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1.

A certain number when sucessively divided by 2, 3 and 5 leave remaindery 1, 2 and 3 respectively. Then what is the complete remainder? a) 20 b) 21 c) 22 d) 23

Answer»

Correct option: (d) 23

Explanation:

d1 = 2 d2 = 3 d3= 5 

r1 = 1 r2 = 2 r3= 3

Complete remainder = d1 d2 r3 + d1 r2 + r1 

= 2 x 3 x 3 + 2 x 2 + 1 

= 18 + 4 + 1 = 23

2.

What is the sum of all the numbers between 300 and 1,000 which are divisible by 179? a) 2,517 b) 2,527 c) 2,607 d) 2,506

Answer»

Correct option: (d) 2506

Explanation:

⇒ 179 x 2 + 179 x 3 + 179 x 4 + 179 x 5 

⇒ 179 (2 + 3 + 4 + 5) 

⇒ 179 x 14 = 2506

3.

A certain number 'X' when divided by 51 leaves a remainder 26 what is the remainder if the number X is divided by 17? a) 6 b) 7 c) 8 d) 9

Answer»

Correct option: (d) 9

Explanation:

X = 51Q + 26 

X = 3 x 17Q + 17 + 9 

X = 17 (3Q + 1) + 9 

Remainder = 9

4.

When "N" is divided by "4" the remainder is '3' what is the remainder when "2N" is divided by 4? a) 1 b) 2 c) 3 d) 4

Answer»

Correct option: (b) 2

Explanation:

Q = Quotient 

N = 4Q + r ⇒ N = 4Q + 3

When '2N' is divided by 4.. 

2N = 2 (4q + 3) ⇒ 2N = 8q + 6 

2N = 4 (2q + 1) + 2 

Remainder = 2

5.

A certain umber when divided by 39 leaves a remainder 20, what is the remainder when the same number be divided by 13? a) 7 b) 11 c) 0 d) 5

Answer»

Correct option: (a) 7

Explanation:

Let the number = x 

Divisor (d) = 39 

Remainder (r) = 20

X = (d x q) + r 

X = (39 x q) + 20 

When divided by "13" 

X = 13 x 3 x q + 13 + 7

 X =13 (3q + 1) + 7 

Remainder = 7

6.

What least number must be added to 3,000 to a number exactly divisible by 19? a) 1 b) 2 c) 3 d) 4

Answer»

Correct option: (b) 2

Explanation:

3,000 19 ⇒ remainder = 17 

Number to be added = (19 - 17) = 2

7.

A number when divided by 119 leaves 19 as remainder if the same number is divided by 17 the remainder obtained. a) 2 b) 3 c) 1 d) 5

Answer»

Correct option: (a) 2

Explanation:

Let, the Number = x 

Quotient = q 

Divisor = (d) = 119 

Remainder = (r) = 19 

X = (d x q) + r 

X = (119 x q) +19

Same number when divided by "17" 

x = (17 x 7 x q) + 17 + 2

= 17 (7q + 1) + 2 

Remainder is "2"

8.

Find the number which is nearest to 3,105 and exactly divisible by 21. a) 3,106 b) 3,108 c) 3,110 d) 3,111

Answer»

Correct option: (b) 3,108

Explanation:

On dividing 3,105 by 21, remainder obtained '18' 

Number to be added (21-18) = 3 

Required number = (3105 + 3) = 3108

9.

A certain number when sucessively divided by 3 and 7 it leaves remainders 1 and 3 respectively. Find the complete remainder. a) 7 b) 8 c) 9 d) 10 

Answer»

Correct option: (d) 10

Explanation:

d1 = 3 d2 = 7 

r1 = 1 r2 = 3

Complete remainder = d1 r2 + r1 

= 3 x 3 + 1 = 10