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1.

Determine the amount of `CaCl_(2)` (i = 2.47) dissolved in 2.5 L of water such that its osmotic pressure is 0.75 atm at `27^(@)C`.

Answer» Using ralation `pi=iCRT=i(n)/(V)RT`
`n=(piV)/(iRT)=(0*75xx2.5)/(2*47xx0*0821xx300)=0*0308` mole
Molar mass of `CaCl_(2)=40+2xx35*5=111` g `mol^(-1)`
`therefore` amount of `CaCl_(2)` dissolved
`=0*0308xx111=3*42g`.
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