Explore topic-wise InterviewSolutions in .

In first figure, (101 + 15) - (35 + 43) = 116 - 78 = 38. 

The same pattern would be followed in second figure. 

∴ Missing number = (48 + 184) - (56 + 34) = 232 - 90 = 142. 

Ans. (B) 142 

Gap of letters between the two consecutive terms is increased by +1. So, the missing would be L. 

The series is b a b c / b a b c / b a b c 

So, pattern babc is repeated 

Ans. (D) bacc 

Series is aaabb/aaabb/aaabb. So, pattern aaabb is repeated. 

Ans. (C) aabab 

we proceed step by step to solve the above series : 

Steps: 

1. The first blank space should be filled in by ‘b’ so that we have two ‘a’s followed by b’ s 

2. Second blank space should be filled in by ‘a’ so that we have three a’s followed by three b’ s 

3. The last blank space must be filled in by ‘a’ to keep the series in sequence 

Ans. (A) 

The number at the bottom are the H.C.F. of above given numbers 

Clearly 9, is the HCF of 36, 18 and 27. 

Ans. (C) 9 

The number ‘143’ given inside the triangle is the combination of √1, √16, √9 . In same manner number ‘236’ is combination of √4 ,√9 √36 . Thus, the answer is ‘4’. 

Ans. (C) 4  

The sequence is a combination of two series. 

I 14, 12, 9, 4, (.....) and 

II 15, 16, 18, 21 

The pattern followed in I is -2, -3, -5, ..... 

∴ missing number = 4 - 7 = - 3

Ans. - 3 

In first figure 12×14/2 =84 . In second figure 9×18/2 =81  

Let the missing number In third figure be x. Then 11 x x/2= 88 or x=88x2/11= 16

Ans. (A) 16

The square of the number at the bottom is equal to the product of the two upper numbers. Thus, In first figure, 4 × 9 = 6² = 36. 

In second figure, 9 × 16 = 12² = 144. 

Let the missing number in third figure be x. 

Then, 16 × x = 20² = 400 or x = 400/16 =25 

Ans. (D) 25

4² + 5² = 16 + 25 = 41 

1² + 2² = 1 + 4 = 5 

6² + 7 = 36 + 49 = 85 

Ans. (C) 85

In first figure, 6 × 3 + 3 × 5 = 33 

In second figure, 5 × 4 + 4 × 7 = 48 

∴ In third figure, 5 × 4 + 3 × 5 = 35 

Ans. (D) 35 

The letters in the first row form a series C,D,E (a series consecutive letters). The letter in the second row form a series I, K, M (a series of alternate letters). Similarly, the letters in the third row will form the series D, G, J (a series in which each letter is there steps ahead of the previous one). So, the missing letter is G. Also, the number in the second column is equal to the product of the numbers in the first and third columns. So, missing number is (4 + 7) i.e. 28 Thus, the answer is 28 G. 

Ans. (B) 28G 

The series is a b c d / b c d e a / c d e a b / b e a b c 

Thus the letters are written in a cyclic order. 

Ans. (A) deabc 

In the first row, 6 + 9 = 15 

In the second row, 8 + 12 = 20 

∴ In the third row, missing number = 4 + 6 = 10. 

By taking e = 5, I = 4, m = 6, y = 7 and x = 8 the number series runs as 46758 67485 74658 46785. By taking the digits in the groups of five, we find that first digit of the first group (i.e. 4) is the third digit of the second group and the last two digits have interchanged their positions. The same rule applies in others groups also. 

Ans. (D) 46785  

As per series a, ak, ak², ak³, ....... 

a = 9+, k = 2 

ak³ = 9 × 2³ = 72 

Ans. 72