52639 + Interview Questions in Secondary School in Chemistry Page 21 InterviewSolution

1001.	2) material which are different to compressare calledmaterial
Answer» ANSWER: What is this I didn't UNDERSTAND Is their any OPTIONS

1001.

2) material which are different to compressare calledmaterial

Answer»

ANSWER:

What is this I didn't UNDERSTAND Is their any OPTIONS

Discussion

1002.	What is the screening constant of Na
Answer» ANSWER: SCREENING constant of Na is 8.8 I HOPE THIS ANSWER WILL HELPFULL TO YOU. PLSS MARK ME AS BRAINLIEST.

1002.

What is the screening constant of Na

Answer»

ANSWER:

SCREENING constant of Na is 8.8

I HOPE THIS ANSWER WILL HELPFULL TO YOU.

PLSS MARK ME AS BRAINLIEST.

Discussion

1003.	Metalloids are sonorous, yes or no?
Answer» Answer: Sometimes yes, sometimes no; but it largely DEPENDS on the metalloid used Explanation: This is because metalloid exhibits both the properties of metals and non-metals, we have to TAKE into consideration that to produce a RINGING sound (sonorous) it has to be HARD to take the impact to produce a sound, but this might not be the CASE as most of the metalloids are brittle. Thank you!

1003.

Metalloids are sonorous, yes or no?

Answer»

Answer:

Sometimes yes, sometimes no; but it largely DEPENDS on the metalloid used

Explanation:

This is because metalloid exhibits both the properties of metals and non-metals, we have to TAKE into consideration that to produce a RINGING sound (sonorous) it has to be HARD to take the impact to produce a sound, but this might not be the CASE as most of the metalloids are brittle.

Thank you!

Discussion

1004.	Write the production of CH3-CH=CH-CH3+Cl2
Answer» Answer: 2,3 dichloro butane Explanation: when ALKENES UNDERGO CHLORINATION to form chlorine substituted PRODUCTS

1004.

Write the production of CH3-CH=CH-CH3+Cl2

Answer»

Answer:

2,3 dichloro butane

Explanation:

when ALKENES UNDERGO CHLORINATION to form chlorine substituted PRODUCTS

Discussion

1005.	Material which are different to compress are called ______ material
Answer» ANSWER: INCOMPRESSIBLE i THINK

1005.

Material which are different to compress are called ______ material

Answer»

ANSWER:

INCOMPRESSIBLE i THINK

Discussion

1006.	Chemical kinetics class 12
Answer» $\rm\huge\underline{Answer}$ the BRANCH of SCIENCE concerned with the substances of which matter is composed, the investigation of their PROPERTIES and reactions, and the USE of such reactions to form NEW substances.

1006.

Chemical kinetics class 12

Answer»

$\rm\huge\underline{Answer}$

the BRANCH of SCIENCE concerned with the substances of which matter is composed, the investigation of their PROPERTIES and reactions, and the USE of such reactions to form NEW substances.

Discussion

1007.	PB 3 O 4 + 8 HCL = 23 pbcl2 + cl2 + 4 H2O which is oxidizing agent
Answer» ANSWER: PB is OXIDISING agent. hope it HELPED

1007.

PB 3 O 4 + 8 HCL = 23 pbcl2 + cl2 + 4 H2O which is oxidizing agent

Answer»

ANSWER:

PB is OXIDISING agent.

hope it HELPED

Discussion

1008.	To prepare succinic anhydride write the following points1)Aim 2)Apparatus3)Chemicals4)Result
Answer» ANSWER: hyrurih4ishgeir7ehodyrhjdiejrnoxjwhkt8jdbrhdu jjdjkejri4ir8dhowi4jriodosk3kfkidid Explanation: hieirir84irjjdiwi2i0rihifidi2jjridufjrj i9ejfjdot RESORT rigifidkrkoitirjoeowo4ooficjbrjeiie

1008.

To prepare succinic anhydride write the following points1)Aim 2)Apparatus3)Chemicals4)Result

Answer»

ANSWER:

hyrurih4ishgeir7ehodyrhjdiejrnoxjwhkt8jdbrhdu jjdjkejri4ir8dhowi4jriodosk3kfkidid

Explanation:

hieirir84irjjdiwi2i0rihifidi2jjridufjrj i9ejfjdot RESORT rigifidkrkoitirjoeowo4ooficjbrjeiie

Discussion

1009.	A solution of glucose received from some research laboratory has been marked mole fraction (x)and molality (m) at 10°C. When you will calculate its molality and mole fraction in your laboratory at 20°C you will findA) mole fraction (x) and molality (m)B) mole fraction (2x) and molality (2m)C) mole fraction (x/2) and molality (m/2)D) mole fraction (x) and (m ± dm) molality
Answer» Answer: a gshsh b sjjsks c KO ans ka garnu d HS and I will SEND you

1009.

A solution of glucose received from some research laboratory has been marked mole fraction (x)and molality (m) at 10°C. When you will calculate its molality and mole fraction in your laboratory at 20°C you will findA) mole fraction (x) and molality (m)B) mole fraction (2x) and molality (2m)C) mole fraction (x/2) and molality (m/2)D) mole fraction (x) and (m ± dm) molality

Answer»

Answer:

a gshsh

b sjjsks

c KO ans ka garnu

d HS and I will SEND you

Discussion

1010.	Explain the enthalpy of neutralisation reaction of strong acid 0.5M HCL andstrong base 0.5 NaoH.write down the following points.1) Aim2)Aapparatus 3)Chemicals 4)Observations5)calculations6) Result.
Answer» 7383.83 9484 9494 9595 0696 9595 0392.9r9r 9r9 9494 9t99293 9r94 0293 9595

1010.

Explain the enthalpy of neutralisation reaction of strong acid 0.5M HCL andstrong base 0.5 NaoH.write down the following points.1) Aim2)Aapparatus 3)Chemicals 4)Observations5)calculations6) Result.

Answer»

7383.83

9484

9494

9595

0696

9595

0392.9r9r

9r9

9494

9t99293

9r94

0293

9595

Discussion

1011.	100 ml of 0.5 M H2SO4 solution is neutralized by 50 ml of 0.1 M NaOH and x ml of 0.1 MCa(OH)2. The value of x is(1) 200 ml (2) 370 ml(3) 475 ml (4) 405 ml
Answer» Answer: 100 mL of 0.5 M H2SO4 is used. 0.1 L of 0.5 M H2SO4 is used. moles of H2SO4 = 0.5 x 0.1 => 0.05 moles of H2SO4. As 50 mL of 0.1 M NaOH is utilized completely

1011.

100 ml of 0.5 M H2SO4 solution is neutralized by 50 ml of 0.1 M NaOH and x ml of 0.1 MCa(OH)2. The value of x is(1) 200 ml (2) 370 ml(3) 475 ml (4) 405 ml

Answer»

Answer:

100 mL of 0.5 M H2SO4 is used. 0.1 L of 0.5 M H2SO4 is used. moles of H2SO4 = 0.5 x 0.1 => 0.05 moles of H2SO4. As 50 mL of 0.1 M NaOH is utilized completely

Discussion

1012.	The outer most subshell of inert gas except helium contains how many electrons ?
Answer» <P>Answer: In other noble gases inner shells are full but valence shell is not full THOUGH s and p SUBSHELLS of the valence shell are full. All the noble gases EXCEPT He have a 'closed' eight-electron outer subshell CONFIGURATION (ns2np6).

1012.

The outer most subshell of inert gas except helium contains how many electrons ?

Answer»

<P>Answer:

In other noble gases inner shells are full but valence shell is not full THOUGH s and p SUBSHELLS of the valence shell are full. All the noble gases EXCEPT He have a 'closed' eight-electron outer subshell CONFIGURATION (ns2np6).

Discussion

1013.	Lamborghini or Bugatti
Answer» ANSWER: BUGATTI. . . ... . ... EXPLANATION: ...

1013.

Lamborghini or Bugatti

Answer»

ANSWER:

BUGATTI. . . ...

.

...

EXPLANATION:

...

Discussion

1014.	Atoms 6C13 and 8O17 are related to each other asA) Isotones B) Isoelectronic C) Isodiaphers D) Isosters
Answer» ANSWER: dicggnchfhfufufufufifuufu fufufufufuddufuuf xhfuffuffufugu Ufufufuufudududususuzuxudud

1014.

Atoms 6C13 and 8O17 are related to each other asA) Isotones B) Isoelectronic C) Isodiaphers D) Isosters

Answer»

ANSWER:

dicggnchfhfufufufufifuufu fufufufufuddufuuf

xhfuffuffufugu Ufufufuufudududususuzuxudud

Discussion

1015.	The ratio of the oxygen in FeO and Fe2O3 is (containing equal amount of Fe).(1) 1 : 3 (2) 2 : 3(3) 1 : 2 (4) 3 : 2
Answer» ANSWER: AAAAAAAA. i. think Explanation: 1 : 2 i hope i m right.

1015.

The ratio of the oxygen in FeO and Fe2O3 is (containing equal amount of Fe).(1) 1 : 3 (2) 2 : 3(3) 1 : 2 (4) 3 : 2

Answer»

ANSWER:

AAAAAAAA. i. think

Explanation:

1 : 2

i hope i m right.

Discussion

1016.	The pH of a sodium acetate–acetic acid buffer is 4.50. Calculate the ratio [CH3COO-]/[CH3COOH].
Answer» THE EQUATION THAT WILL BE USED IS THE HENDERSON-HESSELBACH EQUATION. pH=pka + LOG [BASE]/[ACID] IN THE SYSTEM THE BASE IS CH3COO— WHILE THE ACID IS CH3COOH. • THE pKa OF ACETIC ACID IS 4.75. 4.50 = 4.75 + LOG [CH3COO—] / [CH3COOH] 4.50-4.75= LOG [CH3COO—] / [ CH3COOH] -0. 25 = LOG [CH3COO—] / [CH3COOH] [CH3COO—] / [CH3COOH] = O. 56 I HOPE THIS ANSWER WILL HELPFULL TO YOU. PLS MARK ME AS BRAINBRAINLIEST

1016.

The pH of a sodium acetate–acetic acid buffer is 4.50. Calculate the ratio [CH3COO-]/[CH3COOH].

Answer»

THE EQUATION THAT WILL BE USED IS THE HENDERSON-HESSELBACH EQUATION.

pH=pka + LOG [BASE]/[ACID]

IN THE SYSTEM THE BASE IS CH3COO—

WHILE THE ACID IS CH3COOH.

• THE pKa OF ACETIC ACID IS 4.75.

4.50 = 4.75 + LOG [CH3COO—] / [CH3COOH]

4.50-4.75= LOG [CH3COO—] / [ CH3COOH]

-0. 25 = LOG [CH3COO—] / [CH3COOH]

[CH3COO—] / [CH3COOH] = O. 56

I HOPE THIS ANSWER WILL HELPFULL TO YOU.

PLS MARK ME AS BRAINBRAINLIEST

Discussion

1017.	বিভিন্ন কাজে মিথেনের ব্যবহার
Answer» EXPLANATION: মিথেনের ব্যবহার : ১) জ্বালানিরূপে ২) H2-এর পণ্য উৎপাদনে । ৩) কার্বন ব্ল্যাক প্রস্তুতিতে । ৪) মিথাইল অ্যালকোহল প্রস্তুতিতে । ৫) মোটরগাড়ির টায়ার, টাইপ মেশিনের ফিতা, ছাপাখানার কালি প্রস্তুতিতে । ৬) গ্রামোফোন রেকর্ড প্রস্তুতিতে ।

1017.

বিভিন্ন কাজে মিথেনের ব্যবহার

Answer»

EXPLANATION:

মিথেনের ব্যবহার :

১) জ্বালানিরূপে

২) H2-এর পণ্য উৎপাদনে ।

৩) কার্বন ব্ল্যাক প্রস্তুতিতে ।

৪) মিথাইল অ্যালকোহল প্রস্তুতিতে ।

৫) মোটরগাড়ির টায়ার, টাইপ মেশিনের ফিতা, ছাপাখানার কালি প্রস্তুতিতে ।

৬) গ্রামোফোন রেকর্ড প্রস্তুতিতে ।

Discussion

1018.	Is vilyan se kmno4 ki molrata gyat kare
Answer» $\rm\huge\underline{Answer}$ the branch of science concerned with the SUBSTANCES of which matter is composed, the investigation of their properties and reactions, and the USE of such reactions to FORM NEW substances.

1018.

Is vilyan se kmno4 ki molrata gyat kare

Answer»

$\rm\huge\underline{Answer}$

the branch of science concerned with the SUBSTANCES of which matter is composed, the investigation of their properties and reactions, and the USE of such reactions to FORM NEW substances.

Discussion

1019.	WHAT IS THE LATIN NAME OF XEON
Answer» EXPLANATION: THE LATIN NAME OF XENON is XENON The name is DERIVED from the Greek 'xenos' MEANING stranger.

1019.

WHAT IS THE LATIN NAME OF XEON

Answer»

EXPLANATION:

THE LATIN NAME OF XENON is XENON

The name is DERIVED from the Greek 'xenos' MEANING stranger.

Discussion

1020.	3. By Wade's rules, which cluster description isincorrect?A.[B5H8]–is anidoclusterB.[B6H6]2–is aclosoclusterC.[B10H13]–is anarachnoclusterD.[B4H9]–is anarachnocluster
Answer» Answer: Cherrapunji holds two Guinness WORLD records for receiving the maximum amount of RAINFALL in a SINGLE YEAR, 26,471mm (1,042.2 in) of rainfall between AUGUST 1860 and July 1861 and the maximum amount of rainfall in a single month (9,300mm) in July 1861. Explanation: sorry for spamming your question. please drop 30 thanks I will return you back.

1020.

3. By Wade's rules, which cluster description isincorrect?A.[B5H8]–is anidoclusterB.[B6H6]2–is aclosoclusterC.[B10H13]–is anarachnoclusterD.[B4H9]–is anarachnocluster

Answer»

Answer:

Cherrapunji holds two Guinness WORLD records for receiving the maximum amount of RAINFALL in a SINGLE YEAR, 26,471mm (1,042.2 in) of rainfall between AUGUST 1860 and July 1861 and the maximum amount of rainfall in a single month (9,300mm) in July 1861.

Explanation:

sorry for spamming your question.

please drop 30 thanks I will return you back.

Discussion

1021.	34 g of hydrogen peroxide is present in 1120 mL of solution. Volume strength of solution is
Answer» Answer: 34 g of H_(2)O_(2) is PRESENT in 1120 " mL of " SOLUTION. This solution is CALLED. 1NofH2O2=5.6 volume STRENGTH.

1021.

34 g of hydrogen peroxide is present in 1120 mL of solution. Volume strength of solution is

Answer»

Answer:

34 g of H_(2)O_(2) is PRESENT in 1120 " mL of " SOLUTION. This solution is CALLED. 1NofH2O2=5.6 volume STRENGTH.

Discussion

1022.	what volume of water will contain 2.4 Na of neutrons ? ( where Na = Avogadro number = 6.022 × 10²³ )
Answer» Answer: Correct option is B 10N a The density of WATER is 18 G/mol. 18 mL of water corresponds to 18 g or 1 mole. They contain N a (Avogadro's NUMBER) of molecules. Each water molecule contains total 2+8=10 electrons (2 from 2 H ATOMS and 8 from ONE O atom). Hence, 18 mL of water will contain 10 N a electrons.

1022.

what volume of water will contain 2.4 Na of neutrons ? ( where Na = Avogadro number = 6.022 × 10²³ )

Answer»

Answer:

Correct option is

B

10N

a

The density of WATER is 18 G/mol.

18 mL of water corresponds to 18 g or 1 mole. They contain N

a

(Avogadro's NUMBER) of molecules.

Each water molecule contains total 2+8=10 electrons (2 from 2 H ATOMS and 8 from ONE O atom).

Hence, 18 mL of water will contain 10 N

a

electrons.

Discussion

1023.	2 1 What iš Science?
Answer» $\huge \bigstar { \underline{ \mathtt{ \red{A}{ \pink{n}{ \color{blue}{s}{ \color{gold}{w}{ \color{aqua}{e}{ \color{lime}{r}}}}}}}}}★$ SCIENCE is SUBJECT •••(◠‿・)—☆

1023.

2 1 What iš Science?

Answer»

$\huge \bigstar { \underline{ \mathtt{ \red{A}{ \pink{n}{ \color{blue}{s}{ \color{gold}{w}{ \color{aqua}{e}{ \color{lime}{r}}}}}}}}}★$

SCIENCE is SUBJECT •••(◠‿・)—☆

Discussion

1024.	The degree of hydrolysis of 0.1 M nh4cl solution is 1%. If the concentration of nh4cl is made 0.4 M, what is the new degree of hydrolysis
Answer» ANSWER: dicggnchfhfufufufufifuufu fufufufufuddufuuf xhfuffuffufugu Ufufufuufudududususuzuxudud

1024.

The degree of hydrolysis of 0.1 M nh4cl solution is 1%. If the concentration of nh4cl is made 0.4 M, what is the new degree of hydrolysis

Answer»

ANSWER:

dicggnchfhfufufufufifuufu fufufufufuddufuuf

xhfuffuffufugu Ufufufuufudududususuzuxudud

Discussion

1025.	20 g of solute X are dissolved in 50 g of water. 15 g of solute Y are dissolved in 70 g of benzene. Themolalities of the solutes in these two solutions are the same. Hence, the ratio of the molecular weights of solute X to that of the solute Y is
Answer» Answer: 15 g of SOLUTE Y are dissolved in 70 g of benzene. The molalities of the SOLUTES in these TWO SOLUTIONS are the same. HENCE, the ratio of the molecular. Explanation: hope it helped you

1025.

20 g of solute X are dissolved in 50 g of water. 15 g of solute Y are dissolved in 70 g of benzene. Themolalities of the solutes in these two solutions are the same. Hence, the ratio of the molecular weights of solute X to that of the solute Y is

Answer»

Answer:

15 g of SOLUTE Y are dissolved in 70 g of benzene. The molalities of the SOLUTES in these TWO SOLUTIONS are the same. HENCE, the ratio of the molecular.

Explanation:

hope it helped you

Discussion

1026.	All matter in any state is made up of small
Answer» Answer: ATOMS Explanation: All MATTER in any state is MADE up of SMALL atoms

1026.

All matter in any state is made up of small

Answer»

Answer:

ATOMS

Explanation:

All MATTER in any state is MADE up of SMALL atoms

Discussion

1027.	The conductometry cell constant of conductivity is
Answer» Conductivity of cell= Conductance MULTIPLIED by cell CONSTANT. I HOPE THIS ANSWER WILL HELPFULL TO YOU. PLSS MARK ME AS BRAINLIEST.

1027.

The conductometry cell constant of conductivity is

Answer»

Conductivity of cell= Conductance MULTIPLIED by cell CONSTANT.

I HOPE THIS ANSWER WILL HELPFULL TO YOU.

PLSS MARK ME AS BRAINLIEST.

Discussion

1028.	Iron + oxygen => Ferric oxide ( Rust)
Answer» Explanation: HOPE it HELPS you PLZ MARK me as BRAINLIEST

1028.

Iron + oxygen => Ferric oxide ( Rust)

Answer»

Explanation:

HOPE it HELPS you

PLZ MARK me as BRAINLIEST

Discussion

1029.	2 g of iron sulphate crystals are heated in a dry boiling tube. a. List any two observations. b. Name the type of chemical reaction taking place. c. Write the chemical equation for the reaction.
Answer» ANSWER: fififufif tififiewudt of the YEAR again when we all PLEDGE to Explanation: changehtfrfhffjvfxjciihguxtuxucuofxoudxouuocuoucoiydidoudououdoudoduduooduifpfipfuofouyidrtifgkgjvkhjgfdutgih

1029.

2 g of iron sulphate crystals are heated in a dry boiling tube. a. List any two observations. b. Name the type of chemical reaction taking place. c. Write the chemical equation for the reaction.

Answer»

ANSWER:

fififufif tififiewudt of the YEAR again when we all PLEDGE to

Explanation:

changehtfrfhffjvfxjciihguxtuxucuofxoudxouuocuoucoiydidoudououdoudoduduooduifpfipfuofouyidrtifgkgjvkhjgfdutgih

Discussion

1030.	What is precipitation?Explain briefly.
Answer» ANSWER: PRECIPITATION is the PROCESS of RAIN

1030.

What is precipitation?Explain briefly.

Answer»

ANSWER:

PRECIPITATION is the PROCESS of RAIN

Discussion

1031.	Give examples states of matter which are fluid in nature
Answer» ANSWER: answer is LIQUID CRYSTAL STATES

1031.

Give examples states of matter which are fluid in nature

Answer»

ANSWER:

answer is LIQUID CRYSTAL STATES

Discussion

1032.	A Solution of 1.2 g of a non volatile substance in 100 gm acetone at 20c and vapour pressure of 182. 5 mm of Hg if vapour pressure of acetone in 20 cin 185 mm of Hg calculate the molecular mass of the substance?
Answer» When 1.2 G of a non-volatile substance was dissolved in 100 g of acetone at 20oC, its vapour PRESSURE was 183 TORR. The MOLAR mass (g mol-1 ) of the substance is: 32.

1032.

A Solution of 1.2 g of a non volatile substance in 100 gm acetone at 20c and vapour pressure of 182. 5 mm of Hg if vapour pressure of acetone in 20 cin 185 mm of Hg calculate the molecular mass of the substance?

Answer»

When 1.2 G of a non-volatile substance was dissolved in 100 g of acetone at 20oC, its vapour PRESSURE was 183 TORR. The MOLAR mass (g mol-1 ) of the substance is: 32.

Discussion

1033.	Calcuate the molarity of 10.6percentw/v of na2co3
Answer» Answer: HI ! Explanation: MOLARITY can be FOUND with this formula: molarity=number of moles/VOLUME (L) We KNOW the volume, which is. 500mL = 0.5 L. ... We have 10.6g/106g/mol = 0.1mol. From n = MV, 0.1 = M x 0.5, so M = 0.1/0.5 = 0.2.

1033.

Calcuate the molarity of 10.6percentw/v of na2co3

Answer»

Answer:

HI !

Explanation:

MOLARITY can be FOUND with this formula: molarity=number of moles/VOLUME (L) We KNOW the volume, which is. 500mL = 0.5 L. ... We have 10.6g/106g/mol = 0.1mol. From n = MV, 0.1 = M x 0.5, so M = 0.1/0.5 = 0.2.

Discussion

1034.	They are used to protect body and clothing from chemical hazards?
Answer» ANSWER: Personal PROTECTIVE equipment (PPE) is protective clothing, helmets, goggles, or other garments or equipment designed to PROTECT the wearer's body from injury or infection. The hazards addressed by protective equipment include PHYSICAL, electrical, heat, chemicals, biohazards, and airborne particulate matter. *HOPE* *YOU* *LIKE* *THIS* *ANSWER* *PLEASE* *MARK* AS *BRAINLIST*.

1034.

They are used to protect body and clothing from chemical hazards?

Answer»

ANSWER:

Personal PROTECTIVE equipment (PPE) is protective clothing, helmets, goggles, or other garments or equipment designed to PROTECT the wearer's body from injury or infection. The hazards addressed by protective equipment include PHYSICAL, electrical, heat, chemicals, biohazards, and airborne particulate matter.

HOPE YOU LIKE THIS ANSWER

PLEASE MARK AS BRAINLIST.

Discussion

1035.	China rose sollution imparts_____colour in basic medium
Answer» ANSWER: SOAK some PETALS of china rose in warm water for a couple of hours. The red-coloured solution is used as an indicator for detecting an ACID or a base solution. It turns into magenta in acidic medium and green in basic medium. Hence, it is a natural indicator.

1035.

China rose sollution imparts_____colour in basic medium

Answer»

ANSWER:

SOAK some PETALS of china rose in warm water for a couple of hours. The red-coloured solution is used as an indicator for detecting an ACID or a base solution. It turns into magenta in acidic medium and green in basic medium. Hence, it is a natural indicator.

Discussion

1036.	With the help of this solution determining the molarity of given kmno4 solutions
Answer» Answer: To determine the concentration/molarity of KMnO4 SOLUTION by titrating it against standard solution of FERROUS ammonium sulphate. (Molar mass of FeSO4(NH4)2SO4 . 6H2O = 392 G mol– 1). (i) Weigh 4.9000 g of ferrous ammonium sulphate and transfer it into a 250 ML measuring flask through a funnel.

1036.

With the help of this solution determining the molarity of given kmno4 solutions

Answer»

Answer:

To determine the concentration/molarity of KMnO4 SOLUTION by titrating it against standard solution of FERROUS ammonium sulphate. (Molar mass of FeSO4(NH4)2SO4 . 6H2O = 392 G mol–

1). (i) Weigh 4.9000 g of ferrous ammonium sulphate and transfer it into a 250 ML measuring flask through a funnel.

Discussion

1037.	एल्डिहाइड और कीटोन का LiAIH4 द्वारा अपचयन पर टिप्पणी लिखिए।Write note on reduction of Aldehyde and Ketone of LiAlH4.
Answer» ANSWER: I don't KNOW the answer of this QUESTION

1037.

एल्डिहाइड और कीटोन का LiAIH4 द्वारा अपचयन पर टिप्पणी लिखिए।Write note on reduction of Aldehyde and Ketone of LiAlH4.

Answer»

ANSWER:

I don't KNOW the answer of this QUESTION

Discussion

1038.	As per IUPAC nomenclature, the name of the complex [Co (H2O)4(NH3 )2]C13 is
Answer» Explanation: ANSWER :- ⬇️ [Co (H2O)4(NH3 )2]C13 is Diaminetetraaquacobalt (III) chloride.

1038.

As per IUPAC nomenclature, the name of the complex [Co (H2O)4(NH3 )2]C13 is

Answer»

Explanation:

ANSWER :- ⬇️

[Co (H2O)4(NH3 )2]C13 is Diaminetetraaquacobalt (III) chloride.

Discussion

1039.	What will the element with atmic number 118 be ?
Answer» OGANESSON is the ELEMENT with ATOMIC NUMBER 118.

Discussion

1040.	Longest wavelength occurs for
Answer» ANSWER: To find the longest wavelength, energy released should be minimum. Complete step-by-step answer: The Balmer SERIES is a particular PART of the electromagnetic spectrum of hydrogen with definite starting and final ORBITAL through which the electronic TRANSITION occurs.

1040.

Longest wavelength occurs for

Answer»

ANSWER:

To find the longest wavelength, energy released should be minimum. Complete step-by-step answer: The Balmer SERIES is a particular PART of the electromagnetic spectrum of hydrogen with definite starting and final ORBITAL through which the electronic TRANSITION occurs.

Discussion

1041.	500ml of 0.1 M HCL+100ml of 0.1 nhso4+400ml of 0.1M ca(oH)2 write solution step by step
Answer» Answer: Calculate the pH of the resultant mixtures:a) 10 ML of 0.2M Ca (OH)2 + 25 mL of 0.1M HCL B) 10 mL of 0.01M H2SO4 + 10 mL of 0.01M Ca (OH)2 C) ...

1041.

500ml of 0.1 M HCL+100ml of 0.1 nhso4+400ml of 0.1M ca(oH)2 write solution step by step

Answer»

Answer:

Calculate the pH of the resultant mixtures:a) 10 ML of 0.2M Ca (OH)2 + 25 mL of 0.1M HCL B) 10 mL of 0.01M H2SO4 + 10 mL of 0.01M Ca (OH)2 C) ...

Discussion

1042.	What happens when crystalline CuSo⁴ is heated ? write the colour of the new substance formed.
Answer» Answer: When crystalline COPPER sulphate(CUSO4) is heated, it loses the water of crystallisation and thereby results in the formation of anhydrous copper sulphate. The colour of the new SUBSTANCE formed is white. Explanation: I HOPE it can help you☺❤

1042.

What happens when crystalline CuSo⁴ is heated ? write the colour of the new substance formed.

Answer»

Answer:

When crystalline COPPER sulphate(CUSO4) is heated, it loses the water of crystallisation and thereby results in the formation of anhydrous copper sulphate. The colour of the new SUBSTANCE formed is white.

Explanation:

I HOPE it can help you☺❤

Discussion

1043.	Find pressure after opening stopcork
Answer» $\rm\huge\underline{Answer}$ the branch of science concerned with the SUBSTANCES of which MATTER is composed, the investigation of their properties and reactions, and the use of such reactions to FORM new substances.

1043.

Find pressure after opening stopcork

Answer»

$\rm\huge\underline{Answer}$

the branch of science concerned with the SUBSTANCES of which MATTER is composed, the investigation of their properties and reactions, and the use of such reactions to FORM new substances.

Discussion

1044.	What happens when react with water
Answer» EXPLANATION: Metals react with water and produce a metal oxide and hydrogen GAS. ... It reacts with hot water to form MAGNESIUM hydroxide and hydrogen. It also starts floating due to the bubbles of hydrogen gas sticking to its surface. Metals LIKE aluminium, iron and zinc do not react EITHER with cold or hot water.

1044.

What happens when react with water

Answer»

EXPLANATION:

Metals react with water and produce a metal oxide and hydrogen GAS. ... It reacts with hot water to form MAGNESIUM hydroxide and hydrogen. It also starts floating due to the bubbles of hydrogen gas sticking to its surface. Metals LIKE aluminium, iron and zinc do not react EITHER with cold or hot water.

Discussion

1045.	What is the use of common salt in soap industries
Answer» Answer:- → Common salt is mainly ADDED to the neat soap after the saponification reaction when the soap is washed with NaCl or Brine SOLUTION in order to separate glycerin. → It is mainly added for precipitation to separate it from the AQUEOUS solution. Salt is also used in order to separate glycerol from the WATER. __________________

1045.

What is the use of common salt in soap industries

Answer»

Answer:-

→ Common salt is mainly ADDED to the neat soap after the saponification reaction when the soap is washed with NaCl or Brine SOLUTION in order to separate glycerin.

→ It is mainly added for precipitation to

separate it from the AQUEOUS solution.

Salt is also used in order to separate

glycerol from the WATER.

__________________

Discussion

1046.	At triple point of a one-component system, the vapour pressure of solid phase as compared to that of the liquid phase is?A. SameB. LessC. MoreD. More or less, depending on the system
Answer» ANSWER: same OPTION C Explanation: same option c

1046.

At triple point of a one-component system, the vapour pressure of solid phase as compared to that of the liquid phase is?A. SameB. LessC. MoreD. More or less, depending on the system

Answer»

ANSWER:

same OPTION C

Explanation:

same option c

Discussion

1047.	Calculate the number of protons , neutrons and electrons in 5.4 gram of NH4+ ions ?
Answer» ANSWER: what's NEW in box and subscribe my CHANNEL THE NUCLEAR FAMILY

1047.

Calculate the number of protons , neutrons and electrons in 5.4 gram of NH4+ ions ?

Answer»

ANSWER:

what's NEW in box and subscribe my CHANNEL THE NUCLEAR FAMILY

Discussion

1048.	Explain the process of manufacturing bleaching powder
Answer» BLEACHING powder can be prepared by NaCl. preparation of Bleaching powder by NaCl ➤ The chlorine gas produced during the chlor-alkali process is used for manufacturing Bleaching powder by the action of chlorine gas on dry SLAKED lime. Ca(OH)2 + Cl2 ⸻➤CaOCl2 + H2O. Ca(OH)2 - Dry slaked lime. Cl2 - Chlorine. CaOCl2- CALCIUM of chloride ( Bleaching powder) H2O - water. ⸻➤ Uses of CaOCl2 :- For Bleaching cotton , linen , wood pupl and washed CLOTHES in LAUNDRY. As an oxidising agent in chemical industry. For disinfecting water ( to make it free from germs.) _______________ ●Hope it helps you

1048.

Explain the process of manufacturing bleaching powder

Answer»

BLEACHING powder can be prepared by NaCl.

preparation of Bleaching powder by NaCl ➤

The chlorine gas produced during the chlor-alkali process is used for manufacturing Bleaching powder by the action of chlorine gas on dry SLAKED lime.

Ca(OH)2 + Cl2 ⸻➤CaOCl2 + H2O.

Ca(OH)2 - Dry slaked lime.

Cl2 - Chlorine.

CaOCl2- CALCIUM of chloride ( Bleaching powder)

H2O - water.

⸻➤ Uses of CaOCl2 :-

For Bleaching cotton , linen , wood pupl and washed CLOTHES in LAUNDRY.
As an oxidising agent in chemical industry.
For disinfecting water ( to make it free from germs.)

_______________

●Hope it helps you

Discussion

1049.	List out the importance of PH in our daily life
Answer» Answer: pH is very important in our digestive system. In the stomach, hydrochloric acid is secreted as FOOD enters the stomach. It turns the pH of the stomach between 1 and 3. This pH is important for the ACTIVATION of the enzyme pepsin, which helps in the DIGESTION of protein in food. Hope it helps pls mark me as BRAINLIEST

1049.

List out the importance of PH in our daily life

Answer»

Answer:

pH is very important in our digestive system. In the stomach, hydrochloric acid is secreted as FOOD enters the stomach. It turns the pH of the stomach between 1 and 3. This pH is important for the ACTIVATION of the enzyme pepsin, which helps in the DIGESTION of protein in food.

Hope it helps

pls mark me as BRAINLIEST

Discussion

1050.	Are decomposition reaction give example
Answer» ANSWER: decomposition reaction occurs when one reactant breaks down into two or more products. This can be REPRESENTED by the general equation: AB → A + B. Examples of decomposition reactions include the BREAKDOWN of hydrogen peroxide to WATER and oxygen, and the breakdown of water to hydrogen and oxygen.

1050.

Are decomposition reaction give example

Answer»

ANSWER:

decomposition reaction occurs when one reactant breaks down into two or more products. This can be REPRESENTED by the general equation: AB → A + B. Examples of decomposition reactions include the BREAKDOWN of hydrogen peroxide to WATER and oxygen, and the breakdown of water to hydrogen and oxygen.

Discussion

Explore topic-wise InterviewSolutions in .

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एल्डिहाइड और कीटोन का LiAIH4 द्वारा अपचयन पर टिप्पणी लिखिए।Write note on reduction of Aldehyde and Ketone of LiAlH4.​

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Answer:-

__________________

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2 1 What iš Science?

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500ml of 0.1 M HCL+100ml of 0.1 nhso4+400ml of 0.1M ca(oH)2 write solution step by step

What happens when crystalline CuSo⁴ is heated ? write the colour of the new substance formed.

Find pressure after opening stopcork

What happens when react with water

What is the use of common salt in soap industries

At triple point of a one-component system, the vapour pressure of solid phase as compared to that of the liquid phase is?A. SameB. LessC. MoreD. More or less, depending on the system

Calculate the number of protons , neutrons and electrons in 5.4 gram of NH4+ ions ?

Explain the process of manufacturing bleaching powder

List out the importance of PH in our daily life

Are decomposition reaction give example