InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
Adsorption of a gas on the surface of solid is generally accompanied by a decrease in entropy. Still it is a spontaneous process. Explain. |
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Answer» According to the equation ∆G = ∆H – T∆S For a process to be spontaneous, ∆G should be negative. ∆H of adsorption is always negative. For a gas. ∆S is also negative. Thus, in an adsorption process, which is spontaneous, a. combination of these two factors always makes ∆G negative. |
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| 352. |
Among the electrolytes Na2SO4 , CaCI2 , Al2(SO4)3 and NH4Cl, the most effective coagulating agent for Sb2S3 Sol is ………(a) Na,SO4 (b) CaCl2 (c) Al2(SO4)3(d) NH4Cl |
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Answer» (c) Al2(SO4)3 |
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| 353. |
How do size of particles of adsorbent, pressure of a gas and prevailing temperature influence of extent of adsorption of a gas on a solid? |
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Answer» 1. Effect of size of the particles of adsorbent: Greater the specific area of the solid available for adsorption of adsorbent, greater would be its adsorbing power. That is why porous or finely divided forms of adsorbents more strongly. However, the size of pores should be large enough to allow the diffusion of gas molecules. 2. Effect of pressure: Increase in pressure initially increases the adsorption which later attains equilibrium at high pressure. \(\frac{x}{m}\) = kP1/n (n>1) |
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| 354. |
1. Heat of adsorption is greater for chemisorption than physisorption. Why? 2. What is colloldion? 3. Differentiate between peptization and coagulation. |
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Answer» 1. Due to the formation of chemical bond between adsorbate and adsorbent. 2. 4% solution of nitro cellulose in a mixture of alcohol and ether. 3. Peptisation is the process of converting a precipitate into colloidal sol by adding an electrolyte. Rut coagulation is the settling of colloidal particles |
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| 355. |
Which of the following does not involve coagulation? (a) peptisation (b) formation of delta regions (c) treatment of drinking water by potash alum (d) clotting of blood by the use of ferric chloride |
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Answer» (a) peptisation |
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| 356. |
Consider the following statements. (i) Enzymes are complex protein molecules with three dimensional structures. (ii) Enzymes catalyse the chemical reaction in living organism. (iii) Enzymes arc not specific in catalytic action.Which of the above statement is J are correct? (a) (iii) only (b) (ii) & (iii) (c) (i) & (ii) (d) (i) & (iii) |
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Answer» (c) (i) & (ii) |
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| 357. |
What is deeniulsification? Explain about the various techniques of deemulsification. |
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Answer» Emulsion can be separated into two separate layers. This process is called Deemulsification. Various deemulsilication techniques are given below. 1. Distilling of one component 2. Adding an electrolyte to destroy the charge. 3. Destroying the emulsifier using chemical methods. 4. Using solvent extraction to remove one component. 5. By freezing one of the components. 6. By applying centrifugal force. 7. Adding dehydrating agents for water in oil type. 8. Using ultrasonic waves. 9. Heating at high pressures. |
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| 358. |
The temperature at which enzyme activity is high (or) maximum is called ……(a) critical temperature (b) optimum temperature (c) low temperature (d) high temperature |
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Answer» (b) optimum temperature |
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| 359. |
Consider the following statements.(i) Zeolites are alumino silicates made of silicon and aluminium tetrahedra. (ii) Zeolites carrying Na ions are used as basic catalyst. (iii) As silicon is tetravalent and aluminium is trivalent, the zeolite matrix carries extra positive charge. Which of the above statement is / are correct? (a) (i) & (ii) (b) (i), (ii) & (iii) (c) (iii) only (d) (ii) only |
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Answer» (a) (i) & (ii) |
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| 360. |
Enzymes can be active in human body at a temperature of ……(a) 98°F (b) 105°F (c) 37°F (d) 50°F |
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Answer» Enzymes can be active in human body at a temperature of 98°F |
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| 361. |
(a) How can a colloidal solution and a true solution of the same colour be distinguished from each other? (b) List four applications of adsorption. |
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Answer» 1. The path of light becomes visible when passed through a colloidal solution while it is not visible in case of a true solution. This is because of Tyndall effect caused by the scattering of light by colloidal particles. 2. Applications of adsorption:
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| 362. |
Which one of the following is an example for homogeneous catalysis? (a) Hydrogenation of oil (b) manufacture of NH3 by Haber’s process (c) manufacture of sulphuric acid by contact process (d) hydrolysis of sucrose in the presence of dilute hydrochloric acid |
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Answer» (d) hydrolysis of sucrose in the presence of dilute hydrochloric acid |
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| 363. |
What are active centres? |
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Answer» 1. The surfiice of a catalyst is not smooth. It bears steps, cracks and corners. Hence the atoms on such locations of the surface are coordinatively unsaturated. 2. The have residual force of attraction. Such sites are called active centres. So the surface cames high surface free energy. |
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| 364. |
Who explained the action of catalyst in adsorption theory? (a) Berzellius (b) Langmuir (c) Thomas Graham (d) Dalton |
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Answer» (b) Langmuir |
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| 365. |
Assertion (A) : The manufacture of sulphuric acid by contact process is an example of heterogeneous catalysis.Reason (R) : The catalyst Pt (or) VO5 , reactants and products are in different phases in contact process.(a) Both A and R are correct and R is the correct explanation of A. (b) Both A and R are correct but R is not correct explanation of A. (c) Both A and R are wrong. (d) A is wrong but R is correct. |
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Answer» (a) Both A and R are correct and R is the correct explanation of A. |
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| 366. |
Describe the action of active centres present in the catalyst. |
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Answer» 1. Active centres increases the rate of the reaction by adsorbing and activating the reactants. 2. Increase in the activity of a catalyst by increasing the surface area. Increase in the surface area of metals and metal oxides by reducing the particle size increases the rate of the reaction. 3. The action of catalytic poison occurs when the poison blocks the active centres of the catalyst. 4. A promoter (or) activator increases the number of active centres on the surface. |
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| 367. |
Assertion (A) : Ester hydrolysis of acid (or) alkali catalyst is an example of homogeneous catalysis. Reason (R) : Ester, H2O acid (or) alkali and the products are in liquid form. (a) Both A and R are correct but R is the correct explanation of A. (b) Both A and R are wrong. (c) A is correct but R is wrong. (d) A is wrong but R is correct, |
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Answer» (a) Both A and R are correct but R is the correct explanation of A. |
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| 368. |
Find the odd one outOxidation, Peptisation, Reduction, Decomposition, Hydrolysis. |
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Answer» Peptisation. It is a dispersion method of preparation ofcoiloid whereas others are condensation methods of preparation of colloids. |
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| 369. |
In the decomposition of hydrogen peroxide which acts as a negative catalyst? (a) Dilute acid (b) Glycerol (c) a (or) b (d) Ethanol |
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Answer» (c) a (or) b |
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| 370. |
Find the odd one out.Decomposion of acetaldehyde by I2 Decomposition of H2O2 by Pt, Ester hydrolysis with acid, Hydrolysis of cane sugar. |
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Answer» Decomposition of H2O2 by Pt. It is heterogeneous catalysis whereas others are homogeneous catalysis. |
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| 371. |
The negative catalyst in the decomposition of H2O2 is ……(a) Ethanol (b) Acetic acid (c) Ethanoic acid (d) Methanol |
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Answer» The negative catalyst in the decomposition of H2O2 is Ethanol |
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| 372. |
In the reaction 2H2 + O2 → 2H2O acts as a catalytic poison for Pt catalyst. (a) Co (b) Mo (c) As2O3 (d) H2S |
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Answer» A catalytic poison for Pt catalyst Co |
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| 373. |
The catalyst poison in contact process of manufacture of SO3 is …… (a) As2O3 (b) H2S (c) CO (d) As2S3 |
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Answer» The catalyst poison in contact process of manufacture of SO3 is As2O3 |
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| 374. |
Which method is used for identification, detection and estimation of many substances even if they are in micro quantities? (a) Lassaigne’s test (b) Canus method (c) Kjeldhals method (d) Chromatography |
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Answer» (d) Chromatography |
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| 375. |
The migration of sol particles under the influence of electric field is called ………(a) electro osmosis (b) electro dialysis (c) electrophoresis (d) dialysis |
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Answer» (c) electrophoresis |
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| 376. |
Which one of the following is used for detection of pressure of charge on sol particles?(a) Cataphoresis (b) Electro dialysis (c) Dialysis (d) Ultrafilteration |
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Answer» (a) Cataphoresis |
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| 377. |
Which of the following is positively charged colloid? (a) haemoglobin(b) starch (c) clay (d) AS2S3 |
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Answer» (a) haemoglobin |
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| 378. |
Which one of the following is a positively charged colloid? (a) Ag (b) AU (c) Basic dyes (d) Clay |
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Answer» (c) Basic dyes |
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| 379. |
Method by which lyophobic sol can be protected.(i) By addition of oppositely charged sol.(ii) By addition of an electrolyte.(iii) By addition of lyophilic sol.(iv) By boiling. |
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Answer» (iii) By addition of lyophilic sol. |
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| 380. |
Which one of the following is a negatively charged colloid? (a) Ferric hydroxide (b) Clay (c) Basic dyes (d) Haemoglobin |
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Answer» Clay is a negatively charged colloid. |
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| 381. |
Which one of the following is a negatively charged colloid? (a) Pt (b) Al(OH)3 (c) Fe (OH)3(d) Basic dyes |
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Answer» Pt is a negatively charged colloid |
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| 382. |
Which of the following statements are correct?(i) Mixing two oppositely charged sols neutralises their charges and stabilises the colloid.(ii) Presence of equal and similar charges on colloidal particles provides stability to the colloids.(iii) Any amount of dispersed liquid can be added to emulsion without destabilising it.(iv) Brownian movement stabilises sols. |
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Answer» (ii), (iv) (ii) Presence of equal and similar charges on colloidal particles provides stability to the colloids. (iv) Brownian movement stabilises sols. |
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| 383. |
An emulsion cannot be broken by __________ and ___________.(i) heating(ii) adding more amount of dispersion medium(iii) freezing(iv) adding emulsifying agent |
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Answer» (ii), (iv) (ii) adding more amount of dispersion medium (iv) adding emulsifying agent |
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| 384. |
How is a sol different from an emulsion ? |
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Answer» In sol, the dispersed phase-Solid Dispersion medium-Liquid Example: Paint In Emulsion, the dispersed phase is liquid and dispersion medium is also liquid. Example: Milk. |
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| 385. |
Give the expression for Fruendlich adsorption isotherm. |
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Answer» The expression for Fruendlich adsorption isotherm : x/m= kp1/n |
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| 386. |
Give one example each of 'oil in water' and 'water in oil' emulsion. |
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Answer» Oil in water: Milk/vanishing cream. Water in oil: Butter/cold cream. |
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| 387. |
Explain the mechanism of enzyme catalysis. |
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Answer» (1) Binding of enzyme to substrate to form an activated complex. E + S → ES* (2) Decomposition of the activated complex to from the product. ES* → E + P |
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| 388. |
Explain the following terms giving suitable example in each case: (i) Gel (ii) homogeneous catalysis (iii) Sol |
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Answer» (i) A gel is a colloidal solution in which dispersed phase is a liquid and dispersion medium is a solid. ex- jellies (ii) When the reactants, products and catalyst are in the same physical states the catalysis is called homogeneous catalysis. (iii) A sol is a colloidal solution in which dispersed phase is a solid and dispersion medium is a liquid. |
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| 389. |
Give one example each of sol and gel. |
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Answer» Sol: Paint/cell fluids. Gel : Cheese/butter/jellies |
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| 390. |
Explain What is observe when (i) An electrolyte, NaCl is added to hydrate ferric oxide sol. (ii) Electric current is passed through a colloidal sol. (iii) When a beam of light is passed through a colloidal sol. |
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Answer» (i) The positively charged colloidal particles of Fe(OH)3 get coagulated by the positively charged Cl- ions provided by NaCl. (ii) On passing direct current, colloidal particles move towards the positively charged electrode where they lose their charge and get coagulated. (iii) Scattering of light by the colloidal particles takes place and the path of light becomes visible (Tyndall effect). |
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| 391. |
What is the cause of Brownian movement among colloidal particles? |
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Answer» Due to collision between particles. |
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| 392. |
Name the promoter used in Haber’s process? |
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Answer» Molybdenum the promoter used in Haber’s process . |
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| 393. |
What is meant by adsorption isotherm? |
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Answer» A plot between the amount of adsorbate adsorbed and pressure or concentration of adsorbate at constant temperature is called adsorption isotherm. |
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| 394. |
Fill in the blanks1. …….. or …….. used as promoter for iron in Haber’s process2. …….. destroys the activity of platinum in contact process3. In the reaction CH3COOC2H5 + H2O → CH3COOH + C5H5OH ……. is act as auto calyst.4. The decomposition of H2O2 rate is decreased by ………5. As ……..is lowered in the presence of catalyst, more molecules take part in the reaction and hence the rate of the reaction increases.6. The mechanism of friedel crafts reaction is explained by ………theory.7. The catalyst used for the oxidation of HCl by air is …….8. Thermal decomposition of KClO3 in the presence of …….. follows …….. theory.9. Intermediate compound formation theory is unable to explain the mechanism of ………10. Hydrogenation of ethylene in the presence of nickel catalyst follows …….. theory |
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Answer» 1. Mo (or) Al2O3 2. AS2O3 catalyst poison 3. CH3COOH 4. ethanol (or) Glycerol, negative catalyst 5. Activation energy 6. intermediate compound formation 7. CuCI2 8. MnO2 , intermediate compound formation theory 9. heterogeneous catalysis 10. adsorption |
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| 395. |
Why is it necessary to remove CO when ammonia is obtained by Haber’s process? |
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Answer» CO acts as poison catalyst for Haber’s process and lowers the activity of solution therefore it is necessary to remove when NH3 obtained by Haber’s process. |
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| 396. |
The phenomenon observed when a beam of light is passed through a colloidal solution is ……(a) Cataphoresis (b) Electrophoresis (c) Coagulation (d) Tyndall effect |
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Answer» (d) Tyndall effect-scattering of light |
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| 397. |
Which of the following phenomenon is applicable to the process shown in the Fig. 5.1? (i) Absorption (ii) Adsorption (iii) Coagulation (iv) Emulsification |
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Answer» (ii) Adsorption of ionic species from solution. |
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| 398. |
Consider the following statements. (i) When pressure increases, the amount of physisorplion also increases. (ii) Permanent gases like H2 , N2 and O2 cannot be liquefied easily.(iii) Lesser is the surface area, higher is the amount adsorbed. Which of the above statement is / are correct? (a) (i) & (ii) (b) (iii) only (c) (ii) only (d) (i) only |
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Answer» (a) (i) & (ii) |
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| 399. |
Match the column I & II using the code given below the column.Column - IColumn - IIA. Haber,s process1. Anhydrous AlCl3B. Vanaspathi preparation2. Pt(or) V2O5C. Contavt process3. Fe/MoD. Freidel crafts reaction4. NickelABCD(a)1234(b)3421(c)4312(d)2143 |
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Answer» (b) 3 4 2 1 |
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| 400. |
Which one of the following is not applicable to the phenomenon of adsorption?(i) ΔH > 0(ii) ΔG < 0(iii) ΔS < 0(iv) ΔH < 0 |
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Answer» (i) ΔH > 0 is not applicable to the phenomenon of adsorption. |
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