52639 + Interview Questions in Secondary School in Chemistry Page 70 InterviewSolution

3451.	Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log (x/m)versus log p is shown in the given graph, x/mis proportional to: (A) p²/³ (B) p²(C) p³ (D) p³/²
Answer» ANSWER: I THINK answer is OPTION (B)

3451.

Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log (x/m)versus log p is shown in the given graph, x/mis proportional to: (A) p²/³ (B) p²(C) p³ (D) p³/²

Answer»

ANSWER:

I THINK answer is OPTION

(B)

Discussion

3452.	Write the product of 1. butan-2-one with LiAlH42. CH3CH2CHO + [Ag(NH3)2]OH ------> ?
Answer» ANSWER: not ABLE to GET the QUESTION CORRECTLY

3452.

Write the product of 1. butan-2-one with LiAlH42. CH3CH2CHO + [Ag(NH3)2]OH ------> ?

Answer»

ANSWER:

not ABLE to GET the QUESTION CORRECTLY

Discussion

3453.	100 mL of a water sample contains 0.81 g of calcium bicarbonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO₃is: (molar mass of calcium bicarbonate is 162 gmol⁻¹and magnesium bicarbonate is 146 gmol⁻¹) (A) 10, 000 ppm (B) 1, 000 ppm(C) 5,000 ppm (D) 100 ppm
Answer» ANSWER: (A) 10,000 PPM CORRECT answer Thanks for the QUESTION..

3453.

100 mL of a water sample contains 0.81 g of calcium bicarbonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO₃is: (molar mass of calcium bicarbonate is 162 gmol⁻¹and magnesium bicarbonate is 146 gmol⁻¹) (A) 10, 000 ppm (B) 1, 000 ppm(C) 5,000 ppm (D) 100 ppm

Answer»

ANSWER:

(A) 10,000 PPM CORRECT answer

Thanks for the QUESTION..

Discussion

3454.	An organic compound ‘X’ showing the following solubility profile is:(A) Oleic acid (B) o – Toluidine (C) Benzamide (D) m – Cresol
Answer» Answer: Solution:- (D) m-Cresol OLEIC acid is also soluble in NAHCO3 o-toluidine is not soluble in NaOH as well as NaHCO3 *Benzamide is also not soluble in NaOH & NaHCO3 hope it USE full....✌ plzz mark as brainlist.....XD

3454.

An organic compound ‘X’ showing the following solubility profile is:(A) Oleic acid (B) o – Toluidine (C) Benzamide (D) m – Cresol

Answer»

Answer:

Solution:- (D) m-Cresol

*OLEIC acid is also soluble in NAHCO3

*o-toluidine is not soluble in NaOH as well as NaHCO3

*Benzamide is also not soluble in NaOH & NaHCO3

hope it USE full....✌

plzz mark as brainlist.....XD

Discussion

3455.	The size of the iso-electronic species CI⁻, Ar and Ca²⁺ is affected by(A) Principal quantum number of valence shell (B) Azimuthal quantum number of valence shell (C) electron – electron interaction in the outer orbitals (D) nuclear charge
Answer» Answer: NUCLEAR CHARGE because PQN of all the SPECIES is same hence size is inversely proportional to +charge and DIRECTLY to - charge

3455.

The size of the iso-electronic species CI⁻, Ar and Ca²⁺ is affected by(A) Principal quantum number of valence shell (B) Azimuthal quantum number of valence shell (C) electron – electron interaction in the outer orbitals (D) nuclear charge

Answer»

Answer:

NUCLEAR CHARGE because PQN of all the SPECIES is same hence size is inversely proportional to +charge and DIRECTLY to - charge

Discussion

3456.	The correct order of hydration enthalpies of alkali metal ions is:(A) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺ (B) Na⁺ > Li⁺ > K⁺ > Rb⁺ > Cs⁺ (C) Na⁺ > Li⁺ > K⁺ > Cs⁺ > Rb⁺ (D) Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺
Answer» Answer: option A) Explanation: ANSWER Solution:- (A) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺ Hydration enthalpy depends upon IONIC POTENTIAL (charge/ SIZE). As ionic potential increases hydration enthalpy increases. HOPE IT HELPS YOU

3456.

The correct order of hydration enthalpies of alkali metal ions is:(A) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺ (B) Na⁺ > Li⁺ > K⁺ > Rb⁺ > Cs⁺ (C) Na⁺ > Li⁺ > K⁺ > Cs⁺ > Rb⁺ (D) Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺

Answer»

Answer:

option A)

Explanation:

ANSWER

Solution:- (A) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺

Hydration enthalpy depends upon IONIC POTENTIAL (charge/ SIZE). As ionic potential increases hydration enthalpy increases.

HOPE IT HELPS YOU

Discussion

3457.	For silver Cₚ (JK⁻¹ mol⁻¹) = 23 + 0.01T . If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of ∆H will be close to:(A) 13 kJ (B) 62 kJ(C) 16 kJ (D) 21 kJ
Answer» ANSWER: C. will be CORRECT answers Explanation: HOPE the answer will help you

3457.

For silver Cₚ (JK⁻¹ mol⁻¹) = 23 + 0.01T . If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of ∆H will be close to:(A) 13 kJ (B) 62 kJ(C) 16 kJ (D) 21 kJ

Answer»

ANSWER:

C. will be CORRECT answers

Explanation:

HOPE the answer will help you

Discussion

3458.	For the reaction 2A + B → C, the values of initial rate at different reactant concentrations are given in the table below: The rate law for the reaction is:(A) Rate = k[A]²[B]²(B) Rate = k[A][B]²(C) Rate = k[A][B] (D) Rate = k[A]²[B]
Answer» Answer: B. will be CORRECT answers EXPLANATION: hope the answer will help you MARK the answer brainliests please

3458.

For the reaction 2A + B → C, the values of initial rate at different reactant concentrations are given in the table below: The rate law for the reaction is:(A) Rate = k[A]²[B]²(B) Rate = k[A][B]²(C) Rate = k[A][B] (D) Rate = k[A]²[B]

Answer»

Answer:

B. will be CORRECT answers

EXPLANATION:

hope the answer will help you

MARK the answer brainliests please

Discussion

3459.	An organic compound neither reacts with neutral ferric chloride solution nor with Fehlingsolution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:
Answer» Answer: C. will be CORRECT answers EXPLANATION: HOPE the answer will help you

3459.

An organic compound neither reacts with neutral ferric chloride solution nor with Fehlingsolution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:

Answer»

Answer:

C. will be CORRECT answers

EXPLANATION:

HOPE the answer will help you

Discussion

3460.	The lanthanoide that would show colour is: (A) Gd³⁺(B) La³⁺(C) Lu³⁺(D) Sm³⁺
Answer» ANSWER: D. will be correct ANSWERS its show YELLOW colour EXPLANATION: hope the answer will HELP you

3460.

The lanthanoide that would show colour is: (A) Gd³⁺(B) La³⁺(C) Lu³⁺(D) Sm³⁺

Answer»

ANSWER:

D. will be correct ANSWERS

its show YELLOW colour

EXPLANATION:

hope the answer will HELP you

Discussion

3461.	The correct order of the spin only magnetic moment of metal ions in the following low spin complexes,[V(CN)₆]⁴⁻ , [Fe(CN)₆]⁴⁻ , [Ru (NH₃)₆]³⁺, and [Cr(NH₃)₆]²⁺ , is: (A) Cr²⁺ > Ru³⁺ > Fe²⁺ > V²⁺ (B) V²⁺ > Cr²⁺ > Ru³⁺ > Fe²⁺ (C) Cr²⁺ > V²⁺ > Ru³⁺ > Fe²⁺ (D) V²⁺ > Ru³⁺ > Cr²⁺ > Fe²⁺
Answer» The correct order of the spin only magnetic moment of metal ions in the following low spin COMPLEXES is the one in option B ( V²⁺ > Cr²⁺ > Ru³⁺ > Fe²⁺ ). Low spin complexes are the one in which pairin of electrons TAKES place in the lower t2g levels before electrons are FILLED in the HIGHER eg levels of the d-orbitals. The magnetic moment of an ion INCREASES with an increase in the number of unpaired electrons in the metal ion. The number of unpaired electrons in the low spin complexes of V²⁺,Cr²⁺,Ru³⁺ and Fe²⁺ is equal to 3,2,1 and 0 respectively. Hence, the order of the magnetic moment follows from the above numbers of the unpaired electrons in the metal ions.

3461.

The correct order of the spin only magnetic moment of metal ions in the following low spin complexes,[V(CN)₆]⁴⁻ , [Fe(CN)₆]⁴⁻ , [Ru (NH₃)₆]³⁺, and [Cr(NH₃)₆]²⁺ , is: (A) Cr²⁺ > Ru³⁺ > Fe²⁺ > V²⁺ (B) V²⁺ > Cr²⁺ > Ru³⁺ > Fe²⁺ (C) Cr²⁺ > V²⁺ > Ru³⁺ > Fe²⁺ (D) V²⁺ > Ru³⁺ > Cr²⁺ > Fe²⁺

Answer»

The correct order of the spin only magnetic moment of metal ions in the following low spin COMPLEXES is the one in option B ( V²⁺ > Cr²⁺ > Ru³⁺ > Fe²⁺ ).

Low spin complexes are the one in which pairin of electrons TAKES place in the lower t2g levels before electrons are FILLED in the HIGHER eg levels of the d-orbitals.
The magnetic moment of an ion INCREASES with an increase in the number of unpaired electrons in the metal ion.
The number of unpaired electrons in the low spin complexes of V²⁺,Cr²⁺,Ru³⁺ and Fe²⁺ is equal to 3,2,1 and 0 respectively.
Hence, the order of the magnetic moment follows from the above numbers of the unpaired electrons in the metal ions.

Discussion

3462.	Diborane (B₂ H₆) reacts independently with O₂and H₂Oto produce, respectively: (A) H₃BO₃ and B₂O₃ (B) B₂O₃ and H₃BO₃(C) HBO₂and H₃BO₃ (D) B₂O₃ and [BH₄]⁻
Answer» Answer: the correct answer should be option a EXPLANATION: It is because when we'll heat DIBORANE some of hydrogen will be there so BORIC acid i.e H3BO3 will FORM after that B2O3 will form..

3462.

Diborane (B₂ H₆) reacts independently with O₂and H₂Oto produce, respectively: (A) H₃BO₃ and B₂O₃ (B) B₂O₃ and H₃BO₃(C) HBO₂and H₃BO₃ (D) B₂O₃ and [BH₄]⁻

Answer»

Answer:

the correct answer should be option a

EXPLANATION:

It is because when we'll heat DIBORANE some of hydrogen will be there so BORIC acid i.e H3BO3 will FORM after that B2O3 will form..

Discussion

3463.	Coupling of benzene diazonium chloride with 1 – naphthol in alkaline medium will give:
Answer» B. will be CORRECT ANSWERS hope the answer will help you

3463.

Coupling of benzene diazonium chloride with 1 – naphthol in alkaline medium will give:

Answer»

B. will be CORRECT ANSWERS

hope the answer will help you

Discussion

3464.	In the following compounds, the decreasing order of basic strength will be:(A) C₂H₅NH₂ > NH₃ > (C₂ H₅)₂ NH (B) NH₃ > C₂H₅NH₂ > (C₂H₅)₂ NH (C) (C₂H₅)₂ NH > C₂H₅NH₂ > NH₃ (D) (C₂H₅)₂ NH > NH₃ > C₂H₅ NH₂
Answer» Answer: in CASE of ethyl GROUP AMINES basicity order is $2 > 3 > 1$ degree amines HENCE OPTION C is correct

3464.

In the following compounds, the decreasing order of basic strength will be:(A) C₂H₅NH₂ > NH₃ > (C₂ H₅)₂ NH (B) NH₃ > C₂H₅NH₂ > (C₂H₅)₂ NH (C) (C₂H₅)₂ NH > C₂H₅NH₂ > NH₃ (D) (C₂H₅)₂ NH > NH₃ > C₂H₅ NH₂

Answer»

Answer:

in CASE of ethyl GROUP AMINES basicity order is

$2 > 3 > 1$

degree amines HENCE OPTION C is correct

Discussion

3465.	Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is(A) A₂B₂O (B) AB₂O₄(C) A₄B₂O (D) A₂BO₄
Answer» ANSWER: correct ans........ is (B) AB²O4 PLZZ MARK AS BRAINLIST.......XD

3465.

Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is(A) A₂B₂O (B) AB₂O₄(C) A₄B₂O (D) A₂BO₄

Answer»

ANSWER:

correct ans........ is

(B) AB²O4

PLZZ MARK AS BRAINLIST.......XD

Discussion

3466.	Fradel crafts reaction?explain.
Answer» In this reaction, alkyl or acyl groups are added to a benzene ring using a Lewis acid. Acylation is the term given to SUBSTITUTING an acyl group such as CH3CO- into another molecule It is an electrophilic aromatic substitution reaction in which a carbocation attacks an aromatic ring with the NET result that one of the aromatic protons is replaced by an alkyl group. It activates the arene substrate, polyalkylation may occur. As one of the most IMPORTANT reactions in aromatic substitution chemistry, the Friedel-Crafts reaction receives extensive coverage in sophomore ORGANIC chemistry. The most widely used Lewis acid for the Friedel-Crafts reactiuon is aluminum chloride

3466.

Fradel crafts reaction?explain.

Answer»

In this reaction, alkyl or acyl groups are added to a benzene ring using a Lewis acid.
Acylation is the term given to SUBSTITUTING an acyl group such as CH3CO- into another molecule

It is an electrophilic aromatic substitution reaction in which a carbocation attacks an aromatic ring with the NET result that one of the aromatic protons is replaced by an alkyl group.

It activates the arene substrate, polyalkylation may occur.

As one of the most IMPORTANT reactions in aromatic substitution chemistry, the Friedel-Crafts reaction receives extensive coverage in sophomore ORGANIC chemistry.

The most widely used Lewis acid for the Friedel-Crafts reactiuon is aluminum chloride

Discussion

3467.	2). 50 ml 0.5 M H,SO, is added to 75 ml 0.25 M H2SO4The molarity of resulting solution is : (a) 0.38 M(b) 0.175 M(c) 0.70 M(d) 0.35 M
Answer» ANSWER: M1V1+M2V2=M3V3 0.5 × 50 × 1000(L) + 0.25 × 75 × 1000(L) = M3×125000 25000 + 18750 =M3 × 125000 M3 = 43750 / 125000 M3 = 0.35 M

3467.

2). 50 ml 0.5 M H,SO, is added to 75 ml 0.25 M H2SO4The molarity of resulting solution is : (a) 0.38 M(b) 0.175 M(c) 0.70 M(d) 0.35 M

Answer»

ANSWER:

M1V1+M2V2=M3V3

0.5 × 50 × 1000(L) + 0.25 × 75 × 1000(L) = M3×125000

25000 + 18750 =M3 × 125000

M3 = 43750 / 125000

M3 = 0.35 M

Discussion

3468.	When we pass carbon dioxide(CO2) through lime water for a long time it becomes a clear solution. Why?
Answer» formation of water soluble calcium BICARBONATE When CO2 is PASSED through lime water, it turns MILKY due to the formation of calcium carbonate which is sinsoluble in water. limewaterCa(OH)2+CO2⟶milkinessCaCO3+H2O However, when excess of CO2 is passed through this solution, the milkiness disappears. This is due to the formation of calcium bicarbonate which is colorless and soluble in water. milkinessCaCO3+H2O+excessCO2⟶water solubleCa(HCO3)2 #ARMY!! PLEASE MARK ME AS *BRAINLIEST* .

3468.

When we pass carbon dioxide(CO2) through lime water for a long time it becomes a clear solution. Why?

Answer»

formation of water soluble calcium BICARBONATE

When CO2 is PASSED through lime water, it turns MILKY due to the formation of calcium carbonate which is sinsoluble in water.

limewaterCa(OH)2+CO2⟶milkinessCaCO3+H2O

However, when excess of CO2 is passed through this solution, the milkiness disappears. This is due to the formation of calcium bicarbonate which is colorless and soluble in water.

milkinessCaCO3+H2O+excessCO2⟶water solubleCa(HCO3)2

#ARMY!! PLEASE MARK ME AS BRAINLIEST .

Discussion

3469.	Write a note on biodiversity
Answer» Biodiversity is SHORT for “BIOLOGICAL DIVERSITY.” Biodiversity is “the VARIETY of all living things, and the systems which connect them.” This includes all the planet's different plants, animals and micro organisms, plus the GENETIC information they contain and the ecosystems of which they are a part.

Discussion

3470.	Explain with reaction , what happen when slaked lime reacts with chlorine?
Answer» Answer: SLAKED lime reacts with CHLORINE GAS to produce the bleaching agent calcium hydrochloride - comman from of swimming POOL chlorine. When chlorine is passed over slaked lime(Ca(OH)2) it is immediately assimilated to produce bleaching powder or either a chloride of lime. hope this HELPS you

3470.

Explain with reaction , what happen when slaked lime reacts with chlorine?

Answer»

Answer:

SLAKED lime reacts with CHLORINE GAS to produce the bleaching agent calcium hydrochloride - comman from of swimming POOL chlorine. When chlorine is passed over slaked lime(Ca(OH)2) it is immediately assimilated to produce bleaching powder or either a chloride of lime.

hope this HELPS you

Discussion

3471.	The heat of reaction is -100kJ at 27°c .the value of ∆H for the reaction is-SO2+1/2O2=SO3
Answer» ANSWER: hy Explanation: by

3471.

The heat of reaction is -100kJ at 27°c .the value of ∆H for the reaction is-SO2+1/2O2=SO3

Answer»

ANSWER:

hy

Explanation:

by

Discussion

3472.	The gas equation PV=nRT obeyed under:Isothermal conditionIsochoric conditionAdiabatic conditionEither of thesep.s the answer is either of these.i need to know the reason why....like some mathematical equation
Answer» ANSWER: This GAS equation is UNIVERSAL which means that for any thermodynamic condition this equation is applicable,some of the quantities are CHANGED but BASIC equation is this only

3472.

The gas equation PV=nRT obeyed under:Isothermal conditionIsochoric conditionAdiabatic conditionEither of thesep.s the answer is either of these.i need to know the reason why....like some mathematical equation

Answer»

ANSWER:

This GAS equation is UNIVERSAL which means that for any thermodynamic condition this equation is applicable,some of the quantities are CHANGED but BASIC equation is this only

Discussion

3473.	On the basis of which principle are impurities in the purification of metals such as Si, Ge and B removed?
Answer» ANSWER: Zone refining or Fractional Crystallization is the method employed to get metal of very HIGH purity i.e ultrapure samples of Ge, Si, B, Ga etc. This method is based on the fact that impurities are more soluble than the pure metal in the MELT.

3473.

On the basis of which principle are impurities in the purification of metals such as Si, Ge and B removed?

Answer»

ANSWER:

Zone refining or Fractional Crystallization is the method employed to get metal of very HIGH purity i.e ultrapure samples of Ge, Si, B, Ga etc. This method is based on the fact that impurities are more soluble than the pure metal in the MELT.

Discussion

3474.	What is compound of sodium nitrate
Answer» ANSWER: AGCL i THINK SOO that is the answer

3474.

What is compound of sodium nitrate

Answer»

ANSWER:

AGCL i THINK SOO that is the answer

Discussion

3475.	The gas equation PV=nRT obeyed under:Isothermal conditionIsochoric conditionAdiabatic conditionEither of thesep.s i know the answer but i want a clear explaination
Answer» EXPLANATION: In all of these it will be OBEYED

3475.

The gas equation PV=nRT obeyed under:Isothermal conditionIsochoric conditionAdiabatic conditionEither of thesep.s i know the answer but i want a clear explaination

Answer»

EXPLANATION:

In all of these it will be OBEYED

Discussion

3476.	Barium chloride reacts with aluminium sulphate to give aluminium chloride and precipitate of barium sulphate
Answer» Answer: This is a PRECIPITATION as well as DOUBLE Displacement REACTION. Explanation : REFER the attached PICTURE.

3476.

Barium chloride reacts with aluminium sulphate to give aluminium chloride and precipitate of barium sulphate

Answer»

Answer:

This is a PRECIPITATION as well as DOUBLE Displacement REACTION.

Explanation :

REFER the attached PICTURE.

Discussion

3477.	EXPLAIN THE TERM AMPHOTERIC AND NAME TWO REAGENTS THAT ARE NEEDED TO SHOW THAT AN OXIDE IS AMPHOTERIC . SUPPORT YOUR ANSWER WITH CHEMICAL EQUATION
Answer» Answer: In chemistry, an amphoteric compound is a molecule or ion that can react both as an acid and as a BASE. MANY metals (such as copper, zinc, tin, lead, aluminium, and beryllium) form amphoteric oxides or hydroxides. Amphoterism depends on the oxidation states of the oxide. Al2O3 is an example of an amphoteric oxide. while with base it will behave chemically as an acid . inorder to ascertain both ONE has to use two REAGENTS i.e.an acid as well as base . e.g. ZnO + 2HCL → ZnCl2 +H2O. Explanation:

3477.

EXPLAIN THE TERM AMPHOTERIC AND NAME TWO REAGENTS THAT ARE NEEDED TO SHOW THAT AN OXIDE IS AMPHOTERIC . SUPPORT YOUR ANSWER WITH CHEMICAL EQUATION

Answer»

Answer:

In chemistry, an amphoteric compound is a molecule or ion that can react both as an acid and as a BASE. MANY metals (such as copper, zinc, tin, lead, aluminium, and beryllium) form amphoteric oxides or hydroxides. Amphoterism depends on the oxidation states of the oxide. Al2O3 is an example of an amphoteric oxide.

while with base it will behave chemically as an acid . inorder to ascertain both ONE has to use two REAGENTS i.e.an acid as well as base . e.g. ZnO + 2HCL → ZnCl2 +H2O.

Explanation:

Discussion

3478.	Does centre of symmetry of any general oraganic molecule always lies inside it ?
Answer» Answer: your CONSIDERATION is true . the CENTRE of symmetry of any general organic MATERIAL always lies inside it thanku MARK me as a brainlyiest

3478.

Does centre of symmetry of any general oraganic molecule always lies inside it ?

Answer»

Answer:

your CONSIDERATION is true . the CENTRE of symmetry of any general organic MATERIAL always lies inside it

thanku

MARK me as a brainlyiest

Discussion

3479.	How to find mole concept
Answer» MOLE Concept n = N/NA ... Molar mass of a SUBSTANCE = (Mass of the Substance in grams)/(Number of MOLES) ... Number of Moles = (Mass of the Sample)/(Molar Mass) ... Number of Atoms or Molecules = (Number of Moles)(6.0221023) ... 1 amu = (1gram)/(6.0221023) = 1.6610-24 grams.

3479.

How to find mole concept

Answer»

MOLE Concept

n = N/NA ...

Molar mass of a SUBSTANCE = (Mass of the Substance in grams)/(Number of MOLES) ...

Number of Moles = (Mass of the Sample)/(Molar Mass) ...

Number of Atoms or Molecules = (Number of Moles)*(6.022*1023) ...

1 amu = (1gram)/(6.022*1023) = 1.66*10-24 grams.

Discussion

3480.	Write down the formula of sodium suphide?
Answer» Answer: the formula of SODIUM sulphide is NA2S HOPE it's HELPS you

3480.

Write down the formula of sodium suphide?

Answer»

Answer:

the formula of SODIUM sulphide is NA2S

HOPE it's HELPS you

Discussion

3481.	coulomb of electricity will be consumed when 100ma current passes through a solution of AgNO3for half an hour during electrolysis
Answer» ANSWER: hello! Explanation: Amount of current = C = 100 mA or 100/1000 A time = t = 1/2hr or (1/2 x 60 x 60) sec amount of ELECTRICITY= Q = ? Q = C x t = (100/1000 A) x (1/2 x 60 x 60) = 180 COULOMB

3481.

coulomb of electricity will be consumed when 100ma current passes through a solution of AgNO3for half an hour during electrolysis

Answer»

ANSWER:

hello!

Explanation:

Amount of current = C = 100 mA or 100/1000 A

time = t = 1/2hr or (1/2 x 60 x 60) sec

amount of ELECTRICITY= Q = ?

Q = C x t

= (100/1000 A) x (1/2 x 60 x 60)

= 180 COULOMB

Discussion

3482.	How to learn valency of first 18 elements easily
Answer» ANSWER: hey frnd first you should learn the 18 elements and then you should do the ELECTRONIC CONFIGURATION of of their atomic number you will get valency EASILY...

3482.

How to learn valency of first 18 elements easily

Answer»

ANSWER:

hey frnd

first you should learn the 18 elements and then you should do the ELECTRONIC CONFIGURATION of of their atomic number you will get valency EASILY...

Discussion

3483.	Sir es question ko ham 1 l volume raka nahi kar sakta
Answer» ANSWER: where is your question follow me then i ANSWERED

3483.

Sir es question ko ham 1 l volume raka nahi kar sakta

Answer»

ANSWER:

where is your question

follow me

then i ANSWERED

Discussion

3484.	What will be the pressure of a gas mixture when 1 lt of H2 gas at 0.8 bar and 1 lt of oxygen at 0.7 bar are introduced in 2 lt vessel ?
Answer» $\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$ GiVen : => Volume of H2 gas (V1) = 1L => Pressure of H2 gas (P1) = 0.8bar => Volume of O2 gas (V2) = 1L => Pressure of O2 gas (P2) = 0.7bar => TOTAL volume after MIXED both (V) = 2L To Find : => Total pressure after mixed both (P) = ? Formula : => As per Bauyle's law relation between pressure of gas and volume is given by... $\underline{ \boxed{ \bold{ \rm{ \pink{P\propto{ \frac{1}{V} \: \blue{\longrightarrow} \: \: \therefore \: PV = constant }}}}}}$ => So, we can say that... $\: \: \: \: \underline{ \boxed{ \bold{ \rm{ \red{P_1V_1 + P_2V_2 = (PV){ \tiny{mixture}}}}}}}$ Calculation : $\leadsto \rm \: (1 \times 0.8) + (1 \times 0.7) = P \times 2 \\ \\ \leadsto \rm \: P = \frac{0.8 + 0.7}{2} = \frac{1.5}{2} \\ \\ \underline{ \boxed{ \bold{ \sf{ \orange{ \therefore \: P{ \tiny{mix}} = 0.75 \: bar}}}}}$

3484.

What will be the pressure of a gas mixture when 1 lt of H2 gas at 0.8 bar and 1 lt of oxygen at 0.7 bar are introduced in 2 lt vessel ?

Answer»

$\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$

GiVen :

=> Volume of H2 gas (V1) = 1L

=> Pressure of H2 gas (P1) = 0.8bar

=> Volume of O2 gas (V2) = 1L

=> Pressure of O2 gas (P2) = 0.7bar

=> TOTAL volume after MIXED both (V) = 2L

To Find :

=> Total pressure after mixed both (P) = ?

Formula :

=> As per Bauyle's law relation between pressure of gas and volume is given by...

$\underline{ \boxed{ \bold{ \rm{ \pink{P\propto{ \frac{1}{V} \: \blue{\longrightarrow} \: \: \therefore \: PV = constant }}}}}}$

=> So, we can say that...

$\: \: \: \: \underline{ \boxed{ \bold{ \rm{ \red{P_1V_1 + P_2V_2 = (PV){ \tiny{mixture}}}}}}}$

Calculation :

$\leadsto \rm \: (1 \times 0.8) + (1 \times 0.7) = P \times 2 \\ \\ \leadsto \rm \: P = \frac{0.8 + 0.7}{2} = \frac{1.5}{2} \\ \\ \underline{ \boxed{ \bold{ \sf{ \orange{ \therefore \: P{ \tiny{mix}} = 0.75 \: bar}}}}}$

Discussion

3485.	What do u mean by schottky defect
Answer» lattice valency defects A Schottky defect is a TYPE of POINT defect in a crystal lattice named after WALTER H. Schottky. In non-ionic crystals it refers to lattice valency defects. In ionic crystals, this type of point defect forms when oppositely charged ions leave their lattice SITES, creating vacancies.

3485.

What do u mean by schottky defect

Answer»

lattice valency defects

A Schottky defect is a TYPE of POINT defect in a crystal lattice named after WALTER H. Schottky. In non-ionic crystals it refers to lattice valency defects. In ionic crystals, this type of point defect forms when oppositely charged ions leave their lattice SITES, creating vacancies.

Discussion

3486.	Conversion of2-butyne to acetic acid
Answer» ANSWER: HOPE this is HELP you......

3486.

Conversion of2-butyne to acetic acid

Answer»

ANSWER:

HOPE this is HELP you......

Discussion

3487.	What are formula units in chemistry??
Answer» Answer: formula unit in chemistry is the EMPIRICAL formula of any ionic or covalent NETWORK SOLID compound used as an independent entity for stoichiometric calculations. It is the lowest whole number ratio of ions REPRESENTED in an ionic compound.

3487.

What are formula units in chemistry??

Answer»

Answer:

formula unit in chemistry is the EMPIRICAL formula of any ionic or covalent NETWORK SOLID compound used as an independent entity for stoichiometric calculations. It is the lowest whole number ratio of ions REPRESENTED in an ionic compound.

Discussion

3488.	Point defect definition...with explanation
Answer» Answer: an imperfection in a crystal's lattice structure, EITHER a missing atom or ion creating a vacancy in the lattice or an extra atom or ion between two NORMAL lattice POINTS creating an INTERSTITIAL.

3488.

Point defect definition...with explanation

Answer»

Answer:

an imperfection in a crystal's lattice structure, EITHER a missing atom or ion creating a vacancy in the lattice or an extra atom or ion between two NORMAL lattice POINTS creating an INTERSTITIAL.

Discussion

3489.	Hii mates...QUESTION: WHAT DO YOU MEAN BY PERMANGANATE??WHAT IS POTASSIUM PERMANGANATE??DON'T COPY FROM GOOGLE
Answer» Answer: HEY mate here's your answer... EXPLANATION: A *salt* *that* *contains* *anion* *MnO4* is *known* as *permanganate. Potassium permanganate* is a *compound* *FORMED* *with* *permanganate. KMnO4* Hope this HELPS you... Yours sincerely *Jalay*

3489.

Hii mates...QUESTION: WHAT DO YOU MEAN BY PERMANGANATE??WHAT IS POTASSIUM PERMANGANATE??DON'T COPY FROM GOOGLE

Answer»

Answer:

HEY mate here's your answer...

EXPLANATION:

A salt that contains anion MnO4 is known as permanganate.
Potassium permanganate is a compound FORMED with permanganate. KMnO4

Hope this HELPS you...

Yours sincerely

Jalay

Discussion

3490.	Balance the equation :6Fe (OH)2 + CO32− + 2H2O → 4Fe (OH)2•2Fe(OH)3CO3 + H2 + OH−
Answer» I'm SORRY, i REALLY WANTED to HELP, but it is very HARD. I' really sorry

Discussion

3491.	What is point defect
Answer» Explanation: MISSING of atom or ION creating a vacancy in the lattice or an extra atom or ion between two normal lattice POINTS creating an interstitial.

3491.

What is point defect

Answer»

Explanation:

MISSING of atom or ION creating a vacancy in the lattice or an extra atom or ion between two normal lattice POINTS creating an interstitial.

Discussion

3492.	How to learn the valency of first 18 elements
Answer» ANSWER: no of ELECTRONS PRESENT in OUTER most SHELL

3492.

How to learn the valency of first 18 elements

Answer»

ANSWER:

no of ELECTRONS PRESENT in OUTER most SHELL

Discussion

3493.	Flourine oxidises HSO-4 to
Answer» Answer: 2HSO4^- + F2 GIVES ........ S2O8^-2 + 2HF hope it helps you.... pls mark as the BRAINLIEST answer

3493.

Flourine oxidises HSO-4 to

Answer»

Answer:

2HSO4^- + F2

GIVES ........

S2O8^-2 + 2HF

hope it helps you....

pls mark as the BRAINLIEST answer

Discussion

3494.	Trace the path of a ray of light passing through a glass prism (ABC) as shown in the figure. If the refractive index of glass is √3, find out the value of the angle of emergence from the prism.
Answer» Answer: 60° Explanation: $\frac{sin i}{sin r} = \frac{N(air)}{N(glass)} \\=> \frac{sin 30}{ 2 sin (e)} = \frac{1}{\sqrt{3} } \\=> \frac{\sqrt{3} }{2} = sin (e) \\=> e = 60$ we GOT 30° by APPLYING SNELL's law e= ANGLE of EMERGENCE

3494.

Trace the path of a ray of light passing through a glass prism (ABC) as shown in the figure. If the refractive index of glass is √3, find out the value of the angle of emergence from the prism.

Answer»

Answer:

60°

Explanation:

$\frac{sin i}{sin r} = \frac{N(air)}{N(glass)} \\=> \frac{sin 30}{ 2 sin (e)} = \frac{1}{\sqrt{3} } \\=> \frac{\sqrt{3} }{2} = sin (e) \\=> e = 60$

we GOT 30° by APPLYING SNELL's law

e= ANGLE of EMERGENCE

Discussion

3495.	Indicator does not affect by salt
Answer» ANSWER: Indicators are substances which gives a PROMINENT sign to identify the presence of acids and alkali in the solution. Salt is produced from the reaction of acids and BASES. ... For this reason, Indicators are not AFFECTED by salt as salt is the PRODUCT of acid and base which is neutral.

3495.

Indicator does not affect by salt

Answer»

ANSWER:

Indicators are substances which gives a PROMINENT sign to identify the presence of acids and alkali in the solution. Salt is produced from the reaction of acids and BASES. ... For this reason, Indicators are not AFFECTED by salt as salt is the PRODUCT of acid and base which is neutral.

Discussion

3496.	If need 10difference only
Answer»

Discussion

3497.	1 mole of CO2,2 mole of N2,2 moles of O2 were mixed at 300 K ,the entropy of mixing is of
Answer» Answer: DEAR friend SEE ATTACHMENT FOLLOW me

3497.

1 mole of CO2,2 mole of N2,2 moles of O2 were mixed at 300 K ,the entropy of mixing is of

Answer»

Answer:

DEAR friend SEE ATTACHMENT

FOLLOW me

Discussion

3498.	(n-1) d³ns² for n=4
Answer» Answer: 3d^34s2 which is VANADIUM and is in TRANSITION ELEMENTS...

3498.

(n-1) d³ns² for n=4

Answer»

Answer:

3d^34s2

which is VANADIUM and is in TRANSITION ELEMENTS...

Discussion

3499.	atoms X and Y form BCC crystal in structure atom its is present at the corner of the cube and Y is at the centre of the cube What is the formula of the compound
Answer» HELLO ! EXPLANATION: The FORMULA will be XY..

3499.

atoms X and Y form BCC crystal in structure atom its is present at the corner of the cube and Y is at the centre of the cube What is the formula of the compound

Answer»

HELLO !

EXPLANATION:

The FORMULA will be XY..

Discussion

3500.	Give two uses of the followinggas carbon
Answer» ANSWER: Carbon dioxide in SOLID and in liquid form is USED for REFRIGERATION and COOLING. It is used as an inert gas in chemical processes, in the storage of carbon powder and in fire extinguishers.

3500.

Give two uses of the followinggas carbon

Answer»

ANSWER:

Carbon dioxide in SOLID and in liquid form is USED for REFRIGERATION and COOLING. It is used as an inert gas in chemical processes, in the storage of carbon powder and in fire extinguishers.

Discussion

Explore topic-wise InterviewSolutions in .

Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log (x/m)versus log p is shown in the given graph, x/mis proportional to: (A) p²/³ (B) p²(C) p³ (D) p³/²

Write the product of 1. butan-2-one with LiAlH42. CH3CH2CHO + [Ag(NH3)2]OH ------> ?

An organic compound ‘X’ showing the following solubility profile is:(A) Oleic acid (B) o – Toluidine (C) Benzamide (D) m – Cresol

The size of the iso-electronic species CI⁻, Ar and Ca²⁺ is affected by(A) Principal quantum number of valence shell (B) Azimuthal quantum number of valence shell (C) electron – electron interaction in the outer orbitals (D) nuclear charge

The correct order of hydration enthalpies of alkali metal ions is:(A) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺ (B) Na⁺ > Li⁺ > K⁺ > Rb⁺ > Cs⁺ (C) Na⁺ > Li⁺ > K⁺ > Cs⁺ > Rb⁺ (D) Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺

HOPE IT HELPS YOU

For silver Cₚ (JK⁻¹ mol⁻¹) = 23 + 0.01T . If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of ∆H will be close to:(A) 13 kJ (B) 62 kJ(C) 16 kJ (D) 21 kJ

For the reaction 2A + B → C, the values of initial rate at different reactant concentrations are given in the table below: The rate law for the reaction is:(A) Rate = k[A]²[B]²(B) Rate = k[A][B]²(C) Rate = k[A][B] (D) Rate = k[A]²[B]

An organic compound neither reacts with neutral ferric chloride solution nor with Fehlingsolution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:

The lanthanoide that would show colour is: (A) Gd³⁺(B) La³⁺(C) Lu³⁺(D) Sm³⁺

Diborane (B₂ H₆) reacts independently with O₂and H₂Oto produce, respectively: (A) H₃BO₃ and B₂O₃ (B) B₂O₃ and H₃BO₃(C) HBO₂and H₃BO₃ (D) B₂O₃ and [BH₄]⁻

Coupling of benzene diazonium chloride with 1 – naphthol in alkaline medium will give:

In the following compounds, the decreasing order of basic strength will be:(A) C₂H₅NH₂ > NH₃ > (C₂ H₅)₂ NH (B) NH₃ > C₂H₅NH₂ > (C₂H₅)₂ NH (C) (C₂H₅)₂ NH > C₂H₅NH₂ > NH₃ (D) (C₂H₅)₂ NH > NH₃ > C₂H₅ NH₂

Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is(A) A₂B₂O (B) AB₂O₄(C) A₄B₂O (D) A₂BO₄

Fradel crafts reaction?explain.

2). 50 ml 0.5 M H,SO, is added to 75 ml 0.25 M H2SO4The molarity of resulting solution is : (a) 0.38 M(b) 0.175 M(c) 0.70 M(d) 0.35 M​

When we pass carbon dioxide(CO2) through lime water for a long time it becomes a clear solution. Why?

Write a note on biodiversity

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The gas equation PV=nRT obeyed under:Isothermal conditionIsochoric conditionAdiabatic conditionEither of thesep.s i know the answer but i want a clear explaination

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Answer:

Explanation :

EXPLAIN THE TERM AMPHOTERIC AND NAME TWO REAGENTS THAT ARE NEEDED TO SHOW THAT AN OXIDE IS AMPHOTERIC . SUPPORT YOUR ANSWER WITH CHEMICAL EQUATION

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How to learn valency of first 18 elements easily ​

Sir es question ko ham 1 l volume raka nahi kar sakta

What will be the pressure of a gas mixture when 1 lt of H2 gas at 0.8 bar and 1 lt of oxygen at 0.7 bar are introduced in 2 lt vessel ?

What do u mean by schottky defect​

Conversion of2-butyne to acetic acid​

What are formula units in chemistry??

Point defect definition...with explanation​

Hii mates...QUESTION: WHAT DO YOU MEAN BY PERMANGANATE??WHAT IS POTASSIUM PERMANGANATE??DON'T COPY FROM GOOGLE​

Jalay

Balance the equation :6Fe (OH)2 + CO32− + 2H2O → 4Fe (OH)2•2Fe(OH)3CO3 + H2 + OH−

What is point defect​

How to learn the valency of first 18 elements​

Flourine oxidises HSO-4 to​

Trace the path of a ray of light passing through a glass prism (ABC) as shown in the figure. If the refractive index of glass is √3, find out the value of the angle of emergence from the prism.

Indicator does not affect by salt

If need 10difference only

1 mole of CO2,2 mole of N2,2 moles of O2 were mixed at 300 K ,the entropy of mixing is of

(n-1) d³ns² for n=4​

atoms X and Y form BCC crystal in structure atom its is present at the corner of the cube and Y is at the centre of the cube What is the formula of the compound​

Give two uses of the followinggas carbon

2). 50 ml 0.5 M H,SO, is added to 75 ml 0.25 M H2SO4The molarity of resulting solution is : (a) 0.38 M(b) 0.175 M(c) 0.70 M(d) 0.35 M

What is compound of sodium nitrate

How to find mole concept

Write down the formula of sodium suphide?

How to learn valency of first 18 elements easily

What do u mean by schottky defect

Conversion of2-butyne to acetic acid

Point defect definition...with explanation

Hii mates...QUESTION: WHAT DO YOU MEAN BY PERMANGANATE??WHAT IS POTASSIUM PERMANGANATE??DON'T COPY FROM GOOGLE

What is point defect

How to learn the valency of first 18 elements

Flourine oxidises HSO-4 to

(n-1) d³ns² for n=4

atoms X and Y form BCC crystal in structure atom its is present at the corner of the cube and Y is at the centre of the cube What is the formula of the compound