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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
101. |
The girdling or ringing experiment to prove that the water moves through the xylem vessels was performed byA. StockingB. MalpighiC. MolischD. Askenasy |
Answer» Correct Answer - B | |
102. |
Ringing/girdling experiment was first performed byA. HartingB. StrasburgerC. GodlewskiD. Bose |
Answer» Correct Answer - A | |
103. |
Meaningful girdling (Ringing) experiments cannot be done on sugarcane becauseA. Phloem is present inside the xylemB. It can not tolerate the injuryC. Vascular bundles are scatteredD. Plants are very delicate |
Answer» Correct Answer - C |
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104. |
Exchange of substances between a cell and its environment is due toA. OsmosisB. Active transportC. DiffusionD. All the above |
Answer» Correct Answer - D | |
105. |
Amount by which water potential is reduced due to presence of solute is calledA. Pressure potentialB. Solute potentialC. Mateic potentialD. None of the above |
Answer» Correct Answer - B | |
106. |
Uniformly sweet taste of Tea or Coffee is due toA. SpereadingB. OsmosisC. PermeabilityD. Diffusion |
Answer» Correct Answer - D | |
107. |
Statement 1: It becomes difficult to open and shut the wooden doors and windows during rainy season. Statement 2: Wooden doors and windows imbibe water in rainy season and thus their volume is increased.A. If both Assertion and Reason are true and the Reason is a correct expanation of the AssertionB. If both Assertion and Reason re true but Reason is not a correct eplanatin of the AssertionC. If Assertion is true but the Reason is falseD. If both Assertion and Reason are false |
Answer» Correct Answer - a | |
108. |
Wooden doors swell up and get stuck during rainy season due toA. EndosmosisB. ImbibitionC. CapillarityD. Exosmosis |
Answer» Correct Answer - B | |
109. |
Statement 1: It becomes difficult to open and shut the wooden doors and windows during rainy season. Statement 2: Wooden doors and windows imbibe water in rainy season and thus their volume is increased.A. Both statements `1` and `2` are correct.B. Statement `1`is correct but statement `2` is incorrect.C. Statement `1` is incorrect but statement`2` is correct.D. Both statements `1` and `2` are incorrect. |
Answer» Correct Answer - A Wooden doors and windows adsorb water in humid rainy season and increase in their volume so that they are hard to open or close. If a dry piece of wood is placed in water it swells and increases its volume During imbibition the water molecules get tightly adsorbed and become immobilised. |
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110. |
Which is not associated with ascent of sap in tall trees?A. Continuity of water columnB. Cohesion and adhesion of water moleculesC. Transpiration pullD. Pressure of tracheary elements |
Answer» Correct Answer - D Pressure of tracheary elements is not associated with ascent of sap in tall tress |
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111. |
Ascent of sap is due to which force The most Important force which pulls water up in tall trees isA. ImbibitionB. Cellular forceC. Cohesive forceD. Atmospheric pressure |
Answer» Correct Answer - C |
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112. |
In thistle funnel experiment, entry of water into thistle funnel stops after some time autumatically due toA. Diffusion of sugar out of thistle funnelB. External and internal solutions become isotonicC. Development of hyrostatic pressure in the thistle funnelD. Development of gydrostatic pressure in the beaker. |
Answer» Correct Answer - C | |
113. |
List any foru mechanism that contribute to the ascent of sap in tall trees |
Answer» (i) Adhesion (ii) choeshion ,(iii) Transpiration pull and (iv)Root pressure | |
114. |
In thistle funnel experiment, during osmosis the level of the solution in the funnelA. IncreasesB. DecreasesC. Remains sameD. First increases then decreases |
Answer» Correct Answer - A In thistle funnel experment, during osmosis the level of the solution in the funnel increases, due to movement of water form beaker to funnel. |
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115. |
The external pressure applied from the upper part of the funnel to prevent osmosis is calledA. Osmotic potentialB. Osmotic pressureC. Turgor pressureD. Potential pressure |
Answer» Correct Answer - B The external pressure applied from the upper part of the funnel to prevent osmosis is called osmotic pressure. |
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116. |
If turgor pressure becomes equol to osmotic pressureA. Water leaves the cellsB. Water enters the cellsC. No exchange of water takes placeD. Solute pass out of the cell |
Answer» Correct Answer - C If turgor pressure becomes equal to osmotic pressure no exchange of water takes place. |
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117. |
Compare the statements a and b Statement a. To counteract the increase in turgor preassure in plant cells the cell wall produces an equal and opposite pressure, i.e., wall pressure Statement b.When plant cells undergo endosmosis, they swell but do not burst .A. Both the statements a and b are correct and a is reason for bB. Statement a is correct and b is wrongC. Statement a is wrong and b is correctD. Both the statemets a and b are correct and a is not the reason for b . |
Answer» Correct Answer - A | |
118. |
A farmer oberved drops of water along the margins of leaves of tomato plants growing in his well irrigated field on a wint er moring give resons of this occurrence why had the water drop appeared only along the leaf margins |
Answer» The drops of water appeared along the margins of leaves of tomato plants due to the prcess of guttation it occurs at night when the fiield is well irrigated and transipration is reduced the guttaltion water is seen along the leaf margins where hydathodes are locate d | |
119. |
Given figure shows `U-`shaped tube with two hands `A` and `B` separated by a semi-permeable membrane `(i)` Adding solute to the right side lowers the value of `Psi_(s)` Causing water to move to the right side of the tube. `(ii)` Applying positive pressure to the left side decreases the vaule of `Psi_(rho)` causing water to move to the right side of the tube. `(iii)` Applying negative pressure to the left side decreases the value of `Psi_(rho)` causing water to move to the right side of the tube. Which of the above statements is`//`are true?A. `(i)` and `(ii)`B. `(i)` onlyC. `(iii)`onlyD. `(i),(ii)` and `(iii)` |
Answer» Correct Answer - B According to the given figure if solute is added to the right side `Psi_(s)` lowers This causes water to move to the right side of the tube. When positive pressure is applied to the left side `Psi_(rho)` increases causing water to move to the right side of the tube. Simiarly when negative pressure is applied to the left side `Psi_(rho)` lower which causes water to move to the left side of the tube. |
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120. |
Which does not cause stomatal opening ?A. Influx of `K^(+)` ionsB. LightC. High `CO_(2)`concentrationD. Circadian thythm |
Answer» Correct Answer - C | |
121. |
Water drops present on leaf margins of Tropaeolum, Balsam and grasses in earls morning are due toA. GuttationB. DewC. OsmosisD. Transpiration . |
Answer» Correct Answer - A | |
122. |
Turgor pressure becomes equal to the wall pressure whenA. Water leaves the cellB. No exchange of water takes placesC. Water enters the cellD. Solute goes from the cell into water |
Answer» Correct Answer - B |
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123. |
Select the correct statement(s) pertaining to transpiration process in plantsA. It is a necessary evil for plantsB. Loss of water takes place through hydathodes in vapour formC. It may also occur through lenticelsD. The process is active during night in `C_(3) plants |
Answer» Correct Answer - A::C |
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124. |
Which of the following physiological process in plants is a necessary evil ?A. TranspirationB. Water absorptionC. PhotosynthesisD. Translocation |
Answer» Correct Answer - A | |
125. |
Oozing out of water drops from injured edges or tips isA. BleedingB. GuttationC. TranspirationD. Oozatioin |
Answer» Correct Answer - A | |
126. |
Oozing out of water drops from injured edges or tips isA. bleedingB. guttationC. transpirationD. oozation |
Answer» Correct Answer - A | |
127. |
Loss or excretion of water in the form of liquid droplets from the margins and tips of leaves is calledA. transpirationB. guttationC. bleedingD. precipitation. |
Answer» Correct Answer - B The loss or excretion of water in the form of liquid droplets from the leaves and other parts of uninjured or intact plant is called guttation. It was first studied by Bergerstein in `1887.` All plants do not show guttation It is restricted to about `345` genera of herbaceous and some woody plants. Common examples are garden nasturtium, oat and other cereals, balsam, tomato cucurbits Guttation takes place through special structures called hydathodes. They are usually found on the margins and tips of the leaves. |
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128. |
Adding solution to pure water will cause development ofA. Positive water potentialB. More Positive water potentialC. More negative water potentialD. Negative water potential |
Answer» Correct Answer - D | |
129. |
Water is mainly transported to shoot tips by the help ofA. CapillarityB. Root pressureC. Transpiration pullD. Canopy structure |
Answer» Correct Answer - C |
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130. |
Stomatal opening is affected byA. Nitrogen concentration , carbon dioxide concentration and lightB. Carbon dioxide concentration , temperature and lightC. Nitrogen concentration , light and temperatureD. Carbon dioxide concentration , nitrogen concentration and temperature |
Answer» Correct Answer - B |
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131. |
Stomatal opening is affected byA. nitrogen concentration, carbon dioxide concentration and lightB. carbond dioxide concentration, temperature and lightC. nitrogen concentration, light and temperatureD. carbon dioxide concentration, nitrogen concentration and temperature |
Answer» Correct Answer - B Carbon dioxide is an effective antitranspirant. A little rise in `CO_(2)` concentration induces partial closure of stomats. Light affects the rate of transpiration in two ways firstly by controlling the stomatal opening and secondly by affecting the temperature. Increase in temperature increases the rate of transpiration. |
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132. |
Who had said that "transpiration is a necessary evil"A. CurtisB. StewardC. AndersonD. J. C. Bose |
Answer» Correct Answer - A |
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133. |
The proteins that form huge pores in the outer membranes ofA. MitochondriaB. PlastidsC. Some bacteriaD. All of the above |
Answer» Correct Answer - D The porins are proteins that form huge pore in the outer membrane of mitochondria, plastids and some bacteria. |
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134. |
Transpiration is a necessary evil in plants. Explain |
Answer» Transpiration a Necessary Evil The plant continuously lose water in the vapour from its body surfaces. If creates a transpiration pull to absorb more and more water from soil through roots. If the plant does not get water in soil, even then loss through transpiration is not stopped, so plant shows wilting sometimes it leads to the physiological wilting (non0recoverable) and plant dies. So, the transpiration is necessary evil. |
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135. |
Lose of water from tips of leaves isA. TranspirationB. GuttationC. BleedingD. Respiration |
Answer» Correct Answer - B | |
136. |
Which ones show physiological process called "necessary evil" (a) Potomogeton (b) Sagitteria (c) Limnophila (d) NymphaeaA. b,c,dB. a,b,cC. a,b,d,D. a,c,d |
Answer» Correct Answer - A | |
137. |
Rate of transpiration is related toA. Light and temperatureB. Light, temperature , atmospheric humidity and windC. Light , temperature and windD. Soil and temperature |
Answer» Correct Answer - B | |
138. |
Stomatal movement is not affected byA. TemperatureB. LightC. `O_(2)` concentrationD. `CO_(2)` concentration |
Answer» Correct Answer - C Stomatal movement is not affected by `O_(2)` conecntration. |
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139. |
Maximum transpiration occurs inA. Algal cellsB. Xerophytic plantsC. Hydriophytic plantsD. Mesophytic plants |
Answer» Correct Answer - D | |
140. |
Who had said that "transpiration is a necessary evil"A. BoseB. StewardC. AndersonD. Curtis |
Answer» Correct Answer - D | |
141. |
The following figure shows : A. Simple diffusionB. Facilitated diffusionC. Active transportD. Osmosis |
Answer» Correct Answer - B The given figure shows facilitated diffusion. |
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142. |
Nonfunctional stomata can be seen inA. mango leafB. Pea leavesC. HydrillaD. Lotus |
Answer» Correct Answer - C | |
143. |
When half the leaves are removed randomly, transpiration will showA. Higher magnitude but lower flux or rate per unitB. Lower magnitude but higher fluxC. Both magnitude and flux increaseD. Both magnitude and flux decrease . |
Answer» Correct Answer - B | |
144. |
Which of the following facilitates opening of stomatal aperture?A. Decresase in turgidity of guard cellsB. Radial orientation of cellulose microfibrils in the cell wall of guard cellsC. Longitudinal orientation of cellulose microfibrils in the cell wall of guard cellsD. Contraction of outer wall of guard cells |
Answer» Correct Answer - B Radial orientation of cellulose microfibrils in the cell wall of guard cells facilitates opening of stomatal aperture. |
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145. |
Accumulation of which one of the following acids results in closure of stomataA. Malic acidB. Aspertic acidC. PEPD. OAA. |
Answer» Correct Answer - A | |
146. |
Latest explanation for closure of stomata isA. Starch glucose theoryB. Active `K^(+)` ions theoryC. ABA theoryD. None of the above |
Answer» Correct Answer - C | |
147. |
Which of the following theory gives the latest explanation for the closure of stomataA. ABA theoryB. Munch theoryC. Starch-glucose theoryD. Active `K^(+)` transport theory |
Answer» Correct Answer - D Active `K^(+)` transport theory proposed by Levitt is the latest and most accepted theory for opening and closing of a stomata. According to this theory, pH of guard cells increase due to active `H^(+)` uptake by cell and `CO_(2)` assimilation by guard cell. Rise is pH of guard cell causes hydrolysis of strach to form phosphoenol pyruvate. Phosphoenol pyruvate combine with `CO_(2)` with the help of PEPase and forms oxalic acid, which gets changed into malic acid. `H^(+)` ions pass out of the guard cells, while `K^(+)` ions of epidermal cells pass into the guard cells `K^(+)` combine with malate. It results in absorption of water from adjacent cells, development of turgor and hence, opening of stomata. |
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148. |
Read the following statements and find out the incorrect statement.A. In diffusion, molecules move in a random fashion, the net result being substances moving from regions of higher concentration to regions of lower concen-tration.B. Diffusion is a slow process and is not dependent on a living system.C. Diffusion is obvious in gases and liquids, but diffusion of slids rather than in solids is more likely.D. Movement by diffusion is passive as no energy expenditure takes place. |
Answer» Correct Answer - C In diffusion molecules moves in a random fashion, the net result being substances moving from regions of higher concentration to regions of lower concentration. Diffusion is a slow process and is not dependent on a living system. Diffusion is obvious in gases and liquids, but diffusion in solids rather than of solids is more likely. Movement by diffusion is passive as no energy expenditure takes place. |
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149. |
Which one will reduce rate of transpiration ?A. Rise in temperature .B. Increase in water uptake .C. Decrease in relative humidity .D. Decrease in light intensity |
Answer» Correct Answer - D | |
150. |
Which of the following is produced during water stess and causes closure of stomataA. CytokininB. AuxinC. `GA(_3)`D. ABA |
Answer» Correct Answer - D |
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