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1.	By how much does √12 + √18 exceed √3+√2 ?
Answer» Required difference = (√12 + √18) - (√3 + √2) = \((\sqrt{4\times3} + \sqrt{9\times2})\) - (√3 + √2) = 2√3 + 3√2 - √3 - √2 = (2√3 - √3) + (3√2 - √2) = √3 + 2√2

By how much does √12 + √18 exceed √3+√2 ?

Answer»

Required difference = (√12 + √18) - (√3 + √2)

= \((\sqrt{4\times3} + \sqrt{9\times2})\) - (√3 + √2) = 2√3 + 3√2 - √3 - √2

= (2√3 - √3) + (3√2 - √2) = √3 + 2√2

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