If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is (A) (1000/√2π).e-25 (B) 1000/√2π (C) (1000/√2π ).e-2.5 (D) 400/√2π
If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is (A) (1000/√2π).e-25 (B) 1000/√2π (C) (1000/√2π ).e-2.5 (D) 400/√2π
nan