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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
Rs. 6000 was lent at compound interest for 2 years. The rates of interest for the first and second years were 10% per annum and 30% per annum respectively. If the rate of interest each year had been 20% per annum, then the additional amount obtained would have been (in Rs. ).A. 60B. 30C. 90D. 120 |
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Answer» Correct Answer - A Amount realised (in Rs.) `=6000(1+(10)/(100))(1+(30)/(100))` =6000(1.1)(1.3)=850 If the rate of interest each year was 20% per annum, amount realised (in Rs. )`=6000(1+(20)/(100))^(2)` `=6000(1.2)^(2)` `=6000(1.44)=8640` `therefore` Additional amount realised = Rs. 60 |
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| 52. |
Rs. 2800 was split into two parts. One part was lent at 20% per annum simple interest for 10 years. The other part was lent at 25% per annum simple interest for 20 years. Each part yielded equal interest. Find the lower part (in Rs.).A. 800B. 900C. 1000D. 1200 |
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Answer» Correct Answer - A Let the one part be Rs. X. `therefore` The other part would be Rs. (2800-x). `((x)(10)(20))/(100)=((2800-x)(20)(25))/(100)` `implies 2x=5(2800-x)` x=2000 `therefore` The lower part =2800-x =800. |
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| 53. |
The difference between the compound interest and the simple interest on a certain sum of money for 2 years at 11% per annum is Rs. 363. Find the sum.A. Rs. 33000B. Rs. 31000C. Rs. 30000D. Rs. 32000 |
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Answer» Correct Answer - C Calculate the interest on the sum in both the cases. |
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| 54. |
50. A sum was split into three parts. The first to lent at 20% per annum for 2 years. The Part the part was lent at 10% per annum for 5 years third part was lent at 30% per annum for 4 yen Each was lent at simple interest and the interest realised from each was the same Find e o ally ratio of the first, second and third parts. the times (a) 24000 b) 4200 um is (c) R 4400 d the (d) R 40000 S. A sum of money amounts to 72000 in 3 year |
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Answer» Correct Answer - `15 : 12 : 5` N//A |
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| 55. |
A sum was split into three parts. The first part was lent at 10% per annum for 4 years. The second part was lent at 20% per annum for 6 years. The third part was lent at 30% per annum for 5 years. Each part was lent at simple interest and the same amount of simple interest was realised from each. Find the ratio of the first, second and third parts.A. `15:5:2`B. `20:7:2`C. `15:5:4`D. `20:9:4` |
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Answer» Correct Answer - C N//A |
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| 56. |
A sum of Rs. 3000 is partly lent at 3% per annum simple interest for `(7)/(2)` years and partly at 2% per annum simple interest for 4 years. If total interest earned is Rs. 280, then the sum lent at 3% per annum isA. Rs. 1600B. Rs. 1400C. Rs. 1800D. Rs. 2000 |
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Answer» Correct Answer - A Use formula for amount at different rates. |
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| 57. |
Find the least integral number of years in which a sum at `20%` per annum compound interest will be more than double.A. 4B. 5C. 3D. 6 |
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Answer» Correct Answer - A i) Let the sum be Rs P. ii) `P(1+20/100)^(n) gt 2P`, solve the inequality for n. |
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| 58. |
A sum of Rs 3000 is lent out in two parts. The smaller part is lent at `10%` per annum and the larger part is lent at `20%` per annum. If the total interest in a year is Rs 500m then find the sum lent is 10% per annum (in Rs.).A. 800B. 1000C. 1000D. 900 |
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Answer» Correct Answer - B i) Let the two parts be Rs `x` and Rs `(300-x)`, respectively. ii) In `(x xx 10)/100 + ((300-x)20)/100=500`, find `x`. |
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| 59. |
The integral number of years in which a sum of money at 25% per annum under compound interest will become more than twice itself is at least.A. 3B. 2C. 4D. 1 |
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Answer» Correct Answer - C i) Let the sum be Rs. P. ii) `P(1+20/100)^(n) gt 2P`, solve the inequality for n. |
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| 60. |
Given that carbon-14 `(C_(14))` decays at a constant rate in such a way that it is reduced to 25% in 1244 years. Find the age of a tree in which the carbon is only 6.25% of the original.A. 3122 yearsB. 3210 yearsC. 3124 yearsD. 3214 years |
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Answer» Correct Answer - C (i) Use formula for depreciation. (ii) In first 1562 years, it reduces to 20%. (iii) In next 1562 years, it reduces to 20% of 20%, i.e., 4%. |
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| 61. |
Find the compound interest on Rs 50,000 for 3 years, compounded annually, and the rate of interest being `10%, 12%` and `15%` for the three successive years, respectively.A. 20840B. 70840C. 60720D. 67560 |
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Answer» Correct Answer - A (i) Use formula for amount at different rates. (ii) `C.I. =P[(1+(R_(1))/(100))(1+(R_(2))/(100))(1+(R_(3))/(100))-1]` |
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| 62. |
A certain sum amounts to Rs. 4800 in 4 years and to Rs. 5250 in 5 years at simple interst. Find the interest for 2 years. |
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Answer» Correct Answer - Rs. 900 N//A |
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| 63. |
The simple interest on Rs. 1800 at R% per annum for 2 years is equal to the simple interest on Rs. 4800 at 15% per annum for 1 year. Find the simple interest (in Rs. ) on Rs. 2400 for 3 years at R% per annum. |
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Answer» Correct Answer - 1440 N//A |
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| 64. |
Find the sum to be invested to earn a simple interest of Rs. 360 in 8 months at the rate of 15% per annum. |
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Answer» Let Rs P be the required sum. Given that, Simple interest = Rs. 360, Rate of interest (R )= 15% and Time period (T)=8 months `=(8)/(12)` years But, simple interest `=(PTR)/(100)` `therefore (Pxx(8)/(12)xx15)/(100)=360 implies P =3600` Hence, required sum= Rs. 3600. |
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| 65. |
A certain sum amounts to Rs. 320 at 6% per anuum simple interest and to Rs. 360 at 8% per annum simple interest. Find the principal. |
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Answer» Correct Answer - Rs. 200 N//A |
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| 66. |
Ravi borrowed Rs 15,000 at the rate of `15%` per annum for 2 years under simple interest. As he could not repay the loan after two years, the moneylander lender increased the rate of interest to `20%` per annum for the further period. If Ravi wants to repaythe entire amount at the end of a total period of 3 years and 4 months, then how muchhe has to pay. (in Rs.)A. 24500B. 24000C. 23.5D. 23000 |
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Answer» Case 1: For the first two years `P=15,000, R=15%, T=2` `I = (15,000 xx 15 xx 2)/(100) = Rs 4500` Case 2: For the remaining time period `P=15,000, R=20%, T=16` months `I = (15,000 xx 20 xx 16/12)/(100)` `rArr I=(15,000 xx 20 xx 16)/(1200) = Rs 4000`. `therefore` Total amount that Ravi has to pay =15,000 + 4500 + 400 = Rs 23,500 |
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| 67. |
Find the simple interest on (a) Rs. 2500 at 15% per annum for 2 years. (b) Rs. 3000 at `17 (1)/(3)%` per annum for `1(1)/(2)` years. |
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Answer» (a) Given, Principal (P)=Rs. 2500, Rate (R )=15% and Time period (T)=2years `therefore` Simple interest `=(PTR)/(100)=(2500xx2xx15)/(100)=750` Hence, simple interest = Rs. 750 (b) Given, Principal (P)=Rs. 3000 Rate (R )`=17(1)/(3)%=(52)/(3)%` per annum And time period(T) `=1(1)/(2)` years `therefore` Simple interest `=(PTR)/(100)=(3000xx(3)/(2)xx(52)/(3))/(100)=780` Hence, simple interest =Rs. 780 |
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| 68. |
Kailash set up a factory by investing Rs. 1000000. During the first two years, his profits were 10% and 15% respectively. If he reinvested the profit of each year at the beginning of the next year, his total profit (in Rs. ) isA. 265000B. 25000C. 275000D. 27060 |
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Answer» Correct Answer - A (i) `A=P(1+(R_(1))/(100))(1+(R_(2))/(100))` (ii) Find the amount at the end of a year. (iii) The amount at the end of one year will be the principal for the second year. |
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| 69. |
In what time will the sum of Rs. 1875 yield a compound interest of Rs. 477, at 12% per annum, compounded annually ?A. 2 yearsB. 1 yearsC. 3 yearsD. `1(1)/(2)` years |
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Answer» Correct Answer - A (i) Use `C.I.=P(1+(R )/(100))^(N)-P` and evaluate N. (ii) C.I. =Rs. 477, P=Rs. 1875, R=12%, find n. |
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