residue mixed with water forms Y. On passing excess of `CO_(2)` through Y in water, a clear solution Z is obtained. On boiling Z, compound X is reformed. The compound X isA. `Ca(HCO_(3))_(2)`B. `CaCO_(3)`C. `Na_(2)CO_(3)`D. `K_(2)CO_(3)` |
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Answer» Correct Answer - B `underset((X))(CaCO_(3))rarrCaO+CO_(2)uarr` `CaO+H_(2)O rarrunderset(Y)(Ca(OH)_(2))` `Ca(OH)_(2)+2CO_(2)rarr underset(Z)(Ca(HCO_(3))_(2))` `Ca(HCO_(3))_(2)overset(Delta)(rarr)CaCO_(3)+H_(2)O+CO_(2)uarr` `Cu^(+2)+CN^(-)+underset((X))((CN)_(2)uarr)` |
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| 24. |
When a substance A reacts with water it produces a combustible gas B and a solution of substance C in water. When another substance D reacts with this solution of C, it also produces the same gas B on warming but D can produce gas B on reaction with dilute sulphuric acid at room temperature. A imparts a deep golden yellow colour a smokeless flame to Bunsen burner. A,B,C, and D respectively are `:`A. `Na,H_(2),NaOH, Zn`B. `K,H_(2),KOH,Al`C. `Ca,H_(2),Ca(OH)_(2),Sn`D. `CaC_(2),C_(2)h_(2),Ca(OH)_(2),Fe` |
| Answer» Correct Answer - 1 | |
| 25. |
A white powder (A) on heating gave a non-combustible gas and a residue (B). The white compound A on reaction with `H_(2)S` in alkaline medium forms a precipitate (C ) which dissolves in dil. `CH_(3)COOH`. (B) can be disssolved in dil HCl to prepare a solution which gives a white precipitate with `K_(4)[Fe(CN)_(6)]`. Compuound B isA. `CaO`B. `CuO`C. `CoO`D. `ZnO` |
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Answer» Correct Answer - D `ZnCO_(3)overset(Delta)(rarr)underset((B))(ZnO)+CO_(2)` yellow when hot but white when cold |
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| 26. |
A white powder (A) on heating gave a non-combustible gas and a residue (B). The white compound A on reaction with `H_(2)S` in alkaline medium forms a precipitate (C ) which dissolves in dil. `CH_(3)COOH`. (B) can be disssolved in dil HCl to prepare a solution which gives a white precipitate with `K_(4)[Fe(CN)_(6)]`. Which of the following is true about B ?A. on heating it becomes yellowB. dissolves in `CH_(3)COOH`C. is balck in colourD. is insoluble in HCl |
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Answer» Correct Answer - A `ZnCO_(3)overset(Delta)(rarr)underset((B))(ZnO)+CO_(2)` yellow when hot but white when cold |
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| 27. |
Which of the following will not give positive chromyl chloride test?A. `HgCl_(2)`B. `AgCl`C. `PbCl_(2)`D. `KCl` |
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Answer» Correct Answer - D Chlorides of `Hg, Pb,Sb` and `Sn` do not give this test. |
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| 28. |
Hydrochloride acid contains `Cl-` ions but it does not give positive chromyl chloride test, why? |
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Answer» Because in presence of water chromic acid is obtained in place of chromyl chlorde. `K_(2)Cr_(2)O_(7)+2 HCl+H_(2)O to2H_(2)CrO_(4)+2KCl` |
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| 29. |
Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to the formation ofA. `Na[Fe(H_(2)O)_(5)NOS]`B. `Na_(2)[Fe(H_(2)O)_(5)NOS]`C. `Na_(3)[Fe(CN)_(5)NOS]`D. `Na_(4)[Fe(CN)_(5)NOS]` |
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Answer» Correct Answer - D `Na_(4)[Fe(CN)_(5)NO]+S^(2-)rarr Na_(4)[Fe(CN)_(5)NOS]` Sodium thio-nitroprusside (violet)] |
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| 30. |
In the chromyl chloride test, the reagent used isA. `K_(2)CrO_(4)`B. `K_(2)Cr_(2)O_(7)+NaOH`C. `K_(2)Cr_(2)O_(7)+H_(2)SO_(4)`D. `(NH_(4))_(2)Cr_(2)O_(7)` |
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Answer» Correct Answer - C Informative |
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| 31. |
Concentrated nitric acid, upon long standing, turns yellow-brown due to the formation of:A. `NO`B. `NO_(2)`C. `N_(2)O`D. `N_(2)O_(4)` |
| Answer» Correct Answer - B | |
| 32. |
A fire work gave green light. It probably contained a salt ofA. CaB. SrC. BaD. Mg |
| Answer» Correct Answer - B | |
| 33. |
Salt + conc. `H_(2)SO_(4)+` Ethyl alcohol `overset(Delta) rarr` Gas. Evolving gas (vapours) burns with green edged flame acidic radical may be. |
| Answer» Correct Answer - `BO_(3)^(-3)` | |
| 34. |
Some of the following statements are correct and some are incorrect. i) Both MnS and ZnS are soluble in dil. `CH_(3)COOH and HCl` ii) On adding of hot dilute acetic acid to a solution of barium oxalate and calcium oxalate only calcium oxalate dissolves. iii) `Hg_(2)^(2)` on reaction with ammonia solution give a black ppt. iv) Both `Hg_(2)Cl_(2)` and `SnCl_(4)` does not respond to chromyl chloride test. The wrong statements are `:`A. `(i),(iii),(iv)`B. `(ii),(iv)`C. `(i),(ii)`D. `(i),(ii),(iii)` |
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Answer» Correct Answer - C Only ZnS is soluble in `CH_(3)COOH` but not MnS and barium oxalate dissolves in acetic acid. |
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| 35. |
Solute (X) is highly soluble in water. On adding conc. `H_(2)SO_(4)`, There is no reaction and a clear solution is obtained -A. `NaNO_(3)`B. `Na_(2)HPO_(4)`C. `KI`D. `KCI` |
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Answer» Correct Answer - 2 `Cu(NH_(3))_(4)(NO_(3))_(2)+4CH_(3)COOHrarr Cu(NO_(3))_(2)+4CH_(3)COONH_(4)` `2Cu(NO_(3))_(2)+K_(4)[Fe(CN)_(6)]rarrunderset(("chocolate brown"))(Cu_(2)(NO_(3))_(2)+4KNO_(3))` |
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| 36. |
Which of the following statement(s) is (are) correct with reference to the ferrous and ferric ions ?A. `Fe^(2+)` gives brown colour with potassium ferricyanideB. `Fe^(2+)` gives blue colour with potassium ferricyanide.C. `Fe^(2+)` gives red colour with potassium thiocyanate.D. `Fe^(2+)` gives brown colour with potassium thiocyanate. |
| Answer» Correct Answer - B,C | |
| 37. |
In nitroprusside ion the iron and NO exist as Fe (II) and `NO^(+)` rather than the Fe(III) and NO. these forms can be differentiated byA. estimating the concentration of ironB. measuring the concentration of CNC. measuring the solid state magnetic momentD. thermally decomposing the compound |
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Answer» Correct Answer - C |
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| 38. |
Statement I A very dilute acidic solution of `Cd^(2+)` and `Ni^(2+)` gives yellow precipitate of CdS on passing `H_(2)S`. Statement II Solubility product of CdS is more than that of `NiS`. |
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Answer» Correct Answer - C In group analysis, `Cd^(2+)` belongs to Groups-II and `Ni^(2+)` belongs to III-B . Both ppted as sulphides. The `K_(sp)` of sulphides of Group -II cations are less then that of III-B ation |
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| 39. |
Which of the following can be separated by using dil. HCl ?A. `Ag^(+)` and `Cu^(2+)`B. `Ag^(+)` and `Hg_(+2)^(2+)`C. `Hg_(2)^(2+)` and `Cd^(2+)`D. `Ag^(+)` and `Al^(3+)` |
| Answer» Correct Answer - A,C,D | |
| 40. |
A red solid is insoluble in water.However it becomes soluble if some `KI` is added to water.Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube.The red solid is :A. `(NH_(4))_(2)Cr_(2)O_(7)`B. `HgI_(2)`C. `HgO`D. `Pb_(3)O_(4)` |
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Answer» Correct Answer - 2 `Hgl_(2) darr + 2l^(-) to [Hgl_(4)]^(2-)` (colourless soluble complex) `Hgl_(2) overset(Delta)to Hg+l_(2) uarr` (violet colour) |
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| 41. |
Which of the following sulphides is yellow in colour?A. `CdS`B. CoSC. CuSD. ZnS |
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Answer» Correct Answer - 1 CdS-yellow ppt CoS `&` CuS are black While ZnS is white |
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| 42. |
Which one of the following compounds on reaction with `Na_(2)O_(3)` in alkaline medium gives yellow colour solution?A. `Cr(OH)_(3)`B. `Zn(OH)_(2)`C. `Al(OH)_(3)`D. none of these |
| Answer» Correct Answer - A | |
| 43. |
(A) `:` CdS and `As_(2)S_(3)` both have yellow colour and precipitated by passing `H_(2)S` through solution in dil HCl. ® `:` Both can be separated by yellow ammonium sulphide. |
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Answer» Correct Answer - 2 `Cd^(2+)` belongs to group IIA `As^(3+)` belongs to group IIB |
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| 44. |
How many of the following substances are blue ? `(i) Fe(BO_(2))_(2)" " CoAl_92)O_(4)` `(iii)Co(BO_(2))_(2)" "(iv)NaCoPO_(4)` |
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Answer» Correct Answer - 3 `CoO.Al_(2)O_(3),Co(BO_(2))_(2),NaCoPO_(4)` are blue coloured |
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| 45. |
Which of the following ions can be separated by using `H_(2)S` in the presence of dil. HCl ?A. `Cu^(2+),Co^(2+)`B. `Hg_(2)^(2+), Cu^(2+)`C. `Pb^(2+),Ni^(2+)`D. `Cu^(2+),Bi^(2+)` |
| Answer» Correct Answer - A::C | |
| 46. |
The cations are grouped on the basis ofA. Their valencyB. Solubility product of radicalsC. Lattice energiesD. Ionic radii |
| Answer» Correct Answer - 2 | |
| 47. |
A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating rod solid in a test tube produces violet coloured fumes and droplets of metal appear on the cooler parts of test tube. The red solid isA. `Pb_(3)O_(4)`B. `(NH_(4))_(2)Cr_(2)O_(7)`C. `HgI_(2)`D. `HgO` |
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Answer» Correct Answer - 3 `HgI_(2)` is insoluble in water but when KI is added , it is soluble in water. |
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| 48. |
`PbCrO_(4)` is yellow in colour due toA. `Pb^(+2)`B. `CrO_(4)^(-2)`C. `Cr^(+3)`D. all |
| Answer» Correct Answer - 2 | |
| 49. |
Potassium chromate solution is added to an aqueous solution of a metal chlrodie. The precipitate thus obtained are insoluble in acetic acid. These are subjected to flame test, the colour of the flame isA. LilacB. Apple greenC. Crimson redD. Goldent yellow |
| Answer» Correct Answer - 2 | |
| 50. |
A substance `(A)` is water insoluble On bubbling `Cl_(2)` through its suspension in water, it produces a coloured aqueous solution, forming a single product, `(A)` may be `:`A. `BiOCl`B. `CuCl`C. `Hg_(2)Cl_(2)`D. All of these |
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Answer» Correct Answer - 2 `(1)` will not be oxidized by `Cl_(2)` `(2)` and `(3)` will be oxidized, but `(3)` will give colour `HgCl_(2)` only . `" ":." "(2)` is the answer. `underset("white")(2CuCl(s))+Cl_(2)(g)rarrunderset("coloured")(2CuCl_(2)(aq.))` |
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