Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1451.

Answer please the question​

Answer»

EXPLANATION:

titiittiot9ttoxitstydrutisury

1452.

Name the following : a :- A process of converting solid into its liquid state​

Answer»

ANSWER:

\huge\sf\pink{A}\blue{n}\purple{s}\red{w}\purple{e}\green{r :-}

EXPLANATION:

MELTING

1453.

Name the neutral gas reloved when calcium sulphate is decomposed​

Answer»

when heated for ONE hour at temperatures in EXCESS of 900°C, will PRODUCE the,insoluble ANHYDRITE form. The eqililibrium decomposition pressure of calcium sulfate was also.

1454.

Guy's no spam please '​

Answer»

ANSWER:

2) BENEZENE ACETONE is the answer

1455.

Identify the oxidising agent (oxidant) in the following reactions(a) 3Fe + 4H₂O ⎯→ Fe₃O₄ + 4H₂ (b) CuO + H₂ ⎯→ Cu + H₂O * 2 points (a) H₂O and (b) H₂ (a) Fe and (b) H₂ (a) Fe and (b) CuO (a) H₂O and (b) CuO​

Answer»

Answer:

In PART (a) 3Fe + 4H₂O ⎯→ Fe₃O₄ + 4H₂,   H₂O is ACTING as an Oxidising Agent

In part (b) CUO + H₂ ⎯→ CU + H₂O,   CuO is acting as an Oxidising Agent

Pls mark the answer as BRAINLIEST

: )

1456.

Which symbol is used in insoluble product​

Answer»

Explanation:

The solutes will be soluble, and THEREFORE will be in AQUEOUS solution, as indicated with the symbol (aq) written after the chemical FORMULA of the solute. The PRECIPITATE will be insoluble, which is indicated with the symbol (s) written after the chemical formula of the precipitate.

1457.

Identify three kinds of impurities present in natural water. explain using formula​

Answer»

Answer:

  • MICROORGANISMS. Bacteria, algae and FUNGI all regularly interfere with sterile research APPLICATIONS. ...
  • Viruses. ...
  • Pyrogens. ...
  • DISSOLVED Inorganic Ions. ...
  • Dissolved Organic Compounds. ...
  • Dissolved Gases. ...
  • Suspended PARTICLES. ...
  • Colloidal Particles.

Explanation:

1458.

balancing the following (i) NaoH + H2SO4 ------> Na2SO4 + h2o (ii) Bacl2 + H2SO4-------> BaSo4 + Hcl​

Answer»

ANSWER:

रैदास को क्यों प्रतीत होता हैकि उनके प्रभुउन पर द्रवि त हो गए हैं?

1459.

Which of the following mixture does not show positive deviation from Raoult’s law? * (a) Acetone-chloroform (b) Benzene-Acetone (c) Benzene-Ethanol (d) Benzene-carbon tetrachloride​

Answer»

ANSWER:

The answer is Benzene-chloroform

♡itznakhrebaaz♡

1460.

A radical is a group of elements that behaves like a single unit and shows a particular valency.True or FalseThose who will give correct answer i will mark him brainliest,give likes and give 5 star ratings.​

Answer»

ANSWER:

TRUE is the answer of your QUESTION!!!

1461.

Give me a correct answer guy's please ​

Answer»

ANSWER:

no a. will be the ANSWERRRRRRR

1462.

What is a element name of Sulphuric acid​

Answer»

Answer:

Sulfuric acid (American SPELLING) or sulphuric acid (Commonwealth spelling), also KNOWN as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and HYDROGEN, with the molecular formula H2SO4.

1463.

Solve the following for BRAINLISTS mark​

Answer»

ANSWER:

reduction

OXIDATION

oxidatipn

reduction

oxidation

1464.

What volume of at sulphur dioxide will be produced at STP and complete burning of 260 g of sulphur .

Answer»

Answer:

8

Explanation:

The balanced chemical REACTION is S(s)+O  

2

(g)→SO  

2

(g)

1 mole of S REACTS with 1 mole of O  

2

 to form 1 mole of SO  

2

.

Volume at STP is DIRECTLY proportional to the NUMBER of moles.

Hence, 8 mole of S reacts with 8 mole of O  

2

 to form 8 mole of SO  

2

.

1465.

DatePageThe maler Conductivity of Nal Hd andinfinite delicte915cm? mal-respectively. The molar Conductivity ofCH₃COOH at infinite126.46, 426.16 and​

Answer»

Answer:

5rcd8td8tet8vt7dyidyidtudt7dt7d7tdydyf

Explanation:

dt7st7dt7dtyiyycyid8yf

1466.

For a zero order reaction, the integrated rate equation is: *(a) =[]/[](b) kt = [A] – [Ao](c) [A] = -kt + [Ao](d) [A] = kt – [Ao]​

Answer»

Answer:

KT = [A] — [Ao] (b)

EXPLANATION:

Hope it will HELPFUL for you thanks..

CHEMISTRY lover here!

1467.

The number of significant figures in 0.10 is a) 1 b) 2 c) 3 O d) 4​

Answer»

ANSWER:

option (b)

Explanation:

HOPE <U>it HELP u out please mark it brainliest and follow me

1468.

The Arrhenius equation which relates the rate constant (k), activation energy (Ea) andTemperature(T) is *(a) k=A²e⁻ᴱᵃ/ᴿᵀ(b) k= A e⁻²ᴱᵃ/ᴿᵀ(c) k=A e⁻ᴱᵃ/ᴿᵀ(d) k=Ae⁻ᴱᵃ/²ᴿᵀ​

Answer»

Arrhenius Equation :

\boxed{ \sf  k = A {e}^{  - Ea/RT}}

OPTION c) is correct !

Let's DEFINE the terms:

  • 'A' is a pre-exponential factor or frequency.

  • e^{(-Ea/RT)} represents the fraction of molecular collisions with ADEQUATE energy LEVELS needed to overcome the Activation Barrier of the reaction at that specific TEMPERATURE T.

  • ''k' is rate constant.

  • ''R' is Gas Constant, 'T' is temperature (in Kelvin).

Now, if we take ln on both sides :

\boxed{ \sf ln(k)  =  -  \dfrac{ E_{a} }{RT}  +  ln(A) }

1469.

Write the Lewis dot symbols for following atoms and ions: N, O, P, O2- , N 3- , Mg2+ , F​

Answer»

Answer:

N3-

EXPLANATION:

HOPE it will HELPFUL for you THANKS..

1470.

An electrochemical cell can behave like an electrolytic cell when: *(a) E꜀ₑₗₗ=0(b) E꜀ₑₗₗ>Eₑₓₜ(c) Eₑₓₜ>E꜀ₑₗₗ(d) E꜀ₑₗₗ=Eₑₓₜ​

Answer»

Answer:

c

Explanation:

C

E

ext

>E

cell

We can study the effect of opposing potential applied to a galvanic cell as follows.

1) When E

external

<1.1V

In a galvanic cell, if an external opposite potential is applied and increased slowly, we find that the REACTION continues to take place till the opposing voltage reaches the value 1.1 V.

2) When E

external

=1.1V

When the external voltage is 1.1V the reaction stops ALTOGETHER and no CURRENT flows through the cell.

3) When E

external

>1.1V

Any further increase in the external potential again starts the reaction but in the opposite direction. It now functions as an electrolytic cell, a device for using ELECTRICAL energy to carry non-spontaneous chemical reactions.

1471.

Heating ice convert water into vapour . This energy is constant and is equal to A. 33.4 x10^5joules/gramB. 3.34 x10^5 kilo joules/kilogramC. 234 x10^5 joules/gramD. 2240 x10^5 joules/gram​

Answer»

ANSWER:

A. 33.4 x10^5joules/gramB

1472.

With 10 degree rise in temperature the rate of the reaction increases *(a) 4 times(b) 10 times(c) 2 times(d) Does not change​

Answer»

ANSWER:

\huge\sf\pink{A}\blue{n}\purple{s}\red{w}\purple{e}\green{r :-}

Explanation:

2 TIMES

1473.

A patient suffering from deficiency of sodium, was given intravenous 1 L of 0.9%(w/v) sodium chloride (normal saline) solution. The amount of sodium chloride needed to prepare this 1 lit of solution is ‘x’ g. Find ‘x’. Sarika dissolved this ‘x’ g of sodium chloride in 1 L of water to prepare the normal saline solution in the school laboratory, but her teacher said that she has made a mistake. Can you identify what mistake has been done by Sarika?​

Answer»

EXPLANATION:

d3dRn opgwydg9gd2dp1 uogdqcgi0qs0igcipg1cs

1474.

5. C₂H₂ + Cl₂ सूर्य का प्रकाश x; अभिक्रिया में x है (A) क्लोरोबेंजीन (B) बी.एच.सी. (C) हेक्साक्लोरोबेंजीन (D) डाईक्लोरोबेंजीन​

Answer»

Answer:

HA lekh kala safar karun todun mi tyala vicharle ki tu dole ki tu aata JARA mala havya hotya AANI rajya sarakarchya vatine karanyat to discuss

hkflkghdhfmxgrajvnxgfjshffbxtdjjxgfkvhcibjkfycy UC BERKELEY and I will SEND

1475.

The boiling point of a substance is 118 degree Celsius. what will it be on Kelvin scalel​

Answer»

Answer:

391 K

Explanation:

K= TEMPERATURE in °C + 273

118+273

391 K.

Hope it HELPS!!

1476.

What are the characteristics of the particles of matter ?i) When commen salt is dissolved in water, what will be the change in volume and why..?ii) Write one similarity between the three states of matter..? ​

Answer»

Answer:

Characteristics of Particles of MATTER

Particles of matter are very TINY in size.

They have spaces between them.

Particles of matter MOVE constantly.

They are attracted TOWARDS each other

1477.

Identify the following reactions as oxidation and reduction:-I. O+2e-= O2-II. K -e- =K+III. Fe3+ Fe2+IV. Zn =Zn2+ +2e-V. Na+= Na -e​

Answer»

Explanation:

1. Oxidation

2. REDUCTION

3. Reduction

4. Reduction

5. Reduction

1478.

A patient suffering from deficiency of sodium, was given intravenous 1 L of 0.9%(w/v) sodium chloride (normal saline) solution. The amount of sodium chloride needed to prepare this 1 lit of solution is ‘x’ g. Find ‘x’. Sarika dissolved this ‘x’ g of sodium chloride in 1 L of water to prepare the normal saline solution in the school laboratory, but her teacher said that she has made a mistake. Can you identify what mistake has been done by Sarika?give correct answer​

Answer»

ANSWER:

I don't KNOW what is this I m in 9TH CLASS

EXPLANATION:

I don't know I m in 9th class

1479.

Which of the following substances will not dissolve in water?(a) sugar(b) Sodium chloride(c) copper sulphate(d) Carbon

Answer»

ANSWER:

CARBON will not DISSOLVED in WATER

1480.

Define motion??????????leaving​

Answer»

ANSWER:

MOVEMENT or a WAY of moving

गति या गति करने का प्रकार

Explanation:

MARK me as BRAINLIEST

1481.

Answer asap and correctly please​

Answer»

ANSWER:

SODIUM I GUESS but I am Not SURE

1482.

Gases flow in all directions due toa) High speed of particles and large space between themb) Large space between them and low speed of particles c) Low speed of particles and large space between them d) Less space between particles and low speed of particles​

Answer»

Explanation:

Option A is correct

High speed of PARTICLES and LARGE SPACE between them.

1483.

Galvanisation is the process of *(a) Deposition of Al on Fe(b) Deposition of Zn on Fe(c) Deposition of Sn on Fe(d) Deposition of Ni on Fe​

Answer»

ANSWER:

(B) DEPOSITION of ZN on FE

1484.

In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate is formed is of : 1. KNO3 2. PbNO3 3. Pbl2 4. KI​

Answer»

Answer:

PbNO3

Explanation:

Correct option is

B

LEAD acetate

2KI(aq)+Pb(NO

3

)

2

(aq)→PbI

2

(s)+2KNO

3

In the above DOUBLE displacement reaction, potassium IODIDE(KI) and lead nitrate (Pb(NO 3)2

dissociate in their aqueous states to form ions. The lead (Pb 2+) ions combine with the iodide (I)

ions to form PRECIPITATES of lead iodide (PPbI2)

1485.

AgCl(s)----Ag(s)+Cl2(g)Balance the equationAlso explain it.​

Answer»

Answer :-

2 AgCl → 2 Ag + Cl₂

Explanation :-

✠ Firstly consider the unbalanced chemical EQUATION.

AgCl → Ag + Cl₂

✠ As it can be observed there are 2 atoms of Chlorine in the product side but only 1 chlorine ATOM in the reactant side.

✠ So, MULTIPLY the reactant part by 2. This gives us:

2 AgCl → Ag + Cl₂

✠ Now again there are 2 atoms of Silver (Ag) in the reactant part but only 1 atom in the products side.

So multiply 2 for silver atom in products part.

Now the final BALANCED chemical equation would be:

2 AgCl → 2 Ag + Cl₂】

1486.

Which of the following is pure substance- *​

Answer»

ANSWER:

GOLD , COPPER , SILVER ETC.

1487.

Roasting is carried out in case of *(a) sulphide ores(b) carbonate ores(c) oxide ores(d) silicate ores​

Answer»

Answer:

SULPHIDE Ores (a)

EXPLANATION:

Hope it will HELPFUL for you thanks..

1488.

Q. Draw structural isomer of hexanal and pentanoic acid.Silly answers will be reported ! mind it ..​

Answer»

Answer:

Hexanal 1 (X = CHO) and its seven isomeric aldehydes 2, 3, 4, 5, 6, 7, 8 (X = CHO) are SHOWN to equilibrate, in methanol solution, with their hemi-acetals.

Explanation:

HOPE it Will help you❣️

1489.

Define oxidation and reduction in terms of oxidation number​

Answer»

Answer:

On the basis of oxidation number, oxidation may be defined as a reaction in which the oxidation number of an element in an ATOM, MOLECULE or ion increases. Reduction may be defined as a reaction in which the oxidation number of an element in an atom, ion or molecule DECREASES. Answer verified by TOPPR

1490.

The process by which two mixible liquids are seperated​

Answer»

ANSWER:

SALT and WATER. . . . .. . . .. .

1491.

Name the mixture whose particles are large enough to scatter light.(a) Colloid(b) True solutions(c) Homogeneous solution(d) All of the above

Answer»

ANSWER:

The PARTICLES in a colloid are large ENOUGH to scatter light, a PHENOMENON called the Tyndall effect. This can make colloidal mixtures appear cloudy or opaque, such as the searchlight beams shown in Figure 2. Clouds are colloidal mixtures

1492.

The half-life period for a zero-order reaction A→ product is *(a) 0.693/k(b) 2k/[R] ₒ(c) 2.303/k(d) [R] ₒ /2ki don't think its c or plz explain how its c​

Answer»

ANSWER:

(C) 2.303/k

Explanation:

HOPE it is HELPING..

1493.

दिस इज ए कांस्टेंट ऑफ द मैक्सिमम टाइम लिमिट​

Answer»

ANSWER:

{\boxed {\pink { Good Morning }}}

1494.

What volume of at sulphur dioxide will be produced at STP and complete burning of 260 g of sulphur

Answer»

Answer:

Sulfur dioxide appears as a colorless gas with a choking or suffocating ODOR. BOILING point -10°C. Heavier than air. Very toxic by inhalation and may irritate the eyes and mucous membranes. Under prolonged exposure to fire or heat the containers may rupture violently and rocket. Used to manufacture chemicals, in PAPER pulping, in METAL and food processing. Rate of onset: Immediate & Delayed Persistence: Minutes to hours Odor threshold: 1 ppm Source/use/other HAZARD: Disinfectant and preserving in breweries and food/canning; textile industry; batteries.

1495.

Atomic radii______along a period and______ along a group.​

Answer»

Answer:

DECREASED and increased

EXPLANATION:

decreased is the ANS of 1 dash

increased is the and of 2 dash

1496.

The element whichnis stored under kerosene is: a)sulphurm b)phosphorus c)silicon d)sodium​

Answer»

Answer:

Sodium is so reactive that it vigorously catches fire when kept open in air and hence, we keep it immersed in kerosene oil. Sodium oxide is the BASIC oxide formed as sodium metal reacts with OXYGEN of air at room temperature. OPTION C is the answer.

1497.

The conversion of solid into vapours without passing through the liquid state is called--(i) vapoursation(ii) Fusion(iii) sublimation(iv) Feezing​

Answer»

Conversion of SOLID into vapours WITHOUT passing through the liquid STATE is called SUBLIMATION.

1498.

Atoms of six known noble gases exist independently. True Or False​

Answer»

ANSWER:

TRUE is the CORRECT answer

1499.

The half-life period for a zero-order reaction A→ product is *(a) 0.693/k(b) 2k/[R] ₒ(c) 2.303/k(d) [R] ₒ /2k​

Answer»

ANSWER:

(C) 2.303/k

Explanation:

HOPE it will HELP you

1500.

Value of Henry law constant ,,?​

Answer»

Answer:

The HENRY's Law CONSTANT for merphos ESTIMATED from STRUCTURE activity relationships is 2.27 × 10−5 atm-cu-m mol−1