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46501.

Unatempted. A 0.200 g sample containing Cu(II) was analyzed iodometrically :Cu(II) is reduced to copper(I) by iodine2Cu2+ +41-2Cul +1,.If 20 ml 0.10 M Na,s,o, is required for titration of liberated I,then the percentage of copper in sample will be (Cu = 63.5 ; I =127)(A) 31.75%(C) 53%(B) 63,5%(D) 37%​

Answer»

Correct answer is option 'B'. Can you explain this answer?Related Test: Part Test 1 - NEET 2020NEET QuestionBy Vaibhav CHAUDHARY · AUG 30, 2020 ·NEETAnswer ReportShareSave Kartik Bansal answered FEB 12, 20192 moles of Cu2+ = 1 mole of I2= 2 moles of hypo.so moles of hypo used = 20 x 10-3 x 0.1 = 2 milli moles = milli moles of copper Hence percentage of copper UpvoteThis discussion on A 0.200 gm sample containing copper (II) was analysed iodometrically, copper (II) is reduced tocopper (I) by iodine. 2Cu2+ + 4I–——? 2 CuI + I2If 20.0mL of 0.10 M Na2S2O3 is required for titration of the liberated iodine then the percentage of copper in the sample will be (Cu = 63.5 g/mole)a)31.75 %b)63.5 %c)53 %d)37 %Correct answer is option 'B'. Can you explain this answer? is done on EduRev Study Group by NEET Students. The Questions and Answers of A 0.200 gm sample containing copper (II) was analysed iodometrically, copper (II) is reduced tocopper (I) by iodine. 2Cu2+ + 4I–——? 2 CuI + I2If 20.0mL of 0.10 M Na2S2O3 is required for titration of the liberated iodine then the percentage of copper in the sample will be (Cu = 63.5 g/mole)a)31.75 %b)63.5 %c)53 %d)37 %Correct answer is option 'B'. Can you explain this answer? are solved by group of students and teacher of NEET, which is also the largest student community of NEET. If the answer is not AVAILABLE please wait for a while and a community MEMBER will probably answer this soon. You can study other questions, MCQs, videos and tests for NEET on EduRev and even discuss your questions like A 0.200 gm sample containing copper (II) was analysed iodometrically, copper (II) is reduced tocopper (I) by iodine. 2Cu2+ + 4I–——? 2 CuI + I2If 20.0mL of 0.10 M Na2S2O3 is required for titration of the liberated iodine then the percentage of copper in the sample will be (Cu = 63.5 g/mole)a)31.75 %b)63.5 %c)53 %d)37 %Correct answer is option 'B'. Can you explain this answer? over here on EduRev! Apart from being the largest NEET community, EduRev has the largest solved Question bank for NEET.

46502.

If the gas contains only three molecules with velocities of 100, 200, 500 m/sec; what is the RMS velocity of gas ?​

Answer»

i will HELP you but you have to do me BRIANLIEST

46503.

Revisit Question # 1Two gases X and Y react as per following reaction.X(g) + 3Y|g) — XY; g)In an attempt to determine the rate law for the reaction, the followingresult was obtained at 350 K.Experiment [X] (mol/u [Y][mol/L) Rate of formation of XY,(mol/\/min)0.008020.0160.0240.10.10.00814Using the above results, the rate law of the reaction should be​

Answer» SORRY i didn't UNDERSTAND
46504.

How many different type of functional groups are present in following compound :​

Answer» EXPLANATION: the functional groups are(1) PRIMARY amine(2) Secondary amine(3)Ketone(4) Alcohol(5) acid anhydride
46505.

What are the factors which determine the magnitude of ionisation energy?​

Answer»

rs Affecting Ionisation Energy:•Size of the positive nuclear CHARGE. As the nuclear charge increases, its attraction for the outermost electron increases and more energy is required to remove an electron.•Size of ATOM (distance of outermost electron from the nucleus).•Screening (shielding) effect of inner shell electrons.Hope it helps you...PLEASE MARK my ANSWER as the brainliest answer...

46506.

3M, 2L of aq. solution of NaCl is mixed with IM, 3L of AgNO (aq.) solutionNaCl(aq) + AgNO (aq.) AgCl) + NaNO (aq.)Which of the following isláze correct for resulting solution?(A) [Na'] = 1.2M (B) (Ag) = 0.6M(C) INO) = 0.6M (D) [CH] = 1.2M​

Answer» 3M is 2L HARD 3m is not hard he is simple EXPLANATION:PLEASE mark has brainlist
46507.

S-P overlapping is present inHCIHFCl₂HBr​

Answer»

haa HLO i dint understand that Explanation:of U dont MIND ask ONES again

46508.

hydrogen forms a stoichometric Hydraides with which of the following (a) lanthanum (b) potassium (c) titanium (d) platinum​

Answer»

In other words, alkali metals HYDRIDES are ionic in which ions occupy holes in lattice. SINCE HYDRIDE ion is formed by COMPLETE transfer of an electron, therefore, the ratio of metal to hydrogen is always fixed and hence alkali metals form only STOICHIOMETRIC hydrides.

46509.

Please tell i seriously need answer.....​

Answer» C2+ is the answer I think. EXPLANATION:PLS mark me as brain list and thanks
46510.

Calculate the formula unit of Kc1 , Naco3 ( atomic mass of k- 29ce , cI- 35.5u, Na - 23u, C - 12u , O- 16u. ​

Answer»

Calculate the formula unit of KC1 , Naco3 ( ATOMIC mass of k- 29ce , cI- 35.5 U, Na - 23u, C - 12u , O- 16u. · 25. Name the ...

46511.

25. Name the adsorbent useb) In gas masks to remove chlorine.​

Answer»

: Activated Charcoal Is Used In GAS Mask ,To AVOID Poisonous Gases LIKE CO, CH⁴ HOPE It Helped You !

46512.

1) What are the factors which determine the magnitude of ionisation energy?​

Answer»

isation energy depends upon the size of atom, because with increase in size, the distance between nucleus and valence ELECTRONS increases and hence force of ATTRACTION between nucleus and valence electron DECREASES.

46513.

CALCULATE The number of moles contain 25 g of CaCO3 ?

Answer»

0.25Explanation:weight of CALCIUM carbonate GIVEN= 25 g. = 0.25 moles. THUS number of moles in 25 g of calcium carbonate is 0.25.hope it HELPS you

46514.

The number of atoms present in 0.5 moles of oxygen gas are______​

Answer» 1 MOLE has6.022*10^23 atoms0.5 MOLES will have 3.011*10^23
46515.

Describe the molecular orbitals theory of homonuclear diatomic molecules​

Answer»

With such an approach, the electronic STRUCTURES of VIRTUALLY all commonly encountered homonuclear DIATOMIC molecules, molecules with two identical atoms, can be understood. The molecular ORBITAL approach correctly predicts that the O2 molecule has two unpaired electrons and hence is attracted into a magnetic field.Hope it HELPS...Borahae❣❣

46516.

what must be percantage of white flower plant in second filial generation (f2) if plant of f1 generation self pollinated​

Answer»

how was that.............................

46517.

from 150g of urea(NH2CONH2) when 3 × 10²³ molecules are removed then the remaining moles of urea will be​

Answer» TION:This is the ANSWER , HOPE it helps youplease mark me as brainliest
46518.

Select the CORRECT order(s) of bond length. (A) ds (S0,) >ds (SO)(B) d. (H,O,) >do_o(0,F)(C) dx-(NO) > dx_o (NO)(D) ds-f (axial)

Answer»

these are 4 SIDES in qudritaral 360'as then 4$of the 80' is then 1 side so there is NON as WELL is they sdt is 360

46519.

Concentration of reactants increases then rate of reaction [ ]a) Decreasesb) Increasesc) Does not changed) Zero​

Answer»
46520.

Chenista Mathematics25.0 E sample of an alloy was heated to 100.0°C and dropped to a beaof water at 27.0°C. The temperature of the water rose to a final value of 3heat losses to the room and the heat capacity of the beaker itself, what isthe alloyDeselectSkip​

Answer»

er of soil which is just below the top-soil is called B-horizon. It is ALSO KNOWN as sub-soil. The sub-soil is MADE up of slightly bigger rock particles than that of top-soil. ... The sub-soil has very little humus (decayed ORGANIC matter).

46521.

Calculate the formula unit of Kc1 , Naco3 ( atomic mass of k-39ce , CI-35.5U, Na-23u, C-12u, O-16u. ■dont spam the question■​

Answer» SORRY I had SPAM your
46522.

Odd man out volume area length force​

Answer» FORCE...YO By the WAY HII
46523.

IS The number of moles contain 25 g of CaCO3 : - (RAM: - Ca=40, C=12, O=16) = 3 moles

Answer»

number of moles CONTAINING 25 gram of caco3 m c is equal to 40 c is equal to 12 is equal to 16 is equal to 3 moles

46524.

S-P overlapping is present in​

Answer»

If you LIKE the ANSWER Please FOLLOW me on the brainly Explanation:s-p overlapping one such type of overlapping. Here there is a overlapping between the s- and p- ORBITAL's of the molecules. This type of overlapping is generally seen in the NH3 molecules. This formed by overlapping between 3 orbital's of hydrogen and 3 of nitrogen.

46525.

निम्नलिखित के लिए कारण बताइए :(i)कक्ष ताप पर HF द्रव है और HCI गैस​

Answer»

intermolecular Hydrogen BONDING is PRESENT in HF WHEREAS HCl has not.

46526.

व्हाट इज द मीनिंग ऑफ फ्रूट​

Answer»

aapka matlab FRUIT KA hindi me matlab...so... फलExplanation:MARK me brainlistand follow me

46527.

The no of -bonds in 1-hexen-3-yne is​

Answer»

Here is your ANSWER I was PLAYING CHESS with my FATHER.

46528.

Can be reduced to aluminium by coke electrolysis h2 co2 ​

Answer»

In extraction of aluminium following reaction takes place:2Al 2 O 3 ⟶4Al+3O 2 Oxygen is given off at the positive carbon anode. Carbon dioxide is also given off at the anode because hot oxygen reacts with the carbon anode to FORM carbon dioxide gas. C+O 2 ⟶CO 2 The carbon ANODES slowly disappear because each molecule of carbon dioxide which is given off takes a little piece of carbon away with it.Hence, The role of coke in the ELECTROLYTIC reduction of alumina is to prevent burning of carbon rods

46529.

How many carbons are present in parent carbon chain of following compound LaII CCIwCN​

Answer» TION:I think 3 are PRESENT mark as brainliest
46530.

Find the molecular Find the molecular masses of the following1) KNO. 2) MGCI, 3) Ca(OH)4) H, SO5) NaHCO,6) Na, SO​

Answer»

How to Find Molecular MASS (Molecular WEIGHT)Determine the molecular formula of the molecule.Use the PERIODIC table to determine the atomic mass of each ELEMENT in the molecule.Multiply each element's atomic mass by the number of ATOMS of that element in the molecule.

46531.

А. 1.Name the Solute and Solvent in the given solutions : A]Tincture of iodine B]Soda water]2.23 g of salt is dissolved in 100 g of water at 293K. Find the concentration of the solution atthis temperature3.A] Name the components of a colloidal solution and defineB] How will you identify the given solution is a colloid?4. Based on the following characteristics distinguish in a tabular form the behaviour of Truesolution, Suspension and Colloidal solution :a) Appearance b) Particle size c) StabilityS.A) How will you confirm that a colourless liquid given to you is pure water?BDifferentiate between mixtures and compounds (any 2 points)[3]6. Water is considered as a compound of Hydrogen and Oxygen and not a mixture of Hydrogenand Oxygen. Comment on the statement.​

Answer» SORRY because I don't knowExplanation:sorry I didn't KNOW ANSWER of the QUESTION
46532.

Are koi to thank kr do mere answers ko...............please...​

Answer»

okkkkkkkk SURE....,....DONE!

46533.

The number of moles contain 25 g of CaCO3 is : - (RAM: - Ca=40, C=12, O=16)

Answer»

jfkksoaokwksixidjkssjsjsjsjsmsmExplanation:jwoaksnsjs

46534.

An element X has configuration 2K 8L 2M while element Y has configuration 2K 6L. Which isincorrect statement?(1) X is alkaline earth metal(2) Oxide of X is basic in nature(3) Y is divalent in nature(4) Formula of compound formed by Xand Yis X2YAnd it correct and agin free 100 pts​

Answer»

(3) Y IS DIVALENT IN NATUREIS THE CORRECT ANSWERMARK ME AS THE BRAINLIEST

46535.

Draw line spectrum of hgydrogen ?​

Answer» PLEASE MARK me as a BRANILIST
46536.

How will you identify the given solution is a colloid?​

Answer»

it's a colloidal ARRANGEMENT, it can demonstrate this following properties are appears to be homogeneous however really HETEROGENEOUS, its molecule can't be seen by stripped EYE and it INDICATES tyndall IMPACT. ... A colloid has bigger particles which don't settle out yet do disseminate light.

46537.

Choose the incorrect order. (1) Nitrogen < Oxygen (Electronegativity)(2) Potassium > Sodium (Metallic character)(3) Mgo < CO (Basic strength)(4) Oxygen > Carbon (Electron affinity)And it correct agin points for free​

Answer»

the answer is (3)Explanation:It is so because mg is a metal and being a metal it forms a metallic oxide which is basic in NATURE...so it has more basic strength than NON metallic oxide(CO).HOPE it helps❤:)

46538.

Consider the following reactionHOThe major product (X) of the reaction​

Answer» CONSIDER the following reaction:CH 3 − D∣C H− CH 3 ∣C H −CH 3 + B∙ r⟶X+HBrIdentify the structure of the major product 'X'
46539.

Which ofthe following electronic configuration iscorrect for zinc ? Atomic number = 30a) [Ar] 3d10 4p²?b.) [Ar] 4s² 3d104p¹c.) [Ar] 4s²4p6d.) [Ar] 4s² 3d10​

Answer»

a) [AR] 3D10 4p²Explanation:I HOPE it HELP for you

46540.

for a particular reaction the oxidation number of oxidant changes from - 1 to -2 ,-1 to 0 , 0 to 1 ,both a and b​

Answer»

tion:Among the various options given in QUESTION statement, the correct option is second one that is for a particular reaction the oxidation number of OXIDANT changes from -1 to 0.Oxidation number is defined as the charge number on the ELEMENT when considered as a composition of ions. Now in onxidation process, the element will lose an ELECTRON so if it has -1 charge, then losing an electron will make it 0

46541.

Iron reacts with air in presence of water and forms a brown powder which is called rust. Chemically rust is OptionsO iron oxidehydrated iron oxideO iron sulphateiron carbonate​

Answer»

oxide..Rust is an iron oxide, a usually reddish brown oxide formed by the reaction of iron and OXYGEN in the presence of WATER or air MOISTURE. ... Rust consists of hydrated iron(III) oxides Fe2O3·nH2O and iron(III) oxide-hydroxide (FEO(OH), Fe(OH)3). It is typically associated with the corrosion of refined iron.

46542.

This temperature.3.A] name the components of a colloidal solution and define.​

Answer»

There are two components of colloidal solution-- dispersed phase and DISPERSING MEDIUM. The solute like component of colloid solution is CALLED dispersed phase and solvent like component is called dispersing medium. The dispersed phase and dispersing medium may be solid,LIQUID or gas.Explanation:HOPE it's help full to you....

46543.

Pv=1/3mnu² what is m and n​

Answer» TION:jeduidjoekwowowpwwowowooowoooppppep
46544.

A compound contains At in simple cubic lattice with Be in the cubic void.Determine the simplest formula if one ofAt in the simple cubic cell is replaced byctABC7ООООO A₃B&CD AB2CABCchemistry​

Answer»

ABC7Explanation:PLEASE MARK me BRAINLIEST and FOLLOW me

46545.

Important reactions of chapter metals and nonmetals of class 10 please provide me correct answer for (brainliest) ​

Answer» REACTION of metal with WATER. Reaction of metals with acid. Reaction of metals REACT with SOLUTIONS of other metal salts
46546.

The collision theory is applicable only to the reactions between simple gaseous moleculessolid moleculesliquid moleculesboth b and c​

Answer»

tsyeyisieyytwgskeleyesfsutsysyskfwtsjts5biweeklysmileys GTA haajuahsteyeeyesudusysjyejwuwuwhwjweuktie2U3h3u

46547.

8.281 has how many significant figures?​

Answer» 4 SIGNIFICANT figureExplanation:
46548.

Assertion:brown fumes are produced when Lead Nitrate is heated. Reason:Nitrogen dioxide gas is produced as a byproduct due to the decomposition of Lead Nitrate.what option is correct from the above pic...​

Answer»

if both ASSERTION and REASON are CORRECT and reason is correct EXPLANATION of assertion

46549.

What is meant by ionisation energy?​

Answer»

Ionization energy, also called ionization potential, in CHEMISTRY and physics, the AMOUNT of energy required to remove an electron from an isolated atom or molecule.Explanation:please MARK me as brainlist ❣️

46550.

Prove that the third equation of motion and convert the SI unit of the force into CGS unit .​

Answer» ANSWER attached.Hope it helps....PLEASE MARK ME AS THE BRAINLIESTFOLLOW ME TOOTHANK ME ALSOPLEASE GUYS!!!!