Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.	At what temperature do the ratings of Celsius and Fahrenheit scales coincide?
Answer» Let T_B = T_B – x Let T_C = T_f - x As \(\frac{T_C - 0}{100}\) = \(\frac {T_f - 32}{180}\) \(\frac{x}{100} = \frac{x - 32}{180}\) ∴ 180x = 100x – 3200 80x = -3200 x = -\(\frac{3200}{80}\) = -40° x = -40° ∴ Hence -40°C and -40° f are identical Temperature.

At what temperature do the ratings of Celsius and Fahrenheit scales coincide?

Answer»

Let T_B = T_B – x

Let T_C = T_f - x

As \(\frac{T_C - 0}{100}\) = \(\frac {T_f - 32}{180}\)

\(\frac{x}{100} = \frac{x - 32}{180}\)

∴ 180x = 100x – 3200

80x = -3200

x = -\(\frac{3200}{80}\) = -40°

x = -40°

∴ Hence -40°C and -40° f are identical Temperature.

Discussion

2.	If the gap between steel sails on the railway track of 66 m long is 3.63 cm at 10°C. Then at what value of temperature will just touch of steel is 11 × 10-6 °C.
Answer» L₀ = 66 m = 6600 cm α = 11 × 10^-6 °C. ∆L = L_t – L₀ = 3.63 t₁ = 10°C t₂ = ? \(a = \frac{Δ L}{L_0Δ T}\) ΔT = \(\frac{Δ L}{L_0 \times a}\) Δ T = \(\frac{3.63}{6600 \times 11 \times 10^{-6}}\) Δ T = t₂- t₁ = 50 ⇒ t₂ – 10 = 50 ⇒ t₂ = 50 + 10 = 60°C so final temperature t₂ = 60°C

If the gap between steel sails on the railway track of 66 m long is 3.63 cm at 10°C. Then at what value of temperature will just touch of steel is 11 × 10-6 °C.

Answer»

L₀ = 66 m = 6600 cm

α = 11 × 10^-6 °C.

∆L = L_t – L₀ = 3.63

t₁ = 10°C

t₂ = ?

\(a = \frac{Δ L}{L_0Δ T}\)

ΔT = \(\frac{Δ L}{L_0 \times a}\)

Δ T = \(\frac{3.63}{6600 \times 11 \times 10^{-6}}\)

Δ T = t₂- t₁ = 50

⇒ t₂ – 10 = 50

⇒ t₂ = 50 + 10 = 60°C

so final temperature t₂ = 60°C

Discussion

3.	According to Boyle’s law the relation between pressure (P) and volume of a gas is:(a) P ∝ V (b) P = V (c) P ∝ \(\frac{1}{V}\)(d) V ∝ P
Answer» Correct answer is (c) P ∝ \(\frac{1}{V}\)

Discussion

4.	If you keep ice at 0°C and water at 0°C in either of your hands, in which hand you will feel more chillness? Why?
Answer» The hand consisting of ice at 0°C would feel more chillness because, ice undergoes melting. More amount of energy (chillness) is transferred to hand. In addition ice has latent heat of fusion.

Discussion

5.	When a certain quantity of ice is melting remains the same. (a) Volume (b) Temperature (c) Mass (d) Density
Answer» (b) Temperature

Discussion

6.	Avogadro’s Number _____ mol. (a) 6.023 × 1023 (b) 6.025 × 1025 (c) 6.24 × 1024 (d) 6.022 × 1022
Answer» (a) 6.023 × 10²³ N = 6.023 × 10²³

Avogadro’s Number _____ mol. (a) 6.023 × 1023 (b) 6.025 × 1025 (c) 6.24 × 1024 (d) 6.022 × 1022

Answer»

(a) 6.023 × 10²³

N = 6.023 × 10²³

Discussion

7.	The ratio of change in area of a metal to its original area is \(\frac{Δ A}{A_0}\) = (a) \(a_A\)(b) \(a_AΔT\)(c) \(\frac{a_A}{ΔT}\)(d) unity
Answer» Correct answer is (b) \(a_AΔT\)

Discussion

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Explore topic-wise InterviewSolutions in Current Affairs.

At what temperature do the ratings of Celsius and Fahrenheit scales coincide?

If the gap between steel sails on the railway track of 66 m long is 3.63 cm at 10°C. Then at what value of temperature will just touch of steel is 11 × 10-6 °C.

According to Boyle’s law the relation between pressure (P) and volume of a gas is:(a) P ∝ V (b) P = V (c) P ∝ \(\frac{1}{V}\)(d) V ∝ P

If you keep ice at 0°C and water at 0°C in either of your hands, in which hand you will feel more chillness? Why?

When a certain quantity of ice is melting remains the same. (a) Volume (b) Temperature (c) Mass (d) Density

Avogadro’s Number _____ mol. (a) 6.023 × 1023 (b) 6.025 × 1025 (c) 6.24 × 1024 (d) 6.022 × 1022

The ratio of change in area of a metal to its original area is \(\frac{Δ A}{A_0}\) = (a) \(a_A\)(b) \(a_AΔT\)(c) \(\frac{a_A}{ΔT}\)(d) unity