

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
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A source is moving towards the observer with the speed of 40 m/s and emitting the sound of frequency 100 Hz. Find the observed frequency by standing observer if the velocity of propagation of sound is 340 m/s.1. 89 Hz2. 113 Hz3. 110 Hz4. 230 Hz |
Answer» Correct Answer - Option 2 : 113 Hz CONCEPT:
Theapparent frequencyheard by the observer is given by the formula: \(f=f_0\left ( \frac{v\pm v_o}{v \pm v_s} \right )\) where f is apparent frequency, f0is the original frequency of the source, v is the speed of sound in air, vsis the speed of the source, vois the speed of the observer. CALCULATION: Given that v = 340 m/s; vs= 40m/s (-ve) moving towards; v0= 0; f = 100 Hz \(f=f_0\left ( \frac{v\pm v_o}{v \pm v_s} \right )\) \(f=100\times \left ( \frac{340}{340-40} \right )\) f = 340/3Hz = 113 Hz So the correct answer isoption 2. |
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