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cutaneous TISSUE (from Latin subcutaneous 'beneath the skin'), ALSO called the HYPODERMIS, hypoderm (from Greek 'beneath the skin'), subcutis, superficial fascia, is the lowermost LAYER of the integumentary SYSTEM in vertebrates.

श्वसन से जुड़ी विभिन्न पेशियों के संकुचन के साथ फेफड़े फैल जाते हैं जिससे छाती के भीतर का दबाव बदल जाता है और फेफडों में हवा भर जाती है। यह निश्वास है जिसके लिए पेशीय शक्ति की आवश्यकता होती है। उन्हीं पेशियों के शिथिलन के साथ आपके फेफड़ों से हवा बाहर निकलती है और आप उच्छवास लेते हैं।

सोडियम क्लोराइड को अमोनियम क्लोराइड से पृथक करने के लिए सब्लीमेशन प्रोसेस का इस्तेमाल करते हैं सब्लीमेशन एक प्रकार की वह विधि है जिसमें किसी ठोस पदार्थ को गर्म करने पर वह बिना द्रव अवस्था में बदले सीधे गैस की अवस्था को प्राप्त कर जाता है इसे हिंदी में उर्दू पाचन भी कहते हैं आप सोडियम क्लोराइड और अमोनियम क्लोराइड के मिश्रण को गर्म कर दीजिए जिससे कि अमोनियम क्लोराइड इवेपरेट हो जाएगा इनकी सप्लीमेंट हो जाएगा आवश्यक कंसेशन के थ्रू आप कनेक्ट करके अलग कर सकते हैं इस प्रकार से सोडियम क्लोराइड और अलग अलग हो जाएंगे धन्यवाद

The four most important factors that influence CROP yield are soil FERTILITY, availability of water, climate, and diseases or pests. ... The absence of any one of these nutrients has the potential to DECREASE crop yield by negatively affecting the associated GROWTH FACTOR.

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bUHAFURGVYUGHSDJFDMFHKEJHS,DMFCELWKS,DMZSDSExplanation:

Tajmahel DAMAGE because of ACID RAIN

100HzExplanation:SECOND ONE RIGHT ANSWER

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20 m/secExplanation:Initial VELOCITY (U) = 10 m/secInitial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mInitial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third LAW of Motion,Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asInitial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400 Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400 v = 20 m/secInitial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400 v = 20 m/sec_____________________________Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400 v = 20 m/sec_____________________________ANSWER =Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec 2 Distance (s) = 30 mFinal velocity (v) = ??Using Newton's Third law of Motion,v 2 =u 2 +2asv 2 =10 2 +2×5×30 v 2 =100+300 v 2 =400 v = 400 v = 20 m/sec_______________________ ANSWER =FINAL VELOCITY = 20 m/secMARK ME AS BRAINLIEST ANSWER

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listen metals can be hammered answer CEXPLANATION:It is the ability of a solid to BEND or be hammered into other shapes without BREAKING. Examples of malleable metals are gold, iron, aluminum, COPPER, silver, and lead. Gold and silver are highly malleable. When a piece of hot iron is hammered it takes the SHAPE of a sheet

ii) III) ODD TERM- CentrosomeCategory- PLANT CELL

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By placing the thick round piece of CLOTH on their head, the porter INCREASES the area of contact of load with their head. Now the force of load falls on the larger area due to which the pressure on the head DECREASES and it becomes easier for a porter to carry the heavy load.Explanation:HOPE it MAY help you..

if an object moves at a constant SPEED of 10 ms- 1 on a CIRCULAR PATH with RADIUS r then the object moves 20 m .

answer is option C CLAUDE air liquefaction system employ EXPANDED

re able to sit on electrical POWER lines because the electrical current ESSENTIALLY ignores the bird's presence and continues to TRAVEL through the wire instead of through the bird's BODY. A bird's body is not a good conductor of electricity.Nikkuuuu~

Osmosis is the movement of solvent particles across a SEMIPERMEABLE MEMBRANE from a dilute solution into a concentrated solution. Diffusion is the movement of particles from an area of higher CONCENTRATION to lower concentration. The OVERALL EFFECT is to equalize concentration throughout the medium.Have a great day ahead

The MAIN difference between STARS and planets is that stars have high temperatures compared to planets. Stars undergo nuclear reactions—usually they burn hydrogen in their CORES, releasing massive amounts of energy. ... Planets do not GENERATE their own energy through nuclear reactions.

Rutherford scattering is the elastic scattering of CHARGED particles by the Coulomb interaction. It is a physical PHENOMENON explained by Ernest Rutherford in 1911 that led to the DEVELOPMENT of the planetary Rutherford model of the ATOM and eventually the Bohr model.

The roof and walls of the auditorium or cinema hall are generally covered with sound ABSORBENT materials like draperies or compressed fibreboard to reduce reverberation. These materials reduce the FORMATION of echoes by ABSORBING sound waves.04-Jul-2021

Hmax=1002×10=5m. So the maximum height reached by the body when it is thrown VERTICALLY upwards with a velocity of 10m/s is 5 m. So this is the REQUIRED ANSWER. HENCE OPTION (A) is the correct answer.

There are a NUMBER of lizards with blue tongues, all found in Australia, all thought to have the blue tongue as a MEANS of protection against PREDATORS. Just to name a few: The Eastern blue tongue lizard, the PYGMY blue tongue lizard, and the bob-tailed blue tongue lizard.mark this answer as a brainliest.

By PLACING the thick round piece of CLOTH on their head, the porter increases the area of contact of LOAD with their head. Now the FORCE of load falls on the larger area due to which the PRESSURE on the head decreases and it becomes easier for a porter to carry the heavy load.Explanation:❤HOPE IT HELPS❤

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it's about FISH CROCODILE has LUNGS

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I don't UNDERSTOOD BROO SRRY I can't ANSWER it

During the PROCESS of digestion, the carbohydrates break down to SIMPLE SUGARS the proteins into glycerol and the FATS into fatty acids.

option a- SODIUM metabisulphateExplanation:It is USED for the preservation of fishes, MEAT etc

it is BOTANY if it is CORRECT PLS MARK me the BRAINLIEST

(i) Despotism or ACQUIREMENT(ii) STUDYING the theories(iii) NATURAL resources(iv) FEDERAL government.

The human body is a very complex ORGANIC body. It is a functional system composed of many tissues and ORGANS. Its principal components INCLUDE the zang and FU viscera, the non-organ structures, the SENSE organs and orifices, the material bases of vital activities (essence, Qi, blood, body fluids, etc.)

using v =u + at45 = 20 + a × 425= 4aa = 25/4= 6.25 KM HR -2 is the acceleration

By USING CARBOARD, chart PAPER, two simple PLANE mirrors, celotape etc.Explanation:

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lenticelsplant:MANGO TREE