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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
At what rate percent perannum simple interest will a sum double itself in 10 years?(a) 8% (b) 10%(c) 12% (d) `12 1/2%` |
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Answer» let principal amoun be P. Amount=P+simple interest Amount=2P simple interest=P simple interest= `(P xx R xx T)/100=P` T=10 yrs so R=Rate =10% |
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| 2. |
Divide Rs2379 into 3 parts so that their amounts after 2, 3 and 4 years respectivelymay be equal, the rate of interest being 5% per annum at simple interest. Thefirst part is(a) Rs759 (b) Rs 792 (c) Rs 818 (d) Rs 828 |
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Answer» Let the three parts be `x,y and z` respectively. Now Amount=principal amount +simple interest simple interest=`(PxxRxxT)/100` given amount on all three of them are same. =>`x+(10x)/100=y+(15y)/100=z+(20z)/100` =>`110x=115y=120z` =>`y=(110x)/115` and z=`(11x)/12` Also `x+y+z=2379` substituting values we get=>x=Rs.828. |
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| 3. |
In a bank if `4750Rs` is deposited in simple interest, it becomes an amount of `6650Rs` after a period of time of `4` years. According to the same rate of interest, in how many days `85000Rs` will amount `106250Rs`? |
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Answer» Let the rate of simple interest be `r%` per annum. In the first case, the amount `=6650Rs` and the principal `=4750Rs` `:.` Interest `=Rs(6650-4750)=1900Rs`. Accordingly we get, `(4750xx rxx4)/(100)=1900` `impliesr=(1900xx100)/(4750xx4)=10` `:.` The rate of interest in percent per annum `=10%` Also, let `85000Rs` amounts `106250Rs` in `t` years. i.e, principal `=85000Rs`, Amount `=106250Rs` `:.` Interest `=Rs(106250-85000)=21250Rs` `:.` Rate of interest per annum `=10%` and period of time `=t` years `:.(85000xx10xxt)/(100)=21250` `impliest=(21250xx100)/(85000xx10)=(5)/(2)=2(1)/(2)` `:.Rs85000` amounts `Rs106250` in `2(1)/(2)` years. |
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| 4. |
In how many years will acertain sum become 3 times itself at 25% per annum under simple interest?(a) 5 (b) 8 (c) 12 (d) 6 |
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Answer» Principal amount be P. Amount= principal amount+simple interest 3P=P +simple interest =>simple interest=2P =>`2P=(P xx R xx T)/100` given R=25% =>`2 xx 4=8 yrs=T` |
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| 5. |
A certain money amounts `9440Rs` on simple interest in `3` years. If the rate of simple interest be `25%` increased per annum, then the money will become `9800Rs` after same period of time. Find the principal and the rate of interest in percent per annum. |
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Answer» The difference between two given amounts `=Rs(9800-9440)=360Rs` Since the principal and period of time are the same, we can say that due to `25%` increase of interest, the increase in amount is `Rs360` `:.25%` of interest `=Rs360` `1%` of interest `Rs(360)/(25)` `100%` of interest `=Rs(360)/(25)` `100%` of interest `=Rs(360xx100)/(25)=Rs1440` `:.` Simple interest in `3` years `=Rs1440` So, the principal `=Rs(9440-1440)=Rs8000` Now, let the rate of interest be `r%` in percent per annum `:.(8000xxrxx3)/(100)=1440impliesr=(1440xx100)/(8000xx3)=6` `:.` The required principal `=8000Rs` and rate of interest in percent per annum `=6%`. |
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| 6. |
A person deposited `50000Rs` for his son of age `10` years, in a monetary fund. The fund investing that money at the rate of `4%` simple interest per annum, gave the sone a quantity of `1200Rs` at the end of every year. The annual expenses of the fund is `300Rs`. After fulfilling `18` years, what amount the boy will get from the fund? |
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Answer» At the rate of `4%` per annum, the interest of `Rs50000` in `1` year `=Rs(50000xx4xx1)/(100)=Rs2000` The annual expenses of the fund `=Rs(1200+300)=Rs1500` `:.` Rest of the money `=Rs(2000-1500)=Rs500` `:.` After completion of `18` years, the total quantity of simple interest `=Rs(18-10)xx500=Rs4000`. `:.` The total amount the boy will get from the fund at the end of `18` years `=Rs(50000+4000)` `=Rs54000`. `:.` The required amount `=Rs54000`. |
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| 7. |
Find the simple interest,when:(i) Principal= Rs 4500, Rateof Interest= 4% per annum and Time =6 months.(ii) Principal= Rs 12000, Rateof Interest= 18% per annum and Time =4 months.(iii) Principal= Rs 1000, Rateof Interest= 10% per annum and Time =73 days. |
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Answer» Simple interest =`(P xx R xx T)/100` where P is the principal amount , R is the rate and T is time. 1. P=4500,R=4,T=0.5 applying in formula, simple interest=Rs.90 2.1. P=12000,R=18,T=`1/3` applying in formula, simple interest=Rs.720 3.1. P=1000,R=10,T=0.2 applying in formula, simple interest=Rs.20 |
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| 8. |
Aslamchacha got Rs 100000 when he retired from his service. He deposited some of that money in the bank and rest of his money in the post-office and got `5400Rs` in total per year as interest. If the rates of simple interest per annum in the bank and in the post-office are `5%` and `6%` respectively, then find the money he had deposited in the bank and post-office. |
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Answer» Let Aslamchacha deposited `Rs x` in the bank. `:.` He deposited `Rs(100000-x)` Now, the simple interest of `Rs x` in `1` year `=Rs (x xx5xx1)/(100)=Rs(5x)/(100)` Again, the simple interest of `Rs(100000-x)` in `1` year at the rate of `6%` per annum `=Rs((100000-x)xx6xx1)/(100)=Rs(600000-6x)/(100)` As per question, `(6000000-6x)/(100)+(5x)/(100)=5400` `implies(6000000-6x+5x)/(100)=5400` `implies600000-x=540000` `impliesx=600000-540000=60000` `:.` Aslamchacha deposited `Rs60000` in the bank. `:.` He deposited `Rs(100000-60000)=Rs40000` in the Post Office. `:.` Aslamchacha deposited `Rs60000` in the bank and `Rs40000` in the post-office. |
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| 9. |
A person took a loan of `Rs40000` at the rate of `10%` simple interest per annum to contruct a house. After `2` years he gave return `Rs20000` to the bank. After more `2` years what amount should he return to the bank so as to repay his completely? |
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Answer» At the rate of `10%` per annum, the simple interest of `Rs40000` in `2` years `=Rs(40000xx10xx2)/(100)=Rs8000` When the person gave `Rs20000` to the bank, it will cut `Rs8000` from `Rs20000` as interest and the rest of the money, i.e., `Rs(20000-8000)=Rs12000` will be subtracted from the principal `Rs40000`. Thus, for the next `2` years , the person will have to pay interest on the principal `Rs(40000-12000)=Rs28000`. Now, the simple interest of `Rs28000` in `2` years at the rate of `10%` per annum `=Rs(28000xx10xx2)/(100)` `=Rs5600` `:.` The total amount `=Rs(28000+5600)=Rs33600` Hence, the person have to pay `Rs3300` to the bank after more `2` years so as to repay his loan completely. |
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| 10. |
The simple interest of a principal in `1` year and `9` months at the rate of simple interest of `5%` per annum is `63Rs` more than of the same principal in `2` years and `4` months at the rate of simple interest of `4(1)/(2)%` per annum. Find the principal. |
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Answer» `1` year and `9` months `=(1+(9)/(12))` years `=(7)/(4)` years. Similarly, `2` years and `4` months `=(2+(4)/(12))` years `=(7)/(3)` years. Now, let the principal be `Rs x`. So, the simple interest of `Rs x` in `(7)/(4)` years at the rate of `9%` simple interest per annum `=Rs(x xx5xx7)/(100xx4)=Rs(7x)/(80)` Again, the simple interest of `Rs x` in `(7)/(3)` years at the rate of `4(1)/(2)%` simple interest per annum `=Rs(x xx9xx7)/(100xx2xx3)=Rs(21x)/(200)` As per question, `(21x)/(200)-(7x)/(80)=63implies(42x-35x)/(400)=63` or, `(7x)/(400)=63` or, `7x=63xx400` or, `x=(63xx400)/(7)` or, `x=3600` `:.` The required prinicpal `=Rs3600` |
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| 11. |
A bank gives `5%` simple interest per annum. In that bank, Dipubabu deposits `15,000Rs` at the beginning of the year, but withdraws `3000Rs` after `3` months and then again, after `3` months he deposits `8000Rs`. Determine the amount (principal along with interest) Dipubabu will get at the end of the year. |
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Answer» `3` months `=(3)/(12)` year `=(1)/(4)` year Now, simple interest of `Rs15000` in `3` months at the rate of `5%` per annum `=Rs(150000xx1xx5)/(100xx4)=Rs(375)/(2)=Rs187.50` Withdrawing `Rs3000`, the principal becomes `=Rs(15000-3000)=Rs12000` `:.` Then the simple interest of `Rs12000` in `3` months at the rate of `5%` per annum `=Rs(12000xx5xx1)/(100xx4)=Rs150` The rest time `=1` year - (`3` months `+3` months) `=12` months `-6` months `=6` months. `=(6)/(12)` year `=(1)/(2)` year `:.` The principal of the last months `=Rs(12000+8000)=Rs20000`. `:.` The simple interest of `Rs20000` in `6` months at the rate of `5%` per annum `=Rs(20000xx5xx1)/(2xx100)=Rs500` `:.` The toal interest `=Rs(500+150+187.50)=Rs837.50` `:.` Total amount `=Rs(20000+837.50)=Rs20837.50` `:.` Dipubabu will get an amount `Rs20837.50`. |
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| 12. |
Rahamatchaha takes a loan amount of `2,40,000Rs` from a bank for constructing a building at the rate of simple interest of `12%` per annum. After `1` year of taking the loan he rents the house at the rate of `5200Rs` per month. Then, determine the number of years he would take to repay his loan along with interest from the income of the houserent. |
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Answer» Let Rahamatchacha repay his loan along with interest after `x` years of the construction of the building. Now, the houserent per month `=Rs5200` `:.` Houserent of `1` year `=Rs5200xx12` `:.` Houserent of `x` years `=Rs5200xx12xx x`. Since, the house was rented after `1` years. `:.` The loan was repaid after `(x+1)` years. Now, the simple interest of `Rs240000` in `(x+1)` years `=Rs(240000xx12xx(x+1))/(100)` `=Rs2400xx12(x+1)` `:.` Amount `=Rs{240000+2400xx12(x+1)}` `=Rs2400[100+12x+12]` `=Rs2400(112+12x)` `:.2400(112+12x)=5200xx12x` `implies112+12x=(5200xx12x)/(2400)` `implies112+12x=26ximplies26x-12x=112` `implies14x=112` `impliesx=(112)/(14)=8` `:.` The required time `=(8+1)` years `=9` years. |
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| 13. |
Soma auntie deposits `6,20,000Rs` in such a way in three banks at the rate of simple interest of `5%` per annum for `2` years , `3` years and `5` years respectively so that the total interests in the `3` banks are equal. Calculate the money deposited by Soma auntie in each of the three banks. |
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Answer» Let Soma auntie deposited `Rs x`, `Rs y` and `Rs z` respectively in the `1st`, `2nd`, and `3rd` bank. As per question, `x+y+z=620000`………`(1)` The simple interest of `Rs x` in `2` years at the rate of `5%` per annum `=Rs(x xx5xx2)/(100)=Rs(x)/(10)` At the same rate, simple interest of `Rs y` in `3` years `=Rs(yxx5xx3)/(100)=Rs(3y)/(20)` Also, at the same rate, simple interest of `Rs z` in `5` years `=Rs(zxx5xx5)/(100)=Rs(z)/(4)` As per question, `(x)/(10)=(3y)/(20)=(z)/(4)=k` (let) `implies2x=3y=5z=k` [Multiplying by `20`] `impliesx=(k)/(2)`, `y=(k)/(3)` and `z=(k)/(5)` Now, putting these values of `x`, `y`, `z` in `(1)` we get, `(k)/(2)+(k)/(3)+(k)/(5)=620000` or, `(15k+10k+6k)/(30)=620000` or, `31k=620000xx30` or, `k=(620000xx30)/(31)` or, `k=20000xx30=600000` `:.x=(600000)/(2)=300000` `y=(600000)/(3)=200000` `z=(600000)/(5)=120000` `:.` Some auntie deposited `Rs300000`, `Rs200000` and `Rs120000` respectively in these banks. |
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| 14. |
If the total interest of a principal in `6`years be `30%` of the principal , then the total interest will be equal to the principal inA. `10` yearsB. `20` yearsC. `22` yearsD. `30` years |
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Answer» Let the principal be `Rsx` and the rate of yearly simple interest be `r%` Then, the interest in `6` years `=Rs x xx(30)/(100)=Rs(3x)/(10)` `:.(x xx rxx6)/(100)=(3x)/(10)impliesr=(3x xx100)/(x xx6xx10)=5` `:.` The rate of interest `=5%` Also, let the required time `=t` years `:.(x xx5xxt)/(100)=ximpliest=(100xx x)/(5xx x)=20` `:.` The required time `=20`years. |
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| 15. |
Find the interest of `300Rs` from `3rd` March to `15` May, `2016` at the rate of annual simple interest of `6%` |
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Answer» Time `=28` days in March `+30` days in April `+15` days in May. `=73` days `=(73)/(365)` year `=(1)/(5)` year `:.` Total interest `=Rs(300xx6xx1)/(100xx5)=Rs(18)/(5)=Rs3.60` `:.` The required interest `=Rs3.60` |
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| 16. |
Find the principal of which the monthly interest is `1Rs` at the rate of `5%` annual simple interest. |
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Answer» Let the principal be `Rs x` Now, `1` month `=(1)/(12)` year `:.` Simple interest `=Rs(x xx5xx1)/(100xx12)=Rs(x)/(240)` As per question, `(x)/(240)=1impliesx=240` `:. ` The required principal `=Rs240` |
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| 17. |
If the interest of a principal in `10` years be `(2)/(5)th` part of itself, then find the yearly percentage of rate of simple interest. |
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Answer» Let the principal be `Rs x` and the yearly rate of simple interest be `r %` `:.` The interest of `10` years `=Rs(x xxrxx10)/(100)=Rs(xr)/(10)` `:.` Amount `=Rs(x+(xr)/(10))` As per question, `(2)/(5)(x+(xr)/(10))=(xr)/(10)` `implies(2x)/(5)+(2)/(5)xx(xr)/(10)=(xr)/(10)=(xr)/(10)implies(2x)/(5)=(xr)/(10)-(xr)/(25)` `implies(2x)/(5)=(5xr-2xr)/(50)` `implies(2x)/(5)=(3xr)/(50)` `impliesr=(2x xx50)/(5xx3x)=(20)/(3)=6(2)/(3)` `:.` Anuual rate of interest `=6(2)/(3)%` |
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| 18. |
The total interest of a principal of `Rs2000` in `18` months at the rate of yearly simple interest `6%` isA. `Rs 120`B. `Rs 180`C. `Rs 216`D. `Rs 260` |
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Answer» `18` months `=(18)/(12)` years `=(3)/(2)` years Here, `P=Rs2000` Rate of interest , `r%=6%` Period, `t=(3)/(2)` years `:.` Total interest `=Rs(2000xx6xx3)/(2xx100)=Rs180` `:.` The required total interest `=Rs180` |
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| 19. |
If principal amounts double in `10` years, then the rate of yearly simple interest isA. `5%`B. `10%`C. `15%`D. `20%` |
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Answer» Let the principal be `Rs x` and the yearly rate of simple interest be `r%` If the principal amounts `Rs 2x` in `10` years, then the interest `=Rs(2x-x)=Rs x` `:.` Total interest in `10` years `=(P rt)/(100)=Rs(x xx rxx10)/(100)=Rs(x r)/(10)` `:.(xr)/(10)=ximpliesr=(x xx10)/(x)=10` `:.` Rate of yearly simple interest `=10%` |
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| 20. |
Determine the total amount of `Rs5000` at the rate of `7(1)/(2)%` simple interest per annum is `5` years. |
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Answer» Here, `p=Rs5000`, `r=7(1)/(2)=(15)/(2)` and `t=5` `:.I=(prt)/(100)=Rs(5000xx(15)/(2)xx5)/(100)=Rs1875` Hence the required amount `=Rs(5000+1875)=Rs6875` |
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| 21. |
The ratio of the principal and the amount (principal along with interest) in `1` year is `8:9` , the rate of simple interest per annum is __________. |
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Answer» `12(1)/(2)%` , since let principal `=Rs8x` and amount `=Rs9x` `:. ` Interest `=Rs(9x-8x)=Rsx`. `:.` Simple interest per annum `=(x)/(8x)xx100%=(25)/(2)%=12(1)/(2)%` |
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| 22. |
The amount of `Rs 2p` in `t` years at the rate of simple interest of `(r )/(2)%` per annum is `Rs(2p+_________)`. |
| Answer» Answer: `(prt)/(100)` | |
| 23. |
A man who gives a loan is called __________________. |
| Answer» Answer: creditor | |
| 24. |
If the interest of a principal in `2` years be `(1)/(8)` of it, then find the rate of simple interest per annum. |
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Answer» Let the principal `=Rs p` and rate of interest `=r%` As per question, interest `=Rs pxx(1)/(8)=Rs (p)/(8)` Time , `t=2` years `:. Rs(p)/(8)=Rs(pxxrxx2)/(100)` [by formula] or, `r=(100)/(2xx8)=(25)/(4)=6(1)/(4)` Hence the required rate of simple interest per annum `=6(1)/(4)%` |
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| 25. |
The interest given or received for a certain period of time on certain amount of principal is called "Total interest". |
| Answer» Corect Answer: 1 | |
| 26. |
At what rate of simple interest in percent per annum, the ratio of principal and its interest after `20` years is `1:1` ? |
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Answer» Let the rate of simple interest per annum `=r%` Also, if the principal be `Rs p`, then by the question, the simple interest `= Rs p`. Also , time , `t=20` years `:. Rsp p=Rs(pxxrxx20)/(100)impliesr=5` Hence the required rate of simple interest per annum `=5%`. |
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