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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Following diagram represents _________(a) whisker reinforced composite(b) matrix only(c) fiber only(d) aluminum alloyI have been asked this question in final exam.I want to ask this question from Structures in chapter Structures and Loads of Aircraft Design

Answer»

Right option is (a) whisker reinforced composite

Easiest EXPLANATION: Above diagram is showing a TYPICAL whisker reinforced composite material. Short strand of the reinforcing MATERIALS are RANDOMLY located THROUGHOUT the matrix. Chopped Fiberglass is an example of such arrangement.

2.

A column has effective length as 20unit. Determine Euler load of EI = 1000 unit.(a) 24.67 unit(b) 10 unit(c) 40 unit(d) 50.99 unitThe question was posed to me in final exam.This interesting question is from Structural-Analysis Fundamentals in portion Structures and Loads of Aircraft Design

Answer»

The correct option is (a) 24.67 unit

To EXPLAIN: EULER load = \(\frac{\pi^2 EI}{(Effective \,LENGTH)^2}\)

= \(\frac{\pi^2*1000}{20^2} \) = 24.67 unit.

3.

Which of the following is an example of air load?(a) Gust(b) Taxi(c) Wheel stress(d) LandingThis question was posed to me in quiz.Enquiry is from Loads Categories topic in section Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) GUST

Explanation: Gust is primarily experienced during flight PHASE of an aircraft. Gust is experienced during flight in air. HENCE, gust is an example of air load. Landing, TAXI etc. are examples of the ground loads.

4.

The largest load that is expected to be experienced by aircraft is called __________(a) limit load(b) normal stress(c) normal strain(d) shear stressI have been asked this question in quiz.I need to ask this question from Loads Categories topic in portion Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) LIMIT load

The explanation is: Limit load is the largest load that is expected to be experienced by aircraft. Shear force will produce shear stress. Stress is force per UNIT area and strain is DEFINED as CHANGE in DIMENSIONS divided by original dimension.

5.

Column has length of 1.2 m and radius of gyration as 1.5m. Determine slenderness ratio. Consider column is fixed at one end free at other end.(a) 1.6(b) 7.8(c) 98(d) 12.45I had been asked this question by my school principal while I was bunking the class.My question is taken from Structural-Analysis Fundamentals in division Structures and Loads of Aircraft Design

Answer»

Right answer is (a) 1.6

The EXPLANATION: For, given column which is fixed at one END and free at other effective LENGTH L = 2*1.2m = 2.4m.

Now, SLENDERNESS ratio = effective length / radius of gyration = 2.4/1.5 = 1.6.

6.

Determine the actual length of the column which has slenderness ratio of 2.9 and radius of gyration as 1.6. Consider column is fixed at both ends.(a) 9.28(b) 0.0045(c) 2.3674(d) 4.862The question was posed to me during a job interview.My doubt is from Structural-Analysis Fundamentals topic in chapter Structures and Loads of Aircraft Design

Answer»

Right option is (a) 9.28

The explanation: GIVEN, COLUMN is fixed at both ends.

Actual LENGTH = slenderness ratio*RADIUS of gyration/0.5 = 2.9*1.6/0.5 = 9.28.

7.

Following diagram represents ___________(a) v-n diagram combined of gust and Maneuver(b) v-n diagram landing(c) takeoff speed(d) drag coefficient vs liftThe question was asked in an interview for internship.The doubt is from Air Loads in division Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) v-n diagram combined of gust and Maneuver

To EXPLAIN: Above diagram is illustrating a typical V-n diagram. Above diagram is a typical combined V-n diagram of gust and Maneuver. Drag coefficient vs LIFT coefficient graph is nothing but the drag POLAR. Takeoff speed is based on takeoff LOADS.

8.

Magnesium is used for ________(a) control hinges(b) highest strength application(c) lofting(d) draftingI had been asked this question in class test.This interesting question is from Structures topic in division Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) control hinges

For explanation I WOULD SAY: Magnesium is USED in control hinges, wheels, engine mounts ETC. Magnesium has good strength to weight ratio. It can tolerate high temperatures and is EASILY formed. Magnesium can be easily formed by casting, forging etc.

9.

Composite material has only one material.(a) True(b) FalseI had been asked this question in quiz.The doubt is from Structures in division Structures and Loads of Aircraft Design

Answer»

Correct OPTION is (b) False

The explanation: Composite MATERIAL is formed by USING TWO or more DIFFERENT materials. Composites are used to get desired properties of material. However, they can be costlier than non-composite materials.

10.

An object is subjected to some force. As a result of the force object undergoes in the deformation. If deformation of length is 0.28mm and Actual length is 20 mm then, find simple strain.(a) 0.014(b) 10.0014(c) 23.002(d) 0.00215The question was asked in my homework.The question is from Structures Fundamentals topic in chapter Structures and Loads of Aircraft Design

Answer»

Correct choice is (a) 0.014

For explanation I WOULD say: STRAIN = change in DIMENSION / original dimension = 0.28/20 = 0.014.

11.

What is the advantage of wood?(a) Easy to fabricate(b) Moisture sensitivity(c) Complexity during fabrication(d) Non availabilityThe question was posed to me in quiz.Origin of the question is Structures in section Structures and Loads of Aircraft Design

Answer»

The correct answer is (a) Easy to fabricate

The BEST explanation: WOODS are easy to fabricate and repair. This is one of the advantages of the wood. Wood has some drawbacks as well such as moisture SENSITIVITY. TODAY wood is largely used in homebuilt aircrafts.

12.

What is creep?(a) Under low sustained stress, it is tendency of some materials to get deform slowly and permanently(b) Under zero stress, it is permanent deformation(c) High lift device(d) Anti ice deviceI have been asked this question in unit test.The query is from Structures topic in portion Structures and Loads of Aircraft Design

Answer»

Right choice is (a) Under low SUSTAINED STRESS, it is tendency of some materials to get deform slowly and permanently

Easy explanation: Creep is nothing but the tendency of some materials to get deform slowly and permanently under low but sustained stress. For most of materials used in aerospace, creep is a problem at elevated temperatures. Although some titanium, PLASTICS will exhibit creep at ROOM temperatures.

13.

Loads during takeoff and landing will be equal in magnitude.(a) True(b) FalseI got this question by my school principal while I was bunking the class.This key question is from Loads Categories topic in chapter Structures and Loads of Aircraft Design

Answer»

The correct choice is (B) False

The explanation is: Loads will be of DIFFERENT magnitude and of different kinds. During LANDING, landing gear are used to WITHSTAND the impact loads at the TIME of touchdown. However, at takeoff they do not experience such impact loads. Hence, magnitude of the loads will be different.

14.

If actual speed of aircraft is 100 m/s and is flying at certain altitude with density ratio of 0.3 then, find equivalent at speed at that altitude.(a) 54.77m/s(b) 125ft/s^2(c) 1.2M(d) 1.5MI have been asked this question in homework.Enquiry is from Air Loads in section Structures and Loads of Aircraft Design

Answer»

The CORRECT CHOICE is (a) 54.77m/s

The explanation: EQUIVALENT airspeed = actual speed * (Density ratio)^0.5

= 100*(0.3^0.5) = 54.77 m/s.

15.

Following diagram represents _________(a) maneuver v-n diagram(b) drag polar(c) load factor vs drag(d) thrust required graphThis question was posed to me in quiz.Question is taken from Air Loads in portion Structures and Loads of Aircraft Design

Answer»

The correct choice is (a) MANEUVER v-n diagram

To explain I would say: Above diagram represents a typical Maneuver CHARACTERISTICS. A typical Maneuver V-N diagram is shown in the above diagram. Drag POLAR is GRAPHICAL representation of the aircraft drag properties. Typically it is used to show drag VARIATION. Thrust required is used to oppose the drag produced.

16.

Following diagram represents _______________(a) typical bending(b) twisted metal(c) shear(d) tensionThe question was posed to me in semester exam.My question comes from Structures Fundamentals topic in division Structures and Loads of Aircraft Design

Answer»

Right answer is (a) TYPICAL bending

Explanation: The above DIAGRAM is showing a typical bending concept. Bending as shown in the diagram is a combination of tension and compression. As shown in the diagram top PORTION is experiencing compression. BOTTOM portion is experiencing tension as seen in the diagram.

17.

A material has elastic constant of 100MPa and Poisson’s ratio as 10. Find the shear modulus of the material.(a) 4.55MPa(b) 2.345MPa(c) 1.2Gpa(d) 345.23KPaI have been asked this question by my school teacher while I was bunking the class.The origin of the question is Structures Fundamentals in section Structures and Loads of Aircraft Design

Answer»

Right answer is (a) 4.55MPa

For explanation I would say: SHEAR MODULUS = ELASTIC constant / (2+2*Poisson’s ratio)

= 100 MPA / (2+2*10) = 4.55 MPa.

18.

Almost all the forces acting on aircraft can be categorized as _____(a) body or surface forces(b) body forces only(c) only as surface force(d) neither body nor surface forceThis question was posed to me during a job interview.My doubt is from Loads Categories in chapter Structures and Loads of Aircraft Design

Answer»

Right choice is (a) body or surface FORCES

To explain I would say: TYPICALLY, all aircraft forces are categorized as body forces or surface forces. Body forces are those forces which are acting through volume of the body. Typical example of body force is force due to GRAVITY. Surface force is acting through surface of an object such as shear force.

19.

Design load is defined as ________(a) the Highest possible load that structure is designed to withstand without braking(b) the highest normal stress when strain is only quarter(c) the lowest load that structure has to withstand(d) lift and drag onlyThe question was asked in quiz.This is a very interesting question from Loads Categories in chapter Structures and Loads of Aircraft Design

Answer» RIGHT option is (a) the Highest possible load that structure is designed to WITHSTAND without braking

The explanation: Design load is the highest possible load that structure is designed to withstand without braking. The AIRCRAFT structure is always designed in order to withstand higher loads than the limit loads. Some factor of safety or safety margin is always USED. Design load is also termed as the ULTIMATE load.
20.

Which of the following is correct?(a) Factor of safety is provided to improve safety of an aircraft(b) Lift is always same as weight(c) Weight is never same as lift(d) Thrust required is same as weight alwaysThe question was posed to me during a job interview.This interesting question is from Loads Categories in division Structures and Loads of Aircraft Design

Answer»

Correct choice is (a) Factor of safety is provided to improve safety of an AIRCRAFT

The best EXPLANATION: The factor of safety is USED in order to increase safety of the aircraft. Lift is not ALWAYS same as the aircraft WEIGHT. Weight will be same as the lift during cruise. Thrust required is not always same as the weight.

21.

Following diagram represents ____________(a) typical stress strain diagram(b) lift curve slope(c) drag curve slope(d) drag polarThis question was posed to me in an international level competition.My enquiry is from Structures Fundamentals topic in chapter Structures and Loads of Aircraft Design

Answer»

The correct option is (a) typical stress strain diagram

Explanation: Above diagram is showing typical relationship between stress and strain. As shown in diagram up to certain VALUES of stress curve FOLLOWS linear relationship. This is due to hook’s law. Lift curve slope is showing a typical VARIATION in lift COEFFICIENT with respect to angle of attack.

22.

Following diagram represents __________(a) gust V-n diagram(b) maneuver diagram only(c) load factor variation with thrust(d) drag polarI got this question in an interview for internship.My doubt stems from Air Loads in chapter Structures and Loads of Aircraft Design

Answer» RIGHT ANSWER is (a) gust V-n diagram

For explanation I would say: A typical gust V-n diagram is shown in the above diagram. Here, in this V-n diagram we are assuming that the aircraft is experiencing gust at 1G. Maneuver V-N diagram is different from the gust diagram. Drag POLAR is USED to relate drag and lift.
23.

If my factor of safety is 2 and design load of my aircraft is 1000N then, at which value of ultimate load my aircraft can withstand without breaking?(a) 2KN(b) 9N(c) 1208KN(d) 1.208KNThis question was addressed to me in an interview for job.My question is taken from Loads Categories topic in chapter Structures and Loads of Aircraft Design

Answer» CORRECT OPTION is (a) 2KN

To explain: Ultimate load without breaking = factor of safety * design load = 2*1000 = 2KN.
24.

Choose an appropriate incorrect option.(a) At any given time, an aircraft can only experience any one type of load(b) At cruise, lift will be same as weight(c) Aerodynamic centre is located at quarter chord point for typical subsonic a/c(d) Lift is an example of Aerodynamic forceI got this question during an interview.The query is from Loads Categories in chapter Structures and Loads of Aircraft Design

Answer»

Correct choice is (a) At any given time, an aircraft can only EXPERIENCE any one TYPE of load

Easy explanation: At any given time, aircraft can experience the number of different TYPES of LOADS. For example, at cruise aircraft experiences airloads, powerplant load etc. At cruise, lift and weight will be equal. Lift is an Aerodynamic FORCE.

25.

My aircraft is flying at particular altitude. At that altitude ratio of actual airspeed to the equivalent airspeed is 1.4 then, what should be the desire value of density ratio?(a) 0.51(b) 1.89(c) 0.12(d) 0.189This question was addressed to me during an interview.My question is taken from Air Loads topic in section Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) 0.51

To EXPLAIN: DENSITY ratio = (1/ratio of ACTUAL airspeed and EQUIVALENT airspeed)^2

= (1/1.4)^2 = 0.51.

26.

If stain in body is 0.01 in longitudinal direction and has length of 52 mm then, find the deformation in length of the body.(a) 0.52mm(b) 4m(c) 2m(d) 22mmThis question was posed to me in quiz.This interesting question is from Structures Fundamentals topic in portion Structures and Loads of Aircraft Design

Answer»

Right answer is (a) 0.52mm

Easy EXPLANATION: Change in length = ORIGINAL length*STRAIN = 52*0.01 = 0.52mm.

27.

Which of the following is correct?(a) Radius of gyration K = (I/A)^0.5(b) Radius of gyration K = (I/A)^0.8(c) Radius of gyration K = (I/A)*0.2(d) Radius of gyration K = (I/A)*0.8The question was posed to me during an internship interview.My question comes from Structural-Analysis Fundamentals topic in chapter Structures and Loads of Aircraft Design

Answer» RIGHT option is (a) Radius of gyration K = (I/A)^0.5

To explain I WOULD say: Above relationship is used to correlate radius of gyration K with moment of INERTIA I and cross section AREA A. Correct relationship is given by, radius of gyration K=(I/A)^0.5 where, I = moment of inertia and A is the cross section area.
28.

Stress and pressure are same.(a) True(b) FalseThe question was posed to me during an online exam.I'm obligated to ask this question of Structural-Analysis Fundamentals in division Structures and Loads of Aircraft Design

Answer»

Right answer is (b) False

The BEST EXPLANATION: Stress and pressure are two different properties. Stress is produced due to internal FORCES. Pressure is result of external force. Stress is DEFINED as internal resistive force per unit cross section area. Unit of pressure and stress will be the same but not their physical explanation.

29.

Air loads are loads typically experienced by an aircraft during flight in air.(a) True(b) FalseI have been asked this question during an interview.I would like to ask this question from Loads Categories topic in portion Structures and Loads of Aircraft Design

Answer»

Correct OPTION is (a) True

Easiest explanation: Air loads are defined as those loads which are acting on the aircraft during flight in the air. Air loads may include MANEUVER, GUST, buffet, control deflection etc.

30.

Which of the following is not categorized as powerplant load?(a) Taxing(b) Thrust(c) Torque(d) Duct pressureThis question was addressed to me in my homework.This question is from Loads Categories in chapter Structures and Loads of Aircraft Design

Answer»

The correct answer is (a) TAXING

Best explanation: Taxing is not an EXAMPLE of power plant load. Powerplant load MAY include Thrust, torque, DUCT PRESSURE, vibration etc. Thrust is propulsive force produced by the powerplant of an aircraft.

31.

An aircraft is cruising with lift of 150N. Find the weight of aircraft.(a) 0.150KN(b) 150KN(c) 123N(d) 15KNI have been asked this question in an online interview.This is a very interesting question from Air Loads in chapter Structures and Loads of Aircraft Design

Answer» RIGHT OPTION is (a) 0.150KN

Best explanation: At cruise, Weight W = LIFT = 150N = 0.150KN.
32.

An aircraft is cruising with cruise speed of 250m/s. All of the sudden aircraft experiences in a gust with velocity of 10m/s. determine the change in angle of attack due to this upward gust.(a) ∼2.3°(b) ∼6°(c) ∼5.6°(d) 9°This question was addressed to me by my school teacher while I was bunking the class.The query is from Air Loads topic in chapter Structures and Loads of Aircraft Design

Answer» RIGHT choice is (a) ∼2.3°

Best explanation: Change in AOA = ARCTAN (GUST velocity / CRUISE speed)

= arctan (10/250)

= arctan 0.04 = 2.29 ∼ 2.3 deg.
33.

Determine the value of stress produced if body is subjected to a force of hundred Newton and cross sectional area of 10 m^2.(a) 10Pa(b) 15MPa(c) 20GPa(d) 27PaThe question was posed to me in an internship interview.My question is taken from Structures Fundamentals topic in division Structures and Loads of Aircraft Design

Answer» RIGHT option is (a) 10PA

To elaborate: STRESS = FORCE / c/s AREA = 100/10 = 10Pa.
34.

For high strength applications ____ is widely used.(a) 7075 aluminum alloy(b) 7089 magnesium zinc(c) 1098 gallium(d) Ge-Zn alloyThe question was posed to me by my college professor while I was bunking the class.I'd like to ask this question from Structures topic in section Structures and Loads of Aircraft Design

Answer»

The CORRECT answer is (a) 7075 aluminum ALLOY

Explanation: For HIGH STRENGTH application 7075 aluminum alloy is widely used. 7075 is alloyed with zinc, copper and magnesium. Corrosion resistance is lessened by alloying. Aluminum sheet is FREQUENTLY clad with a thin layer of pure aluminum.

35.

When an aircraft flies in air, it experiences _________(a) lift, drag, thrust loads, etc(b) only lift load(c) only gust load(d) only drag forceThe question was asked at a job interview.This question is from Air Loads in division Structures and Loads of Aircraft Design

Answer» CORRECT option is (a) lift, drag, thrust loads, etc

The explanation: When an aircraft flies in the air, it might EXPERIENCE various types of loads such as lift, drag Thrust, vibration, gust etc. Only SINGLE load cannot be experienced in real life. At a time there will be NUMBER of loads acting on the aircraft during FLIGHT.
36.

Let us consider the ambient air temperature is 25°C and aircraft has Mach number of 1.5. Find the stagnation temperature.(a) 432.32K(b) 789K(c) 123.56K(d) 213.458KI had been asked this question during an interview.My doubt is from Structures in portion Structures and Loads of Aircraft Design

Answer»

Correct CHOICE is (a) 432.32K

The best I can explain: GIVEN, ambient air temperature T1 = 25°C = 25+273.15 = 298.15K, MACH NUMBER = 1.5

Stagnation temperature for air is given by,

Stagnation temperature = T1*(1+0.2*M^2)

= (25+273.15)*(1+0.2*1.5^2) = 432.32K.

37.

Find the radius of gyration if, moment of inertia I is 160 unit and 10 unit as area.(a) 4 unit(b) 5 unit(c) 2.3 unit(d) 5.6 unitThe question was asked by my school principal while I was bunking the class.I need to ask this question from Structural-Analysis Fundamentals in division Structures and Loads of Aircraft Design

Answer»

The correct option is (a) 4 unit

Easiest explanation: RADIUS of gyration = \(\sqrt{\frac{MOMENT \,of\, inertia}{Area}}\)

= \(\sqrt{\frac{160}{10}}\) = 4 unit.

38.

When we step on an upright soda can, it would fail due to __________(a) crippling(b) bending(c) torsion(d) shearingI have been asked this question during a job interview.The query is from Structural-Analysis Fundamentals topic in portion Structures and Loads of Aircraft Design

Answer»

The correct option is (a) CRIPPLING

To elaborate: When we step on an upright soda can, it would fail due to crippling. Here, walls of cross section will COLLAPSE WITHOUT WARNING and the ability to carry load will BECOME virtually zero. This can be viewed as the short Column with very thin walls.

39.

Which of the following is correct?(a) Corrosion is major problem in terms of material lifespan(b) Corrosion cannot be considered as major factor at all(c) Lift on corrosive material will always be same as weight(d) Weight of corrosive material will always be same as thrust loadingThis question was posed to me at a job interview.My question comes from Structures in division Structures and Loads of Aircraft Design

Answer»

Right choice is (a) Corrosion is MAJOR problem in terms of material lifespan

The best I can EXPLAIN: Since the early days of AVIATION, corrosion of materials has been a major problem. Aircraft materials are exposed to salt water SPRAY, atmospheric moisture, fuels, oils, exhaust, plumes etc. Stress corrosion can lead to fracture at a stress level one tenth of normal ultimate stress.

40.

How do you define slenderness ratio?(a) Ratio of column’s effective length to c/s radius of gyration(b) Ratio of slender body width to the bluff body height(c) Ratio of lift to drag(d) Ratio of Thrust to weightI had been asked this question in semester exam.This question is from Structural-Analysis Fundamentals in chapter Structures and Loads of Aircraft Design

Answer»

Correct choice is (a) Ratio of column’s effective length to c/s radius of gyration

The explanation is: The ratio of column’s effective length to c/s radius of gyration can be termed as slenderness ratio. The effective length of the column is determined based on the end constraints such as PINNED JOINTS, FIXED ENDS etc.

41.

Load factor is defined as _______________(a) ratio of lift produced to the weight of aircraft(b) aerodynamic efficiency(c) thrust loading(d) power to weight ratioI had been asked this question in semester exam.This intriguing question comes from Air Loads topic in chapter Structures and Loads of Aircraft Design

Answer» RIGHT option is (a) ratio of lift produced to the weight of aircraft

The explanation: Load FACTOR is defined as the ratio of lift produced and the weight of the aircraft. For cruising flight lift is equal to weight. Hence, at such flight condition load factor is UNITY. Aerodynamic efficiency is defined as ratio of lift to DRAG. It is directly affected by aerodynamics of the aircraft. THRUST loading is ratio of thrust to weight ratio.
42.

The dive speed in v-n diagram represents _________(a) maximum dynamic pressure(b) maximum manifold pressure of supercharger(c) hydraulic actuator speed limit(d) rate of climbI have been asked this question in semester exam.My question is based upon Air Loads in division Structures and Loads of Aircraft Design

Answer»

The CORRECT choice is (a) maximum dynamic pressure

The explanation: Maximum dynamic pressure is being represented by the DIVE speed in a typical V-n DIAGRAM. Manifold pressure at intake is almost equal to the ATMOSPHERIC. Supercharger is used to increase manifold pressure by large amounts. Rage of climb is VERTICAL velocity.

43.

When aircraft is in air, it can only experience air load.(a) True(b) FalseI had been asked this question in an interview.This interesting question is from Air Loads in section Structures and Loads of Aircraft Design

Answer»

The CORRECT choice is (b) False

Easy explanation: No, it is not true. In the air, it is not only experiencing the air loads rather an aircraft will EXPERIENCE number of different types of loads. For example, lift, drag etc. are air loads HOWEVER Thrust force is a power plant load which is experienced by aircraft during flight in air. HENCE, the given STATEMENT is not true.

44.

Which of the following is correct?(a) G = 0.5*E / (1+μ)(b) G = 0.5*E(c) G = 0.5*E*(1+μ)(d) G = 0.5 / (1+μ)I have been asked this question in unit test.This interesting question is from Structures Fundamentals topic in portion Structures and Loads of Aircraft Design

Answer»

The correct answer is (a) G = 0.5*E / (1+μ)

To explain: Above EQUATION is showing a typical relationship between SHEAR modulus G, elastic constant E and Poisson’s RATIO µ. Correct relationship is given as follows: G = 0.5*E / (1+μ) where, G = shear modulus, E = elastic constant or YOUNG’s modulus, μ = Poisson’s ratio.

45.

If a column has slenderness ratio of 2.2 and 1.8 as the radius of gyration. Determine effective length of the column.(a) 3.96(b) 8.98(c) 4.5(d) 1.09This question was posed to me in class test.The above asked question is from Structural-Analysis Fundamentals topic in section Structures and Loads of Aircraft Design

Answer»

Correct option is (a) 3.96

To EXPLAIN: EFFECTIVE length = SLENDERNESS RATIO*radius of GYRATION = 2.2*1.8 = 3.96.

46.

If elastic constant of material is 6.6MPa then, find the value of direct stress. Given direct strain is 0.25.(a) 1.67MPa(b) 123678Pa(c) 120KPa(d) 1.219MPaThis question was addressed to me in homework.The question is from Structures Fundamentals topic in section Structures and Loads of Aircraft Design

Answer» RIGHT OPTION is (a) 1.67MPa

Explanation: Stress = ELASTIC constant*strain = 6.67 MPA*0.25 = 1.67MPa.
47.

Consider a body is subjected to some force F which is acting on cross section area of 10m^2. If stress due to application of the force is 25Pa then, found the value of F.(a) 250N(b) 1500N(c) 0.89KN(d) 890NI had been asked this question in a national level competition.My question comes from Structures Fundamentals in portion Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) 250N

The BEST EXPLANATION: FORCE or load = stress produced* cross section area = 25*10 = 250N.

48.

A typical aircraft has level cruise speed of 0.6M. Find the dive speed for given subsonic aircraft.(a) 0.9M(b) 1.9M(c) 330m/s(d) 345m/sThe question was posed to me in quiz.The question is from Air Loads topic in portion Structures and Loads of Aircraft Design

Answer»

The CORRECT answer is (a) 0.9M

The best I can EXPLAIN: DIVE SPEED = cruise speed + 0.5*cruise speed

= 0.6 + 0.5*0.6 = 0.9M.

49.

Which of the following is correct?(a) Wood sufferers from moisture sensitivity(b) Wood is not available, it is rare to find(c) Lift of wooden box will be same as drag(d) Wood surface is not sensitive to moisture at allThe question was posed to me during an interview.My enquiry is from Structures in section Structures and Loads of Aircraft Design

Answer»

Correct answer is (a) Wood sufferers from moisture SENSITIVITY

Best explanation: Wood sufferers from moisture sensitivity. Wood is not rare to find. Wood OFFERS GOOD strength to WEIGHT ratio and is EASY to fabricate. Lift will not be same as drag.

50.

Whiskers are ________(a) isotropic(b) isothermal(c) isobaric(d) isentropic compressionThis question was addressed to me by my college director while I was bunking the class.Question is taken from Structures topic in division Structures and Loads of Aircraft Design

Answer»

Right choice is (a) ISOTROPIC

To elaborate: WHISKERS are Isotropic. Whiskers have same material properties in all directions and hence, termed as isotropic. Isothermal process has constant temperature. Isobaric process has constant PRESSURE that means pressure will not change during such processes.