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RS. 358964

Amount RECEIVED by each PERSON= 16871308/47 = 358964

484

NA

RS 20

NA

164

Let US say x boys and x girls joined the group.

(64 + x) / (40 + x) = 4/3

192 + 3x = 160 + 4X => x = 32

Number of members in the group = 64 + x + 40 + x

= 104 + 2X = 168.

<P> 150, 200

The incomes of A and B be 3P and 4P.
Expenditures = Income - Savings
(3P - 100) and (4P - 100)
The ratio of their EXPENDITURE = 1:2
(3P - 100):(4P - 100) = 1:2
2P = 100 => P = 50
Their incomes = 150, 200

9 : 10

M/S = 6/7 = M = 6/7S
M+8/S+8 = 8/9
Therefore, 9M + 72 = 8S + 64
= 9x 6/7 S + 72 = 8S + 64
Solving this, S = 28, M = 24
Therefore, After 12 YRS, ratio = 24 + 12/28 + 12 = 36/40 = 9/10

3

NA

14

NA

2 : 3 : 4

Originally, LET the NUMBER of SEATS for Mathematics, Physics and BIOLOGY be 5x, 7X and 8x respectively. Number of increased sears are (140% of 5x), (150% of 7x) and (175% of 8x)

i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x)

i.e., 7x, 21x/2 and 14x

Required ratio = 7x:21x/2:14x

= 14x : 21x : 28x = 2:3:4

200%

NA

RS. 14000

S/4 = A/S = S : A = 4 : 5
Therefore, AMAR's salary = 5/9 X 25200 = 14000

36

36

2:1

10% of X = 20% of y

10x/100 = 20y/100 => x/10 = y/5

x/y = 10/5 = 2/1

x:y = 2:1.

14.19

Formula = THIRD PROPORTIONAL = (B × b)/a 
A = 63 and B = 29.9 
(29.9 × 29.9)/ 63 = 894.01/63 = 14.19

1900 men

2000 ---- 54

2000 ---- 39

 X ----- 20

 x*20 = 2000*39

 x = 3900

2000

-------

1900

Rs. 16800

Total PROFIT = Rs. 48000
Sum of the ratios= 16 + 21 + 23

2 : 1

10% of X = 20% of y

10x/100 = 20y/100 => x/10 = y/5

x/y = 10/5 = 2/1

x:y = 2:1

9:12:15:17

NA

8 : 5

Let the SECOND number be X.
∴ First number = x x x 37.5/100 = 62.5x/100
∴ RATIO = x/62.5x/100 = x x100/62.5
x = 8/5

7 : 5

7 : 5

RS. 427.5

Rs. 427.5

4

(2*2)/1 = 4

3

Let the least NUMBER to be SUBTRACTED be 'x', then 11 - x, 15 - x, 21 - x and 30 - x are in proportion.
<=> (11 - x):(15 - x) = (21 - x):(30 -x)(21 - x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 - x)(30 - x) = (15 - x)(21 - x)

9, 6, 12

Let the numbers be a, b and c.

Given that a, b and c are in the ratio 3 : 2 : 4. 

let, a = 3x, b = 2x and c = 4x

Given, (a+b) + (c - b) = 21

= > a + b+ c - b = 21

after 4 months

A's CAPITAL X A's TIME/B's capital x B's time = A's Profit/B's profit
5000 x 24/4000x x = 3/2

1078 CM CUBE

1078 cm cube

9, 6, 12

Let the numbers be a, b and C.
a:b:c = 3:2:4
Given, (a + b) + (c - b) = 21
=> a + c = 21
=> 3x + 4x = 21 => x = 3
a, b, c are 3x, 2x, 4x
a, b, c are 9, 6, 12.

7 : 3

Let the 1st no. be X and 2nd no. be y
Therefore, 39% of x = 91% of y

21 : 22

Originally, LET the number of boys and GIRLS in the college be 7x and 8X respectively. 

Their INCREASED number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22

50

5:1 = X: 10
x = 50

30

Let the three PARTS A, B, C. 

Then, A:B = 2:3 and B:C = 5:8

= (5 * 3/5) : (8 * 3/5) = 3:24/5

A:B:C = 2:3:24/5

= 10:15:24 => B = 98 * 15/49 = 30.

11:19

NA

4:5

NA

RS. 78,750

Let shailesh's monthly INCOME be Rs. X.
Mehul's monthly income 
= Rs. 3x/2
Prasant's monthly income = Rs. 15x/8
∴ x + 3x/2 + 15x8 = 183750
= 8x + 12X + 15x/8 = 183750
= 35x = 183750 x 8
= x = 183750 x 8/35
= 42000
∴ Prashant's monthly income= Rs. (15/8 x 42000) = Rs. 78750

8 : 3

Ratio = 64000 X 12 : 48000 x 6
= 768000 : 288000 = 8 : 3

2000 Rs.

Let the shares of A, B, C and D be 5X, 2x, 4x and 3x Rs. RESPECTIVELY. 

Then, 4x - 3x = 1000 => X = 1000.

B's share = Rs. 2x = 2 * 1000 = Rs. 2000.

Cannot be determined.

NA

2:3:6

1/3: 1/2: 1/1 = 2:3:6

30 years

Let the age of FATHER be x and SON be y
x/y = 2/1
∴ x = 2y ......(i)
Five years EARLIER. x-5/y-5 = 11/5
∴ 5x - 11Y = -30

2:3

Number of men in the COLONY = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated PERSONS in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3

2.912

Formula = FOURTH PROPORTIONAL = (B × C)/a
A = 0.5 , B = 1.12 and C = 1.3 
(1.12 × 1.3)/0.5
1.456/0.5 = 2.912

9:10:8

Let the AMOUNTS of A,B and C be 8x, 9x and 7x respectively.
Therefore, 8x + 9x + 7x = 7200

51 YEARS

Let the present AGES of father and son be 17x years and 7x years respectively.
According to the question.
17x-6/7x-6 = 3/1
= 21X - 18 = 17x - 6
= 21x - 17x = 18 - 6
= 4x = 12
= x = 12/4 = 3
∴ Father's present AGE = 17 x 3 = 51 years

Rs.6800

Cost of the CAMEL = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 ELEPHANTS
10 elephants = Rs.170000
P = Rs.[(24 * 4 * 4 * 170000)/(10 * 16 * 6 * 10)]
P = Rs.(65280000/9600) => P = Rs.6800

4:5

NA

4

Let the PRESENT ages of Mahesh, NILESH and RAMESH be m, n and R respectively.

m/n = 5/x

4 : 7

According to the question.
R/U = 24 - 8/36 - 8
= R/U = 16/28 = 4/7
R : U = 4 : 7

528

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)

= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available

=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = [(1200)(30)(3)] / (25)(2.5) - 1200 => x = 528.

RS. 204

Given RATIO = 1/2:2/3:3/4 = 6:8:9

1st PART = 782 * 6/23 = Rs. 204.

not POSSIBLE to find

NA