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1.

`(9^(1//3)xx27^(-1//2))/(3^(1//6)xx3^(-2//3))` को सरल कीजिए ।

Answer» यहाँ
`(9^(1//3)xx27^(-1//2))/(3^(1//6)xx3^(-2//3))=(9^(1//3)xx3^(2//3))/(3^(1//6)xx27^(1//2))=((3^(2))^(1//3)xx3^(2//3))/(3^(1//6)xx(3^(3))^(1//2))`
`=(3^((2)/(3)+(2)/(3)))/(3^((1)/(6)+(3)/(2)))=(3^((4)/(3)))/(3^(((1+9))/(6)))=3^((4)/(3)-(5)/(3))=3^(-1//3)=(1)/(3^(1//3))`
Discussion
2.

निम्न को सरल कीजिए- `(i)` `(3^(2))^(3)` `(ii)` `4^(2)xx4^(3)`

Answer» `(i)` यहाँ `(3^(2))^(3)=3^(2)xx3^(2)xx3^(2)=3^(6)=(3xx3)xx(3xx3)xx(3xx3)=729`
`(ii)` `4^(2)xx4^(3)=4^(2+3)=4^(5)=4xx4xx4xx4xx4=1024`
`(iii)` `((11)/(12))^(3)=((11)^(3))/((12)^(3))=(11xx11xx11)/(12xx12xx12)=(1331)/(1728)`
Discussion