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51.

A solution of 30 litres of milk and water, has ` 70%` milk. How many litres of water must be added so that the volumes of milk and water will be in the ratio ` 3 : 2`?A. 6B. 3C. 5D. 4

Answer» Correct Answer - C
52.

If ` 7 3/4 : 11 2/3 = 93 : ( 2x + 10)`, then what is the value of x ?

Answer» Correct Answer - 65
53.

Express 81 : 93 in its simplest form.

Answer» The HCF of 81 and 93 is 3.
We divide each term by 3.
Then, ` 81 : 93 = 81/3 : 93/3 = 27 : 31`
`:. ` The ratio 81 : 93 in its simplest form is 27 : 31.
54.

What number must be subtracted from each of the numbers 32, 38, 17 and 20, so that the terms formed will be in proportion ?

Answer» Correct Answer - 2
55.

Express the ratio 51:525 in the lowest terms.

Answer» Correct Answer - `200:21`
56.

Express the ratio ` 1. 5` litres : 250 ml in the lowest terms.

Answer» Correct Answer - ` 6 : 1`
57.

Express the ratio ` 3/5 : 7/9` in the lowest terms.

Answer» Correct Answer - ` 27 : 35`
58.

Express the ratio `(4)/(5):(8)/(7)` in the lowest terms

Answer» Correct Answer - `7:10`
59.

if x:5=9:5, then what is the value of x?

Answer» Correct Answer - 9
60.

If `(x)/(2a-3b)=(y)/(3b-4c)=(z)/(4c-2a)`, then find the value of `x^(3)+y^(3)+z^(3)`.

Answer» Correct Answer - 3xyz
61.

If `(a)/(b)=(c)/(d)=(e)/(f)=(3)/(4)`, then what is the value of `(3a-4c-e)/(3b-4d-f)`?

Answer» Correct Answer - `(3)/(4)`
62.

If ` a : b =2 : 3 ," then find "(3a - b) : ( 2a+ 3b)`.

Answer» Correct Answer - ` 3 : 13`
63.

If A=3B=5C, then A:B:C=_______.

Answer» Correct Answer - `15:5:3`
64.

If ` a/b = c/d = e/f = 2/5`, then ` (3a+4c+9e)/(3b+4d+9f) = ` _________ .

Answer» Correct Answer - ` 2/5`
65.

If ` a : b = 4 : 5 ," find "(5a-b)/(10a+3b)`.

Answer» Given, ` a/b = 4/5`
` rArr a = (4b)/5`
`(5a-b)/((10a+3b))=(5((4b)/5) - b)/(10((4b)/5)+3b)=(3b)/(11b) = 3/11`.
66.

The outer angles of triangle are in the ratio 5 : 6 : 7. What are the angles ?

Answer»

Sum of outer angle = 360°

Let the angles be 5x , 6x , 7x

5x + 6x + 7x = 360°

18x = 360°

x = 20°

Angles are = 5x = 5 x 20 = 100°

6x = 6 × 20 = 1200

7x = 7 × 20 = 140°

67.

In a regular polygon, the ratio of the inner and outer angle is 7 : 2. What is each angle? How many sides does the polygon

Answer»

Let the inner angle be 7x and the outer angle 2x .

Inner angle + outer angle = 180°

7x + 2x = 180°

9x = 180°

x = 180 ÷ 9 = 20°

Inner angle = 7x = 7 × 20 = 140°

Outer angle = 2x = 2 × 20 = 40°

Sum of the outer angles of a polygon of n sides is 360°.

Since it is a regular polygon, the outer angles are equal,

n × 40 = 360°

n = \(\frac{360}{40}\) = 9

Number of sides of the polygon = 9

68.

If ` x /(y+z) = y/(z + x) = z /(x + y)` , then find the value of each fraction.

Answer» Correct Answer - ` -1`
69.

The LCM of two coprime numbers is 1,302. If oneof the numbers is 42, what is the other number? in detail​

Answer» Correct Answer - Rs. 200
70.

Discount is calculated on ……………A) C.PB) LossC) S.PD) Marked price

Answer»

Correct option is D) Marked price

D) Marked Price

71.

Anji sold a land for ₹3,00,000 and gain 20% then how much did he purchase it?A) 2,75,000B) 2,25,000C) 2,00,000D) 2,50,000

Answer»

Correct option is D) 2,50,000

72.

S.P – C.P = ……………….?A) lossB) profitC) M.PD) None

Answer»

Correct option is B) profit

73.

Gain % = ……………..?(A) \(\frac{Profit}{S.P}\) x 100(B) \(\frac{Profit \times C.P.}{100}\)(C) \(\frac{Profit}{C.P}\) x 100(D) \(\frac{C.P.}{Profit}\) x 100

Answer»

Correct option is (C) \(\frac{Profit}{C.P.}\) x 100
 

74.

If C.P of 11 books is equal to S.P of 15 books then ………………?A) 33\(\frac13\) % – LossB) 33\(\frac13\) % – ProfitC) 30% – LossD) 25% – Loss

Answer»

Correct option is B) 33\(\frac13\) % – Profit

75.

The percentage of shaded portion is A) 40%B) 16% C) 30%D) 25%

Answer»

Correct option is D) 25%

76.

The incomes of A and B are in ratio ` 4 : 3`. The expenditures of A and B are in the ratio ` 5 :2` . If B saves Rs. 3000, then which of the following cannot be the sacvings of A ?A. Rs. 1500B. Rs.2500C. Rs.3500D. Rs. 4500

Answer» Correct Answer - D
`{:(," "A," "B),("Income"," "4x," "3x),("Expenditure"," "5y," "2y),("Savings",4x-5y,3x-2y):}`
Given, ` 3x - 2y = 3000 rArr x = 1000 + (2y)/3`
Now, saving of ` A = 4x - 5y = 4(1000+(2y)/3)`
` -5y rArr 4000+(8y)/3 - 5y rArr 4000 - (7y)/3`.
`:.` The saving of A cannot be more than Rs. 4000.
` :.` Hence, the correct answer is option (d).
77.

Last year the price of a commodity was ₹ 80; this year the price goes up by ₹? 20. Find percentage increase.A) 20%B) 25%C) 100%D) 80%

Answer»

Correct option is B) 25%

78.

At what rate a sum triples itself in 8 years 4 months?A) 30%B) 18%C) 12%D) 24%

Answer»

Correct option is D) 24%

79.

If P = ₹ 3000, R = 9% T = 2\(\frac12\)(1/2)y, then I = .....?A) ₹575B) ₹685C) ₹655D) ₹675

Answer»

Correct option is D) ₹675

80.

If T = 4 years, P = ₹6500, A = ₹8840, then Rate of interest (R) = …………..%A) 9%B) 9.5%C) 8%D) 9.1%

Answer»

Correct option is A) 9%

81.

28% of a number is 168. Then 82% of it isA) 438B) 492C) 600D) 392

Answer»

Correct option is B) 492

82.

If A = ₹ 15624, P = ₹12,600, R = 9% T = ……………?A) 2\(\frac13\)YB) 3\(\frac23\) YC) 3\(\frac12\)YD) 3\(\frac23\)Y

Answer»

Correct option is B) 2\(\frac23\)Y
 

83.

The length and breadth of a rectangle are in the ratio 8 : 5. The length is 9 centimetres more than the breadth. What are the length and breadth of the rectangle?

Answer»

Let the length of the rectangle = 8x and breadth = 5x

Their difference = 8x – 5x = 3x

This is given as 9 m, 8x – 5x = 9

3x = 9, x = 9 ÷ 3 = 3

∴ Length of the rectangle = 8 × 3 = 24 cm

Breadth of the rectangle = 5 × 3 = 15 cm

84.

Area of a rectangle is 2400 sq.cm. If length and breadth are in the ratio 8 : 3, find length and breadth? If length and breadth are increased by 20 cm, then find the ratio between length and breadth

Answer»

Length = 8x

Breadth = 3x

\(8x\times3x=2400,\)

\(24x^2=2400\)

\(x^2=\frac{2400}{24}=100;\)

\(x^2=\sqrt{100}=10\)

length = 8 × 10 = 80,

Breadth = 3 × 10 = 30

When length and breadth are increased by 20, then length = 100;

Breadth = 50

length : breadth = 2 : 1

85.

The length, breadth and height of a rectangle block are in the ratio 3 : 2 : 5 and its volume is 3750 cubic centimetres. Calculate the length, breadth and height.

Answer»

Let breadth be 3x , length be 2x and height be 5x , then

3x × 2x × 5x = 3750

30 × 3 = 37

x = 5

Breadth = 3x = 3 × 5 = 15 cm

Length = 2x = 2 × 5 = 10 cm

Height = 5x = 5 × 5 = 25 cm

86.

The area of a rectangle is 600. If its length is 30, then the ratio of l: b is …………….A) 3 : 4B) 3 : 2C) 3 : 5D) 4 : 3

Answer»

Correct option is B) 3 : 2

87.

The breadth and length of two rectangles are in the ratio 2 : 3. In another rectangle, whose breadth is 1 cm less and length is 3 cm less than those of the first, this ratio is 3 : 4. Calculate the breadth and length of both rectangles.

Answer»

Ratio between the breadth and length of the first rectangle = 2 : 3

Breadth of the first rectangle = 2x

Length of the first rectangle = 3x

Breadth of the second rectangle = 2x – 1

Length of the second rectangle = 3x – 3

Ratio between the breadth and length = 3 : 4

so, (2x – 1) : (3x – 3) = 3 : 4

3 (3x – 3) = 4 (2x – 1)

9x – 9 = 8x – 4

9x – 8x = -4 + 9

x = 5

Breadth of the first rectangle = 2x = 2 × 5 = 10 cm

Length of the first rectangle = 3x = 3 × 5 = 15 cm

Breadth of the second rectangle = 2x – 1 = 10 – 1 = 9 cm

Length of the second rectangle = 3x – 3 = 15 – 3 = 12 cm

88.

The capacities of three water tanks are in the ratio 2 : 3 : 5. The smallest of them can hold 2500 litres. How many litres can the other two hold ?

Answer»

Ratio of the capacities = 2 : 3 : 5

Let the capacities be 2x , 3x , 5x

Quantity of water in smaller tank = 2x = 2500

x = 1250 litres

Capacity of second tank = 3x = 3 × 1250 = 3750 litres

Capacity of third tank = 5x = 5 × 1250 = 6250 litres

89.

Johny invested 50000 rupees, Jaleel 40000 rupees and Jayan 20000 rupees to start a business together. They got 3300 rupees as profit in a month, which they divided in the ratio of their investments. How much did each get ?

Answer»

Ratio of the investment = 50000 : 40000 : 20000 = 5 : 4 : 2

Profit of one month = 3300 rupees

Amount of johny got = 3300 x \(\frac{5}{11}\)

= 1500 rupees

Amount of jaleel got = 3300 x \(\frac{4}{11}\)

= 1200 rupees

Amount of Jayan got = 3300 x \(\frac{2}{11}\)

= 600 rupess.

90.

The cost of a precious stone varies as the cube of its weight. The stone broke into 3 pieces whose weights are in the ratio ` 1 : 2 : 3`. As a result its cost reduces . If the cost of the unbroken stone is Rs. 96, 336, then find the loss incurred due to breakage.A. ` Rs. 80,280`B. ` Rs. 16,056`C. ` Rs. 40,140`D. ` Rs. 8028`

Answer» Correct Answer - A
(i) Let the weights of the three pieces be x, 2x and 3x and their costs be `C_(1), C_(2) and C_(3)` respectively .
(ii) `C_(1)/x^(3) = C_(2)/(2x)^(3) = C_(3)/(3x)^(3) = (96, 336)/(6x)^(3)`.
(iii) Find `C_(1),C_(2) and C_(3)` and then `96,336 - (C_(1)+C_(2)+C_(3))`.
91.

Ram wanted to distribute a cartain amount between his two children Lava and Kusha in the ratio ` 5 : 7` But it was found that due to incorrect calculacions Lava got one-sixth of the total amount more than what he should get. Find the share of Kucha, in rupees, if Lava got Rs. 560 in all.A. 300B. 350C. 400D. 450

Answer» Correct Answer - C
(i) Frame the linear equation and solve it .
(ii) Let the actual shares of Lava and Kusha be Rs.5x and Rs. 7x respectively.
(iii) As the amount is `(5x+7x)`, one sixth of total amount = 2x.
(iv) the amount is divided in the ratio `(5x+2x) : (7x-2x)`.