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1.

Coefficient of drag over a sphere at hypersonic speed is dependent on the Mach number.(a) True(b) FalseI had been asked this question during an interview.I would like to ask this question from Time-Marching Technique in division Time-Marching Technique of Aerodynamics

Answer»

Correct choice is (b) False

The best explanation: The coefficient of drag for a sphere that is kept at hypersonic FLOW is GIVEN by:

cd = \(\frac {D}{q_∞ S}\)

Where, S = πR^2 (R being the radius of the sphere)

This results in the value of cd being 1. CLEARLY, this RESULT is independent of the Mach number of the flow. The only CONDITION is that the Mach number should be in the range of hypersonic regime for this result to be valid.

2.

Which of these methods is not a local inclination method for computing pressure distribution?(a) Newtonian theory(b) Tangent wedge theory(c) Tangent cone theory(d) Oblique shock methodThe question was posed to me in an interview.This question is from Time-Marching Technique topic in portion Time-Marching Technique of Aerodynamics

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The correct answer is (d) OBLIQUE shock METHOD

To elaborate: There are three other local surface inclination inclinations, in addition to Newtonian theory. Methods that are widely used to estimate distributions of pressure over HYPERSONIC BODIES are the tangent WEDGE method, tangent cone method and shock – expansion method.

3.

According to Newton’s theory, what happens to the lift to drag value with decreasing angle of attack of a flat plate?(a) Remains same(b) Increase monotonically(c) Decreases parabolically(d) Becomes zero with maximum angle of attackI had been asked this question at a job interview.My enquiry is from Time-Marching Technique in section Time-Marching Technique of Aerodynamics

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Correct answer is (b) Increase monotonically

To elaborate: The lift/drag ratio for inviscid hypersonic flow over a flat plate is given by:

\(\FRAC {L}{D}\) = cotα

On plotting the curve, as the angle of attack decreases, L/D ratio monotonically INCREASES. Obviously this is a HYPOTHETICAL condition as SKIN friction drag is not incorporated in this.

4.

What is the formula for coefficient of drag over a circular cylinder at hypersonic speed?(a) cd = \(\frac {D}{q_∞ S}\)(b) cd = \(\frac {D}{2q_∞ S}\)(c) cd = \(\frac {2D}{q_∞ S}\)(d) cd = Dq∞SThis question was posed to me during an online exam.Question is taken from Time-Marching Technique topic in section Time-Marching Technique of Aerodynamics

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Right CHOICE is (a) cd = \(\frac {D}{q_∞ S}\)

To elaborate: At HYPERSONIC speed, COEFFICIENT of DRAG over circular cylinder can be predicted using the Newton’s THEORY. It is given by:

cd = \(\frac {D}{q_∞ S}\)

Where, S = 2R is the cross – sectional area and R is the radius of the cylinder

cd = \(\frac {4}{3}\) which is obtained using Newton’s theory.

5.

According to the Newtonian model for fluid flow, what is the coefficient of pressure at the rear of the surface while free stream flows horizontally towards it?(a) One(b) Zero(c) Infinity(d) 0.5The question was posed to me in a job interview.I'd like to ask this question from Time-Marching Technique topic in portion Time-Marching Technique of Aerodynamics

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The CORRECT choice is (b) Zero

To explain: The Newtonian MODEL for fluid flow is only able to predict the coefficient of pressure in the FRONTAL region of the surface where the free stream IMPACTS the body. The portion which does not experience any IMPACT from the incoming flow is known to be in the shadow which has zero coefficient of pressure.

6.

According to the Newtonian theory, which of these is preserved after the impact of the incident particles?(a) Normal momentum(b) Tangential momentum(c) Normal velocity(d) Tangential velocityI had been asked this question in an internship interview.The origin of the question is Time-Marching Technique topic in portion Time-Marching Technique of Aerodynamics

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The correct CHOICE is (b) TANGENTIAL momentum

Easy explanation: When there is an incoming stream of particles on a flat plate with a FREE stream VELOCITY, the normal momentum is transferred to the surface after the impact. On the other hand, the tangential momentum is preserved. This result was obtained by Newton with an ASSUMPTION that the particles do not interact with each other and hence are linear.

7.

Newton theory is applicable for which of these flows?(a) Subsonic flow(b) Supersonic flow(c) Transonic flow(d) Hypersonic flowThis question was addressed to me during an online exam.The above asked question is from Time-Marching Technique topic in section Time-Marching Technique of Aerodynamics

Answer» RIGHT answer is (d) Hypersonic flow

To elaborate: NEWTON’s theory is more accurate for hypersonic flows with Mach numbers greater than 5. This is because as the free stream Mach NUMBER INCREASES and the angle between free stream and inclined FLAT plate increases, the accuracy of Newtonian theory also increases.
8.

At what angle does the coefficient of lift over a flat plate become maximum?(a) 66.6 deg(b) 54.7 deg(c) 33.3 deg(d) 90 degI got this question by my college director while I was bunking the class.My question is from Time-Marching Technique topic in portion Time-Marching Technique of Aerodynamics

Answer» RIGHT answer is (B) 54.7 deg

The best explanation: According to the Newton’s theory, the coefficient of LIFT is given by:

cl = 2sin^3α

This VALUE is maximum for α = 54.7 DEGREES.
9.

Newton’s theory gives much more accurate results for 2 – dimensional shapes.(a) True(b) FalseThis question was addressed to me in unit test.Asked question is from Time-Marching Technique topic in chapter Time-Marching Technique of Aerodynamics

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The correct choice is (b) False

The BEST I can EXPLAIN: For three – dimensional bodies such as a cone, Newtonian theory is generally more accurate in contrast with two – dimensional bodies like wedge. One more important property to note is that Newton’s theory gets MUCH more accurate with increasing MACH number.

10.

What is a Newtonian theory used for?(a) Finding lift coefficient over blunt body(b) Finding pressure coefficient over blunt body(c) Finding drag coefficient over sharp wedge(d) Finding pressure coefficient over coneThe question was posed to me at a job interview.My enquiry is from Time-Marching Technique topic in section Time-Marching Technique of Aerodynamics

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Right choice is (b) Finding pressure COEFFICIENT over BLUNT BODY

Easiest explanation: NEWTONIAN theory was developed in ORDER to predict the coefficient of pressure over the bluff body when there is incoming flow. It is given by the following relation:

Cp = 2sin^2θ

Where, the coefficient of pressure is given by:

Cp = \(\frac {1}{2} \frac {(p – p_∞)}{ρV^{2}}\)

11.

As a result of chemically reacting gas, which of these features differ compared to the ideal gas??(a) Pitching moment coefficient(b) Temperature(c) Drag(d) LiftThe question was asked in examination.The question is from Time-Marching Technique topic in section Time-Marching Technique of Aerodynamics

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Correct choice is (a) Pitching moment coefficient

The explanation: CHEMICALLY reactive flow in hypersonic flow determines the pitching moment over the space shuttle. The pressure on the FORWARD part of the shuttle BODY is usually higher for a chemically reactive gas, and it is lower in the rearward part. This LEADS to a positive pitching moment of the shuttle.

12.

What is the pressure exerted by the incoming stream of particles on an inclined flat plate based on Newton’s theory?(a) \(\frac {F}{A}\) = ρV\(_∞^2\)sin^2θ(b) \(\frac {F}{A}\) = ρV∞sin^2θ(c) \(\frac {F}{A}\) = ρV\(_∞^2\)cos^2θ(d) \(\frac {F}{A}\) = ρV\(_∞^2\)sinθThis question was addressed to me in exam.My question is from Time-Marching Technique in division Time-Marching Technique of Aerodynamics

Answer»

Correct option is (a) \(\frac {F}{A}\) = ρV\(_∞^2\)sin^2θ

The explanation is: For an incoming stream of particles over the inclined surface, the particles move ALONG the surface after the collision and hence the normal velocity is V∞sinθ. Where, θ is the angle formed between the incoming free stream velocity and the flat plate.

The RATE of mass flow of the particles over the flat inclined plate with an area A is given by ρAV∞sinθ.

Thus the force is given by product of mass flux and velocity change.

(ρAV∞sinθ)(V∞sinθ) = ρAV\(_∞^2\)sin^2θ = F

And since pressure is equal to force UPON area, therefore it is \(\frac {F}{A}\) = ρV\(_∞^2\)sin^2θ

13.

What is the relation according to the Newton’s theory for hypersonic problems?(a) Cp = 2sinθ(b) Cp = 2sin^2θ(c) Cp = cosθ(d) Cp = 2sinθcosθThe question was asked in a national level competition.This is a very interesting question from Time-Marching Technique topic in portion Time-Marching Technique of Aerodynamics

Answer» CORRECT choice is (b) Cp = 2sin^2θ

Easy explanation: By using the relation of oblique shock theory and applying the limits M∞ → ∞ because hypersonic flows theoretically range from Mach number = 5 to infinity and γ → 1, we get the result for Newtonian theory. It is given by:

Cp = 2sin^2θ

Where, θ is the LOCAL inclination ANGLE of the surface with respect to the free stream VELOCITY.