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1.

A Wheatstone bridge is balanced when the galvanometer shows __________ reading.(a) 0A(b) 1A(c) Infinity(d) -1AThe question was asked in an internship interview.My question is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in section Simple Resistive Circuits of Electric Circuits

Answer»

The correct OPTION is (a) 0A

To explain: A Wheatstone BRIDGE is balanced when the galvanometer SHOWS 0A reading when resistors OBEY P/Q=R/S.
Discussion
2.

What will be the resistance between B and C when the network given below is converted into delta?(a) 13Ω(b) 8.66Ω(c) 6.5Ω(d) 7.33ΩI got this question in an internship interview.The origin of the question is Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in chapter Simple Resistive Circuits of Electric Circuits

Answer»

Correct CHOICE is (b) 8.66Ω

To elaborate: RESISTANCE between B and C = 2+4+ ((2*4)/3).
Discussion
3.

__________ are difficult to measure using Wheatstone bridge.(a) Higher resistances(b) Currents(c) Lower resistances(d) VoltagesI have been asked this question in semester exam.My doubt stems from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits in section Simple Resistive Circuits of Electric Circuits

Answer»

Correct choice is (C) LOWER resistances

The EXPLANATION: SPECIFICALLY Kelvin Bridge is used for measuring lower resistances.
Discussion
4.

The star and delta networks would be electrically equal if resistances measured between any pair of terminals __________(a) Is different(b) Greater in star(c) Greater in delta(d) Is equalThe question was asked during an interview.This interesting question is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The correct option is (d) Is equal

The explanation: The star and delta networks WOULD be ELECTRICALLY equal if a RESISTANCE MEASURED between any pair of terminals is same.
Discussion
5.

Convert the given star network into Pi network and calculate the sum of all the resistances in the obtained Pi network.(a) 125.5Ω(b) 122.5Ω(c) 127.8Ω(d) 129.8ΩThe question was asked in unit test.The origin of the question is Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in division Simple Resistive Circuits of Electric Circuits

Answer»

Correct choice is (b) 122.5Ω

Easy explanation: CONVERSION of GIVEN network into DELTA GIVES the resistances.

After that SUM of the resistances equals 122.5Ω.
Discussion
6.

Find VAB if iAB = 5A.(a) 32.76V(b) 35.56V(c) 36.12V(d) 34.21VThis question was addressed to me at a job interview.I'm obligated to ask this question of Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits in division Simple Resistive Circuits of Electric Circuits

Answer»

Correct answer is (d) 34.21V

The explanation: By CONVERTING the star circuits into the DELTA and then measuring the equivalent RESISTANCE, voltage value can be calculated USING this resistance and the given CURRENT value.
Discussion
7.

If R2 = RC RA / (RA +RB +RC ) then R3equals?(a) RA RB / (RA +RB +RC )(b) RC RA / (RA +RB +RC )(c) RB RC / (RA +RB +RC )(d) RX RA / (RA +RB +RC )This question was posed to me in unit test.My question is taken from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The correct OPTION is (a) RA RB / (RA +RB +RC )

For explanation: R3 = RA RB / (RA +RB +RC ).
Discussion
8.

5Ω, Rc=4.67Ω(a) Ra=4Ω, Rb=4.30Ω, Rc=4.66Ω(b) Ra=3Ω, Rb=4Ω, Rc =5Ω(c) Ra=5.2Ω, Rb=4.2Ω, Rc =4.89ΩI have been asked this question in an interview for internship.The doubt is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in portion Simple Resistive Circuits of Electric Circuits

Answer»

Correct CHOICE is (B) Ra=3Ω, Rb=4Ω, Rc =5Ω

To EXPLAIN: By USING the standard formulae the delta CIRCUIT can be converted into star circuit.
Discussion
9.

Star connection can also be called as Y (or) T connection.(a) True(b) FalseThis question was posed to me in examination.This intriguing question originated from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in section Simple Resistive Circuits of Electric Circuits

Answer»

The correct choice is (a) True

Explanation: Star CONNECTION can also be called as Y (or) T connection because the star can be shaped into Y or T WITHOUT DISTURBING the electrical equivalence of both the structures.
Discussion
10.

The other name for Delta connection is ___________(a) Star connection(b) Pi connection(c) T connection(d) Y connectionI got this question in an interview for internship.This interesting question is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in chapter Simple Resistive Circuits of Electric Circuits

Answer»

Right CHOICE is (b) PI connection

The BEST I can explain: Delta connection is also known as Pi connection because the ∆ can be shaped into π without disturbing the ELECTRICAL EQUIVALENCE of both the structures.
Discussion
11.

If P/Q=1, unknown resistance S=1000Ω and R could be varied from 0 to 100Ω then the bridge could be ___________(a) A balanced circuit(b) A rectified circuit(c) An unbalanced circuit(d) An identical circuitThis question was addressed to me in an online interview.Enquiry is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in section Simple Resistive Circuits of Electric Circuits

Answer»

Correct option is (c) An unbalanced CIRCUIT

Best EXPLANATION: P/Q=R/S. If P/Q=1 then according to GIVEN range of R and S, the bridge circuit could never be a balanced ONE.
Discussion
12.

Lower resistances are difficult to measure using Wheatstone bridge circuit because of ____________(a) Leakage currents(b) I^2R effects(c) Power dissipation(d) Thermal breakdownThis question was posed to me during an interview.I need to ask this question from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in division Simple Resistive Circuits of Electric Circuits

Answer» CORRECT answer is (b) I^2R effects

The best I can explain: A standard Wheatstone BRIDGE couldn’t measure lower resistances because of thermoelectric voltages which are generated at the junctions of the dissimilar METALS and also because of thermal heating effects- that is, i^2R effects.
Discussion
13.

Find the unknown resistance value in given circuit.(a) 10.2Ω(b) 11.7Ω(c) 10.5Ω(d) 11.5ΩThis question was posed to me in class test.I would like to ask this question from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits in section Simple Resistive Circuits of Electric Circuits

Answer» CORRECT ANSWER is (a) 10.2Ω

The BEST I can EXPLAIN: A/B=C/D. USING this D= 10.2Ω.
Discussion
14.

The relation between the resistances in the given Wheatstone bridge circuit is _____________(a) P/S = R/Q(b) PR = QS(c) P/Q = R/S(d) PQ = RSThis question was addressed to me in homework.This question is from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits topic in portion Simple Resistive Circuits of Electric Circuits

Answer» CORRECT OPTION is (C) P/Q = R/S

For EXPLANATION: The RELATION is P/Q=R/S or PS=QR.
Discussion
15.

The Wheatstone Bridge is mainly used to measure ______________(a) Currents(b) Voltages(c) Node potentials(d) ResistancesThis question was addressed to me in quiz.I want to ask this question from Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits in section Simple Resistive Circuits of Electric Circuits

Answer»

The correct option is (d) Resistances

Easiest EXPLANATION: Resistances can be MEASURED by various methods. Wheatstone bridge is one such METHOD. In this method resistances in the range of 1Ω to 1 MΩ can be measured.
Discussion
16.

A 122mv, 12mA d’Arsonval movement is to be used in voltmeter whose full scale reading is 120v. The resistance inserted by 120v _____________(a) 1200Ω(b) 12000Ω(c) 1000Ω(d) 10,000ΩI got this question during an interview.The question is from Measuring Voltage and Current topic in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The CORRECT OPTION is (d) 10,000Ω

Easiest EXPLANATION: R =120/12 * 10^-3

= 10,000Ω.
Discussion
17.

A 100mv, 5mA d’Arsonval movement is to be used in an ammeter whose full-scale reading is 1A. Calculate RA.(a) 0.7 ohms(b) 0.5 ohms(c) 0.1 ohms(d) 0.2 ohmsI had been asked this question by my college director while I was bunking the class.This intriguing question comes from Measuring Voltage and Current in section Simple Resistive Circuits of Electric Circuits

Answer»

Right CHOICE is (c) 0.1 ohms

The explanation is: 5MA is flowing through the COIL which IMPLIES 995mA are diverted through RA.

V = iR

= 100 * 10^-3

= 995 * 10^-3 RA

RA= 0.100Ω.
Discussion
18.

An ideal ammeter functions as __________ circuit(a) A short(b) An open(c) A power(d) An infiniteThe question was posed to me in an interview for job.Question is from Measuring Voltage and Current topic in division Simple Resistive Circuits of Electric Circuits

Answer» CORRECT choice is (a) A SHORT

Explanation: An ideal AMMETER offers a zero equivalent resistance. So acts a short circuit.
Discussion
19.

An ideal voltmeter functions as __________ circuit(a) A short(b) An open(c) A power(d) An infiniteThe question was asked during an internship interview.My query is from Measuring Voltage and Current topic in section Simple Resistive Circuits of Electric Circuits

Answer»

The correct choice is (b) An OPEN

For explanation I would say: An IDEAL VOLTMETER offers an infinite equivalent resistance. So acts as an open CIRCUIT.
Discussion
20.

A 25mv, 2mA d’Arsonval movement is to be used in voltmeter whose full scale reading is 100v. The resistance inserted by 100v meter into circuit is ___________(a) 1 * 10^5Ω(b) 1 * 10^6Ω(c) 1 * 10^4Ω(d) 1 * 10^3ΩI have been asked this question at a job interview.Question is from Measuring Voltage and Current in division Simple Resistive Circuits of Electric Circuits

Answer»

The CORRECT ANSWER is (a) 1 * 10^5Ω

Easy explanation: V = iR

R = v/i

= 100/1mA

= 100,000Ω.
Discussion
21.

A 20mv, 1mA d’Arsonval movement is used in an ammeter whose full-scale reading is 10 mA. Determine RA.(a) 2.222Ω(b) 6.667Ω(c) 5.92Ω(d) 3.333ΩI got this question during an online interview.I'm obligated to ask this question of Measuring Voltage and Current in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The CORRECT answer is (a) 2.222Ω

To elaborate: 1 mA flowing through COIL implies that 9mA must be diverted through RA.

V = ir

20 * 10^-3 = 9 * 10^-3 RA

RA= 2.222Ω.
Discussion
22.

Digital meters are preferable than analog meters.(a) True(b) FalseThe question was asked in an online quiz.The origin of the question is Measuring Voltage and Current topic in section Simple Resistive Circuits of Electric Circuits

Answer»

Right answer is (a) True

To explain: Features like easy connection, Introduction of LESS RESISTANCE into the CIRCUIT to which they all CONNECTED and also due to READ out mechanism digital meter are preferred.
Discussion
23.

Continuous voltages (or) current signals are measured using(a) Tachometers(b) Sonometers(c) Analog meters(d) Digital metersI had been asked this question in homework.My query is from Measuring Voltage and Current in portion Simple Resistive Circuits of Electric Circuits

Answer»

Correct choice is (d) Digital meters

The explanation is: Digital meters are used to MEASURE current (or) VOLTAGE SIGNALS at discrete points in TIME known as sampling TIMES.
Discussion
24.

An ideal voltmeter has ___________ equivalent resistance and ideal ammeter has ___________ equivalent resistance.(a) Unity, Unity(b) Zero, infinite(c) Infinite, Zero(d) Zero, ZeroThe question was asked by my college professor while I was bunking the class.This intriguing question comes from Measuring Voltage and Current in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The correct ANSWER is (c) INFINITE, Zero

For explanation: An ideal voltmeter has Infinite equivalent RESISTANCE and ideal AMMETER has zero equivalent resistance.
Discussion
25.

____________ helps in current measurement by placing it in ____________ with the circuit element.(a) Voltameter, Parallel(b) Ammeter, series(c) Voltmeter, series(d) Ammeter, parallelI got this question during an internship interview.The doubt is from Measuring Voltage and Current in section Simple Resistive Circuits of Electric Circuits

Answer» RIGHT choice is (b) Ammeter, series

The BEST EXPLANATION: In series, CURRENT is same. So Ammeter is PLACED in series and is used to measure current.
Discussion
26.

Why is current division necessary?(a) In series current is the same(b) In parallel current differs(c) Because the voltage is also different(d) Because of Kirchhoff’s laws.The question was posed to me in a national level competition.My question is based upon The Voltage Divider and Current Divider Circuits topic in chapter Simple Resistive Circuits of Electric Circuits

Answer» RIGHT answer is (b) In PARALLEL current DIFFERS

The best EXPLANATION: In parallel current differs.
Discussion
27.

Voltage division is necessary for parallel resistance networks(a) True(b) FalseI had been asked this question in exam.This key question is from The Voltage Divider and Current Divider Circuits in chapter Simple Resistive Circuits of Electric Circuits

Answer»

Right choice is (B) False

The EXPLANATION is: In parallel, connection voltage is same so no division is REQUIRED.
Discussion
28.

R1 = 1Ω, R2 = 3Ω, R3 = 5Ω and R4 = 7Ω connected in parallel. Total Current = 23A. Then V, I1 , I2=?(a) 12.26v, 1.725, 2.875(b) 12.23v, 2.875, 1.725(c) 11.26v, 1.95, 1.74(d) 11.23v, 1.74, 1.95The question was asked during a job interview.I need to ask this question from The Voltage Divider and Current Divider Circuits in chapter Simple Resistive Circuits of Electric Circuits

Answer»

Correct OPTION is (a) 12.26v, 1.725, 2.875

The explanation is: V = I/R

V = I (R1+ R2) R1R2= 12.26v

I1 = IR2/ R1+ R2 = 1.725A

I2= IR1/ R1+ R2

= 2.875A.
Discussion
29.

For a parallel connected resistor R1, R2 and a voltage of V volts. Current across the first resistor is given by(a) I R1(b) I R2(c) I R1 / R1 + R2(d) I R2 / R1 + R2I got this question in exam.Question is taken from The Voltage Divider and Current Divider Circuits topic in chapter Simple Resistive Circuits of Electric Circuits

Answer» RIGHT option is (d) I R2 / R1 + R2

The explanation: I1 = V / R1

R = R1. R2 / R1+ R2

= I .R1. R2 / R1 . R1 + R2

I1 = I R2 / R1 + R2.
Discussion
30.

R1 = 1Ω, R2 = 3Ω, R3 = 5Ω and R4 = 7Ω connected in series. Total voltage = 20V, Current I, V2 =?(a) I = 1.23, V2 = 3.75(b) I = 1.25, V2 = 3.75(c) I = 1.15, V2= 3.73(d) I = 1.16, V2 = 3.72The question was asked in a job interview.My doubt stems from The Voltage Divider and Current Divider Circuits in portion Simple Resistive Circuits of Electric Circuits

Answer» RIGHT CHOICE is (b) I = 1.25, V2 = 3.75

Explanation: I = 20/ 1 + 3 + 5 + 7 = 1.25A

V2 = V. R2 / R1 + R2 + R3 + R4

= 20(3)/16

= 3.75V.
Discussion
31.

If there are 3 Resistors R1, R2 and R3 in series and V is total voltage and I is total currentthen Voltage across R2 is(a) V R3/ R1 + R2 + R3(b) V R2/ R1 + R2 + R3(c) V R1/R1 + R2 + R3(d) VI have been asked this question in an interview for internship.My question is taken from The Voltage Divider and Current Divider Circuits in section Simple Resistive Circuits of Electric Circuits

Answer» RIGHT choice is (b) V R2/ R1 + R2 + R3

To explain: V2 =I R2

= V R2/ R1 + R2 + R3.
Discussion
32.

Where current division problem arises(a) Series connected resistors(b) Parallel connected resistors(c) When resistors are equal(d) Both series and parallel resistors.I had been asked this question in my homework.The above asked question is from The Voltage Divider and Current Divider Circuits in chapter Simple Resistive Circuits of Electric Circuits

Answer»

The CORRECT choice is (B) PARALLEL connected resistors

Easiest EXPLANATION: In parallel voltage is same and current is the difference.
Discussion
33.

Where voltage division problem arises(a) Series connected resistors(b) Parallel connected resistors(c) When resistors are equal(d) Both series and parallel resistors.This question was addressed to me in an interview.This question is from The Voltage Divider and Current Divider Circuits in division Simple Resistive Circuits of Electric Circuits

Answer»

The correct choice is (a) SERIES connected resistors

The BEST explanation: In series, VOLTAGE is the difference and current same.
Discussion