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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Higher the viscosity, the slower the liquid flows.(a) True(b) FalseThe question was asked during an interview for a job.The question is from States of Matter in chapter States of Matter of Chemistry – Class 11

Answer»

The CORRECT answer is (a) True

To explain I WOULD SAY: Viscosity is defined as the resistance to the flow of a liquid. It opposes a liquid’s layer movement with respect to one another. So, the above statement: the higher the viscosity, the slower the liquid FLOWS is true.

2.

The surface tension of ___________ at critical temperature.(a) one(b) zero(c) two(d) threeThis question was addressed to me in a job interview.This is a very interesting question from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

Correct answer is (b) ZERO

To explain I would SAY: The SURFACE tension in liquids decreases with RISE in temperature. As surface tension decreases, molecules become more active when temperature increases and surface tension becomes zero at critical temperature TC.

3.

A water drop is spherical in shape due to ____________(a) Viscosity(b) Poise(c) Surface tension(d) ReflectionThis question was posed to me in an internship interview.This is a very interesting question from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Right option is (c) Surface TENSION

For explanation I WOULD say: Surface Tension is the tendency of a fluid to OCCUPY least surface area as possible. It is defined as the force per UNIT distance. So, the spherical shape that is acquired by a WATER drop is due to surface tension.

4.

If the angle of contact between the liquid and container is 90 degrees then? (C is the cohesive and A is the Adhesive force)(a) C > A(b) C = A(c) C < A(d) C is not equal to AI got this question during an interview.This interesting question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

The correct answer is (b) C = A

For EXPLANATION: When the angle of contact between the liquid and container is 90 degrees then the cohesive and adhesive FORCES in a liquid are equal. Cohesive force is the ATTRACTION between SIMILAR atoms and adhesive between different atoms.

5.

Path in liquid in which layers do not meet each other is _______(a) laminar flow(b) tubular flow(c) viscosity(d) straight pathI have been asked this question in my homework.Origin of the question is States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Right CHOICE is (a) laminar flow

To explain I would say: The type of flow in LIQUIDS when each path flows in a different path, that do not INTERFERE with each other is laminar flow. At any point in the fluid, the VELOCITY of a fluid is constant is a CHARACTERISTIC of laminar flow.

6.

What is S.I. unit of Surface Tension?(a) Dyne/meter(b) Newton-meter(c) Newton/meter(d) Dyne-meterThe question was posed to me in an online interview.Enquiry is from States of Matter in chapter States of Matter of Chemistry – Class 11

Answer»

The correct choice is (c) Newton/meter

Explanation: Surface Tension is the TENDENCY of a FLUID to occupy least surface AREA as possible. It is defined as the force per unit DISTANCE. So, the units of surface tension are Newton/meter in S.I. the SYSTEM, Dyne/cm in C.G.S system.

7.

In a liquid, the force required to maintain the flow of layers is 5N, velocity gradient in du/dx, area of contact is 20m^2. Then what is the value of viscosity?(a) 6.25 dz/du(b) 0.15 dz/du(c) 0.2 dz/du(d) 0.25 dz/duThis question was addressed to me during an online exam.I'd like to ask this question from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

The CORRECT choice is (d) 0.25 dz/du

To explain I WOULD say: The formula of force required to maintain the flow of LAYERS is given by the formula F = ηAdu/dz, where η is the coefficient of viscosity, A is the area of contact and du/dz is the velocity GRADIENT. So by substituting we get an ANSWER as0.25dz/du.

8.

Viscosity of liquid _________ with rise in temperature.(a) Increases(b) Decreases(c) Remains constant(d) Is independentThis question was addressed to me by my college director while I was bunking the class.This is a very interesting question from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

Right choice is (a) Increases

The EXPLANATION: As there is a RISE in TEMPERATURE the viscosity of liquid increases while the viscosity of gas DECREASES. In liquids, due to rise in temperature, molecules have high thermal ENERGY so the can overcome intermolecular attractions.

9.

1 poise = ____________(a) 0.1 kgm^-1s^-1(b) 1 kgm^-1s^-1(c) 10 kgm^-1s^-1(d) 100 kgm^-1s^-1I have been asked this question in an internship interview.The origin of the question is States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Right option is (a) 0.1 kgm^-1s^-1

To explain I WOULD say: Poise is the unit of viscosity. It’s S.I. unit is 1 Newton second per square meter. It’s Pascal second. In C.G.S. system, the unit of viscosity is poise that is named after a SCIENTIST Jean Louise

Poiseuille. So, it’s 1 poise = 0.1 kgm^-1s^-1.

10.

What is the boiling point at pressure 1 atm known as?(a) Standard boiling point(b) Normal boiling point(c) Van der Waal boiling point(d) Saturated boiling pointThe question was asked during an interview.I would like to ask this question from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

Correct CHOICE is (c) Van DER WAAL boiling point

For EXPLANATION I would say: The boiling point at pressure 1 atm is known as normal boiling point. Normal boiling point is slightly greater than the STANDARD boiling point as molecules change into the vapor phase and density of vapor increases.

11.

Which of the following is an expression for Boyle’s temperature?(a) a/Rb(b) 27a/R(c) a/b(d) Ra/8bThe question was posed to me during an online interview.I need to ask this question from States of Matter in chapter States of Matter of Chemistry – Class 11

Answer»

The correct option is (a) a/Rb

The best explanation: Boyle’s TEMPERATURE Tb is given a/Rb, where a and b are the VAN der Waal’s constants for PRESSURE and volume correction. The temperature TILL which a GAS behaves like an ideal gas is Boyle’s temperature.

12.

In van der Waal’s equation, b is known as ______________(a) volume constant(b) pressure constant(c) volume correction(d) pressure correctionThe question was asked during an interview.My question is based upon States of Matter in chapter States of Matter of Chemistry – Class 11

Answer» RIGHT option is (c) volume correction

Explanation: In the van der Waal’s equation (P – an^2/V^2)(V – nb) = nRT, b is the volume correction term and is 4 times as the volume of a molecule. The LETTER a is the PRESSURE correction term in the van der Waal’s equation.
13.

The value of b for carbon dioxide is given as 42.69 x 10^-6m^3/mol. What do you think is the volume of a molecule?(a) 7.59 m^3(b) 7.03 m^3(c) 76.09 m^3(d) 7.09 m^3I had been asked this question in an international level competition.Question is taken from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Correct OPTION is (d) 7.09 m^3

The best I can explain: From VAN der WAAL’s equation (P – an^2/V^2)(V – NB) = nRT, we know that V = b/NA = 42.69 x 10^-6m^3/mol/6.023 x 1023 molecules/mol. That equals 7.09 m^3/molecule. So the volume of a molecule is 7.09m^3.

14.

Which of the following can be the value of “b” for Helium?(a) 23.71 x 10^-6 m^2/mol(b) 23.71 x 10^-6 m^3/mol(c) 23.71 x 10^-6 m^3 mol(d) 23.71 x 10^-6 m/molThis question was addressed to me by my college professor while I was bunking the class.My question is based upon States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

Correct answer is (b) 23.71 x 10^-6 m^3/MOL

The best explanation: From van der Waal’s equation (P – an^2/V^2)(V – NB) = nRT, we have that UNITS of VOLUME and number of moles x b are same. So L = mol x b; units of b is L/mol otherwise can be written as m^3/mol.

15.

If the value of a is greater, what does it mean?(a) the gas liquefies easily(b) the gas cannot liquify easily(c) gas obeys ideal gas law(d) gas particles have random motionI had been asked this question in an interview.This interesting question is from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer» CORRECT answer is (a) the GAS liquefies easily

The best I can EXPLAIN: The value of an in van der Waals equation is a measure of the MAGNITUDE of intermolecular attractive FORCES within a gas. It is independent of temperature and pressure. As attractive forces are more, the gas can be liquefied easily.
16.

A gas that is liquefied by applying pressure below critical temperature is called ____________ of the substance.(a) vapor(b) liquid(c) solid(d) plasmaI have been asked this question during an interview.My question comes from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

The CORRECT choice is (a) vapor

Explanation: At critical temperature liquid state changes into gaseous state continuously the surface that SEPARATES both this state DISAPPEARS and gas below critical temperature can be liquefied by applying PRESSURE and this is called vapor of the SUBSTANCE.

17.

A fluid is a _______________(a) gas(b) liquid(c) solid(d) both gas and liquidI had been asked this question at a job interview.The query is from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

Right CHOICE is (d) both gas and liquid

The explanation: A fluid is a gas or liquid that can be used to recognize the continuity. The fluid is SOMETHING deforms under shear stress APPLICATION and flows from ONE place to ANOTHER, it is also a subset of States of matter.

18.

Which of the following is Greater?(a) Boyle’s temperature(b) Boyle’s temperature = critical temperature(c) Critical temperature(d) Boyle’s temperature = 1/critical temperatureI got this question by my school teacher while I was bunking the class.The above asked question is from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer» RIGHT answer is (a) Boyle’s temperature

To explain I would say: Boyle’s temperature TB is given by a/Rb critical temperature TC is given by 8a/27Rb, where a is the PRESSURE correction TERM and b is a VOLUME correction term as PER van der Waal’s equation. So Boyle’s temperature is greater than the critical temperature.
19.

What is the ratio of critical temperature to Boyle’s temperature of the same gas?(a) 8/27(b) 27/8(c) 8(d) 27I had been asked this question during a job interview.This interesting question is from States of Matter topic in division States of Matter of Chemistry – Class 11

Answer»

Correct option is (a) 8/27

To elaborate: The maximum TEMPERATURE gas can remain LIQUID is known as critical temperature. The temperature till which a gas behaves like an IDEAL gas is Boyle’s temperature. Boyle’s temperature TB is given by a/Rb critical temperature TC is given by 8a/27Rb. So the RATIO is 8/27.

20.

Which of The following is a critical temperature for Carbon dioxide?(a) 32-degree centigrade(b) 30.98-degree centigrade(c) 40-degree centigrade(d) 30.91 degree KelvinI have been asked this question by my school teacher while I was bunking the class.This key question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

The correct option is (b) 30.98-degree centigrade

Easy explanation: The critical temperature of carbon DIOXIDE is a MAXIMUM temperature where the carbon dioxide can remain as a LIQUID below this temperature. The carbon dioxide is GAS so the critical temperature for Carbon dioxide is 30.98 degrees centigrade.

21.

A gas that is of 2 moles occupies a volume of about 500 ml at 300 Kelvin and 50 atmospheric pressure, calculate the compressibility factor of the gas.(a) 1.863(b) 0.7357(c) 0.5081(d) 1.8754I have been asked this question during a job interview.My doubt stems from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Correct option is (c) 0.5081

The best explanation: Compressibility FACTOR Z = PV/nRT; Z = 50 ATM x (500/1000) ml / 2 x 0.082 x 300 K = 25/6×8.2 = 0.5081. That means Z < 1, so this is a negative deviation from ideal gas behaviour. So the gas is more compressible than expected.

22.

What are the units of “b” in van der Waals equation?(a) L/mol(b) L mol(c) 1/L mol(d) LI had been asked this question during an interview.The origin of the question is States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Correct choice is (a) L/mol

To explain: The ideal GAS equation is given as (P – an^2/V^2)(V – nb) = nRT.So by CONSIDERING the equation, we can understand that the units of the volume are equal to the units of a number of moles X be so the units of b. So b’s units = volume / number of moles so it is L/mol.

23.

The value of a in van der Waal equation is _____________ /dependent on ___________(a) pressure(b) temperature(c) pressure and temperature(d) independent of pressure and temperatureI had been asked this question in an interview for job.I would like to ask this question from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer» CORRECT answer is (d) independent of pressure and temperature

For explanation I would say: Value of an in VAN der Waal equation represents a measure of the magnitude of INTERMOLECULAR attractive forces within the gas and it is also independent of temperature and pressure. The van der Waal’s equation is GIVEN by (P – an^2/V^2)(V – nb) = nRT.
24.

Above Boyle temperature real gases show __________ deviation from ideal gases.(a) positive(b) negative(c) no(d) both positive and negativeThis question was posed to me during a job interview.My doubt is from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

The correct OPTION is (a) positive

Explanation: Above Boyle temperature, the value of the compressibility factor is greater than 1. So the gases show positive deviation from IDEAL gases as the forces of ATTRACTION between the gas molecules are very LOW.

25.

Which of the following is a corrected equation of ideal gas equation?(a) (P – an^2V^2)(V – nb) = nRT(b) (P – an^2/V^2)(V + nb) = nRT(c) (P + an^2/V^2)(V – nb) = nRT(d) (P – an^2/V^2)(V – nb) = nRTI had been asked this question in final exam.The question is from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

The correct answer is (d) (P – an^2/V^2)(V – nb) = nRT

To explain I would say: (P – an^2/V^2)(V – nb) = nRT; where p is PRESSURE, a is the magnitude of intermolecular attractive forces within a gas, N is the number of moles, v is volume, B is a VAN der Waal constant, R is the universal gas constant and T is temperature.

26.

What is the temperature known as where a real gas obeys Boyle’s law or as an ideal gas?(a) Boyle temperature(b) Charge temperature(c) Critical temperature(d) Absolute TemperatureThis question was addressed to me in a job interview.I would like to ask this question from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Right choice is (a) Boyle temperature

To elaborate: The temperature at which a REAL gas obeys Boyle’s law and other ideal gas law at a CERTAIN range of pressure is called Boyle temperature or Boyle POINT. It is unique for every gas and depends upon its NATURE.

27.

Which of the following conditions do you think a real gas behaves as an ideal gas?(a) high pressure(b) low pressure(c) intermediate pressure(d) at any pressureI have been asked this question during an online exam.My query is from States of Matter in section States of Matter of Chemistry – Class 11

Answer»

The correct answer is (B) low pressure

Explanation: At low-pressure conditions, Z = 1 handset BEHAVES as an ideal GAS but at high-pressure Z is GREATER than 1 and for intermediate pressure that is less than 1. So at low-pressure condition, a REAL gas behaves as an ideal gas.

28.

PV/nRT is known as ____________(a) compressibility factor(b) volume factor(c) pressure factor(d) temperature factorThis question was posed to me in unit test.This interesting question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Right option is (a) COMPRESSIBILITY factor

The explanation: PV/nRT is known as compressibility factor and is represented by the letter Z. It is a RATIO of PV and nRT; where p is pressure, V is VOLUME, n is the number of moles, R is the universal gas constant and T is TEMPERATURE.

29.

The plot PV vs v at constant temperature is a straight line for real gases.(a) true(b) falseI have been asked this question at a job interview.I would like to ask this question from States of Matter in section States of Matter of Chemistry – Class 11

Answer»

Right answer is (b) false

The best explanation: The plot of PV VS P is not a straight line for real gases because they deviate from Ideal BEHAVIOUR. are there are two types of deviations one is a positive DEVIATION and the other is a negative deviation.

30.

Which of the following statements do you think is the correct one?(a) in gases there is a predominance of intermolecular energy(b) all molecules have the same speed at different temperatures(c) collisions of gas molecules are elastic(d) do not exert the same pressure in all directionsI had been asked this question in class test.The doubt is from States of Matter topic in division States of Matter of Chemistry – Class 11

Answer»

Right choice is (C) collisions of gas molecules are elastic

Easy explanation: Collisions are elastic as the TOTAL amount of energy before and after the collision is the same. The correct STATEMENTS of the incorrect ones are: in gases, there is a PREDOMINANCE of thermal energy, the distribution of SPEEDS remains constant at a particular temperature and the gases exert the same pressure in all directions of the container.

31.

Which of the following is not a postulate of Kinetic molecular theory of gases?(a) the actual volume of gas molecules is negligible(b) there are high forces of attraction between the gas molecules(c) collisions are elastic in gas molecules(d) kinetic energy of gas molecules is directly proportional to the absolute temperatureThe question was asked during an internship interview.My doubt is from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

Right answer is (b) there are high forces of ATTRACTION between the gas molecules

The best explanation: According to Kinetic molecular THEORY of GASES, there are no forces of attraction between the particles of gas at normal temperature and pressure. This is because gases expand and occupy all the SPACE available.

32.

The temperature of a gas is 100 K it is heated until it is 200 k then, what do you understand regarding kinetic energy in this process?(a) halved(b) tripled(c) quadrupled(d) doubledThis question was posed to me in exam.I need to ask this question from States of Matter in section States of Matter of Chemistry – Class 11

Answer» RIGHT ANSWER is (d) doubled

The explanation: According to the kinetic molecular theory of GASES, if the Absolute Temperature of a gas is doubled then the kinetic energy is also doubled because they are directly proportional to each other so here the answer is doubled. If the temperature doubles from 100 k to 200 k, kinetic energy also doubles.
33.

There is an increase in temperature of an object then the kinetic energy of the object __________(a) decreases(b) increases(c) remains the same(d) it is not related to the temperatureThis question was addressed to me in quiz.I want to ask this question from States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

The correct answer is (b) increases

To elaborate: From the kinetic MOLECULAR THEORY of gases we can know that the kinetic energy of an object is proportional directly to the Absolute Temperature of that object so when the temperature of an object increases OBVIOUSLY the kinetic energy ALSO increases.

34.

Collisions of gas molecules are ___________(a) perfectly elastic(b) inelastic(c) always occur in a proper and predicted motion(d) not conservedThe question was asked in a job interview.Asked question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Correct ANSWER is (a) perfectly elastic

Explanation: The total energy of molecules before the collision is equal to the total energy after the collision. That means there may be an EXCHANGE of energy between the molecules but the total energy does not CHANGE, so the COLLISIONS of gas molecules are elastic.

35.

At an instance different particles have ________ speeds.(a) same(b) different(c) opposite(d) similarI have been asked this question in a job interview.This intriguing question originated from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

The correct OPTION is (b) different

Explanation: ACCORDING to the kinetic molecular THEORY of gases, the assumption that different particles have different speeds at a time is because particles do not ALWAYS have the same speeds and move in different directions but we can assume that the distribution of speeds is CONSTANT at a particular temperature.

36.

Why do you think the pressure is exerted by the gas on the walls of the container in all directions?(a) they consist of identical particles(b) collide with each other during random motion(c) lack of definite shape(d) more forces of attractionThe question was asked in quiz.This intriguing question comes from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

Right ANSWER is (b) collide with each other during random motion

To explain I would say: As the particles of gas travel in STRAIGHT lines and move in a random motion and collide with each other and also collide with the WALLS of the CONTAINER, the pressure is exerted on the walls of the container in all DIRECTIONS.

37.

Gases do not have a fixed shape.(a) true(b) falseThe question was asked in an interview.My question is from States of Matter in section States of Matter of Chemistry – Class 11

Answer»

The correct option is (a) true

The explanation: Particles do not have a fixed shape because they are ALWAYS in RANDOM motion and particles NEVER occupy fixed position the KEEP on moving and never occupy a particular shape this is the reason to prove that the above statement is true.

38.

Gases ________ and occupy all the space that is available to them.(a) contract(b) compress(c) expand(d) shrinkThis question was posed to me in examination.Query is from States of Matter in section States of Matter of Chemistry – Class 11

Answer» CORRECT OPTION is (c) expand

To explain I would say: At normal temperature and pressure, there is no force of ATTRACTION between the gas PARTICLES. So they expand and occupy the space that is AVAILABLE. This statement supports the assumption.
39.

What is the mean velocity of one Mole neon gas at a temperature of 400 Kelvin?(a) 11.533 m/s(b) 357.578 m/s(c) 367.79 m/s(d) 34 m/sThis question was addressed to me in an interview.Question is taken from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

The correct option is (a) 11.533 m/s

For EXPLANATION: The formula for mean velocity of a GAS is given by the expression \(\SQRT{2RT/M}\). for one mole of neon gas M is TAKEN as 0.02 KG, temperature as 400 k, R as 8.314 kgm^2s^-2, so by substituting we get an answer as 11.533 m/s.

40.

Which of the following assumption explains great compressibility of gases?(a) the actual volume of the gas molecules is negligible(b) there is no force of attraction(c) particles are always in random motion(d) different particles have different speedsI had been asked this question in an interview for job.This interesting question is from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer» RIGHT choice is (a) the actual volume of the gas molecules is negligible

For EXPLANATION: Gas molecules are considered as point masses because the actual volume of gas molecules is negligible when compared to the space between them, so this assumption EXPLAINS the greater compressibility of GASES.
41.

What is the ratio of the velocities of 2 moles of hydrogen to five moles of helium?(a) \(\sqrt{14}\)(b) \(\sqrt{10}\)(c) \(\sqrt{20}\)(d) \(\sqrt{50}\)The question was posed to me by my school teacher while I was bunking the class.This key question is from States of Matter topic in chapter States of Matter of Chemistry – Class 11

Answer»

The correct choice is (b) \(\sqrt{10}\)

Best explanation: The formula of average speed is given by \(\sqrt{2RT/M}\). We KNOW that the velocity of gas molecules is inversely PROPORTIONAL to the root over the MASS of the gas. So here the RATIO of velocities is \(\sqrt{5×4/2×1}\) = \(\sqrt{10}\).

42.

Which among the following options do you think has the highest average speed?(a) chlorine(b) hydrogen(c) neon(d) oxygenI have been asked this question in quiz.I'm obligated to ask this question of States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

The correct answer is (b) HYDROGEN

For explanation: The formula of average SPEED is given by \(\sqrt{2RT/M}\), where R is universal gas constant, T is a TEMPERATURE in Kelvin and M is the MASS in kilograms. From the formula, we understand that the average speed is inversely proportional to the ROOT over the mass. As hydrogen has the least mass among the options it has the highest average speed.

43.

What is the most probable speed of oxygen gas with the mass of 32 grams at 27-degree centigrade?(a) 33.74 m/s(b) 44.78 m/s(c) 57.94 m/s(d) 549.14 m/sThe question was asked by my school teacher while I was bunking the class.Origin of the question is States of Matter in chapter States of Matter of Chemistry – Class 11

Answer»

Right answer is (B) 44.78 m/s

Explanation: The FORMULA for the most probable speed of a gas is given as \(\sqrt{8RT/πM}\). Here R is a universal gas constant which is ALWAYS EQUAL to 8.314 kgm^2s^-2, T=300 Kelvin and M = 0.032 kg So by substituting, we GET an answer as 44.78 m/s.

44.

The root mean square speed of a gas at a certain condition is 1.128 times greater than the most probable speed.(a) true(b) falseI got this question in examination.My question comes from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Right CHOICE is (b) false

Best explanation: The RATIO of root mean SQUARE speed to the mean probable speed is 1.224. So the above statement is CONSIDERED to be WRONG. The ratio between the main probable speed and the average speed and root mean square speed is 1: 1.128: 1.224.

45.

Which of the following is greater for identical conditions and the same gas?(a) most probable speed(b) average speed(c) root mean square speed(d) most probable and average speed have the same valueThis question was addressed to me by my school principal while I was bunking the class.My question is based upon States of Matter topic in section States of Matter of Chemistry – Class 11

Answer»

The correct option is (c) root mean square speed

Explanation: According to the formula, the root mean square speed is greater than the AVERAGE speed and the average speed is greater than the most probable speed at GIVEN IDENTICAL CONDITIONS and for the same gas.

46.

What is the ratio of root mean square speed of 16 grams of Oxygen to 4 grams of hydrogen?(a) 2(b) 3(c) 4(d) 1I have been asked this question in an interview for internship.This interesting question is from States of Matter in chapter States of Matter of Chemistry – Class 11

Answer»

The correct ANSWER is (a) 2

The explanation: The formula of root MEAN square speed of particles is given as \(\sqrt{3RT/M}\). We know that the velocity of GAS molecules is inversely proportional to the root over the mass of the gas here the mass of oxygen to the mass of hydrogen RATIO is the answer. So \(\sqrt{16/4}\) = 2.

47.

The speed of three particles is recorded as 3 m/s, 4 m/s, and 5 m/s. What is a root mean square speed of these particles?(a) 4.082 m/s(b) 2.07 m/s(c) 3.87 m/s(d) 3.082 m/sI have been asked this question in an online quiz.This interesting question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Correct answer is (a) 4.082 m/s

Best explanation: The root means SQUARE speed of particles is NOTHING but the square root over the SUM of squares of the particle’s speeds by a total NUMBER of particles. So by substituting, √3^2 + 4^2 + 5^2/3 = 4.082 m/s.

48.

Calculate the root mean square speed of hydrogen in m/s at 27°C?(a) 2835.43 m/s(b) 2635.43 m/s(c) 2735.43 m/s(d) 2731.43 m/sThis question was posed to me in an internship interview.Asked question is from States of Matter topic in portion States of Matter of Chemistry – Class 11

Answer»

Right option is (c) 2735.43 m/s

The explanation: The formula of root mean square speed is given by URMS = \(\sqrt{3RT/M}\). We have R = 8.314 kgm^2/s^2, M = 10^-3 kg/mol and T = 300 k. So by SUBSTITUTING the formula we get, urms = \(\sqrt{3×8.314×300/10^{-3}}\) = 2735.43 m/s.

49.

What is the ratio of urms to ump in oxygen gas at 298k?(a) 1.124(b) 1.224(c) 1.228(d) 1.128This question was addressed to me by my school principal while I was bunking the class.I'd like to ask this question from States of Matter topic in division States of Matter of Chemistry – Class 11

Answer»

Right answer is (B) 1.224

Explanation: The ratio of root mean SQUARE speed, represented as urms to the most probable speed, represented as ump is always the same for IDENTICAL conditions and same GAS. It is \(\sqrt{3RT/M}\) DIVIDED by \(\sqrt{8RT/πM}\) = 1.224.

50.

In a balloon of total pressure 6 atm there is a gaseous composition of 44 grams of carbon dioxide 16 grams of by oxygen and 7 grams of nitrogen, what is the ratio of nitrogen partial pressure do the total pressure in the balloon?(a) 0.25(b) 0.5(c) 0.75(d) 1The question was posed to me during an interview for a job.The above asked question is from States of Matter in portion States of Matter of Chemistry – Class 11

Answer»

Right option is (a) 0.25

Explanation: The partial PRESSURE of a gas is given by the mole fraction of the gas X the TOTAL pressure, so the RATIO of the partial pressure to the total pressure is the mole fraction of nitrogen is 7/14 divided by 44/44 + 16/32 2 + 7/14 = 0.25.